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What would happen if you robbed the momentum from a falling object?


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In my world, some individuals have the ability to absorb and distribute momentum from sources around them. I am considering what would happen physically if someone was taking all of the momentum from a falling object (like a rock for example). My question is, would the falling object just stop midair or would it keep falling slowly?



I ask this question as if the object is stopped completely couldn't this magic user just have an unlimited power source from continuously absorbing the gravitational force on the object?










share|improve this question







New contributor



Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$














  • $begingroup$
    Hi Whitty, welcome to Worldbuilding! Magic and science don't coexist together very well, so potentially it can work either way. If the wording of your question is to be followed literally, then the speed would be nullified, but the gravity would be not.
    $endgroup$
    – Alexander
    9 hours ago










  • $begingroup$
    How much are we stealing here? Are you just applying a counter force to stop it? Or are you literally pulling all energy out of the object, which would result in the object getting colder.
    $endgroup$
    – Trevor
    9 hours ago










  • $begingroup$
    Does the momentum get conserved? Then the momentum thief needs to put that momentum somewhere. If he tries to absorb it into himself he gets crushed like the rock hit him. Or does this magic make the momentum go away? Then the magic is doing something outside normal physics.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    Also, it's usually good form to wait a day or two before you assign the green check mark. That gives the possibility of several answers.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    @Trevor I know this isn't accurate with physics, but in my magic system the different "forms" of energy, such as kinetic and thermal are separate. Depending on how talented the individual is the more energy they could pull out and use.
    $endgroup$
    – Whitty
    8 hours ago


















4












$begingroup$


In my world, some individuals have the ability to absorb and distribute momentum from sources around them. I am considering what would happen physically if someone was taking all of the momentum from a falling object (like a rock for example). My question is, would the falling object just stop midair or would it keep falling slowly?



I ask this question as if the object is stopped completely couldn't this magic user just have an unlimited power source from continuously absorbing the gravitational force on the object?










share|improve this question







New contributor



Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$














  • $begingroup$
    Hi Whitty, welcome to Worldbuilding! Magic and science don't coexist together very well, so potentially it can work either way. If the wording of your question is to be followed literally, then the speed would be nullified, but the gravity would be not.
    $endgroup$
    – Alexander
    9 hours ago










  • $begingroup$
    How much are we stealing here? Are you just applying a counter force to stop it? Or are you literally pulling all energy out of the object, which would result in the object getting colder.
    $endgroup$
    – Trevor
    9 hours ago










  • $begingroup$
    Does the momentum get conserved? Then the momentum thief needs to put that momentum somewhere. If he tries to absorb it into himself he gets crushed like the rock hit him. Or does this magic make the momentum go away? Then the magic is doing something outside normal physics.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    Also, it's usually good form to wait a day or two before you assign the green check mark. That gives the possibility of several answers.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    @Trevor I know this isn't accurate with physics, but in my magic system the different "forms" of energy, such as kinetic and thermal are separate. Depending on how talented the individual is the more energy they could pull out and use.
    $endgroup$
    – Whitty
    8 hours ago














4












4








4





$begingroup$


In my world, some individuals have the ability to absorb and distribute momentum from sources around them. I am considering what would happen physically if someone was taking all of the momentum from a falling object (like a rock for example). My question is, would the falling object just stop midair or would it keep falling slowly?



I ask this question as if the object is stopped completely couldn't this magic user just have an unlimited power source from continuously absorbing the gravitational force on the object?










share|improve this question







New contributor



Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




In my world, some individuals have the ability to absorb and distribute momentum from sources around them. I am considering what would happen physically if someone was taking all of the momentum from a falling object (like a rock for example). My question is, would the falling object just stop midair or would it keep falling slowly?



I ask this question as if the object is stopped completely couldn't this magic user just have an unlimited power source from continuously absorbing the gravitational force on the object?







magic physics






share|improve this question







New contributor



Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question







New contributor



Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question






New contributor



Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 9 hours ago









WhittyWhitty

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214 bronze badges




New contributor



Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Whitty is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















  • $begingroup$
    Hi Whitty, welcome to Worldbuilding! Magic and science don't coexist together very well, so potentially it can work either way. If the wording of your question is to be followed literally, then the speed would be nullified, but the gravity would be not.
    $endgroup$
    – Alexander
    9 hours ago










  • $begingroup$
    How much are we stealing here? Are you just applying a counter force to stop it? Or are you literally pulling all energy out of the object, which would result in the object getting colder.
    $endgroup$
    – Trevor
    9 hours ago










  • $begingroup$
    Does the momentum get conserved? Then the momentum thief needs to put that momentum somewhere. If he tries to absorb it into himself he gets crushed like the rock hit him. Or does this magic make the momentum go away? Then the magic is doing something outside normal physics.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    Also, it's usually good form to wait a day or two before you assign the green check mark. That gives the possibility of several answers.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    @Trevor I know this isn't accurate with physics, but in my magic system the different "forms" of energy, such as kinetic and thermal are separate. Depending on how talented the individual is the more energy they could pull out and use.
    $endgroup$
    – Whitty
    8 hours ago


















  • $begingroup$
    Hi Whitty, welcome to Worldbuilding! Magic and science don't coexist together very well, so potentially it can work either way. If the wording of your question is to be followed literally, then the speed would be nullified, but the gravity would be not.
    $endgroup$
    – Alexander
    9 hours ago










  • $begingroup$
    How much are we stealing here? Are you just applying a counter force to stop it? Or are you literally pulling all energy out of the object, which would result in the object getting colder.
    $endgroup$
    – Trevor
    9 hours ago










  • $begingroup$
    Does the momentum get conserved? Then the momentum thief needs to put that momentum somewhere. If he tries to absorb it into himself he gets crushed like the rock hit him. Or does this magic make the momentum go away? Then the magic is doing something outside normal physics.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    Also, it's usually good form to wait a day or two before you assign the green check mark. That gives the possibility of several answers.
    $endgroup$
    – puppetsock
    8 hours ago










  • $begingroup$
    @Trevor I know this isn't accurate with physics, but in my magic system the different "forms" of energy, such as kinetic and thermal are separate. Depending on how talented the individual is the more energy they could pull out and use.
    $endgroup$
    – Whitty
    8 hours ago
















$begingroup$
Hi Whitty, welcome to Worldbuilding! Magic and science don't coexist together very well, so potentially it can work either way. If the wording of your question is to be followed literally, then the speed would be nullified, but the gravity would be not.
$endgroup$
– Alexander
9 hours ago




$begingroup$
Hi Whitty, welcome to Worldbuilding! Magic and science don't coexist together very well, so potentially it can work either way. If the wording of your question is to be followed literally, then the speed would be nullified, but the gravity would be not.
$endgroup$
– Alexander
9 hours ago












$begingroup$
How much are we stealing here? Are you just applying a counter force to stop it? Or are you literally pulling all energy out of the object, which would result in the object getting colder.
$endgroup$
– Trevor
9 hours ago




$begingroup$
How much are we stealing here? Are you just applying a counter force to stop it? Or are you literally pulling all energy out of the object, which would result in the object getting colder.
$endgroup$
– Trevor
9 hours ago












$begingroup$
Does the momentum get conserved? Then the momentum thief needs to put that momentum somewhere. If he tries to absorb it into himself he gets crushed like the rock hit him. Or does this magic make the momentum go away? Then the magic is doing something outside normal physics.
$endgroup$
– puppetsock
8 hours ago




$begingroup$
Does the momentum get conserved? Then the momentum thief needs to put that momentum somewhere. If he tries to absorb it into himself he gets crushed like the rock hit him. Or does this magic make the momentum go away? Then the magic is doing something outside normal physics.
$endgroup$
– puppetsock
8 hours ago












$begingroup$
Also, it's usually good form to wait a day or two before you assign the green check mark. That gives the possibility of several answers.
$endgroup$
– puppetsock
8 hours ago




$begingroup$
Also, it's usually good form to wait a day or two before you assign the green check mark. That gives the possibility of several answers.
$endgroup$
– puppetsock
8 hours ago












$begingroup$
@Trevor I know this isn't accurate with physics, but in my magic system the different "forms" of energy, such as kinetic and thermal are separate. Depending on how talented the individual is the more energy they could pull out and use.
$endgroup$
– Whitty
8 hours ago




$begingroup$
@Trevor I know this isn't accurate with physics, but in my magic system the different "forms" of energy, such as kinetic and thermal are separate. Depending on how talented the individual is the more energy they could pull out and use.
$endgroup$
– Whitty
8 hours ago










3 Answers
3






active

oldest

votes


















5














$begingroup$

A falling object has momentum proportional to its mass and velocity ($p = mv$). If a person could magically absorb that momentum, they could decrease it to 0 by reducing the velocity to 0. The object would stop, but at that point it would have no more momentum to absorb. They could then let the object fall again, accumulating more momentum, before harvesting the momentum and bringing it back to 0. Alternatively, you could partially harvest the momentum at any point, causing the object to decelerate but not stop. You can't continuously harvest momentum from a stationary object, since it has zero momentum to begin with.



In short, you can harvest momentum though a series of drops with full stops, or do it continuously by causing the object to fall slower than it would under gravity alone. But you can't get momentum out of a stationary object - as you point out, this would be an unlimited source of energy (i.e. a perpetual motion machine). As an example, a hydroelectric dam generates no power by simply holding the reservoir upstream - it generates power by allowing some of the water to fall and harvesting its kinetic energy.






share|improve this answer











$endgroup$















  • $begingroup$
    A falling object has momentum $vec p = m vec v$ with respect to Earth. But the question says nothing about the frame of reference in which the ungodly magicians operate. It has a different and larger momentum with respect to the Sun. It has a different and much smaller momentum relative to other falling objects. If the magician is running, the falling object will have a different momentum relative to the magician. Mechanics does not define an absolute value for the momentum of an object; all it says is that the total momentum of an isolated system is constant with respect to an intertial.
    $endgroup$
    – AlexP
    7 hours ago












  • $begingroup$
    @AlexP Excellent point. I figure the wizard would have to harvest momentum with respect to him/herself, which would generally be the same as the earth's reference frame. But if that's not the case, the wizard can indeed perform some interesting and seemingly physics-defying feats.
    $endgroup$
    – Nuclear Wang
    6 hours ago










  • $begingroup$
    @AlexP Momentum is typically talked about within a single reference frame. It doesn't matter which frame you use, momentum will be conserved in that frame. However, if there was a "preferred frame," like if the people who thought light propagated through aether were right, then you might be onto something
    $endgroup$
    – Cort Ammon
    4 mins ago



















1














$begingroup$

Momentum is p=mv. V is velocity. I have to ask you:Velocity relative to what? For example, Earth is around you, and has quite a lot of momentum. Assuming that your character can absorb Earth's momentum and redistribute it to much smaller things around him you can use a very small fraction of Earth's momentum to accelerate, say, a stone, to velocities, where very intersting things happen.



"But won't Earth fall into the sun if it loses all its velocity" - Once again, frame of reference matters: Is the Sun the frame of reference? If it is Earth will become a static object at zero m/s relative to the sun, neither falling nor orbiting. Maybe that will slowly disturb the other planets orbits?. If the frame of reference is, say, the galaxy, then earth will eventually leave the solar system as it stays behind. Not good.






share|improve this answer









$endgroup$























    1














    $begingroup$

    You already have a great set of answers here: I'd just like to give you some insight into why this is the way physics is.



    Objects falling under gravity have a constant force and a varying momentum. As pointed out by @Nuclear Wang and @Geronimo,



    $ Momentum = mass * velocity $



    But force:



    $ F = mass * acceleration
    = mass * frac{v-u}{time}$



    where v is your final velocity and u is your initial velocity.



    When you rob an object of momentum, you do not rob it of acceleration. You simply set its velocity to 0. So if you did this once your object would stop for a moment in mid air before beginning to accelerate again due to gravity.



    If you prefer a mathematical proof:



    $ Distance~~Travelled = (u*time) + frac{1}{2}*acceleration*time^2 $



    The equation above (which was devised by Newton) shows that taking away momentum (which is just speed) doesn't stop an object. Newton demands you deal with acceleration too.



    To answer your question, you need to travel towards the source of gravity every so slightly to generate momentum, so you can't harness this forever.
    One final piece of math:



    $ Distance~~Travelled = frac{(final~~velocity)^2-(starting~~velocity)^2}{2 * grav~acceleration} $



    If the distance travelled is zero, you haven't changed your velocity (which is zero when you're holding the object in the air). If your velocity is zero, your momentum is zero. Gotta give if you wanna get.



    By the way, your comment on splitting up 'magical energies' actually has some bases in science. It's widely hypothesised, if not believed, that every force in our universe is some combination of these four. Electromagnetic covers heat, magnets, electricity and light. Graviton for gravity, and the strong nuclear holds protons and neutrons together in the atomic shell. The weak nuclear is responsible for some flukey stuff, and honestly you won't deepen your world knowledge by reading into it. Freel free to though.






    share|improve this answer










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    mcRobusta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      5














      $begingroup$

      A falling object has momentum proportional to its mass and velocity ($p = mv$). If a person could magically absorb that momentum, they could decrease it to 0 by reducing the velocity to 0. The object would stop, but at that point it would have no more momentum to absorb. They could then let the object fall again, accumulating more momentum, before harvesting the momentum and bringing it back to 0. Alternatively, you could partially harvest the momentum at any point, causing the object to decelerate but not stop. You can't continuously harvest momentum from a stationary object, since it has zero momentum to begin with.



      In short, you can harvest momentum though a series of drops with full stops, or do it continuously by causing the object to fall slower than it would under gravity alone. But you can't get momentum out of a stationary object - as you point out, this would be an unlimited source of energy (i.e. a perpetual motion machine). As an example, a hydroelectric dam generates no power by simply holding the reservoir upstream - it generates power by allowing some of the water to fall and harvesting its kinetic energy.






      share|improve this answer











      $endgroup$















      • $begingroup$
        A falling object has momentum $vec p = m vec v$ with respect to Earth. But the question says nothing about the frame of reference in which the ungodly magicians operate. It has a different and larger momentum with respect to the Sun. It has a different and much smaller momentum relative to other falling objects. If the magician is running, the falling object will have a different momentum relative to the magician. Mechanics does not define an absolute value for the momentum of an object; all it says is that the total momentum of an isolated system is constant with respect to an intertial.
        $endgroup$
        – AlexP
        7 hours ago












      • $begingroup$
        @AlexP Excellent point. I figure the wizard would have to harvest momentum with respect to him/herself, which would generally be the same as the earth's reference frame. But if that's not the case, the wizard can indeed perform some interesting and seemingly physics-defying feats.
        $endgroup$
        – Nuclear Wang
        6 hours ago










      • $begingroup$
        @AlexP Momentum is typically talked about within a single reference frame. It doesn't matter which frame you use, momentum will be conserved in that frame. However, if there was a "preferred frame," like if the people who thought light propagated through aether were right, then you might be onto something
        $endgroup$
        – Cort Ammon
        4 mins ago
















      5














      $begingroup$

      A falling object has momentum proportional to its mass and velocity ($p = mv$). If a person could magically absorb that momentum, they could decrease it to 0 by reducing the velocity to 0. The object would stop, but at that point it would have no more momentum to absorb. They could then let the object fall again, accumulating more momentum, before harvesting the momentum and bringing it back to 0. Alternatively, you could partially harvest the momentum at any point, causing the object to decelerate but not stop. You can't continuously harvest momentum from a stationary object, since it has zero momentum to begin with.



      In short, you can harvest momentum though a series of drops with full stops, or do it continuously by causing the object to fall slower than it would under gravity alone. But you can't get momentum out of a stationary object - as you point out, this would be an unlimited source of energy (i.e. a perpetual motion machine). As an example, a hydroelectric dam generates no power by simply holding the reservoir upstream - it generates power by allowing some of the water to fall and harvesting its kinetic energy.






      share|improve this answer











      $endgroup$















      • $begingroup$
        A falling object has momentum $vec p = m vec v$ with respect to Earth. But the question says nothing about the frame of reference in which the ungodly magicians operate. It has a different and larger momentum with respect to the Sun. It has a different and much smaller momentum relative to other falling objects. If the magician is running, the falling object will have a different momentum relative to the magician. Mechanics does not define an absolute value for the momentum of an object; all it says is that the total momentum of an isolated system is constant with respect to an intertial.
        $endgroup$
        – AlexP
        7 hours ago












      • $begingroup$
        @AlexP Excellent point. I figure the wizard would have to harvest momentum with respect to him/herself, which would generally be the same as the earth's reference frame. But if that's not the case, the wizard can indeed perform some interesting and seemingly physics-defying feats.
        $endgroup$
        – Nuclear Wang
        6 hours ago










      • $begingroup$
        @AlexP Momentum is typically talked about within a single reference frame. It doesn't matter which frame you use, momentum will be conserved in that frame. However, if there was a "preferred frame," like if the people who thought light propagated through aether were right, then you might be onto something
        $endgroup$
        – Cort Ammon
        4 mins ago














      5














      5










      5







      $begingroup$

      A falling object has momentum proportional to its mass and velocity ($p = mv$). If a person could magically absorb that momentum, they could decrease it to 0 by reducing the velocity to 0. The object would stop, but at that point it would have no more momentum to absorb. They could then let the object fall again, accumulating more momentum, before harvesting the momentum and bringing it back to 0. Alternatively, you could partially harvest the momentum at any point, causing the object to decelerate but not stop. You can't continuously harvest momentum from a stationary object, since it has zero momentum to begin with.



      In short, you can harvest momentum though a series of drops with full stops, or do it continuously by causing the object to fall slower than it would under gravity alone. But you can't get momentum out of a stationary object - as you point out, this would be an unlimited source of energy (i.e. a perpetual motion machine). As an example, a hydroelectric dam generates no power by simply holding the reservoir upstream - it generates power by allowing some of the water to fall and harvesting its kinetic energy.






      share|improve this answer











      $endgroup$



      A falling object has momentum proportional to its mass and velocity ($p = mv$). If a person could magically absorb that momentum, they could decrease it to 0 by reducing the velocity to 0. The object would stop, but at that point it would have no more momentum to absorb. They could then let the object fall again, accumulating more momentum, before harvesting the momentum and bringing it back to 0. Alternatively, you could partially harvest the momentum at any point, causing the object to decelerate but not stop. You can't continuously harvest momentum from a stationary object, since it has zero momentum to begin with.



      In short, you can harvest momentum though a series of drops with full stops, or do it continuously by causing the object to fall slower than it would under gravity alone. But you can't get momentum out of a stationary object - as you point out, this would be an unlimited source of energy (i.e. a perpetual motion machine). As an example, a hydroelectric dam generates no power by simply holding the reservoir upstream - it generates power by allowing some of the water to fall and harvesting its kinetic energy.







      share|improve this answer














      share|improve this answer



      share|improve this answer








      edited 9 hours ago

























      answered 9 hours ago









      Nuclear WangNuclear Wang

      3,2382 gold badges10 silver badges16 bronze badges




      3,2382 gold badges10 silver badges16 bronze badges















      • $begingroup$
        A falling object has momentum $vec p = m vec v$ with respect to Earth. But the question says nothing about the frame of reference in which the ungodly magicians operate. It has a different and larger momentum with respect to the Sun. It has a different and much smaller momentum relative to other falling objects. If the magician is running, the falling object will have a different momentum relative to the magician. Mechanics does not define an absolute value for the momentum of an object; all it says is that the total momentum of an isolated system is constant with respect to an intertial.
        $endgroup$
        – AlexP
        7 hours ago












      • $begingroup$
        @AlexP Excellent point. I figure the wizard would have to harvest momentum with respect to him/herself, which would generally be the same as the earth's reference frame. But if that's not the case, the wizard can indeed perform some interesting and seemingly physics-defying feats.
        $endgroup$
        – Nuclear Wang
        6 hours ago










      • $begingroup$
        @AlexP Momentum is typically talked about within a single reference frame. It doesn't matter which frame you use, momentum will be conserved in that frame. However, if there was a "preferred frame," like if the people who thought light propagated through aether were right, then you might be onto something
        $endgroup$
        – Cort Ammon
        4 mins ago


















      • $begingroup$
        A falling object has momentum $vec p = m vec v$ with respect to Earth. But the question says nothing about the frame of reference in which the ungodly magicians operate. It has a different and larger momentum with respect to the Sun. It has a different and much smaller momentum relative to other falling objects. If the magician is running, the falling object will have a different momentum relative to the magician. Mechanics does not define an absolute value for the momentum of an object; all it says is that the total momentum of an isolated system is constant with respect to an intertial.
        $endgroup$
        – AlexP
        7 hours ago












      • $begingroup$
        @AlexP Excellent point. I figure the wizard would have to harvest momentum with respect to him/herself, which would generally be the same as the earth's reference frame. But if that's not the case, the wizard can indeed perform some interesting and seemingly physics-defying feats.
        $endgroup$
        – Nuclear Wang
        6 hours ago










      • $begingroup$
        @AlexP Momentum is typically talked about within a single reference frame. It doesn't matter which frame you use, momentum will be conserved in that frame. However, if there was a "preferred frame," like if the people who thought light propagated through aether were right, then you might be onto something
        $endgroup$
        – Cort Ammon
        4 mins ago
















      $begingroup$
      A falling object has momentum $vec p = m vec v$ with respect to Earth. But the question says nothing about the frame of reference in which the ungodly magicians operate. It has a different and larger momentum with respect to the Sun. It has a different and much smaller momentum relative to other falling objects. If the magician is running, the falling object will have a different momentum relative to the magician. Mechanics does not define an absolute value for the momentum of an object; all it says is that the total momentum of an isolated system is constant with respect to an intertial.
      $endgroup$
      – AlexP
      7 hours ago






      $begingroup$
      A falling object has momentum $vec p = m vec v$ with respect to Earth. But the question says nothing about the frame of reference in which the ungodly magicians operate. It has a different and larger momentum with respect to the Sun. It has a different and much smaller momentum relative to other falling objects. If the magician is running, the falling object will have a different momentum relative to the magician. Mechanics does not define an absolute value for the momentum of an object; all it says is that the total momentum of an isolated system is constant with respect to an intertial.
      $endgroup$
      – AlexP
      7 hours ago














      $begingroup$
      @AlexP Excellent point. I figure the wizard would have to harvest momentum with respect to him/herself, which would generally be the same as the earth's reference frame. But if that's not the case, the wizard can indeed perform some interesting and seemingly physics-defying feats.
      $endgroup$
      – Nuclear Wang
      6 hours ago




      $begingroup$
      @AlexP Excellent point. I figure the wizard would have to harvest momentum with respect to him/herself, which would generally be the same as the earth's reference frame. But if that's not the case, the wizard can indeed perform some interesting and seemingly physics-defying feats.
      $endgroup$
      – Nuclear Wang
      6 hours ago












      $begingroup$
      @AlexP Momentum is typically talked about within a single reference frame. It doesn't matter which frame you use, momentum will be conserved in that frame. However, if there was a "preferred frame," like if the people who thought light propagated through aether were right, then you might be onto something
      $endgroup$
      – Cort Ammon
      4 mins ago




      $begingroup$
      @AlexP Momentum is typically talked about within a single reference frame. It doesn't matter which frame you use, momentum will be conserved in that frame. However, if there was a "preferred frame," like if the people who thought light propagated through aether were right, then you might be onto something
      $endgroup$
      – Cort Ammon
      4 mins ago













      1














      $begingroup$

      Momentum is p=mv. V is velocity. I have to ask you:Velocity relative to what? For example, Earth is around you, and has quite a lot of momentum. Assuming that your character can absorb Earth's momentum and redistribute it to much smaller things around him you can use a very small fraction of Earth's momentum to accelerate, say, a stone, to velocities, where very intersting things happen.



      "But won't Earth fall into the sun if it loses all its velocity" - Once again, frame of reference matters: Is the Sun the frame of reference? If it is Earth will become a static object at zero m/s relative to the sun, neither falling nor orbiting. Maybe that will slowly disturb the other planets orbits?. If the frame of reference is, say, the galaxy, then earth will eventually leave the solar system as it stays behind. Not good.






      share|improve this answer









      $endgroup$




















        1














        $begingroup$

        Momentum is p=mv. V is velocity. I have to ask you:Velocity relative to what? For example, Earth is around you, and has quite a lot of momentum. Assuming that your character can absorb Earth's momentum and redistribute it to much smaller things around him you can use a very small fraction of Earth's momentum to accelerate, say, a stone, to velocities, where very intersting things happen.



        "But won't Earth fall into the sun if it loses all its velocity" - Once again, frame of reference matters: Is the Sun the frame of reference? If it is Earth will become a static object at zero m/s relative to the sun, neither falling nor orbiting. Maybe that will slowly disturb the other planets orbits?. If the frame of reference is, say, the galaxy, then earth will eventually leave the solar system as it stays behind. Not good.






        share|improve this answer









        $endgroup$


















          1














          1










          1







          $begingroup$

          Momentum is p=mv. V is velocity. I have to ask you:Velocity relative to what? For example, Earth is around you, and has quite a lot of momentum. Assuming that your character can absorb Earth's momentum and redistribute it to much smaller things around him you can use a very small fraction of Earth's momentum to accelerate, say, a stone, to velocities, where very intersting things happen.



          "But won't Earth fall into the sun if it loses all its velocity" - Once again, frame of reference matters: Is the Sun the frame of reference? If it is Earth will become a static object at zero m/s relative to the sun, neither falling nor orbiting. Maybe that will slowly disturb the other planets orbits?. If the frame of reference is, say, the galaxy, then earth will eventually leave the solar system as it stays behind. Not good.






          share|improve this answer









          $endgroup$



          Momentum is p=mv. V is velocity. I have to ask you:Velocity relative to what? For example, Earth is around you, and has quite a lot of momentum. Assuming that your character can absorb Earth's momentum and redistribute it to much smaller things around him you can use a very small fraction of Earth's momentum to accelerate, say, a stone, to velocities, where very intersting things happen.



          "But won't Earth fall into the sun if it loses all its velocity" - Once again, frame of reference matters: Is the Sun the frame of reference? If it is Earth will become a static object at zero m/s relative to the sun, neither falling nor orbiting. Maybe that will slowly disturb the other planets orbits?. If the frame of reference is, say, the galaxy, then earth will eventually leave the solar system as it stays behind. Not good.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 7 hours ago









          GeronimoGeronimo

          1,4814 silver badges14 bronze badges




          1,4814 silver badges14 bronze badges


























              1














              $begingroup$

              You already have a great set of answers here: I'd just like to give you some insight into why this is the way physics is.



              Objects falling under gravity have a constant force and a varying momentum. As pointed out by @Nuclear Wang and @Geronimo,



              $ Momentum = mass * velocity $



              But force:



              $ F = mass * acceleration
              = mass * frac{v-u}{time}$



              where v is your final velocity and u is your initial velocity.



              When you rob an object of momentum, you do not rob it of acceleration. You simply set its velocity to 0. So if you did this once your object would stop for a moment in mid air before beginning to accelerate again due to gravity.



              If you prefer a mathematical proof:



              $ Distance~~Travelled = (u*time) + frac{1}{2}*acceleration*time^2 $



              The equation above (which was devised by Newton) shows that taking away momentum (which is just speed) doesn't stop an object. Newton demands you deal with acceleration too.



              To answer your question, you need to travel towards the source of gravity every so slightly to generate momentum, so you can't harness this forever.
              One final piece of math:



              $ Distance~~Travelled = frac{(final~~velocity)^2-(starting~~velocity)^2}{2 * grav~acceleration} $



              If the distance travelled is zero, you haven't changed your velocity (which is zero when you're holding the object in the air). If your velocity is zero, your momentum is zero. Gotta give if you wanna get.



              By the way, your comment on splitting up 'magical energies' actually has some bases in science. It's widely hypothesised, if not believed, that every force in our universe is some combination of these four. Electromagnetic covers heat, magnets, electricity and light. Graviton for gravity, and the strong nuclear holds protons and neutrons together in the atomic shell. The weak nuclear is responsible for some flukey stuff, and honestly you won't deepen your world knowledge by reading into it. Freel free to though.






              share|improve this answer










              New contributor



              mcRobusta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





              $endgroup$




















                1














                $begingroup$

                You already have a great set of answers here: I'd just like to give you some insight into why this is the way physics is.



                Objects falling under gravity have a constant force and a varying momentum. As pointed out by @Nuclear Wang and @Geronimo,



                $ Momentum = mass * velocity $



                But force:



                $ F = mass * acceleration
                = mass * frac{v-u}{time}$



                where v is your final velocity and u is your initial velocity.



                When you rob an object of momentum, you do not rob it of acceleration. You simply set its velocity to 0. So if you did this once your object would stop for a moment in mid air before beginning to accelerate again due to gravity.



                If you prefer a mathematical proof:



                $ Distance~~Travelled = (u*time) + frac{1}{2}*acceleration*time^2 $



                The equation above (which was devised by Newton) shows that taking away momentum (which is just speed) doesn't stop an object. Newton demands you deal with acceleration too.



                To answer your question, you need to travel towards the source of gravity every so slightly to generate momentum, so you can't harness this forever.
                One final piece of math:



                $ Distance~~Travelled = frac{(final~~velocity)^2-(starting~~velocity)^2}{2 * grav~acceleration} $



                If the distance travelled is zero, you haven't changed your velocity (which is zero when you're holding the object in the air). If your velocity is zero, your momentum is zero. Gotta give if you wanna get.



                By the way, your comment on splitting up 'magical energies' actually has some bases in science. It's widely hypothesised, if not believed, that every force in our universe is some combination of these four. Electromagnetic covers heat, magnets, electricity and light. Graviton for gravity, and the strong nuclear holds protons and neutrons together in the atomic shell. The weak nuclear is responsible for some flukey stuff, and honestly you won't deepen your world knowledge by reading into it. Freel free to though.






                share|improve this answer










                New contributor



                mcRobusta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                $endgroup$


















                  1














                  1










                  1







                  $begingroup$

                  You already have a great set of answers here: I'd just like to give you some insight into why this is the way physics is.



                  Objects falling under gravity have a constant force and a varying momentum. As pointed out by @Nuclear Wang and @Geronimo,



                  $ Momentum = mass * velocity $



                  But force:



                  $ F = mass * acceleration
                  = mass * frac{v-u}{time}$



                  where v is your final velocity and u is your initial velocity.



                  When you rob an object of momentum, you do not rob it of acceleration. You simply set its velocity to 0. So if you did this once your object would stop for a moment in mid air before beginning to accelerate again due to gravity.



                  If you prefer a mathematical proof:



                  $ Distance~~Travelled = (u*time) + frac{1}{2}*acceleration*time^2 $



                  The equation above (which was devised by Newton) shows that taking away momentum (which is just speed) doesn't stop an object. Newton demands you deal with acceleration too.



                  To answer your question, you need to travel towards the source of gravity every so slightly to generate momentum, so you can't harness this forever.
                  One final piece of math:



                  $ Distance~~Travelled = frac{(final~~velocity)^2-(starting~~velocity)^2}{2 * grav~acceleration} $



                  If the distance travelled is zero, you haven't changed your velocity (which is zero when you're holding the object in the air). If your velocity is zero, your momentum is zero. Gotta give if you wanna get.



                  By the way, your comment on splitting up 'magical energies' actually has some bases in science. It's widely hypothesised, if not believed, that every force in our universe is some combination of these four. Electromagnetic covers heat, magnets, electricity and light. Graviton for gravity, and the strong nuclear holds protons and neutrons together in the atomic shell. The weak nuclear is responsible for some flukey stuff, and honestly you won't deepen your world knowledge by reading into it. Freel free to though.






                  share|improve this answer










                  New contributor



                  mcRobusta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  $endgroup$



                  You already have a great set of answers here: I'd just like to give you some insight into why this is the way physics is.



                  Objects falling under gravity have a constant force and a varying momentum. As pointed out by @Nuclear Wang and @Geronimo,



                  $ Momentum = mass * velocity $



                  But force:



                  $ F = mass * acceleration
                  = mass * frac{v-u}{time}$



                  where v is your final velocity and u is your initial velocity.



                  When you rob an object of momentum, you do not rob it of acceleration. You simply set its velocity to 0. So if you did this once your object would stop for a moment in mid air before beginning to accelerate again due to gravity.



                  If you prefer a mathematical proof:



                  $ Distance~~Travelled = (u*time) + frac{1}{2}*acceleration*time^2 $



                  The equation above (which was devised by Newton) shows that taking away momentum (which is just speed) doesn't stop an object. Newton demands you deal with acceleration too.



                  To answer your question, you need to travel towards the source of gravity every so slightly to generate momentum, so you can't harness this forever.
                  One final piece of math:



                  $ Distance~~Travelled = frac{(final~~velocity)^2-(starting~~velocity)^2}{2 * grav~acceleration} $



                  If the distance travelled is zero, you haven't changed your velocity (which is zero when you're holding the object in the air). If your velocity is zero, your momentum is zero. Gotta give if you wanna get.



                  By the way, your comment on splitting up 'magical energies' actually has some bases in science. It's widely hypothesised, if not believed, that every force in our universe is some combination of these four. Electromagnetic covers heat, magnets, electricity and light. Graviton for gravity, and the strong nuclear holds protons and neutrons together in the atomic shell. The weak nuclear is responsible for some flukey stuff, and honestly you won't deepen your world knowledge by reading into it. Freel free to though.







                  share|improve this answer










                  New contributor



                  mcRobusta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.








                  share|improve this answer



                  share|improve this answer








                  edited 7 hours ago





















                  New contributor



                  mcRobusta is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.








                  answered 7 hours ago









                  mcRobustamcRobusta

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                  6211 silver badge6 bronze badges




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                  Check out our Code of Conduct.




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