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How to start and disown a process in a single line?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
2019 Community Moderator Election Results
Why I closed the “Why is Kali so hard” questionWhat happens to the output of a process that has been disowned and lost its terminal?any way to un-disown / re-attach an interactive process to the tty?How to completely detach a processCPU and Memory usage monitoring for a single processstart process (as root) upon user loginIn zsh, how can I more quickly disown the foreground process?Why the kernel kills my process with disown when I logout?How can I detach a process from a bash script?bash - How to make a process works while Skype is workingWhy do I still receive stdout or stderr after disowning a process?





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I noticed that many times I need to start a process and disown it immediately. I trying to achieve this in a single line. Any ideas how to do it?










share|improve this question




















  • 1





    sleep 600 & disown. If it's something else you're after, add more details to your Q.

    – mosvy
    33 mins ago


















0















I noticed that many times I need to start a process and disown it immediately. I trying to achieve this in a single line. Any ideas how to do it?










share|improve this question




















  • 1





    sleep 600 & disown. If it's something else you're after, add more details to your Q.

    – mosvy
    33 mins ago














0












0








0








I noticed that many times I need to start a process and disown it immediately. I trying to achieve this in a single line. Any ideas how to do it?










share|improve this question
















I noticed that many times I need to start a process and disown it immediately. I trying to achieve this in a single line. Any ideas how to do it?







bash process disown






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 25 mins ago







Hardik Khane

















asked 35 mins ago









Hardik KhaneHardik Khane

165




165








  • 1





    sleep 600 & disown. If it's something else you're after, add more details to your Q.

    – mosvy
    33 mins ago














  • 1





    sleep 600 & disown. If it's something else you're after, add more details to your Q.

    – mosvy
    33 mins ago








1




1





sleep 600 & disown. If it's something else you're after, add more details to your Q.

– mosvy
33 mins ago





sleep 600 & disown. If it's something else you're after, add more details to your Q.

– mosvy
33 mins ago










1 Answer
1






active

oldest

votes


















0














The following works for me as desired:



intended_process & disown $!


It seems that the $! part is optional



Thanks for the suggestion @mosvy






share|improve this answer
























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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    0














    The following works for me as desired:



    intended_process & disown $!


    It seems that the $! part is optional



    Thanks for the suggestion @mosvy






    share|improve this answer




























      0














      The following works for me as desired:



      intended_process & disown $!


      It seems that the $! part is optional



      Thanks for the suggestion @mosvy






      share|improve this answer


























        0












        0








        0







        The following works for me as desired:



        intended_process & disown $!


        It seems that the $! part is optional



        Thanks for the suggestion @mosvy






        share|improve this answer













        The following works for me as desired:



        intended_process & disown $!


        It seems that the $! part is optional



        Thanks for the suggestion @mosvy







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 26 mins ago









        Hardik KhaneHardik Khane

        165




        165






























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