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Passing Bash array to Python script
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I am having problem in sending bash array problem_list to python script update_contest.py. Here is my code :
bash file :
echo $problems
declare -a problem_list
for i in $problems;
do
problem_list+=($i)
done
echo ${problem_list[@]}
python3 update_contest.py $id ${problem_list[@]}
python file:
id = (sys.argv)[1]
problem_list = (sys.argv)[2]
print(problem_list)
output in terminal :
A B C D E
A B C D E
A
As can be seen, only A is passed as argument in problem_list.
Thanks in Advance !!!
bash python
asked 20 mins ago
Pratik KalePratik Kale
11
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add a comment |
I am having problem in sending bash array problem_list to python script update_contest.py. Here is my code :
bash file :
echo $problems
declare -a problem_list
for i in $problems;
do
problem_list+=($i)
done
echo ${problem_list[@]}
python3 update_contest.py $id ${problem_list[@]}
python file:
id = (sys.argv)[1]
problem_list = (sys.argv)[2]
print(problem_list)
output in terminal :
A B C D E
A B C D E
A
As can be seen, only A is passed as argument in problem_list.
Thanks in Advance !!!
bash python
asked 20 mins ago
Pratik KalePratik Kale
11
New contributor
Pratik Kale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I am having problem in sending bash array problem_list to python script update_contest.py. Here is my code :
bash file :
echo $problems
declare -a problem_list
for i in $problems;
do
problem_list+=($i)
done
echo ${problem_list[@]}
python3 update_contest.py $id ${problem_list[@]}
python file:
id = (sys.argv)[1]
problem_list = (sys.argv)[2]
print(problem_list)
output in terminal :
A B C D E
A B C D E
A
As can be seen, only A is passed as argument in problem_list.
Thanks in Advance !!!
bash python
asked 20 mins ago
Pratik KalePratik Kale
11
New contributor
Pratik Kale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I am having problem in sending bash array problem_list to python script update_contest.py. Here is my code :
bash file :
echo $problems
declare -a problem_list
for i in $problems;
do
problem_list+=($i)
done
echo ${problem_list[@]}
python3 update_contest.py $id ${problem_list[@]}
python file:
id = (sys.argv)[1]
problem_list = (sys.argv)[2]
print(problem_list)
output in terminal :
A B C D E
A B C D E
A
As can be seen, only A is passed as argument in problem_list.
Thanks in Advance !!!
bash python
bash python
asked 20 mins ago
Pratik KalePratik Kale
11
New contributor
Pratik Kale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 20 mins ago
Pratik KalePratik Kale
11
New contributor
Pratik Kale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 13 mins ago
Pratik Kale
asked 20 mins ago
Pratik KalePratik Kale
11
New contributor
Pratik Kale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 20 mins ago
Pratik KalePratik Kale
11
asked 20 mins ago
Pratik KalePratik Kale
11
11
New contributor
Pratik Kale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Pratik Kale is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
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You are indexing the list of arguments with 2, so only returning its second element, which is the first argument.
Replace this line problem_list = (sys.argv)[2] with problem_list = sys.argv[2,-1].
https://docs.python.org/3/library/sys.html
answered 2 mins ago
aiyqmizaiyqmiz
1
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1 Answer
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1 Answer
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You are indexing the list of arguments with 2, so only returning its second element, which is the first argument.
Replace this line problem_list = (sys.argv)[2] with problem_list = sys.argv[2,-1].
https://docs.python.org/3/library/sys.html
answered 2 mins ago
aiyqmizaiyqmiz
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You are indexing the list of arguments with 2, so only returning its second element, which is the first argument.
Replace this line problem_list = (sys.argv)[2] with problem_list = sys.argv[2,-1].
https://docs.python.org/3/library/sys.html
answered 2 mins ago
aiyqmizaiyqmiz
1
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You are indexing the list of arguments with 2, so only returning its second element, which is the first argument.
Replace this line problem_list = (sys.argv)[2] with problem_list = sys.argv[2,-1].
https://docs.python.org/3/library/sys.html
answered 2 mins ago
aiyqmizaiyqmiz
1
New contributor
aiyqmiz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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You are indexing the list of arguments with 2, so only returning its second element, which is the first argument.
Replace this line problem_list = (sys.argv)[2] with problem_list = sys.argv[2,-1].
https://docs.python.org/3/library/sys.html
answered 2 mins ago
aiyqmizaiyqmiz
1
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aiyqmiz is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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answered 2 mins ago
aiyqmizaiyqmiz
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answered 2 mins ago
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answered 2 mins ago
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