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0

I found this to get user input from the command line. But it is failing into recognizing the new line characters I put into the input. Doing:

#!/bin/bash

read -e -p "Multiline input=" variable;

printf "'variable=%s'" "${variable}";

1. Typing 'multinline' on Multiline input= makes printf output 'variable=multinline'
   


2. Typing 'multi\nline' on Multiline input= makes printf output 'variable=multinline'
   

How printf can print the new line I read by read -p, i.e., output

multi
line

Instead of multinline or multinline?

Related questions:

1. What does the -p option do in the read command?


2. bash: read: how to capture 'n' (newline) character?


3. shell: read: differentiate between EOF and newline


4. https://stackoverflow.com/questions/4296108/how-do-i-add-a-line-break-for-read-command


5. Read arguments separated by newline


6. https://stackoverflow.com/questions/43190306/how-to-add-new-line-after-user-input-in-shell-scripting

bash shell posix input read

share|improve this question

asked 48 mins ago

useruser

15611 silver badge1111 bronze badges

add a comment | 

0

I found this to get user input from the command line. But it is failing into recognizing the new line characters I put into the input. Doing:

#!/bin/bash

read -e -p "Multiline input=" variable;

printf "'variable=%s'" "${variable}";

1. Typing 'multinline' on Multiline input= makes printf output 'variable=multinline'
   


2. Typing 'multi\nline' on Multiline input= makes printf output 'variable=multinline'
   

How printf can print the new line I read by read -p, i.e., output

multi
line

Instead of multinline or multinline?

Related questions:

1. What does the -p option do in the read command?


2. bash: read: how to capture 'n' (newline) character?


3. shell: read: differentiate between EOF and newline


4. https://stackoverflow.com/questions/4296108/how-do-i-add-a-line-break-for-read-command


5. Read arguments separated by newline


6. https://stackoverflow.com/questions/43190306/how-to-add-new-line-after-user-input-in-shell-scripting

bash shell posix input read

share|improve this question

asked 48 mins ago

useruser

15611 silver badge1111 bronze badges

add a comment | 

I found this to get user input from the command line. But it is failing into recognizing the new line characters I put into the input. Doing:

#!/bin/bash

read -e -p "Multiline input=" variable;

printf "'variable=%s'" "${variable}";

1. Typing 'multinline' on Multiline input= makes printf output 'variable=multinline'
   


2. Typing 'multi\nline' on Multiline input= makes printf output 'variable=multinline'
   

How printf can print the new line I read by read -p, i.e., output

multi
line

Instead of multinline or multinline?

Related questions:

1. What does the -p option do in the read command?


2. bash: read: how to capture 'n' (newline) character?


3. shell: read: differentiate between EOF and newline


4. https://stackoverflow.com/questions/4296108/how-do-i-add-a-line-break-for-read-command


5. Read arguments separated by newline


6. https://stackoverflow.com/questions/43190306/how-to-add-new-line-after-user-input-in-shell-scripting

bash shell posix input read

share|improve this question

asked 48 mins ago

useruser

15611 silver badge1111 bronze badges

#!/bin/bash

read -e -p "Multiline input=" variable;

printf "'variable=%s'" "${variable}";

share|improve this question

asked 48 mins ago

useruser

15611 silver badge1111 bronze badges

share|improve this question

asked 48 mins ago

useruser

15611 silver badge1111 bronze badges

asked 48 mins ago

useruser

15611 silver badge1111 bronze badges

asked 48 mins ago

useruser

15611 silver badge1111 bronze badges

1 Answer
1

active

oldest

votes

0

If typing in n (as in the two characters and n) is acceptable, then you can use printf to interpret it:

#!/bin/bash

IFS= read -rep "Multiline input=" variable;

printf -v variable "%b" "$variable"

printf "'variable=%s'n" "${variable}";

For example:

~ ./foo.sh

Multiline input=foonbar

'variable=foo

bar'

From the bash manual:

The backslash character ‘’ may be used to remove any special meaning
for the next character read and for line continuation.

The "line continuation" bit seems to imply you can't escape newlines unless you use a different character as the line delimiter.

share|improve this answer

answered 27 mins ago

murumuru

40.5k55 gold badges9898 silver badges172172 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if already using bash, then instead of printf %b ... the OP could use just variable=${variable//\n/$'n'} (and unlike printf -v, this will also work in ksh and mksh).
  
  – mosvy
  3 mins ago
  

  
  
  
  

add a comment | 

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0

If typing in n (as in the two characters and n) is acceptable, then you can use printf to interpret it:

#!/bin/bash

IFS= read -rep "Multiline input=" variable;

printf -v variable "%b" "$variable"

printf "'variable=%s'n" "${variable}";

For example:

~ ./foo.sh

Multiline input=foonbar

'variable=foo

bar'

From the bash manual:

The backslash character ‘’ may be used to remove any special meaning
for the next character read and for line continuation.

The "line continuation" bit seems to imply you can't escape newlines unless you use a different character as the line delimiter.

share|improve this answer

answered 27 mins ago

murumuru

40.5k55 gold badges9898 silver badges172172 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if already using bash, then instead of printf %b ... the OP could use just variable=${variable//\n/$'n'} (and unlike printf -v, this will also work in ksh and mksh).
  
  – mosvy
  3 mins ago
  

  
  
  
  

add a comment | 

0

If typing in n (as in the two characters and n) is acceptable, then you can use printf to interpret it:

#!/bin/bash

IFS= read -rep "Multiline input=" variable;

printf -v variable "%b" "$variable"

printf "'variable=%s'n" "${variable}";

For example:

~ ./foo.sh

Multiline input=foonbar

'variable=foo

bar'

From the bash manual:

The backslash character ‘’ may be used to remove any special meaning
for the next character read and for line continuation.

The "line continuation" bit seems to imply you can't escape newlines unless you use a different character as the line delimiter.

share|improve this answer

answered 27 mins ago

murumuru

40.5k55 gold badges9898 silver badges172172 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  if already using bash, then instead of printf %b ... the OP could use just variable=${variable//\n/$'n'} (and unlike printf -v, this will also work in ksh and mksh).
  
  – mosvy
  3 mins ago
  

  
  
  
  

add a comment | 

If typing in n (as in the two characters and n) is acceptable, then you can use printf to interpret it:

#!/bin/bash

IFS= read -rep "Multiline input=" variable;

printf -v variable "%b" "$variable"

printf "'variable=%s'n" "${variable}";

For example:

~ ./foo.sh

Multiline input=foonbar

'variable=foo

bar'

From the bash manual:

The backslash character ‘’ may be used to remove any special meaning
for the next character read and for line continuation.

The "line continuation" bit seems to imply you can't escape newlines unless you use a different character as the line delimiter.

share|improve this answer

answered 27 mins ago

murumuru

40.5k55 gold badges9898 silver badges172172 bronze badges

#!/bin/bash

IFS= read -rep "Multiline input=" variable;

printf -v variable "%b" "$variable"

printf "'variable=%s'n" "${variable}";

~ ./foo.sh

Multiline input=foonbar

'variable=foo

bar'

share|improve this answer

answered 27 mins ago

murumuru

40.5k55 gold badges9898 silver badges172172 bronze badges

answered 27 mins ago

murumuru

40.5k55 gold badges9898 silver badges172172 bronze badges

answered 27 mins ago

murumuru

40.5k55 gold badges9898 silver badges172172 bronze badges