Mdthbs

I'd like to create 32 small boxes next to each other that each contain its current index.

|0|1|2|3|...|31|

This code makes me trouble:

documentclass{article}

usepackage{tikz}

usetikzlibrary{positioning}



begin{document}



begin{tikzpicture}[

    node distance=0pt, 

    box/.style={outer sep=0pt, draw, thick, minimum height=0.6cm}]



    node[box](0) {0};



    foreach i in {0, 31} {                

        node[box, right=of i] (i + 1) {i+1};    

    }



    end{tikzpicture}

end{document}

I have the impression that {i+1} is not interpreted, but instead i+1 is actually written for a given i. How can I make tikz to compute i+1 and to assign the result as a name or label?

Even another solution:

documentclass[tikz, border=2mm]{standalone}

usetikzlibrary{positioning}



begin{document}



begin{tikzpicture}[

    node distance=0pt, 

    box/.style={outer sep=0pt, draw, thick, minimum height=0.6cm}]



    node[box](0) {0};



    foreach i [remember=i as lasti (initially 0), count=ni] in {1, ..., 31} {                

        node[box, right=of lasti] (ni) {ni};    

    }



    end{tikzpicture}

end{document}

A variation of Ignasi's answer where you can easily change upper and lower bound of the foreach-range.

documentclass[tikz, border=2mm]{standalone}

usetikzlibrary{positioning}



begin{document}



begin{tikzpicture}[

  node distance=0pt, 

  box/.style={outer sep=0pt, draw, thick, minimum height=0.6cm}

]

  foreach i [remember=i as lasti (initially a)] in {0, ..., 31} {

    if alasti

      node[box](i) {i};

    else

      node[box, right=of lasti](i) {i};

    fi

  }

end{tikzpicture}

end{document}

Yes, your impression is right. One way to enforce evaluation is to use numexpr.

documentclass{article}

usepackage{tikz}

usetikzlibrary{positioning}



begin{document}



begin{tikzpicture}[

    node distance=0pt, 

    box/.style={outer sep=0pt, draw, thick, minimum height=0.6cm}]



    node[box](0) {0};



    foreach i in {0,..., 31} {                

        node[box, right=of i] (thenumexpri + 1relax)

        {thenumexpri+1relax};    

    }



    end{tikzpicture}

end{document}

The less hacky way, though, is to use evaluate.

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{positioning}



begin{document}



begin{tikzpicture}[

    node distance=0pt, 

    box/.style={outer sep=0pt, draw, thick, minimum height=0.6cm}]



    node[box](0) {0};



    foreach i [evaluate=i as nexti using {int(i+1)}] in {0,..., 31} {                

        node[box, right=of i] (nexti)

        {nexti};    

    }



    end{tikzpicture}

end{document}

Here is a pic version thereof.

documentclass[tikz,border=3.14mm]{standalone}

usetikzlibrary{positioning}



begin{document}



begin{tikzpicture}[

    node distance=0pt, 

    box/.style={outer sep=0pt, draw, thick, minimum height=0.6cm},

    pics/boxrow/.style 2 args={code={

    node[box] (#1){#1};

    foreach i [evaluate=i as nexti using {int(i+1)}] in

    {#1,thenumexpr#1+1,...,#2} {                

        node[box, right=of i] (nexti)     {nexti};    

    }

    }}]

 path (0,0) pic{boxrow={0}{30}}

 (0,-1) pic{boxrow={5}{18}};

end{tikzpicture}

end{document}