Inscriptio LabyrinthicaLay out the CarpetFind the Longest Palindrome in a String by Removing...

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Inscriptio Labyrinthica

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Inscriptio Labyrinthica


Lay out the CarpetFind the Longest Palindrome in a String by Removing CharactersGenerate keyboard shortcuts for a menuCompute the specificity of a CSS selectorSwap capitalization of two stringsTwisting Words!Quine multiple timesIt's Not 2015 Anymore!Movie Title Styled StringPerfect PalindromesOdd'em out: letters






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







11












$begingroup$


In the burial place of King Silo of Asturias there is an inscription that reads SILO PRINCEPS FECIT (King Silo made this).



SILO PRINCEPS FECIT



The first letter is found in the very middle, and from there one reads by going in any non-diagonal direction radiating outward. The final letter is found on all four corners. In this challenge, you'll generalize the process to make them.



Input



A string (or equivalent), and an integer. You may make the following assumptions about the input:




  • The string will have an odd length.

  • The integer will be an odd number between 1 and one less than twice the length of the string.


Output



An inscriptio labyrinthica for the string, using the integer for the height (see models). Output should be each letter with no spaces, line break as default to your system/language.



Test cases



Note that an input of 1 or (length * 2 - 1) will result in a horizontal or vertical palindrome.



 Input: FOO, 3    Input: BAR, 1    Input: BAR, 3    Input: BAR, 5

Output: OOO Output: RABAR Output: RAR Output: R
OFO ABA A
OOO RAR B
A
R

Input: ABCDE, 5 Input: ABCDE, 3 Input: *<>v^, 5

Output: EDCDE Output: EDCBCDE ^v>v^
DCBCD DCBABCD v><>v
CBABC EDCBCDE ><*<>
DCBCD v><>v
EDCDE ^v>v^


Scoring



This is code-golf so shortest answer in bytes wins. Standard loopholes forbidden.










share|improve this question











$endgroup$








  • 1




    $begingroup$
    not totally unrelated
    $endgroup$
    – Giuseppe
    12 hours ago










  • $begingroup$
    Can the input contain spaces? If so, how should they be handled?
    $endgroup$
    – Nitrodon
    12 hours ago










  • $begingroup$
    @Nitrodon Sure, and no special handling, just treat them as any other character. So inputing A B C,1 would result in C B A B C (using a value of 1 since I can't show verticality in comments ha)
    $endgroup$
    – guifa
    12 hours ago












  • $begingroup$
    The last test case says height is 3, but the output has 5 rows.
    $endgroup$
    – RootTwo
    11 hours ago






  • 1




    $begingroup$
    May we take the width instead of the height?
    $endgroup$
    – attinat
    2 hours ago


















11












$begingroup$


In the burial place of King Silo of Asturias there is an inscription that reads SILO PRINCEPS FECIT (King Silo made this).



SILO PRINCEPS FECIT



The first letter is found in the very middle, and from there one reads by going in any non-diagonal direction radiating outward. The final letter is found on all four corners. In this challenge, you'll generalize the process to make them.



Input



A string (or equivalent), and an integer. You may make the following assumptions about the input:




  • The string will have an odd length.

  • The integer will be an odd number between 1 and one less than twice the length of the string.


Output



An inscriptio labyrinthica for the string, using the integer for the height (see models). Output should be each letter with no spaces, line break as default to your system/language.



Test cases



Note that an input of 1 or (length * 2 - 1) will result in a horizontal or vertical palindrome.



 Input: FOO, 3    Input: BAR, 1    Input: BAR, 3    Input: BAR, 5

Output: OOO Output: RABAR Output: RAR Output: R
OFO ABA A
OOO RAR B
A
R

Input: ABCDE, 5 Input: ABCDE, 3 Input: *<>v^, 5

Output: EDCDE Output: EDCBCDE ^v>v^
DCBCD DCBABCD v><>v
CBABC EDCBCDE ><*<>
DCBCD v><>v
EDCDE ^v>v^


Scoring



This is code-golf so shortest answer in bytes wins. Standard loopholes forbidden.










share|improve this question











$endgroup$








  • 1




    $begingroup$
    not totally unrelated
    $endgroup$
    – Giuseppe
    12 hours ago










  • $begingroup$
    Can the input contain spaces? If so, how should they be handled?
    $endgroup$
    – Nitrodon
    12 hours ago










  • $begingroup$
    @Nitrodon Sure, and no special handling, just treat them as any other character. So inputing A B C,1 would result in C B A B C (using a value of 1 since I can't show verticality in comments ha)
    $endgroup$
    – guifa
    12 hours ago












  • $begingroup$
    The last test case says height is 3, but the output has 5 rows.
    $endgroup$
    – RootTwo
    11 hours ago






  • 1




    $begingroup$
    May we take the width instead of the height?
    $endgroup$
    – attinat
    2 hours ago














11












11








11


1



$begingroup$


In the burial place of King Silo of Asturias there is an inscription that reads SILO PRINCEPS FECIT (King Silo made this).



SILO PRINCEPS FECIT



The first letter is found in the very middle, and from there one reads by going in any non-diagonal direction radiating outward. The final letter is found on all four corners. In this challenge, you'll generalize the process to make them.



Input



A string (or equivalent), and an integer. You may make the following assumptions about the input:




  • The string will have an odd length.

  • The integer will be an odd number between 1 and one less than twice the length of the string.


Output



An inscriptio labyrinthica for the string, using the integer for the height (see models). Output should be each letter with no spaces, line break as default to your system/language.



Test cases



Note that an input of 1 or (length * 2 - 1) will result in a horizontal or vertical palindrome.



 Input: FOO, 3    Input: BAR, 1    Input: BAR, 3    Input: BAR, 5

Output: OOO Output: RABAR Output: RAR Output: R
OFO ABA A
OOO RAR B
A
R

Input: ABCDE, 5 Input: ABCDE, 3 Input: *<>v^, 5

Output: EDCDE Output: EDCBCDE ^v>v^
DCBCD DCBABCD v><>v
CBABC EDCBCDE ><*<>
DCBCD v><>v
EDCDE ^v>v^


Scoring



This is code-golf so shortest answer in bytes wins. Standard loopholes forbidden.










share|improve this question











$endgroup$




In the burial place of King Silo of Asturias there is an inscription that reads SILO PRINCEPS FECIT (King Silo made this).



SILO PRINCEPS FECIT



The first letter is found in the very middle, and from there one reads by going in any non-diagonal direction radiating outward. The final letter is found on all four corners. In this challenge, you'll generalize the process to make them.



Input



A string (or equivalent), and an integer. You may make the following assumptions about the input:




  • The string will have an odd length.

  • The integer will be an odd number between 1 and one less than twice the length of the string.


Output



An inscriptio labyrinthica for the string, using the integer for the height (see models). Output should be each letter with no spaces, line break as default to your system/language.



Test cases



Note that an input of 1 or (length * 2 - 1) will result in a horizontal or vertical palindrome.



 Input: FOO, 3    Input: BAR, 1    Input: BAR, 3    Input: BAR, 5

Output: OOO Output: RABAR Output: RAR Output: R
OFO ABA A
OOO RAR B
A
R

Input: ABCDE, 5 Input: ABCDE, 3 Input: *<>v^, 5

Output: EDCDE Output: EDCBCDE ^v>v^
DCBCD DCBABCD v><>v
CBABC EDCBCDE ><*<>
DCBCD v><>v
EDCDE ^v>v^


Scoring



This is code-golf so shortest answer in bytes wins. Standard loopholes forbidden.







code-golf string






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 11 hours ago







guifa

















asked 12 hours ago









guifaguifa

5992 silver badges8 bronze badges




5992 silver badges8 bronze badges








  • 1




    $begingroup$
    not totally unrelated
    $endgroup$
    – Giuseppe
    12 hours ago










  • $begingroup$
    Can the input contain spaces? If so, how should they be handled?
    $endgroup$
    – Nitrodon
    12 hours ago










  • $begingroup$
    @Nitrodon Sure, and no special handling, just treat them as any other character. So inputing A B C,1 would result in C B A B C (using a value of 1 since I can't show verticality in comments ha)
    $endgroup$
    – guifa
    12 hours ago












  • $begingroup$
    The last test case says height is 3, but the output has 5 rows.
    $endgroup$
    – RootTwo
    11 hours ago






  • 1




    $begingroup$
    May we take the width instead of the height?
    $endgroup$
    – attinat
    2 hours ago














  • 1




    $begingroup$
    not totally unrelated
    $endgroup$
    – Giuseppe
    12 hours ago










  • $begingroup$
    Can the input contain spaces? If so, how should they be handled?
    $endgroup$
    – Nitrodon
    12 hours ago










  • $begingroup$
    @Nitrodon Sure, and no special handling, just treat them as any other character. So inputing A B C,1 would result in C B A B C (using a value of 1 since I can't show verticality in comments ha)
    $endgroup$
    – guifa
    12 hours ago












  • $begingroup$
    The last test case says height is 3, but the output has 5 rows.
    $endgroup$
    – RootTwo
    11 hours ago






  • 1




    $begingroup$
    May we take the width instead of the height?
    $endgroup$
    – attinat
    2 hours ago








1




1




$begingroup$
not totally unrelated
$endgroup$
– Giuseppe
12 hours ago




$begingroup$
not totally unrelated
$endgroup$
– Giuseppe
12 hours ago












$begingroup$
Can the input contain spaces? If so, how should they be handled?
$endgroup$
– Nitrodon
12 hours ago




$begingroup$
Can the input contain spaces? If so, how should they be handled?
$endgroup$
– Nitrodon
12 hours ago












$begingroup$
@Nitrodon Sure, and no special handling, just treat them as any other character. So inputing A B C,1 would result in C B A B C (using a value of 1 since I can't show verticality in comments ha)
$endgroup$
– guifa
12 hours ago






$begingroup$
@Nitrodon Sure, and no special handling, just treat them as any other character. So inputing A B C,1 would result in C B A B C (using a value of 1 since I can't show verticality in comments ha)
$endgroup$
– guifa
12 hours ago














$begingroup$
The last test case says height is 3, but the output has 5 rows.
$endgroup$
– RootTwo
11 hours ago




$begingroup$
The last test case says height is 3, but the output has 5 rows.
$endgroup$
– RootTwo
11 hours ago




1




1




$begingroup$
May we take the width instead of the height?
$endgroup$
– attinat
2 hours ago




$begingroup$
May we take the width instead of the height?
$endgroup$
– attinat
2 hours ago










6 Answers
6






active

oldest

votes


















3












$begingroup$


Charcoal, 25 19 bytes



E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η‖O←↑


Try it online! Link is to verbose version of code. Explanation:



E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η


Draw a quarter of the inscription.



‖O←↑


Reflect to complete the inscription.






share|improve this answer











$endgroup$





















    2












    $begingroup$


    Jelly, 12 bytes



    Uṡṛ‘HɗŒBŒḄZY


    Try it online!



    A dyadic link taking the string as its left and height as its right argument. Returns a string with line breaks. If a list of strings were acceptable for output, I can remove the final Y saving a byte. Interestingly the original “SILO PRINCEPS FECIT” looks to me like ASCII art of a 3D diamond when I look at it on TIO.






    share|improve this answer









    $endgroup$













    • $begingroup$
      I clicked on the try it just to see and yes, indeed, it does 3D. Weird but cool.
      $endgroup$
      – guifa
      8 hours ago



















    2












    $begingroup$


    R, 93 bytes





    function(s,H,h=H/2-.5,w=length(s)-h-1)write(s[1+outer(abs(-w:w),abs(-h:h),`+`)],"",2*w+1,,"")


    Try it online!



    Takes input as a vector of characters.



    First compute $w$ and $h$ such that the output is of size $(2w+1)times(2h+1)$.



    In the output, we want the character in position $(i,j)$ to be the $1+|i-h|+|j-w|$ th character of the input. The rest is formatting.






    share|improve this answer









    $endgroup$





















      2












      $begingroup$


      Japt -R, 19 16 bytes



      z
      ò@VÔtYVÊaU)êÃê


      Try it






      share|improve this answer









      $endgroup$





















        2












        $begingroup$


        J, 27 bytes



        ([{~]+/&(|@i:)#@[-1+])-:@<:


        Try it online!



        An example will clarify the high-level approach.



        Consider 'ABCDE' f 3



        We notice that what we seek is simply the "cross addition" table of 1 0 1 and 3 2 1 0 1 2 3, which looks like this:



        4 3 2 1 2 3 4
        3 2 1 0 1 2 3
        4 3 2 1 2 3 4


        We then pull those indexes from the original string: [{~.



        All the rest of the code is just boring arithmetic and the use of i: to construct the arguments 1 0 1 and 3 2 1 0 1 2 3.






        share|improve this answer











        $endgroup$





















          0












          $begingroup$


          Wolfram Language (Mathematica), 57 bytes



          (g=Reverse@Rest@#~Join~#&)@BlockMap[g,#,⌈#2/2⌉,1]&


          Try it online!






          share|improve this answer









          $endgroup$









          • 1




            $begingroup$
            @lirtosiast then the first g isn't evaluated the first time the function is called. Try it online!
            $endgroup$
            – attinat
            1 hour ago










          • $begingroup$
            Interesting, any idea why it appears to work when you use @@ or @@@?
            $endgroup$
            – lirtosiast
            58 mins ago










          • $begingroup$
            @lirtosiast It think Print/@f[...] -> Print/@Transpose[g[...]] -> Transpose[Print@g[...]], by which time g is defined.
            $endgroup$
            – attinat
            48 mins ago














          Your Answer






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          6 Answers
          6






          active

          oldest

          votes








          6 Answers
          6






          active

          oldest

          votes









          active

          oldest

          votes






          active

          oldest

          votes









          3












          $begingroup$


          Charcoal, 25 19 bytes



          E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η‖O←↑


          Try it online! Link is to verbose version of code. Explanation:



          E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η


          Draw a quarter of the inscription.



          ‖O←↑


          Reflect to complete the inscription.






          share|improve this answer











          $endgroup$


















            3












            $begingroup$


            Charcoal, 25 19 bytes



            E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η‖O←↑


            Try it online! Link is to verbose version of code. Explanation:



            E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η


            Draw a quarter of the inscription.



            ‖O←↑


            Reflect to complete the inscription.






            share|improve this answer











            $endgroup$
















              3












              3








              3





              $begingroup$


              Charcoal, 25 19 bytes



              E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η‖O←↑


              Try it online! Link is to verbose version of code. Explanation:



              E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η


              Draw a quarter of the inscription.



              ‖O←↑


              Reflect to complete the inscription.






              share|improve this answer











              $endgroup$




              Charcoal, 25 19 bytes



              E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η‖O←↑


              Try it online! Link is to verbose version of code. Explanation:



              E⊘⊕η✂θκ⁺κ⁻Lθ⊘⊖η


              Draw a quarter of the inscription.



              ‖O←↑


              Reflect to complete the inscription.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited 9 hours ago

























              answered 9 hours ago









              NeilNeil

              86.4k8 gold badges46 silver badges183 bronze badges




              86.4k8 gold badges46 silver badges183 bronze badges

























                  2












                  $begingroup$


                  Jelly, 12 bytes



                  Uṡṛ‘HɗŒBŒḄZY


                  Try it online!



                  A dyadic link taking the string as its left and height as its right argument. Returns a string with line breaks. If a list of strings were acceptable for output, I can remove the final Y saving a byte. Interestingly the original “SILO PRINCEPS FECIT” looks to me like ASCII art of a 3D diamond when I look at it on TIO.






                  share|improve this answer









                  $endgroup$













                  • $begingroup$
                    I clicked on the try it just to see and yes, indeed, it does 3D. Weird but cool.
                    $endgroup$
                    – guifa
                    8 hours ago
















                  2












                  $begingroup$


                  Jelly, 12 bytes



                  Uṡṛ‘HɗŒBŒḄZY


                  Try it online!



                  A dyadic link taking the string as its left and height as its right argument. Returns a string with line breaks. If a list of strings were acceptable for output, I can remove the final Y saving a byte. Interestingly the original “SILO PRINCEPS FECIT” looks to me like ASCII art of a 3D diamond when I look at it on TIO.






                  share|improve this answer









                  $endgroup$













                  • $begingroup$
                    I clicked on the try it just to see and yes, indeed, it does 3D. Weird but cool.
                    $endgroup$
                    – guifa
                    8 hours ago














                  2












                  2








                  2





                  $begingroup$


                  Jelly, 12 bytes



                  Uṡṛ‘HɗŒBŒḄZY


                  Try it online!



                  A dyadic link taking the string as its left and height as its right argument. Returns a string with line breaks. If a list of strings were acceptable for output, I can remove the final Y saving a byte. Interestingly the original “SILO PRINCEPS FECIT” looks to me like ASCII art of a 3D diamond when I look at it on TIO.






                  share|improve this answer









                  $endgroup$




                  Jelly, 12 bytes



                  Uṡṛ‘HɗŒBŒḄZY


                  Try it online!



                  A dyadic link taking the string as its left and height as its right argument. Returns a string with line breaks. If a list of strings were acceptable for output, I can remove the final Y saving a byte. Interestingly the original “SILO PRINCEPS FECIT” looks to me like ASCII art of a 3D diamond when I look at it on TIO.







                  share|improve this answer












                  share|improve this answer



                  share|improve this answer










                  answered 8 hours ago









                  Nick KennedyNick Kennedy

                  5,0149 silver badges14 bronze badges




                  5,0149 silver badges14 bronze badges












                  • $begingroup$
                    I clicked on the try it just to see and yes, indeed, it does 3D. Weird but cool.
                    $endgroup$
                    – guifa
                    8 hours ago


















                  • $begingroup$
                    I clicked on the try it just to see and yes, indeed, it does 3D. Weird but cool.
                    $endgroup$
                    – guifa
                    8 hours ago
















                  $begingroup$
                  I clicked on the try it just to see and yes, indeed, it does 3D. Weird but cool.
                  $endgroup$
                  – guifa
                  8 hours ago




                  $begingroup$
                  I clicked on the try it just to see and yes, indeed, it does 3D. Weird but cool.
                  $endgroup$
                  – guifa
                  8 hours ago











                  2












                  $begingroup$


                  R, 93 bytes





                  function(s,H,h=H/2-.5,w=length(s)-h-1)write(s[1+outer(abs(-w:w),abs(-h:h),`+`)],"",2*w+1,,"")


                  Try it online!



                  Takes input as a vector of characters.



                  First compute $w$ and $h$ such that the output is of size $(2w+1)times(2h+1)$.



                  In the output, we want the character in position $(i,j)$ to be the $1+|i-h|+|j-w|$ th character of the input. The rest is formatting.






                  share|improve this answer









                  $endgroup$


















                    2












                    $begingroup$


                    R, 93 bytes





                    function(s,H,h=H/2-.5,w=length(s)-h-1)write(s[1+outer(abs(-w:w),abs(-h:h),`+`)],"",2*w+1,,"")


                    Try it online!



                    Takes input as a vector of characters.



                    First compute $w$ and $h$ such that the output is of size $(2w+1)times(2h+1)$.



                    In the output, we want the character in position $(i,j)$ to be the $1+|i-h|+|j-w|$ th character of the input. The rest is formatting.






                    share|improve this answer









                    $endgroup$
















                      2












                      2








                      2





                      $begingroup$


                      R, 93 bytes





                      function(s,H,h=H/2-.5,w=length(s)-h-1)write(s[1+outer(abs(-w:w),abs(-h:h),`+`)],"",2*w+1,,"")


                      Try it online!



                      Takes input as a vector of characters.



                      First compute $w$ and $h$ such that the output is of size $(2w+1)times(2h+1)$.



                      In the output, we want the character in position $(i,j)$ to be the $1+|i-h|+|j-w|$ th character of the input. The rest is formatting.






                      share|improve this answer









                      $endgroup$




                      R, 93 bytes





                      function(s,H,h=H/2-.5,w=length(s)-h-1)write(s[1+outer(abs(-w:w),abs(-h:h),`+`)],"",2*w+1,,"")


                      Try it online!



                      Takes input as a vector of characters.



                      First compute $w$ and $h$ such that the output is of size $(2w+1)times(2h+1)$.



                      In the output, we want the character in position $(i,j)$ to be the $1+|i-h|+|j-w|$ th character of the input. The rest is formatting.







                      share|improve this answer












                      share|improve this answer



                      share|improve this answer










                      answered 8 hours ago









                      Robin RyderRobin Ryder

                      2,8014 silver badges24 bronze badges




                      2,8014 silver badges24 bronze badges























                          2












                          $begingroup$


                          Japt -R, 19 16 bytes



                          z
                          ò@VÔtYVÊaU)êÃê


                          Try it






                          share|improve this answer









                          $endgroup$


















                            2












                            $begingroup$


                            Japt -R, 19 16 bytes



                            z
                            ò@VÔtYVÊaU)êÃê


                            Try it






                            share|improve this answer









                            $endgroup$
















                              2












                              2








                              2





                              $begingroup$


                              Japt -R, 19 16 bytes



                              z
                              ò@VÔtYVÊaU)êÃê


                              Try it






                              share|improve this answer









                              $endgroup$




                              Japt -R, 19 16 bytes



                              z
                              ò@VÔtYVÊaU)êÃê


                              Try it







                              share|improve this answer












                              share|improve this answer



                              share|improve this answer










                              answered 7 hours ago









                              ShaggyShaggy

                              20.5k3 gold badges20 silver badges69 bronze badges




                              20.5k3 gold badges20 silver badges69 bronze badges























                                  2












                                  $begingroup$


                                  J, 27 bytes



                                  ([{~]+/&(|@i:)#@[-1+])-:@<:


                                  Try it online!



                                  An example will clarify the high-level approach.



                                  Consider 'ABCDE' f 3



                                  We notice that what we seek is simply the "cross addition" table of 1 0 1 and 3 2 1 0 1 2 3, which looks like this:



                                  4 3 2 1 2 3 4
                                  3 2 1 0 1 2 3
                                  4 3 2 1 2 3 4


                                  We then pull those indexes from the original string: [{~.



                                  All the rest of the code is just boring arithmetic and the use of i: to construct the arguments 1 0 1 and 3 2 1 0 1 2 3.






                                  share|improve this answer











                                  $endgroup$


















                                    2












                                    $begingroup$


                                    J, 27 bytes



                                    ([{~]+/&(|@i:)#@[-1+])-:@<:


                                    Try it online!



                                    An example will clarify the high-level approach.



                                    Consider 'ABCDE' f 3



                                    We notice that what we seek is simply the "cross addition" table of 1 0 1 and 3 2 1 0 1 2 3, which looks like this:



                                    4 3 2 1 2 3 4
                                    3 2 1 0 1 2 3
                                    4 3 2 1 2 3 4


                                    We then pull those indexes from the original string: [{~.



                                    All the rest of the code is just boring arithmetic and the use of i: to construct the arguments 1 0 1 and 3 2 1 0 1 2 3.






                                    share|improve this answer











                                    $endgroup$
















                                      2












                                      2








                                      2





                                      $begingroup$


                                      J, 27 bytes



                                      ([{~]+/&(|@i:)#@[-1+])-:@<:


                                      Try it online!



                                      An example will clarify the high-level approach.



                                      Consider 'ABCDE' f 3



                                      We notice that what we seek is simply the "cross addition" table of 1 0 1 and 3 2 1 0 1 2 3, which looks like this:



                                      4 3 2 1 2 3 4
                                      3 2 1 0 1 2 3
                                      4 3 2 1 2 3 4


                                      We then pull those indexes from the original string: [{~.



                                      All the rest of the code is just boring arithmetic and the use of i: to construct the arguments 1 0 1 and 3 2 1 0 1 2 3.






                                      share|improve this answer











                                      $endgroup$




                                      J, 27 bytes



                                      ([{~]+/&(|@i:)#@[-1+])-:@<:


                                      Try it online!



                                      An example will clarify the high-level approach.



                                      Consider 'ABCDE' f 3



                                      We notice that what we seek is simply the "cross addition" table of 1 0 1 and 3 2 1 0 1 2 3, which looks like this:



                                      4 3 2 1 2 3 4
                                      3 2 1 0 1 2 3
                                      4 3 2 1 2 3 4


                                      We then pull those indexes from the original string: [{~.



                                      All the rest of the code is just boring arithmetic and the use of i: to construct the arguments 1 0 1 and 3 2 1 0 1 2 3.







                                      share|improve this answer














                                      share|improve this answer



                                      share|improve this answer








                                      edited 1 hour ago

























                                      answered 8 hours ago









                                      JonahJonah

                                      3,9512 gold badges12 silver badges21 bronze badges




                                      3,9512 gold badges12 silver badges21 bronze badges























                                          0












                                          $begingroup$


                                          Wolfram Language (Mathematica), 57 bytes



                                          (g=Reverse@Rest@#~Join~#&)@BlockMap[g,#,⌈#2/2⌉,1]&


                                          Try it online!






                                          share|improve this answer









                                          $endgroup$









                                          • 1




                                            $begingroup$
                                            @lirtosiast then the first g isn't evaluated the first time the function is called. Try it online!
                                            $endgroup$
                                            – attinat
                                            1 hour ago










                                          • $begingroup$
                                            Interesting, any idea why it appears to work when you use @@ or @@@?
                                            $endgroup$
                                            – lirtosiast
                                            58 mins ago










                                          • $begingroup$
                                            @lirtosiast It think Print/@f[...] -> Print/@Transpose[g[...]] -> Transpose[Print@g[...]], by which time g is defined.
                                            $endgroup$
                                            – attinat
                                            48 mins ago
















                                          0












                                          $begingroup$


                                          Wolfram Language (Mathematica), 57 bytes



                                          (g=Reverse@Rest@#~Join~#&)@BlockMap[g,#,⌈#2/2⌉,1]&


                                          Try it online!






                                          share|improve this answer









                                          $endgroup$









                                          • 1




                                            $begingroup$
                                            @lirtosiast then the first g isn't evaluated the first time the function is called. Try it online!
                                            $endgroup$
                                            – attinat
                                            1 hour ago










                                          • $begingroup$
                                            Interesting, any idea why it appears to work when you use @@ or @@@?
                                            $endgroup$
                                            – lirtosiast
                                            58 mins ago










                                          • $begingroup$
                                            @lirtosiast It think Print/@f[...] -> Print/@Transpose[g[...]] -> Transpose[Print@g[...]], by which time g is defined.
                                            $endgroup$
                                            – attinat
                                            48 mins ago














                                          0












                                          0








                                          0





                                          $begingroup$


                                          Wolfram Language (Mathematica), 57 bytes



                                          (g=Reverse@Rest@#~Join~#&)@BlockMap[g,#,⌈#2/2⌉,1]&


                                          Try it online!






                                          share|improve this answer









                                          $endgroup$




                                          Wolfram Language (Mathematica), 57 bytes



                                          (g=Reverse@Rest@#~Join~#&)@BlockMap[g,#,⌈#2/2⌉,1]&


                                          Try it online!







                                          share|improve this answer












                                          share|improve this answer



                                          share|improve this answer










                                          answered 1 hour ago









                                          attinatattinat

                                          1,6272 silver badges9 bronze badges




                                          1,6272 silver badges9 bronze badges








                                          • 1




                                            $begingroup$
                                            @lirtosiast then the first g isn't evaluated the first time the function is called. Try it online!
                                            $endgroup$
                                            – attinat
                                            1 hour ago










                                          • $begingroup$
                                            Interesting, any idea why it appears to work when you use @@ or @@@?
                                            $endgroup$
                                            – lirtosiast
                                            58 mins ago










                                          • $begingroup$
                                            @lirtosiast It think Print/@f[...] -> Print/@Transpose[g[...]] -> Transpose[Print@g[...]], by which time g is defined.
                                            $endgroup$
                                            – attinat
                                            48 mins ago














                                          • 1




                                            $begingroup$
                                            @lirtosiast then the first g isn't evaluated the first time the function is called. Try it online!
                                            $endgroup$
                                            – attinat
                                            1 hour ago










                                          • $begingroup$
                                            Interesting, any idea why it appears to work when you use @@ or @@@?
                                            $endgroup$
                                            – lirtosiast
                                            58 mins ago










                                          • $begingroup$
                                            @lirtosiast It think Print/@f[...] -> Print/@Transpose[g[...]] -> Transpose[Print@g[...]], by which time g is defined.
                                            $endgroup$
                                            – attinat
                                            48 mins ago








                                          1




                                          1




                                          $begingroup$
                                          @lirtosiast then the first g isn't evaluated the first time the function is called. Try it online!
                                          $endgroup$
                                          – attinat
                                          1 hour ago




                                          $begingroup$
                                          @lirtosiast then the first g isn't evaluated the first time the function is called. Try it online!
                                          $endgroup$
                                          – attinat
                                          1 hour ago












                                          $begingroup$
                                          Interesting, any idea why it appears to work when you use @@ or @@@?
                                          $endgroup$
                                          – lirtosiast
                                          58 mins ago




                                          $begingroup$
                                          Interesting, any idea why it appears to work when you use @@ or @@@?
                                          $endgroup$
                                          – lirtosiast
                                          58 mins ago












                                          $begingroup$
                                          @lirtosiast It think Print/@f[...] -> Print/@Transpose[g[...]] -> Transpose[Print@g[...]], by which time g is defined.
                                          $endgroup$
                                          – attinat
                                          48 mins ago




                                          $begingroup$
                                          @lirtosiast It think Print/@f[...] -> Print/@Transpose[g[...]] -> Transpose[Print@g[...]], by which time g is defined.
                                          $endgroup$
                                          – attinat
                                          48 mins ago


















                                          draft saved

                                          draft discarded




















































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