SQL Server error 242 with ANSI datetimeZero Rows return on querying DMV sys.dm_os_performance_countersUnable...
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SQL Server error 242 with ANSI datetime
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I'm trying to debug a MS SQL Server error 242:
The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.
The error is originated by this statement:
CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
This is my server version:
Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64)
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))
And the language @@LANGUAGE is Italiano.
The same statements works on
Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)
With language: us_english
Without without making explicit convert style it works
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));
Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?
sql-server datetime type-conversion
add a comment |
I'm trying to debug a MS SQL Server error 242:
The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.
The error is originated by this statement:
CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
This is my server version:
Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64)
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))
And the language @@LANGUAGE is Italiano.
The same statements works on
Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)
With language: us_english
Without without making explicit convert style it works
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));
Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?
sql-server datetime type-conversion
Are you converting from char to datetime to varchar? Try with:INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)
– McNets
9 hours ago
@McNets this works:INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime));this not [err 242]INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));
– sgargel
9 hours ago
Try by using/instead of-, or by using your regional settings(dd-mm-yyyy I suppose)
– McNets
9 hours ago
2
@McNets Comments are not for guessing.
– Paul White♦
8 hours ago
mssqltips.com/sqlservertip/5206/…
– Aaron Bertrand♦
6 hours ago
add a comment |
I'm trying to debug a MS SQL Server error 242:
The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.
The error is originated by this statement:
CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
This is my server version:
Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64)
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))
And the language @@LANGUAGE is Italiano.
The same statements works on
Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)
With language: us_english
Without without making explicit convert style it works
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));
Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?
sql-server datetime type-conversion
I'm trying to debug a MS SQL Server error 242:
The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.
The error is originated by this statement:
CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
This is my server version:
Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64)
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))
And the language @@LANGUAGE is Italiano.
The same statements works on
Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)
With language: us_english
Without without making explicit convert style it works
INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));
Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?
sql-server datetime type-conversion
sql-server datetime type-conversion
edited 8 hours ago
Paul White♦
56.9k14 gold badges298 silver badges472 bronze badges
56.9k14 gold badges298 silver badges472 bronze badges
asked 9 hours ago
sgargelsgargel
2001 silver badge13 bronze badges
2001 silver badge13 bronze badges
Are you converting from char to datetime to varchar? Try with:INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)
– McNets
9 hours ago
@McNets this works:INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime));this not [err 242]INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));
– sgargel
9 hours ago
Try by using/instead of-, or by using your regional settings(dd-mm-yyyy I suppose)
– McNets
9 hours ago
2
@McNets Comments are not for guessing.
– Paul White♦
8 hours ago
mssqltips.com/sqlservertip/5206/…
– Aaron Bertrand♦
6 hours ago
add a comment |
Are you converting from char to datetime to varchar? Try with:INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)
– McNets
9 hours ago
@McNets this works:INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime));this not [err 242]INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));
– sgargel
9 hours ago
Try by using/instead of-, or by using your regional settings(dd-mm-yyyy I suppose)
– McNets
9 hours ago
2
@McNets Comments are not for guessing.
– Paul White♦
8 hours ago
mssqltips.com/sqlservertip/5206/…
– Aaron Bertrand♦
6 hours ago
Are you converting from char to datetime to varchar? Try with:
INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)– McNets
9 hours ago
Are you converting from char to datetime to varchar? Try with:
INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)– McNets
9 hours ago
@McNets this works:
INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));– sgargel
9 hours ago
@McNets this works:
INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));– sgargel
9 hours ago
Try by using
/ instead of -, or by using your regional settings (dd-mm-yyyy I suppose)– McNets
9 hours ago
Try by using
/ instead of -, or by using your regional settings (dd-mm-yyyy I suppose)– McNets
9 hours ago
2
2
@McNets Comments are not for guessing.
– Paul White♦
8 hours ago
@McNets Comments are not for guessing.
– Paul White♦
8 hours ago
mssqltips.com/sqlservertip/5206/…
– Aaron Bertrand♦
6 hours ago
mssqltips.com/sqlservertip/5206/…
– Aaron Bertrand♦
6 hours ago
add a comment |
1 Answer
1
active
oldest
votes
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.
You're then converting that to a string with 102 style (rather than 105 for Italian).
You're then relying on an implicit conversion back to datetime to match the type of the target column.
The implicit conversion has a default style of 0 as you can see in the execution plan:
[Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))
(note: you should always specify the maximum length when using varchar)
When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.
When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.
The reason it works on one and not the other is the default DATEFORMAT for the language in each case.
See datetime and SET LANGUAGE.
add a comment |
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VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.
You're then converting that to a string with 102 style (rather than 105 for Italian).
You're then relying on an implicit conversion back to datetime to match the type of the target column.
The implicit conversion has a default style of 0 as you can see in the execution plan:
[Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))
(note: you should always specify the maximum length when using varchar)
When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.
When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.
The reason it works on one and not the other is the default DATEFORMAT for the language in each case.
See datetime and SET LANGUAGE.
add a comment |
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.
You're then converting that to a string with 102 style (rather than 105 for Italian).
You're then relying on an implicit conversion back to datetime to match the type of the target column.
The implicit conversion has a default style of 0 as you can see in the execution plan:
[Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))
(note: you should always specify the maximum length when using varchar)
When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.
When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.
The reason it works on one and not the other is the default DATEFORMAT for the language in each case.
See datetime and SET LANGUAGE.
add a comment |
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.
You're then converting that to a string with 102 style (rather than 105 for Italian).
You're then relying on an implicit conversion back to datetime to match the type of the target column.
The implicit conversion has a default style of 0 as you can see in the execution plan:
[Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))
(note: you should always specify the maximum length when using varchar)
When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.
When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.
The reason it works on one and not the other is the default DATEFORMAT for the language in each case.
See datetime and SET LANGUAGE.
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));
Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.
You're then converting that to a string with 102 style (rather than 105 for Italian).
You're then relying on an implicit conversion back to datetime to match the type of the target column.
The implicit conversion has a default style of 0 as you can see in the execution plan:
[Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))
(note: you should always specify the maximum length when using varchar)
When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.
When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.
The reason it works on one and not the other is the default DATEFORMAT for the language in each case.
See datetime and SET LANGUAGE.
edited 8 hours ago
answered 8 hours ago
Paul White♦Paul White
56.9k14 gold badges298 silver badges472 bronze badges
56.9k14 gold badges298 silver badges472 bronze badges
add a comment |
add a comment |
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Are you converting from char to datetime to varchar? Try with:
INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)– McNets
9 hours ago
@McNets this works:
INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime));this not [err 242]INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));– sgargel
9 hours ago
Try by using
/instead of-, or by using your regional settings(dd-mm-yyyy I suppose)– McNets
9 hours ago
2
@McNets Comments are not for guessing.
– Paul White♦
8 hours ago
mssqltips.com/sqlservertip/5206/…
– Aaron Bertrand♦
6 hours ago