SQL Server error 242 with ANSI datetimeZero Rows return on querying DMV sys.dm_os_performance_countersUnable...

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SQL Server error 242 with ANSI datetime


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}







4















I'm trying to debug a MS SQL Server error 242:




The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.




The error is originated by this statement:



CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO

INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


This is my server version:



Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64) 
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))


And the language @@LANGUAGE is Italiano.



The same statements works on



Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)


With language: us_english



Without without making explicit convert style it works



INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));


Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?










share|improve this question

























  • Are you converting from char to datetime to varchar? Try with: INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)

    – McNets
    9 hours ago













  • @McNets this works: INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));

    – sgargel
    9 hours ago













  • Try by using / instead of -, or by using your regional settings (dd-mm-yyyy I suppose)

    – McNets
    9 hours ago








  • 2





    @McNets Comments are not for guessing.

    – Paul White
    8 hours ago











  • mssqltips.com/sqlservertip/5206/…

    – Aaron Bertrand
    6 hours ago


















4















I'm trying to debug a MS SQL Server error 242:




The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.




The error is originated by this statement:



CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO

INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


This is my server version:



Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64) 
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))


And the language @@LANGUAGE is Italiano.



The same statements works on



Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)


With language: us_english



Without without making explicit convert style it works



INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));


Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?










share|improve this question

























  • Are you converting from char to datetime to varchar? Try with: INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)

    – McNets
    9 hours ago













  • @McNets this works: INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));

    – sgargel
    9 hours ago













  • Try by using / instead of -, or by using your regional settings (dd-mm-yyyy I suppose)

    – McNets
    9 hours ago








  • 2





    @McNets Comments are not for guessing.

    – Paul White
    8 hours ago











  • mssqltips.com/sqlservertip/5206/…

    – Aaron Bertrand
    6 hours ago














4












4








4








I'm trying to debug a MS SQL Server error 242:




The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.




The error is originated by this statement:



CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO

INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


This is my server version:



Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64) 
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))


And the language @@LANGUAGE is Italiano.



The same statements works on



Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)


With language: us_english



Without without making explicit convert style it works



INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));


Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?










share|improve this question
















I'm trying to debug a MS SQL Server error 242:




The conversion of a char data type to a datetime data type resulted in an out-of-range datetime value.




The error is originated by this statement:



CREATE TABLE db.schema.test (
Column1 datetime NULL
) GO

INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


This is my server version:



Microsoft SQL Server 2017 (RTM-CU15) (KB4498951) - 14.0.3162.1 (X64) 
May 15 2019 19:14:30
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Linux (Debian GNU/Linux 9 (stretch))


And the language @@LANGUAGE is Italiano.



The same statements works on



Microsoft SQL Server 2017 (RTM-CU10) (KB4342123) - 14.0.3037.1 (X64)
Jul 27 2018 09:40:27
Copyright (C) 2017 Microsoft Corporation
Standard Edition (64-bit) on Windows Server 2012 R2 Standard 6.3 <X64> (Build 9600: ) (Hypervisor)


With language: us_english



Without without making explicit convert style it works



INSERT INTO db.schema.test (Column1)
VALUES (convert(varchar,convert(datetime,{D '2019-06-30'})));


Convert style 102 is ANSI yyyy.mm.dd, shouldn't be recognized by both English and Italian SQL Server?







sql-server datetime type-conversion






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 8 hours ago









Paul White

56.9k14 gold badges298 silver badges472 bronze badges




56.9k14 gold badges298 silver badges472 bronze badges










asked 9 hours ago









sgargelsgargel

2001 silver badge13 bronze badges




2001 silver badge13 bronze badges













  • Are you converting from char to datetime to varchar? Try with: INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)

    – McNets
    9 hours ago













  • @McNets this works: INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));

    – sgargel
    9 hours ago













  • Try by using / instead of -, or by using your regional settings (dd-mm-yyyy I suppose)

    – McNets
    9 hours ago








  • 2





    @McNets Comments are not for guessing.

    – Paul White
    8 hours ago











  • mssqltips.com/sqlservertip/5206/…

    – Aaron Bertrand
    6 hours ago



















  • Are you converting from char to datetime to varchar? Try with: INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)

    – McNets
    9 hours ago













  • @McNets this works: INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));

    – sgargel
    9 hours ago













  • Try by using / instead of -, or by using your regional settings (dd-mm-yyyy I suppose)

    – McNets
    9 hours ago








  • 2





    @McNets Comments are not for guessing.

    – Paul White
    8 hours ago











  • mssqltips.com/sqlservertip/5206/…

    – Aaron Bertrand
    6 hours ago

















Are you converting from char to datetime to varchar? Try with: INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)

– McNets
9 hours ago







Are you converting from char to datetime to varchar? Try with: INSERT INTO dbo.schema.test (Column1) VALUES CAST('20190630' as datetime)

– McNets
9 hours ago















@McNets this works: INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));

– sgargel
9 hours ago







@McNets this works: INSERT INTO db.schema.test (Column1) VALUES (CAST('20190630' as datetime)); this not [err 242] INSERT INTO db.schema.test (Column1) VALUES (CAST('2019-06-30' as datetime));

– sgargel
9 hours ago















Try by using / instead of -, or by using your regional settings (dd-mm-yyyy I suppose)

– McNets
9 hours ago







Try by using / instead of -, or by using your regional settings (dd-mm-yyyy I suppose)

– McNets
9 hours ago






2




2





@McNets Comments are not for guessing.

– Paul White
8 hours ago





@McNets Comments are not for guessing.

– Paul White
8 hours ago













mssqltips.com/sqlservertip/5206/…

– Aaron Bertrand
6 hours ago





mssqltips.com/sqlservertip/5206/…

– Aaron Bertrand
6 hours ago










1 Answer
1






active

oldest

votes


















8














VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.



You're then converting that to a string with 102 style (rather than 105 for Italian).



You're then relying on an implicit conversion back to datetime to match the type of the target column.



The implicit conversion has a default style of 0 as you can see in the execution plan:



[Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))


(note: you should always specify the maximum length when using varchar)



When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.



When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.



The reason it works on one and not the other is the default DATEFORMAT for the language in each case.



See datetime and SET LANGUAGE.






share|improve this answer




























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    1 Answer
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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    8














    VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


    Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.



    You're then converting that to a string with 102 style (rather than 105 for Italian).



    You're then relying on an implicit conversion back to datetime to match the type of the target column.



    The implicit conversion has a default style of 0 as you can see in the execution plan:



    [Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))


    (note: you should always specify the maximum length when using varchar)



    When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.



    When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.



    The reason it works on one and not the other is the default DATEFORMAT for the language in each case.



    See datetime and SET LANGUAGE.






    share|improve this answer






























      8














      VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


      Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.



      You're then converting that to a string with 102 style (rather than 105 for Italian).



      You're then relying on an implicit conversion back to datetime to match the type of the target column.



      The implicit conversion has a default style of 0 as you can see in the execution plan:



      [Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))


      (note: you should always specify the maximum length when using varchar)



      When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.



      When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.



      The reason it works on one and not the other is the default DATEFORMAT for the language in each case.



      See datetime and SET LANGUAGE.






      share|improve this answer




























        8












        8








        8







        VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


        Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.



        You're then converting that to a string with 102 style (rather than 105 for Italian).



        You're then relying on an implicit conversion back to datetime to match the type of the target column.



        The implicit conversion has a default style of 0 as you can see in the execution plan:



        [Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))


        (note: you should always specify the maximum length when using varchar)



        When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.



        When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.



        The reason it works on one and not the other is the default DATEFORMAT for the language in each case.



        See datetime and SET LANGUAGE.






        share|improve this answer















        VALUES (convert(varchar,convert(datetime,{D '2019-06-30'}),102));


        Starting from the inside, the ODBC escape sequence {D '2019-06-30'} returns a datetime.



        You're then converting that to a string with 102 style (rather than 105 for Italian).



        You're then relying on an implicit conversion back to datetime to match the type of the target column.



        The implicit conversion has a default style of 0 as you can see in the execution plan:



        [Expr1003] = Scalar Operator(CONVERT_IMPLICIT(datetime,CONVERT(varchar(30),[@1],102),0))


        (note: you should always specify the maximum length when using varchar)



        When you use style 102 yyyy.mm.dd you must also set DATEFORMAT to YMD so SQL Server can parse the format under style 0.



        When you use style 105 dd-mm-yyyy, you must set DATEFORMAT to DMY for the same reason.



        The reason it works on one and not the other is the default DATEFORMAT for the language in each case.



        See datetime and SET LANGUAGE.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited 8 hours ago

























        answered 8 hours ago









        Paul WhitePaul White

        56.9k14 gold badges298 silver badges472 bronze badges




        56.9k14 gold badges298 silver badges472 bronze badges






























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