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Convert Date string in timestamp

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0

I can't find the right syntax to convert a string date in epoch timestamp.

The script is:

date -d '2012-03-02 22:00 EDT' +%s

DATEJ=`echo -n '2012-03-02 22:00'`

echo $DATEJ

date -d $DATEJ EDT +%s

and the result is

[gg@raspi8 ~]$ CNVDATTS

1330740000  

'2012-03-02 22:00'  

date: opérande supplémentaire « EDT »  

Saisissez « date --help » pour plus d'informations.  

Where is the fault?

It seems that the variable DATEJ does not give the same as the string in the 1st line. If I don't write EDT, the error is same but mention +%s.

bash date syntax

share|improve this question

edited yesterday

Bart

1,20411 gold badge33 silver badges1818 bronze badges

asked yesterday

Georges GuinchardGeorges Guinchard

4

New contributor

Georges Guinchard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What type of Unix are you running on?
  
  – Kusalananda♦
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  what's the point of the echo -n? why not just DATEJ='2012-03-02 22:00'? Also, you need double-quotes when you use $DATEJ - e.g. date -d "$DATEJ EDT" +%s, otherwise date will get three arguments $DATEJ, EDT, and +%s instead of two....that's why it's complaining about the extra argument (i don't speak or read french but i can make an uneducated guess :)
  
  – cas
  yesterday
  

  
  
  
  

add a comment | 

0

I can't find the right syntax to convert a string date in epoch timestamp.

The script is:

date -d '2012-03-02 22:00 EDT' +%s

DATEJ=`echo -n '2012-03-02 22:00'`

echo $DATEJ

date -d $DATEJ EDT +%s

and the result is

[gg@raspi8 ~]$ CNVDATTS

1330740000  

'2012-03-02 22:00'  

date: opérande supplémentaire « EDT »  

Saisissez « date --help » pour plus d'informations.  

Where is the fault?

It seems that the variable DATEJ does not give the same as the string in the 1st line. If I don't write EDT, the error is same but mention +%s.

bash date syntax

share|improve this question

edited yesterday

Bart

1,20411 gold badge33 silver badges1818 bronze badges

asked yesterday

Georges GuinchardGeorges Guinchard

4

New contributor

Georges Guinchard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What type of Unix are you running on?
  
  – Kusalananda♦
  yesterday
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  what's the point of the echo -n? why not just DATEJ='2012-03-02 22:00'? Also, you need double-quotes when you use $DATEJ - e.g. date -d "$DATEJ EDT" +%s, otherwise date will get three arguments $DATEJ, EDT, and +%s instead of two....that's why it's complaining about the extra argument (i don't speak or read french but i can make an uneducated guess :)
  
  – cas
  yesterday
  

  
  
  
  

add a comment | 

I can't find the right syntax to convert a string date in epoch timestamp.

The script is:

date -d '2012-03-02 22:00 EDT' +%s

DATEJ=`echo -n '2012-03-02 22:00'`

echo $DATEJ

date -d $DATEJ EDT +%s

and the result is

[gg@raspi8 ~]$ CNVDATTS

1330740000  

'2012-03-02 22:00'  

date: opérande supplémentaire « EDT »  

Saisissez « date --help » pour plus d'informations.  

Where is the fault?

It seems that the variable DATEJ does not give the same as the string in the 1st line. If I don't write EDT, the error is same but mention +%s.

bash date syntax

share|improve this question

edited yesterday

Bart

1,20411 gold badge33 silver badges1818 bronze badges

asked yesterday

Georges GuinchardGeorges Guinchard

4

New contributor

Georges Guinchard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

date -d '2012-03-02 22:00 EDT' +%s

DATEJ=`echo -n '2012-03-02 22:00'`

echo $DATEJ

date -d $DATEJ EDT +%s

[gg@raspi8 ~]$ CNVDATTS

1330740000  

'2012-03-02 22:00'  

date: opérande supplémentaire « EDT »  

Saisissez « date --help » pour plus d'informations.  

share|improve this question

edited yesterday

Bart

1,20411 gold badge33 silver badges1818 bronze badges

asked yesterday

Georges GuinchardGeorges Guinchard

4

New contributor

Georges Guinchard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited yesterday

Bart

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asked yesterday

Georges GuinchardGeorges Guinchard

4

New contributor

Georges Guinchard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited yesterday

Bart

1,20411 gold badge33 silver badges1818 bronze badges

edited yesterday

Bart

1,20411 gold badge33 silver badges1818 bronze badges

asked yesterday

Georges GuinchardGeorges Guinchard

4

New contributor

Georges Guinchard is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked yesterday

Georges GuinchardGeorges Guinchard

4

1 Answer
1

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votes

1

The problem here seems to be with the single-quotes in $DATEJ. Your variable imposes them.

Change that to

DATEJ=`echo -n "2012-03-02 22:00"`

and in the final command:

date -d "$DATEJ EDT" +%s

This will work:

$ date -d '2012-03-02 22:00 EDT' +%s

1330740000

$ DATEJ=`echo -n "2012-03-02 22:00"`

$ echo $DATEJ

2012-03-02 22:00

$ date -d "$DATEJ EDT" +%s

1330740000

EDIT

Actually, you don't need to echo the date, unless your script imposes so, so the variable $DATEJ can simply be put as

DATEJ="2012-03-02 22:00"

share|improve this answer

answered yesterday

BartBart

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1

The problem here seems to be with the single-quotes in $DATEJ. Your variable imposes them.

Change that to

DATEJ=`echo -n "2012-03-02 22:00"`

and in the final command:

date -d "$DATEJ EDT" +%s

This will work:

$ date -d '2012-03-02 22:00 EDT' +%s

1330740000

$ DATEJ=`echo -n "2012-03-02 22:00"`

$ echo $DATEJ

2012-03-02 22:00

$ date -d "$DATEJ EDT" +%s

1330740000

EDIT

Actually, you don't need to echo the date, unless your script imposes so, so the variable $DATEJ can simply be put as

DATEJ="2012-03-02 22:00"

share|improve this answer

answered yesterday

BartBart

1,20411 gold badge33 silver badges1818 bronze badges

add a comment | 

1

The problem here seems to be with the single-quotes in $DATEJ. Your variable imposes them.

Change that to

DATEJ=`echo -n "2012-03-02 22:00"`

and in the final command:

date -d "$DATEJ EDT" +%s

This will work:

$ date -d '2012-03-02 22:00 EDT' +%s

1330740000

$ DATEJ=`echo -n "2012-03-02 22:00"`

$ echo $DATEJ

2012-03-02 22:00

$ date -d "$DATEJ EDT" +%s

1330740000

EDIT

Actually, you don't need to echo the date, unless your script imposes so, so the variable $DATEJ can simply be put as

DATEJ="2012-03-02 22:00"

share|improve this answer

answered yesterday

BartBart

1,20411 gold badge33 silver badges1818 bronze badges

add a comment | 

The problem here seems to be with the single-quotes in $DATEJ. Your variable imposes them.

Change that to

DATEJ=`echo -n "2012-03-02 22:00"`

and in the final command:

date -d "$DATEJ EDT" +%s

This will work:

$ date -d '2012-03-02 22:00 EDT' +%s

1330740000

$ DATEJ=`echo -n "2012-03-02 22:00"`

$ echo $DATEJ

2012-03-02 22:00

$ date -d "$DATEJ EDT" +%s

1330740000

EDIT

Actually, you don't need to echo the date, unless your script imposes so, so the variable $DATEJ can simply be put as

DATEJ="2012-03-02 22:00"

share|improve this answer

answered yesterday

BartBart

1,20411 gold badge33 silver badges1818 bronze badges

DATEJ=`echo -n "2012-03-02 22:00"`

date -d "$DATEJ EDT" +%s

$ date -d '2012-03-02 22:00 EDT' +%s

1330740000

$ DATEJ=`echo -n "2012-03-02 22:00"`

$ echo $DATEJ

2012-03-02 22:00

$ date -d "$DATEJ EDT" +%s

1330740000

DATEJ="2012-03-02 22:00"

share|improve this answer

answered yesterday

BartBart

1,20411 gold badge33 silver badges1818 bronze badges

answered yesterday

BartBart

1,20411 gold badge33 silver badges1818 bronze badges

answered yesterday

BartBart

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