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Match blank lines before a word awk

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

I have a long file (showing only a piece):

145 27262253 2093226 747883433 76303046 2.74331

146 27992017 2188217 747883433 76303046 2.8678

147 30385435 2433407 747883433 76303046 3.18913

148 31218703 2514902 747883433 76303046 3.29594

149 33852828 2660530 747883433 76303046 3.48679

150 36161756 2836045 747883433 76303046 3.71682



Alignments      747883433       76303046

Bases   111613795461    11392665612



1 40000373 2754292 838333186 82982133 3.31914

2 35955786 2451917 838333186 82982133 2.95475

3 33056935 2241392 838333186 82982133 2.70105

4 32241895 2172229 838333186 82982133 2.61771

145 29490370 2184347 838333186 82982133 2.63231

146 30252912 2282821 838333186 82982133 2.75098

147 32862262 2544600 838333186 82982133 3.06644

148 33769718 2631164 838333186 82982133 3.17076

149 36673113 2787718 838333186 82982133 3.35942

150 39222287 2975755 838333186 82982133 3.58602



Alignments      838333186       82982133

Bases   125129342261    12391027833



1 35736929 2509527 741319423 80995147 3.09837

2 32185143 2238927 741319423 80995147 2.76427

3 29595482 2043259 741319423 80995147 2.52269

4 28861157 1978254 741319423 80995147 2.44244

I want to match the blank line before Alignments word and the word itself. Expecting:

Alignments      747883433       76303046   



Alignments      838333186       82982133

Is it possible? I have many others blank lines and Alignments words.
My try: | awk '{if($1 ~ /^[[:space:]]*Alignments/) {print $0}}'. However, I get:

Alignments      747883433       76303046

Alignments      838333186       82982133

text-processing awk

share|improve this question

asked 1 hour ago

giannkasgiannkas

122 bronze badges

New contributor

giannkas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You are after a multiline grep/awk. There are several questions that ask the same question.
  
  – Sparhawk
  1 hour ago
  

  
  
  
  

add a comment | 

0

I have a long file (showing only a piece):

145 27262253 2093226 747883433 76303046 2.74331

146 27992017 2188217 747883433 76303046 2.8678

147 30385435 2433407 747883433 76303046 3.18913

148 31218703 2514902 747883433 76303046 3.29594

149 33852828 2660530 747883433 76303046 3.48679

150 36161756 2836045 747883433 76303046 3.71682



Alignments      747883433       76303046

Bases   111613795461    11392665612



1 40000373 2754292 838333186 82982133 3.31914

2 35955786 2451917 838333186 82982133 2.95475

3 33056935 2241392 838333186 82982133 2.70105

4 32241895 2172229 838333186 82982133 2.61771

145 29490370 2184347 838333186 82982133 2.63231

146 30252912 2282821 838333186 82982133 2.75098

147 32862262 2544600 838333186 82982133 3.06644

148 33769718 2631164 838333186 82982133 3.17076

149 36673113 2787718 838333186 82982133 3.35942

150 39222287 2975755 838333186 82982133 3.58602



Alignments      838333186       82982133

Bases   125129342261    12391027833



1 35736929 2509527 741319423 80995147 3.09837

2 32185143 2238927 741319423 80995147 2.76427

3 29595482 2043259 741319423 80995147 2.52269

4 28861157 1978254 741319423 80995147 2.44244

I want to match the blank line before Alignments word and the word itself. Expecting:

Alignments      747883433       76303046   



Alignments      838333186       82982133

Is it possible? I have many others blank lines and Alignments words.
My try: | awk '{if($1 ~ /^[[:space:]]*Alignments/) {print $0}}'. However, I get:

Alignments      747883433       76303046

Alignments      838333186       82982133

text-processing awk

share|improve this question

asked 1 hour ago

giannkasgiannkas

122 bronze badges

New contributor

giannkas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You are after a multiline grep/awk. There are several questions that ask the same question.
  
  – Sparhawk
  1 hour ago
  

  
  
  
  

add a comment | 

I have a long file (showing only a piece):

145 27262253 2093226 747883433 76303046 2.74331

146 27992017 2188217 747883433 76303046 2.8678

147 30385435 2433407 747883433 76303046 3.18913

148 31218703 2514902 747883433 76303046 3.29594

149 33852828 2660530 747883433 76303046 3.48679

150 36161756 2836045 747883433 76303046 3.71682



Alignments      747883433       76303046

Bases   111613795461    11392665612



1 40000373 2754292 838333186 82982133 3.31914

2 35955786 2451917 838333186 82982133 2.95475

3 33056935 2241392 838333186 82982133 2.70105

4 32241895 2172229 838333186 82982133 2.61771

145 29490370 2184347 838333186 82982133 2.63231

146 30252912 2282821 838333186 82982133 2.75098

147 32862262 2544600 838333186 82982133 3.06644

148 33769718 2631164 838333186 82982133 3.17076

149 36673113 2787718 838333186 82982133 3.35942

150 39222287 2975755 838333186 82982133 3.58602



Alignments      838333186       82982133

Bases   125129342261    12391027833



1 35736929 2509527 741319423 80995147 3.09837

2 32185143 2238927 741319423 80995147 2.76427

3 29595482 2043259 741319423 80995147 2.52269

4 28861157 1978254 741319423 80995147 2.44244

I want to match the blank line before Alignments word and the word itself. Expecting:

Alignments      747883433       76303046   



Alignments      838333186       82982133

Is it possible? I have many others blank lines and Alignments words.
My try: | awk '{if($1 ~ /^[[:space:]]*Alignments/) {print $0}}'. However, I get:

Alignments      747883433       76303046

Alignments      838333186       82982133

text-processing awk

share|improve this question

asked 1 hour ago

giannkasgiannkas

122 bronze badges

New contributor

giannkas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

145 27262253 2093226 747883433 76303046 2.74331

146 27992017 2188217 747883433 76303046 2.8678

147 30385435 2433407 747883433 76303046 3.18913

148 31218703 2514902 747883433 76303046 3.29594

149 33852828 2660530 747883433 76303046 3.48679

150 36161756 2836045 747883433 76303046 3.71682



Alignments      747883433       76303046

Bases   111613795461    11392665612



1 40000373 2754292 838333186 82982133 3.31914

2 35955786 2451917 838333186 82982133 2.95475

3 33056935 2241392 838333186 82982133 2.70105

4 32241895 2172229 838333186 82982133 2.61771

145 29490370 2184347 838333186 82982133 2.63231

146 30252912 2282821 838333186 82982133 2.75098

147 32862262 2544600 838333186 82982133 3.06644

148 33769718 2631164 838333186 82982133 3.17076

149 36673113 2787718 838333186 82982133 3.35942

150 39222287 2975755 838333186 82982133 3.58602



Alignments      838333186       82982133

Bases   125129342261    12391027833



1 35736929 2509527 741319423 80995147 3.09837

2 32185143 2238927 741319423 80995147 2.76427

3 29595482 2043259 741319423 80995147 2.52269

4 28861157 1978254 741319423 80995147 2.44244

Alignments      747883433       76303046   



Alignments      838333186       82982133

Alignments      747883433       76303046

Alignments      838333186       82982133

share|improve this question

asked 1 hour ago

giannkasgiannkas

122 bronze badges

New contributor

giannkas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 1 hour ago

giannkasgiannkas

122 bronze badges

New contributor

giannkas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

giannkasgiannkas

122 bronze badges

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giannkas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

giannkasgiannkas

122 bronze badges

5 Answers
5

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0

You can use the below Awk for your problem. Match a empty line and see if the line starting with Alignments immediately starts after that

awk '!NF { line = NR; next } (NR = line + 1 ) && /^Alignments/{ printf "n%sn",$0; }' file

share|improve this answer

answered 1 hour ago

InianInian

7,1101717 silver badges3636 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  we are hardcoring the newline in output... it would print the same if we don't have an empty line...
  
  – msp9011
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @msp9011 : No only if the previous line is empty!
  
  – Inian
  59 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  just check by removing empty line in input file...
  
  – msp9011
  52 mins ago
  

  
  
  
  

add a comment | 

0

Why don't we use grep? :

grep -A1 "^$" file | grep -B1 'Alignments' | grep -v -- "^--$"

share|improve this answer

answered 1 hour ago

msp9011msp9011

5,67955 gold badges4343 silver badges6969 bronze badges

add a comment | 

0

Sed excels in such tasks. First we stick the next line to the current provided the current is empty. Then interrogate and print upon meeting the criterion set.

$ sed -ne '

    /./!N

    /^nAlignments/p

' file.txt 

share|improve this answer

answered 36 mins ago

Rakesh SharmaRakesh Sharma

17611 silver badge22 bronze badges

add a comment | 

0

$ awk '/^$|^Alignments/' input.txt | uniq



Alignments      747883433       76303046



Alignments      838333186       82982133

the uniq makes sure there will be no more than one blank line before, after, or between any Alignments lines.

grep could be used instead. or sed -n. or perl -n. e.g.

$ grep -E '^$|Alignments' input.txt | uniq

share|improve this answer

answered 22 mins ago

cascas

42.3k44 gold badges6262 silver badges112112 bronze badges

add a comment | 

0

Using GNU awk:

awk -v RS='nAlignments[ 0-9]*' '{print RT}' file

The record separtor RS is set to the expected match and is printed for every record using RT (record terminator).

share|improve this answer

answered 13 mins ago

olivoliv

1,94655 silver badges1313 bronze badges

add a comment | 

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0

You can use the below Awk for your problem. Match a empty line and see if the line starting with Alignments immediately starts after that

awk '!NF { line = NR; next } (NR = line + 1 ) && /^Alignments/{ printf "n%sn",$0; }' file

share|improve this answer

answered 1 hour ago

InianInian

7,1101717 silver badges3636 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  we are hardcoring the newline in output... it would print the same if we don't have an empty line...
  
  – msp9011
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @msp9011 : No only if the previous line is empty!
  
  – Inian
  59 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  just check by removing empty line in input file...
  
  – msp9011
  52 mins ago
  

  
  
  
  

add a comment | 

0

You can use the below Awk for your problem. Match a empty line and see if the line starting with Alignments immediately starts after that

awk '!NF { line = NR; next } (NR = line + 1 ) && /^Alignments/{ printf "n%sn",$0; }' file

share|improve this answer

answered 1 hour ago

InianInian

7,1101717 silver badges3636 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  we are hardcoring the newline in output... it would print the same if we don't have an empty line...
  
  – msp9011
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @msp9011 : No only if the previous line is empty!
  
  – Inian
  59 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  just check by removing empty line in input file...
  
  – msp9011
  52 mins ago
  

  
  
  
  

add a comment | 

You can use the below Awk for your problem. Match a empty line and see if the line starting with Alignments immediately starts after that

awk '!NF { line = NR; next } (NR = line + 1 ) && /^Alignments/{ printf "n%sn",$0; }' file

share|improve this answer

answered 1 hour ago

InianInian

7,1101717 silver badges3636 bronze badges

awk '!NF { line = NR; next } (NR = line + 1 ) && /^Alignments/{ printf "n%sn",$0; }' file

share|improve this answer

answered 1 hour ago

InianInian

7,1101717 silver badges3636 bronze badges

answered 1 hour ago

InianInian

7,1101717 silver badges3636 bronze badges

answered 1 hour ago

InianInian

7,1101717 silver badges3636 bronze badges

0

Why don't we use grep? :

grep -A1 "^$" file | grep -B1 'Alignments' | grep -v -- "^--$"

share|improve this answer

answered 1 hour ago

msp9011msp9011

5,67955 gold badges4343 silver badges6969 bronze badges

add a comment | 

0

Why don't we use grep? :

grep -A1 "^$" file | grep -B1 'Alignments' | grep -v -- "^--$"

share|improve this answer

answered 1 hour ago

msp9011msp9011

5,67955 gold badges4343 silver badges6969 bronze badges

add a comment | 

Why don't we use grep? :

grep -A1 "^$" file | grep -B1 'Alignments' | grep -v -- "^--$"

share|improve this answer

answered 1 hour ago

msp9011msp9011

5,67955 gold badges4343 silver badges6969 bronze badges

grep -A1 "^$" file | grep -B1 'Alignments' | grep -v -- "^--$"

share|improve this answer

answered 1 hour ago

msp9011msp9011

5,67955 gold badges4343 silver badges6969 bronze badges

answered 1 hour ago

msp9011msp9011

5,67955 gold badges4343 silver badges6969 bronze badges

answered 1 hour ago

msp9011msp9011

5,67955 gold badges4343 silver badges6969 bronze badges

0

Sed excels in such tasks. First we stick the next line to the current provided the current is empty. Then interrogate and print upon meeting the criterion set.

$ sed -ne '

    /./!N

    /^nAlignments/p

' file.txt 

share|improve this answer

answered 36 mins ago

Rakesh SharmaRakesh Sharma

17611 silver badge22 bronze badges

add a comment | 

0

Sed excels in such tasks. First we stick the next line to the current provided the current is empty. Then interrogate and print upon meeting the criterion set.

$ sed -ne '

    /./!N

    /^nAlignments/p

' file.txt 

share|improve this answer

answered 36 mins ago

Rakesh SharmaRakesh Sharma

17611 silver badge22 bronze badges

add a comment | 

Sed excels in such tasks. First we stick the next line to the current provided the current is empty. Then interrogate and print upon meeting the criterion set.

$ sed -ne '

    /./!N

    /^nAlignments/p

' file.txt 

share|improve this answer

answered 36 mins ago

Rakesh SharmaRakesh Sharma

17611 silver badge22 bronze badges

$ sed -ne '

    /./!N

    /^nAlignments/p

' file.txt 

share|improve this answer

answered 36 mins ago

Rakesh SharmaRakesh Sharma

17611 silver badge22 bronze badges

answered 36 mins ago

Rakesh SharmaRakesh Sharma

17611 silver badge22 bronze badges

answered 36 mins ago

Rakesh SharmaRakesh Sharma

17611 silver badge22 bronze badges

0

$ awk '/^$|^Alignments/' input.txt | uniq



Alignments      747883433       76303046



Alignments      838333186       82982133

the uniq makes sure there will be no more than one blank line before, after, or between any Alignments lines.

grep could be used instead. or sed -n. or perl -n. e.g.

$ grep -E '^$|Alignments' input.txt | uniq

share|improve this answer

answered 22 mins ago

cascas

42.3k44 gold badges6262 silver badges112112 bronze badges

add a comment | 

0

$ awk '/^$|^Alignments/' input.txt | uniq



Alignments      747883433       76303046



Alignments      838333186       82982133

the uniq makes sure there will be no more than one blank line before, after, or between any Alignments lines.

grep could be used instead. or sed -n. or perl -n. e.g.

$ grep -E '^$|Alignments' input.txt | uniq

share|improve this answer

answered 22 mins ago

cascas

42.3k44 gold badges6262 silver badges112112 bronze badges

add a comment | 

$ awk '/^$|^Alignments/' input.txt | uniq



Alignments      747883433       76303046



Alignments      838333186       82982133

the uniq makes sure there will be no more than one blank line before, after, or between any Alignments lines.

grep could be used instead. or sed -n. or perl -n. e.g.

$ grep -E '^$|Alignments' input.txt | uniq

share|improve this answer

answered 22 mins ago

cascas

42.3k44 gold badges6262 silver badges112112 bronze badges

$ awk '/^$|^Alignments/' input.txt | uniq



Alignments      747883433       76303046



Alignments      838333186       82982133

$ grep -E '^$|Alignments' input.txt | uniq

share|improve this answer

answered 22 mins ago

cascas

42.3k44 gold badges6262 silver badges112112 bronze badges

answered 22 mins ago

cascas

42.3k44 gold badges6262 silver badges112112 bronze badges

answered 22 mins ago

cascas

42.3k44 gold badges6262 silver badges112112 bronze badges

0

Using GNU awk:

awk -v RS='nAlignments[ 0-9]*' '{print RT}' file

The record separtor RS is set to the expected match and is printed for every record using RT (record terminator).

share|improve this answer

answered 13 mins ago

olivoliv

1,94655 silver badges1313 bronze badges

add a comment | 

0

Using GNU awk:

awk -v RS='nAlignments[ 0-9]*' '{print RT}' file

The record separtor RS is set to the expected match and is printed for every record using RT (record terminator).

share|improve this answer

answered 13 mins ago

olivoliv

1,94655 silver badges1313 bronze badges

add a comment | 

Using GNU awk:

awk -v RS='nAlignments[ 0-9]*' '{print RT}' file

The record separtor RS is set to the expected match and is printed for every record using RT (record terminator).

share|improve this answer

answered 13 mins ago

olivoliv

1,94655 silver badges1313 bronze badges

awk -v RS='nAlignments[ 0-9]*' '{print RT}' file

share|improve this answer

answered 13 mins ago

olivoliv

1,94655 silver badges1313 bronze badges

answered 13 mins ago

olivoliv

1,94655 silver badges1313 bronze badges

answered 13 mins ago

olivoliv

1,94655 silver badges1313 bronze badges