Can a wire having a 610-670 THz (frequency of blue light) AC frequency supply, generate blue light?Does light...
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Can a wire having a 610-670 THz (frequency of blue light) AC frequency supply, generate blue light?
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$begingroup$
We know that when we give alternating current across a wire then it will generate an electromagnetic wave which propagates outward.
But if we have a supply which can generate 610 to 670 terahertz of alternating current supply then does the wire generate blue light?
electromagnetism visible-light photons
edited 1 hour ago
Peter Mortensen
1,96311424
asked 12 hours ago
user210956user210956
22518
$endgroup$
add a comment |
$begingroup$
We know that when we give alternating current across a wire then it will generate an electromagnetic wave which propagates outward.
But if we have a supply which can generate 610 to 670 terahertz of alternating current supply then does the wire generate blue light?
electromagnetism visible-light photons
edited 1 hour ago
Peter Mortensen
1,96311424
asked 12 hours ago
user210956user210956
22518
$endgroup$
add a comment |
$begingroup$
We know that when we give alternating current across a wire then it will generate an electromagnetic wave which propagates outward.
But if we have a supply which can generate 610 to 670 terahertz of alternating current supply then does the wire generate blue light?
electromagnetism visible-light photons
edited 1 hour ago
Peter Mortensen
1,96311424
asked 12 hours ago
user210956user210956
22518
$endgroup$
We know that when we give alternating current across a wire then it will generate an electromagnetic wave which propagates outward.
But if we have a supply which can generate 610 to 670 terahertz of alternating current supply then does the wire generate blue light?
electromagnetism visible-light photons
electromagnetism visible-light photons
edited 1 hour ago
Peter Mortensen
1,96311424
asked 12 hours ago
user210956user210956
22518
edited 1 hour ago
Peter Mortensen
1,96311424
asked 12 hours ago
user210956user210956
22518
edited 1 hour ago
Peter Mortensen
1,96311424
edited 1 hour ago
Peter Mortensen
1,96311424
edited 1 hour ago
Peter Mortensen
1,96311424
1,96311424
asked 12 hours ago
user210956user210956
22518
asked 12 hours ago
user210956user210956
22518
asked 12 hours ago
user210956user210956
22518
22518
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
An alternating voltage at that frequency is light. There's no 'generate' about it - the power supply is just a light source.
And if you have a wire, that is, a conductor made of metal, then the light won't propagate inside it at depths longer than the skin depth for that material at that particular frequency, which is generally tiny.
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
$endgroup$
3
$begingroup$
I don't object to this, but a periodic change in the electromagnetic field and a periodic fluctuation in electron density and momentum are, to me, distinct concepts. Of course, you are right because the two hybridize as a collective excitation, but that kinda makes it hard to understand at the high school level.
$endgroup$
– Paul Young
12 hours ago
3
$begingroup$
@PaulYoung It is hard to justify when beginners are taught (incorrectly) that "electric current" the same as "electrons moving". But in any case, there is no law of physics that says "the laws of physics must be easy to justify!"
$endgroup$
– alephzero
11 hours ago
$begingroup$
@alpehzero - I agree with you!
$endgroup$
– Paul Young
11 hours ago
3
$begingroup$
This is technically accurate but potentially misleading. Would an observer looking at the wire see the color blue? That is what the OP wants to know.
$endgroup$
– Owen
2 hours ago
2
$begingroup$
@Owen Which aspect of "the light won't propagate inside the wire past the skin depth" is unclear or misleading?
$endgroup$
– Emilio Pisanty
2 hours ago
|
show 2 more comments
$begingroup$
It would be hard to generate such a current and harder still to get it to produce any blue light - though this is theoretically possible.
The main problem is that you are probably thinking of a metal wire. Metals absorb visible light, both reflecting it and turning it into lattice vibrations. This is because the wavelength of visible light is just a few thousand atoms long in size so it is in a "sweet spot" for exciting solid crystals. In fact, the tendency for solid objects to absorb, reflect and otherwise interact with visible light is why it is "visible".
In a normal radio wave, your metal wire will need to be on the order of a wavelength of the radio wave you want to produce. This is typically on the order of meters. Automobiles of the 20th century had metal wires sticking out of them, about 1 meter long, called "antennas", to catch such waves.
But for blue light the wavelength is only about 5 x $10^{-7}$ meters so any useful antenna would be very tiny because an "electron density wave" in your wire would be "turning around" before it got very far.
The electromagnetic spectrum is divided up not so much by "wavelength and frequency" as by the way that any given part of the spectrum interacts with matter. So, radio waves will interact via electron currents in long metal wires. But visible light interacts more with lattice vibrations and non-ionizing atomic transitions. So, "current in a wire" type emission works in frequency up to a thing called "the terahertz gap" https://en.wikipedia.org/wiki/Terahertz_gap . Above this frequency other techniques are usually required. Blue light is about three orders of magnitude higher in frequency than the terahertz gap.
answered 12 hours ago
Paul YoungPaul Young
1,800522
$endgroup$
add a comment |
$begingroup$
Yeah definitely . You can create light corresponding on any frequency by this method. It’s just that creating this circuit will be very challenging. To give you a perspective, the highest frequency that we have obtained with modern electronic circuits is around 10^11 Hz.
answered 12 hours ago
Ishan JawaleIshan Jawale
577
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
An alternating voltage at that frequency is light. There's no 'generate' about it - the power supply is just a light source.
And if you have a wire, that is, a conductor made of metal, then the light won't propagate inside it at depths longer than the skin depth for that material at that particular frequency, which is generally tiny.
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
$endgroup$
3
$begingroup$
I don't object to this, but a periodic change in the electromagnetic field and a periodic fluctuation in electron density and momentum are, to me, distinct concepts. Of course, you are right because the two hybridize as a collective excitation, but that kinda makes it hard to understand at the high school level.
$endgroup$
– Paul Young
12 hours ago
3
$begingroup$
@PaulYoung It is hard to justify when beginners are taught (incorrectly) that "electric current" the same as "electrons moving". But in any case, there is no law of physics that says "the laws of physics must be easy to justify!"
$endgroup$
– alephzero
11 hours ago
$begingroup$
@alpehzero - I agree with you!
$endgroup$
– Paul Young
11 hours ago
3
$begingroup$
This is technically accurate but potentially misleading. Would an observer looking at the wire see the color blue? That is what the OP wants to know.
$endgroup$
– Owen
2 hours ago
2
$begingroup$
@Owen Which aspect of "the light won't propagate inside the wire past the skin depth" is unclear or misleading?
$endgroup$
– Emilio Pisanty
2 hours ago
|
show 2 more comments
$begingroup$
An alternating voltage at that frequency is light. There's no 'generate' about it - the power supply is just a light source.
And if you have a wire, that is, a conductor made of metal, then the light won't propagate inside it at depths longer than the skin depth for that material at that particular frequency, which is generally tiny.
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
$endgroup$
3
$begingroup$
I don't object to this, but a periodic change in the electromagnetic field and a periodic fluctuation in electron density and momentum are, to me, distinct concepts. Of course, you are right because the two hybridize as a collective excitation, but that kinda makes it hard to understand at the high school level.
$endgroup$
– Paul Young
12 hours ago
3
$begingroup$
@PaulYoung It is hard to justify when beginners are taught (incorrectly) that "electric current" the same as "electrons moving". But in any case, there is no law of physics that says "the laws of physics must be easy to justify!"
$endgroup$
– alephzero
11 hours ago
$begingroup$
@alpehzero - I agree with you!
$endgroup$
– Paul Young
11 hours ago
3
$begingroup$
This is technically accurate but potentially misleading. Would an observer looking at the wire see the color blue? That is what the OP wants to know.
$endgroup$
– Owen
2 hours ago
2
$begingroup$
@Owen Which aspect of "the light won't propagate inside the wire past the skin depth" is unclear or misleading?
$endgroup$
– Emilio Pisanty
2 hours ago
|
show 2 more comments
$begingroup$
An alternating voltage at that frequency is light. There's no 'generate' about it - the power supply is just a light source.
And if you have a wire, that is, a conductor made of metal, then the light won't propagate inside it at depths longer than the skin depth for that material at that particular frequency, which is generally tiny.
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
$endgroup$
An alternating voltage at that frequency is light. There's no 'generate' about it - the power supply is just a light source.
And if you have a wire, that is, a conductor made of metal, then the light won't propagate inside it at depths longer than the skin depth for that material at that particular frequency, which is generally tiny.
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
answered 12 hours ago
Emilio PisantyEmilio Pisanty
88k23223456
88k23223456
3
$begingroup$
I don't object to this, but a periodic change in the electromagnetic field and a periodic fluctuation in electron density and momentum are, to me, distinct concepts. Of course, you are right because the two hybridize as a collective excitation, but that kinda makes it hard to understand at the high school level.
$endgroup$
– Paul Young
12 hours ago
3
$begingroup$
@PaulYoung It is hard to justify when beginners are taught (incorrectly) that "electric current" the same as "electrons moving". But in any case, there is no law of physics that says "the laws of physics must be easy to justify!"
$endgroup$
– alephzero
11 hours ago
$begingroup$
@alpehzero - I agree with you!
$endgroup$
– Paul Young
11 hours ago
3
$begingroup$
This is technically accurate but potentially misleading. Would an observer looking at the wire see the color blue? That is what the OP wants to know.
$endgroup$
– Owen
2 hours ago
2
$begingroup$
@Owen Which aspect of "the light won't propagate inside the wire past the skin depth" is unclear or misleading?
$endgroup$
– Emilio Pisanty
2 hours ago
|
show 2 more comments
3
$begingroup$
I don't object to this, but a periodic change in the electromagnetic field and a periodic fluctuation in electron density and momentum are, to me, distinct concepts. Of course, you are right because the two hybridize as a collective excitation, but that kinda makes it hard to understand at the high school level.
$endgroup$
– Paul Young
12 hours ago
3
$begingroup$
@PaulYoung It is hard to justify when beginners are taught (incorrectly) that "electric current" the same as "electrons moving". But in any case, there is no law of physics that says "the laws of physics must be easy to justify!"
$endgroup$
– alephzero
11 hours ago
$begingroup$
@alpehzero - I agree with you!
$endgroup$
– Paul Young
11 hours ago
3
$begingroup$
This is technically accurate but potentially misleading. Would an observer looking at the wire see the color blue? That is what the OP wants to know.
$endgroup$
– Owen
2 hours ago
2
$begingroup$
@Owen Which aspect of "the light won't propagate inside the wire past the skin depth" is unclear or misleading?
$endgroup$
– Emilio Pisanty
2 hours ago
3
3
$begingroup$
I don't object to this, but a periodic change in the electromagnetic field and a periodic fluctuation in electron density and momentum are, to me, distinct concepts. Of course, you are right because the two hybridize as a collective excitation, but that kinda makes it hard to understand at the high school level.
$endgroup$
– Paul Young
12 hours ago
$begingroup$
I don't object to this, but a periodic change in the electromagnetic field and a periodic fluctuation in electron density and momentum are, to me, distinct concepts. Of course, you are right because the two hybridize as a collective excitation, but that kinda makes it hard to understand at the high school level.
$endgroup$
– Paul Young
12 hours ago
3
3
$begingroup$
@PaulYoung It is hard to justify when beginners are taught (incorrectly) that "electric current" the same as "electrons moving". But in any case, there is no law of physics that says "the laws of physics must be easy to justify!"
$endgroup$
– alephzero
11 hours ago
$begingroup$
@PaulYoung It is hard to justify when beginners are taught (incorrectly) that "electric current" the same as "electrons moving". But in any case, there is no law of physics that says "the laws of physics must be easy to justify!"
$endgroup$
– alephzero
11 hours ago
$begingroup$
@alpehzero - I agree with you!
$endgroup$
– Paul Young
11 hours ago
$begingroup$
@alpehzero - I agree with you!
$endgroup$
– Paul Young
11 hours ago
3
3
$begingroup$
This is technically accurate but potentially misleading. Would an observer looking at the wire see the color blue? That is what the OP wants to know.
$endgroup$
– Owen
2 hours ago
$begingroup$
This is technically accurate but potentially misleading. Would an observer looking at the wire see the color blue? That is what the OP wants to know.
$endgroup$
– Owen
2 hours ago
2
2
$begingroup$
@Owen Which aspect of "the light won't propagate inside the wire past the skin depth" is unclear or misleading?
$endgroup$
– Emilio Pisanty
2 hours ago
$begingroup$
@Owen Which aspect of "the light won't propagate inside the wire past the skin depth" is unclear or misleading?
$endgroup$
– Emilio Pisanty
2 hours ago
|
show 2 more comments
$begingroup$
It would be hard to generate such a current and harder still to get it to produce any blue light - though this is theoretically possible.
The main problem is that you are probably thinking of a metal wire. Metals absorb visible light, both reflecting it and turning it into lattice vibrations. This is because the wavelength of visible light is just a few thousand atoms long in size so it is in a "sweet spot" for exciting solid crystals. In fact, the tendency for solid objects to absorb, reflect and otherwise interact with visible light is why it is "visible".
In a normal radio wave, your metal wire will need to be on the order of a wavelength of the radio wave you want to produce. This is typically on the order of meters. Automobiles of the 20th century had metal wires sticking out of them, about 1 meter long, called "antennas", to catch such waves.
But for blue light the wavelength is only about 5 x $10^{-7}$ meters so any useful antenna would be very tiny because an "electron density wave" in your wire would be "turning around" before it got very far.
The electromagnetic spectrum is divided up not so much by "wavelength and frequency" as by the way that any given part of the spectrum interacts with matter. So, radio waves will interact via electron currents in long metal wires. But visible light interacts more with lattice vibrations and non-ionizing atomic transitions. So, "current in a wire" type emission works in frequency up to a thing called "the terahertz gap" https://en.wikipedia.org/wiki/Terahertz_gap . Above this frequency other techniques are usually required. Blue light is about three orders of magnitude higher in frequency than the terahertz gap.
answered 12 hours ago
Paul YoungPaul Young
1,800522
$endgroup$
add a comment |
$begingroup$
It would be hard to generate such a current and harder still to get it to produce any blue light - though this is theoretically possible.
The main problem is that you are probably thinking of a metal wire. Metals absorb visible light, both reflecting it and turning it into lattice vibrations. This is because the wavelength of visible light is just a few thousand atoms long in size so it is in a "sweet spot" for exciting solid crystals. In fact, the tendency for solid objects to absorb, reflect and otherwise interact with visible light is why it is "visible".
In a normal radio wave, your metal wire will need to be on the order of a wavelength of the radio wave you want to produce. This is typically on the order of meters. Automobiles of the 20th century had metal wires sticking out of them, about 1 meter long, called "antennas", to catch such waves.
But for blue light the wavelength is only about 5 x $10^{-7}$ meters so any useful antenna would be very tiny because an "electron density wave" in your wire would be "turning around" before it got very far.
The electromagnetic spectrum is divided up not so much by "wavelength and frequency" as by the way that any given part of the spectrum interacts with matter. So, radio waves will interact via electron currents in long metal wires. But visible light interacts more with lattice vibrations and non-ionizing atomic transitions. So, "current in a wire" type emission works in frequency up to a thing called "the terahertz gap" https://en.wikipedia.org/wiki/Terahertz_gap . Above this frequency other techniques are usually required. Blue light is about three orders of magnitude higher in frequency than the terahertz gap.
answered 12 hours ago
Paul YoungPaul Young
1,800522
$endgroup$
add a comment |
$begingroup$
It would be hard to generate such a current and harder still to get it to produce any blue light - though this is theoretically possible.
The main problem is that you are probably thinking of a metal wire. Metals absorb visible light, both reflecting it and turning it into lattice vibrations. This is because the wavelength of visible light is just a few thousand atoms long in size so it is in a "sweet spot" for exciting solid crystals. In fact, the tendency for solid objects to absorb, reflect and otherwise interact with visible light is why it is "visible".
In a normal radio wave, your metal wire will need to be on the order of a wavelength of the radio wave you want to produce. This is typically on the order of meters. Automobiles of the 20th century had metal wires sticking out of them, about 1 meter long, called "antennas", to catch such waves.
But for blue light the wavelength is only about 5 x $10^{-7}$ meters so any useful antenna would be very tiny because an "electron density wave" in your wire would be "turning around" before it got very far.
The electromagnetic spectrum is divided up not so much by "wavelength and frequency" as by the way that any given part of the spectrum interacts with matter. So, radio waves will interact via electron currents in long metal wires. But visible light interacts more with lattice vibrations and non-ionizing atomic transitions. So, "current in a wire" type emission works in frequency up to a thing called "the terahertz gap" https://en.wikipedia.org/wiki/Terahertz_gap . Above this frequency other techniques are usually required. Blue light is about three orders of magnitude higher in frequency than the terahertz gap.
answered 12 hours ago
Paul YoungPaul Young
1,800522
$endgroup$
It would be hard to generate such a current and harder still to get it to produce any blue light - though this is theoretically possible.
The main problem is that you are probably thinking of a metal wire. Metals absorb visible light, both reflecting it and turning it into lattice vibrations. This is because the wavelength of visible light is just a few thousand atoms long in size so it is in a "sweet spot" for exciting solid crystals. In fact, the tendency for solid objects to absorb, reflect and otherwise interact with visible light is why it is "visible".
In a normal radio wave, your metal wire will need to be on the order of a wavelength of the radio wave you want to produce. This is typically on the order of meters. Automobiles of the 20th century had metal wires sticking out of them, about 1 meter long, called "antennas", to catch such waves.
But for blue light the wavelength is only about 5 x $10^{-7}$ meters so any useful antenna would be very tiny because an "electron density wave" in your wire would be "turning around" before it got very far.
The electromagnetic spectrum is divided up not so much by "wavelength and frequency" as by the way that any given part of the spectrum interacts with matter. So, radio waves will interact via electron currents in long metal wires. But visible light interacts more with lattice vibrations and non-ionizing atomic transitions. So, "current in a wire" type emission works in frequency up to a thing called "the terahertz gap" https://en.wikipedia.org/wiki/Terahertz_gap . Above this frequency other techniques are usually required. Blue light is about three orders of magnitude higher in frequency than the terahertz gap.
answered 12 hours ago
Paul YoungPaul Young
1,800522
edited 9 hours ago
answered 12 hours ago
Paul YoungPaul Young
1,800522
answered 12 hours ago
Paul YoungPaul Young
1,800522
answered 12 hours ago
Paul YoungPaul Young
1,800522
1,800522
add a comment |
add a comment |
$begingroup$
Yeah definitely . You can create light corresponding on any frequency by this method. It’s just that creating this circuit will be very challenging. To give you a perspective, the highest frequency that we have obtained with modern electronic circuits is around 10^11 Hz.
answered 12 hours ago
Ishan JawaleIshan Jawale
577
$endgroup$
add a comment |
$begingroup$
Yeah definitely . You can create light corresponding on any frequency by this method. It’s just that creating this circuit will be very challenging. To give you a perspective, the highest frequency that we have obtained with modern electronic circuits is around 10^11 Hz.
answered 12 hours ago
Ishan JawaleIshan Jawale
577
$endgroup$
add a comment |
$begingroup$
Yeah definitely . You can create light corresponding on any frequency by this method. It’s just that creating this circuit will be very challenging. To give you a perspective, the highest frequency that we have obtained with modern electronic circuits is around 10^11 Hz.
answered 12 hours ago
Ishan JawaleIshan Jawale
577
$endgroup$
Yeah definitely . You can create light corresponding on any frequency by this method. It’s just that creating this circuit will be very challenging. To give you a perspective, the highest frequency that we have obtained with modern electronic circuits is around 10^11 Hz.
answered 12 hours ago
Ishan JawaleIshan Jawale
577
answered 12 hours ago
Ishan JawaleIshan Jawale
577
answered 12 hours ago
Ishan JawaleIshan Jawale
577
answered 12 hours ago
Ishan JawaleIshan Jawale
577
577
add a comment |
add a comment |
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