How to generate a report summary of messages that triggered a specific DSN codeSendmail stopped sending...
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How to generate a report summary of messages that triggered a specific DSN code
Sendmail stopped sending mails, “did not issue MAIL/EXPN/VRFY/ETRN during connection to MTA”How do I stop recurring error messages from appearing in messages and auditd.log?How to generate a text report in Linux?How to output detail message about 5.x.x error on SendmailCan't send mail via sendmailHow do I hide warning messages that come from a specific command?How do you specify a blkparse format specifier that also suppresses summarySendmail error dsn=4.0.0 stat=Deferred: Connection refused by [127.0.0.1]Write script to generate report on every ThursdaySendmail queueing and not sending local mail promptly
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I use Sendmail on CENTOS 5.x,
I hope this is a simple question. =) I need to generate a report summary of messages that triggered a specific DSN code. For example:
Jan 11 07:43:34 server-example sendmail[12732]: p937blksdh3: to=<someuser@recipientdomain.com>, delay=00:00:00, xdelay=00:00:00, mailer=esmtp, pri=102537, relay=mta.recipientdomain.com. [12.34.56.78], dsn=5.7.1, stat=Service unavailable
Normally, I would just grep for this information (something like: grep -i "dsn=5.7.1" /var/log/maillog). But the problem is that this only returns a line like above and doesn't tell me the sender of the message.
Ideally, I'm looking for a one-liner that can do the following:
- Search sendmail maillog for specific DSN.
- Identify the message-id for the email. (I'm guessing
awk '{print $}'would be used?) - Return the message details for each (presumably grepping for the the message id retrieved from step 2).
linux centos grep sendmail
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
add a comment |
I use Sendmail on CENTOS 5.x,
I hope this is a simple question. =) I need to generate a report summary of messages that triggered a specific DSN code. For example:
Jan 11 07:43:34 server-example sendmail[12732]: p937blksdh3: to=<someuser@recipientdomain.com>, delay=00:00:00, xdelay=00:00:00, mailer=esmtp, pri=102537, relay=mta.recipientdomain.com. [12.34.56.78], dsn=5.7.1, stat=Service unavailable
Normally, I would just grep for this information (something like: grep -i "dsn=5.7.1" /var/log/maillog). But the problem is that this only returns a line like above and doesn't tell me the sender of the message.
Ideally, I'm looking for a one-liner that can do the following:
- Search sendmail maillog for specific DSN.
- Identify the message-id for the email. (I'm guessing
awk '{print $}'would be used?) - Return the message details for each (presumably grepping for the the message id retrieved from step 2).
linux centos grep sendmail
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
1
For those of us who aren't specifically familiar withsendmail, it might help if you post a more complete set of log lines, and describe exactly what details you're paying attention to when you do this manually. For example, in the line you've posted, isp937blksdh3the message-id?
– Jander
Jan 22 '11 at 2:59
add a comment |
I use Sendmail on CENTOS 5.x,
I hope this is a simple question. =) I need to generate a report summary of messages that triggered a specific DSN code. For example:
Jan 11 07:43:34 server-example sendmail[12732]: p937blksdh3: to=<someuser@recipientdomain.com>, delay=00:00:00, xdelay=00:00:00, mailer=esmtp, pri=102537, relay=mta.recipientdomain.com. [12.34.56.78], dsn=5.7.1, stat=Service unavailable
Normally, I would just grep for this information (something like: grep -i "dsn=5.7.1" /var/log/maillog). But the problem is that this only returns a line like above and doesn't tell me the sender of the message.
Ideally, I'm looking for a one-liner that can do the following:
- Search sendmail maillog for specific DSN.
- Identify the message-id for the email. (I'm guessing
awk '{print $}'would be used?) - Return the message details for each (presumably grepping for the the message id retrieved from step 2).
linux centos grep sendmail
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
I use Sendmail on CENTOS 5.x,
I hope this is a simple question. =) I need to generate a report summary of messages that triggered a specific DSN code. For example:
Jan 11 07:43:34 server-example sendmail[12732]: p937blksdh3: to=<someuser@recipientdomain.com>, delay=00:00:00, xdelay=00:00:00, mailer=esmtp, pri=102537, relay=mta.recipientdomain.com. [12.34.56.78], dsn=5.7.1, stat=Service unavailable
Normally, I would just grep for this information (something like: grep -i "dsn=5.7.1" /var/log/maillog). But the problem is that this only returns a line like above and doesn't tell me the sender of the message.
Ideally, I'm looking for a one-liner that can do the following:
- Search sendmail maillog for specific DSN.
- Identify the message-id for the email. (I'm guessing
awk '{print $}'would be used?) - Return the message details for each (presumably grepping for the the message id retrieved from step 2).
linux centos grep sendmail
linux centos grep sendmail
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
edited 3 hours ago
Rui F Ribeiro
42.7k1486146
42.7k1486146
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
asked Jan 21 '11 at 21:44
Mike BMike B
3,304205578
3,304205578
1
For those of us who aren't specifically familiar withsendmail, it might help if you post a more complete set of log lines, and describe exactly what details you're paying attention to when you do this manually. For example, in the line you've posted, isp937blksdh3the message-id?
– Jander
Jan 22 '11 at 2:59
add a comment |
1
For those of us who aren't specifically familiar withsendmail, it might help if you post a more complete set of log lines, and describe exactly what details you're paying attention to when you do this manually. For example, in the line you've posted, isp937blksdh3the message-id?
– Jander
Jan 22 '11 at 2:59
1
1
For those of us who aren't specifically familiar with
sendmail, it might help if you post a more complete set of log lines, and describe exactly what details you're paying attention to when you do this manually. For example, in the line you've posted, is p937blksdh3 the message-id?– Jander
Jan 22 '11 at 2:59
For those of us who aren't specifically familiar with
sendmail, it might help if you post a more complete set of log lines, and describe exactly what details you're paying attention to when you do this manually. For example, in the line you've posted, is p937blksdh3 the message-id?– Jander
Jan 22 '11 at 2:59
add a comment |
1 Answer
1
active
oldest
votes
In bash
dsn=5.7.1
$ grep $dsn /var/log/maillog | awk '{print $6}' | awk -F: '{print $1}'
returns:
p937blksdh3
Of the line you posted, I'm guessing that is the message id?
OK, it's not one line. Then grep for that for message details, where are the message details kept?
edited Feb 13 '14 at 18:14
slm♦
258k72547696
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
Thanks. That pointed me in the right direction. The final one-liner I came up with is a variation of that and includes a for loop:grep -i "dsn=5" /var/log/maillog | awk '{print $6}' | sed 's/://' | while read -r x; do grep -i "$x" /var/log/maillog; done
– Mike B
Feb 14 '14 at 0:07
add a comment |
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1 Answer
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1 Answer
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oldest
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votes
In bash
dsn=5.7.1
$ grep $dsn /var/log/maillog | awk '{print $6}' | awk -F: '{print $1}'
returns:
p937blksdh3
Of the line you posted, I'm guessing that is the message id?
OK, it's not one line. Then grep for that for message details, where are the message details kept?
edited Feb 13 '14 at 18:14
slm♦
258k72547696
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
Thanks. That pointed me in the right direction. The final one-liner I came up with is a variation of that and includes a for loop:grep -i "dsn=5" /var/log/maillog | awk '{print $6}' | sed 's/://' | while read -r x; do grep -i "$x" /var/log/maillog; done
– Mike B
Feb 14 '14 at 0:07
add a comment |
In bash
dsn=5.7.1
$ grep $dsn /var/log/maillog | awk '{print $6}' | awk -F: '{print $1}'
returns:
p937blksdh3
Of the line you posted, I'm guessing that is the message id?
OK, it's not one line. Then grep for that for message details, where are the message details kept?
edited Feb 13 '14 at 18:14
slm♦
258k72547696
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
Thanks. That pointed me in the right direction. The final one-liner I came up with is a variation of that and includes a for loop:grep -i "dsn=5" /var/log/maillog | awk '{print $6}' | sed 's/://' | while read -r x; do grep -i "$x" /var/log/maillog; done
– Mike B
Feb 14 '14 at 0:07
add a comment |
In bash
dsn=5.7.1
$ grep $dsn /var/log/maillog | awk '{print $6}' | awk -F: '{print $1}'
returns:
p937blksdh3
Of the line you posted, I'm guessing that is the message id?
OK, it's not one line. Then grep for that for message details, where are the message details kept?
edited Feb 13 '14 at 18:14
slm♦
258k72547696
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
In bash
dsn=5.7.1
$ grep $dsn /var/log/maillog | awk '{print $6}' | awk -F: '{print $1}'
returns:
p937blksdh3
Of the line you posted, I'm guessing that is the message id?
OK, it's not one line. Then grep for that for message details, where are the message details kept?
edited Feb 13 '14 at 18:14
slm♦
258k72547696
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
edited Feb 13 '14 at 18:14
slm♦
258k72547696
edited Feb 13 '14 at 18:14
slm♦
258k72547696
edited Feb 13 '14 at 18:14
slm♦
258k72547696
258k72547696
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
answered Feb 13 '14 at 17:55
user3275885user3275885
1736
1736
Thanks. That pointed me in the right direction. The final one-liner I came up with is a variation of that and includes a for loop:grep -i "dsn=5" /var/log/maillog | awk '{print $6}' | sed 's/://' | while read -r x; do grep -i "$x" /var/log/maillog; done
– Mike B
Feb 14 '14 at 0:07
add a comment |
Thanks. That pointed me in the right direction. The final one-liner I came up with is a variation of that and includes a for loop:grep -i "dsn=5" /var/log/maillog | awk '{print $6}' | sed 's/://' | while read -r x; do grep -i "$x" /var/log/maillog; done
– Mike B
Feb 14 '14 at 0:07
Thanks. That pointed me in the right direction. The final one-liner I came up with is a variation of that and includes a for loop:
grep -i "dsn=5" /var/log/maillog | awk '{print $6}' | sed 's/://' | while read -r x; do grep -i "$x" /var/log/maillog; done– Mike B
Feb 14 '14 at 0:07
Thanks. That pointed me in the right direction. The final one-liner I came up with is a variation of that and includes a for loop:
grep -i "dsn=5" /var/log/maillog | awk '{print $6}' | sed 's/://' | while read -r x; do grep -i "$x" /var/log/maillog; done– Mike B
Feb 14 '14 at 0:07
add a comment |
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1
For those of us who aren't specifically familiar with
sendmail, it might help if you post a more complete set of log lines, and describe exactly what details you're paying attention to when you do this manually. For example, in the line you've posted, isp937blksdh3the message-id?– Jander
Jan 22 '11 at 2:59