Find the Factorial From the Given Prime Relationship
How do governments keep track of their issued currency?
Why doesn't Adrian Toomes give up Spider-Man's identity?
Passing multiple files through stdin (over ssh)
Interview not reimboursed if offer is made but not accepted
What's the name of this light airplane?
How to project 3d image in the planes xy, xz, yz?
Do simulator games use a realistic trajectory to get into orbit?
Soft question: Examples where lack of mathematical rigour cause security breaches?
What risks are there when you clear your cookies instead of logging off?
BGP multihome issue
What can plausibly explain many of my very long and low-tech bridges?
Hottest Possible Hydrogen-Fusing Stars
Was the Tamarian language in "Darmok" inspired by Jack Vance's "The Asutra"?
How to officially communicate to a non-responsive colleague?
What is the giant octopus in the torture chamber for?
Should an arbiter claim draw at a K+R vs K+R endgame?
How to tell your grandparent to not come to fetch you with their car?
What is the actual quality of machine translations?
What makes an item an artifact?
Payment instructions allegedly from HomeAway look fishy to me
Inconsistent behavior of compiler optimization of unused string
Is an early checkout possible at a hotel before its reception opens?
Genetic limitations to learn certain instruments
When 2-pentene reacts with HBr, what will be the major product?
Find the Factorial From the Given Prime Relationship
$begingroup$
$Given$:
$P$, $Q$, $R$ are three distinct Prime Numbers
$P!$ = $Q$ x $R^Q$ x $P$
Find P, Q, R.
mathematics no-computers
asked 10 hours ago
UvcUvc
1,264119
$endgroup$
add a comment |
$begingroup$
$Given$:
$P$, $Q$, $R$ are three distinct Prime Numbers
$P!$ = $Q$ x $R^Q$ x $P$
Find P, Q, R.
mathematics no-computers
asked 10 hours ago
UvcUvc
1,264119
$endgroup$
add a comment |
$begingroup$
$Given$:
$P$, $Q$, $R$ are three distinct Prime Numbers
$P!$ = $Q$ x $R^Q$ x $P$
Find P, Q, R.
mathematics no-computers
asked 10 hours ago
UvcUvc
1,264119
$endgroup$
$Given$:
$P$, $Q$, $R$ are three distinct Prime Numbers
$P!$ = $Q$ x $R^Q$ x $P$
Find P, Q, R.
mathematics no-computers
mathematics no-computers
asked 10 hours ago
UvcUvc
1,264119
asked 10 hours ago
UvcUvc
1,264119
asked 10 hours ago
UvcUvc
1,264119
asked 10 hours ago
UvcUvc
1,264119
asked 10 hours ago
UvcUvc
1,264119
1,264119
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
I think it’s
P = 5, Q = 3, and R = 2.
This gives
$5! = 120 = 3 times 2^3 times 5$.
We note that
$P! = P times (P-1)!$, so $(P-1)! = R^Q times Q$. Noting that one of P, Q, and R had to be at least 5, I noted that $4 = 2^2$ and so $4 times 2 = 2^3$ was probably a convenient way to include these factors of $P!$.
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
$endgroup$
add a comment |
$begingroup$
It's:
$5!=3cdot2^3cdot5$
Because:
$P=5$ as there are exactly $3$ prime factors in the factorial.
Therefore $24=Qcdot R^Q=3cdot2^3$, and so $Q=3$ and $R=2$.
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
$endgroup$
$begingroup$
Great answer and explanation!
$endgroup$
– El-Guest
10 hours ago
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "559"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f84650%2ffind-the-factorial-from-the-given-prime-relationship%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
I think it’s
P = 5, Q = 3, and R = 2.
This gives
$5! = 120 = 3 times 2^3 times 5$.
We note that
$P! = P times (P-1)!$, so $(P-1)! = R^Q times Q$. Noting that one of P, Q, and R had to be at least 5, I noted that $4 = 2^2$ and so $4 times 2 = 2^3$ was probably a convenient way to include these factors of $P!$.
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
$endgroup$
add a comment |
$begingroup$
I think it’s
P = 5, Q = 3, and R = 2.
This gives
$5! = 120 = 3 times 2^3 times 5$.
We note that
$P! = P times (P-1)!$, so $(P-1)! = R^Q times Q$. Noting that one of P, Q, and R had to be at least 5, I noted that $4 = 2^2$ and so $4 times 2 = 2^3$ was probably a convenient way to include these factors of $P!$.
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
$endgroup$
add a comment |
$begingroup$
I think it’s
P = 5, Q = 3, and R = 2.
This gives
$5! = 120 = 3 times 2^3 times 5$.
We note that
$P! = P times (P-1)!$, so $(P-1)! = R^Q times Q$. Noting that one of P, Q, and R had to be at least 5, I noted that $4 = 2^2$ and so $4 times 2 = 2^3$ was probably a convenient way to include these factors of $P!$.
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
$endgroup$
I think it’s
P = 5, Q = 3, and R = 2.
This gives
$5! = 120 = 3 times 2^3 times 5$.
We note that
$P! = P times (P-1)!$, so $(P-1)! = R^Q times Q$. Noting that one of P, Q, and R had to be at least 5, I noted that $4 = 2^2$ and so $4 times 2 = 2^3$ was probably a convenient way to include these factors of $P!$.
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
answered 10 hours ago
El-GuestEl-Guest
23.4k35395
23.4k35395
add a comment |
add a comment |
$begingroup$
It's:
$5!=3cdot2^3cdot5$
Because:
$P=5$ as there are exactly $3$ prime factors in the factorial.
Therefore $24=Qcdot R^Q=3cdot2^3$, and so $Q=3$ and $R=2$.
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
$endgroup$
$begingroup$
Great answer and explanation!
$endgroup$
– El-Guest
10 hours ago
add a comment |
$begingroup$
It's:
$5!=3cdot2^3cdot5$
Because:
$P=5$ as there are exactly $3$ prime factors in the factorial.
Therefore $24=Qcdot R^Q=3cdot2^3$, and so $Q=3$ and $R=2$.
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
$endgroup$
$begingroup$
Great answer and explanation!
$endgroup$
– El-Guest
10 hours ago
add a comment |
$begingroup$
It's:
$5!=3cdot2^3cdot5$
Because:
$P=5$ as there are exactly $3$ prime factors in the factorial.
Therefore $24=Qcdot R^Q=3cdot2^3$, and so $Q=3$ and $R=2$.
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
$endgroup$
It's:
$5!=3cdot2^3cdot5$
Because:
$P=5$ as there are exactly $3$ prime factors in the factorial.
Therefore $24=Qcdot R^Q=3cdot2^3$, and so $Q=3$ and $R=2$.
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
answered 10 hours ago
JonMark PerryJonMark Perry
22.3k643103
22.3k643103
$begingroup$
Great answer and explanation!
$endgroup$
– El-Guest
10 hours ago
add a comment |
$begingroup$
Great answer and explanation!
$endgroup$
– El-Guest
10 hours ago
$begingroup$
Great answer and explanation!
$endgroup$
– El-Guest
10 hours ago
$begingroup$
Great answer and explanation!
$endgroup$
– El-Guest
10 hours ago
add a comment |
Thanks for contributing an answer to Puzzling Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fpuzzling.stackexchange.com%2fquestions%2f84650%2ffind-the-factorial-from-the-given-prime-relationship%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
