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Power/Loss diagram
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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
5
I'm drawing the following diagram:
My doubt is how to make the arrows curved (smooth) near is base. It seems strange this way. Follows the code:
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- ++(-10.5,0)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
tikz-pgf
asked 8 hours ago
Clecio JungClecio Jung
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5
I'm drawing the following diagram:
My doubt is how to make the arrows curved (smooth) near is base. It seems strange this way. Follows the code:
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- ++(-10.5,0)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
tikz-pgf
asked 8 hours ago
Clecio JungClecio Jung
384 bronze badges
New contributor
Clecio Jung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
5
5
5
I'm drawing the following diagram:
My doubt is how to make the arrows curved (smooth) near is base. It seems strange this way. Follows the code:
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- ++(-10.5,0)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
tikz-pgf
asked 8 hours ago
Clecio JungClecio Jung
384 bronze badges
New contributor
Clecio Jung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm drawing the following diagram:
My doubt is how to make the arrows curved (smooth) near is base. It seems strange this way. Follows the code:
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(2,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas} -- ++(0.5,0.5)-- ++(-0.25,0)-- ++(0,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- ++(-10.5,0)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
tikz-pgf
tikz-pgf
asked 8 hours ago
Clecio JungClecio Jung
384 bronze badges
New contributor
Clecio Jung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
Clecio JungClecio Jung
384 bronze badges
New contributor
Clecio Jung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
Clecio JungClecio Jung
384 bronze badges
New contributor
Clecio Jung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 8 hours ago
Clecio JungClecio Jung
384 bronze badges
asked 8 hours ago
Clecio JungClecio Jung
384 bronze badges
384 bronze badges
New contributor
Clecio Jung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Clecio Jung is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
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votes
5
With the to [out=...,in=...] syntax one can make the corners smoother.
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.50,0)--(4.50,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (7.2,0.25)--(7.2,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
answered 8 hours ago
wasawasa
1617 bronze badges
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wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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1 Answer
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With the to [out=...,in=...] syntax one can make the corners smoother.
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.50,0)--(4.50,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (7.2,0.25)--(7.2,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
answered 8 hours ago
wasawasa
1617 bronze badges
New contributor
wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
5
With the to [out=...,in=...] syntax one can make the corners smoother.
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.50,0)--(4.50,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (7.2,0.25)--(7.2,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
answered 8 hours ago
wasawasa
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wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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add a comment |
5
5
5
With the to [out=...,in=...] syntax one can make the corners smoother.
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.50,0)--(4.50,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (7.2,0.25)--(7.2,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
answered 8 hours ago
wasawasa
1617 bronze badges
New contributor
wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
With the to [out=...,in=...] syntax one can make the corners smoother.
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(1.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=180] ++(0.3,0.5)-- ++(0.7,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.50,0)--(4.50,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (7.2,0.25)--(7.2,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
documentclass[tikz,border=20pt]{standalone}
usepackage{mathptmx}
usepackage[outline]{contour}
usetikzlibrary{calc,arrows.meta,patterns,backgrounds}
begin{document}
begin{tikzpicture}
shade[left color=black!10, right color=black!80]
(0,0)-- ++(1,0) to [out=0,in=90]
++(0.2,-0.25) -- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cus}(t)$}
-- ++(0.5,0.5) -- ++(-0.25,0) to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{fe}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{$P_{cur}(t)$}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(2,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Perdas por atrito}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)to [out=0,in=90]
++(0.2,-0.25)-- ++(-0.25,0)-- ++(0.5,-0.5) node[anchor=north]{Outras perdas}
-- ++(0.5,0.5)-- ++(-0.25,0)to [out=90,in=0] ++(-0.25,0.5)-- ++(1,0)--
++(0,-0.5)-- ++(1.5,1.5) node[anchor=west]{$P_o(t)$} -- ++(-1.5,1.5)-- ++(0,-0.5)-- (0,3.25)-- ++(0,-3.25);
draw (0.0,1.5) node[anchor=east]{$P(t)$};
draw[thick, dashed] (4.0,0)--(4.0,3.75) node[anchor=south]{Entreferro};
draw[thick, dashed] (6.5,0.25)--(6.5,3.75) node[anchor=south]{$P_e(t)$};
end{tikzpicture}
end{document}
answered 8 hours ago
wasawasa
1617 bronze badges
New contributor
wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 7 hours ago
answered 8 hours ago
wasawasa
1617 bronze badges
New contributor
wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 8 hours ago
wasawasa
1617 bronze badges
answered 8 hours ago
wasawasa
1617 bronze badges
1617 bronze badges
New contributor
wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
wasa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
Clecio Jung is a new contributor. Be nice, and check out our Code of Conduct.
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Clecio Jung is a new contributor. Be nice, and check out our Code of Conduct.
Clecio Jung is a new contributor. Be nice, and check out our Code of Conduct.
Clecio Jung is a new contributor. Be nice, and check out our Code of Conduct.
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