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I'm trying to create a shell script taking as argument a series of averages and assign for each note an observation, example :

There are 5 averages that are introduced.

There are 2 notes that are: pretty good.

There are 3 notes that are: well

....

for i in $@

if [[ $# -ge 16 ]]; 

then 

    let j++

    echo " there are ${#j} notes that are : pretty good "

elif [[ $# -ge 14 ]]; 

    let k++

    echo " there are ${#k} notes that are : good "

shell-script shell scripting function

share|improve this question

edited Dec 19 '18 at 12:18

Rania

asked Dec 19 '18 at 9:17

RaniaRania

611 bronze badge

bumped to the homepage by Community♦ 39 mins ago

This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please try to format your question by editing it, using the formatting tools provided by U&L. If possible, code that's running would be helpful. Also, I am having a difficult time understanding your question. Can you maybe rephrase it?
  
  – OneK
  Dec 19 '18 at 9:25
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please don't post images of text or code! It makes it impossible to copy the code to an editor, and the reader can't control the colors, the font etc. That JPG with serious compression artifacts is especially hard to read. Just copy and paste the code itself, and make sure to format code in code blocks (see the editing help)
  
  – ilkkachu
  Dec 19 '18 at 10:01
  

  
  
  
  

add a comment
 | 

0

I'm trying to create a shell script taking as argument a series of averages and assign for each note an observation, example :

There are 5 averages that are introduced.

There are 2 notes that are: pretty good.

There are 3 notes that are: well

....

for i in $@

if [[ $# -ge 16 ]]; 

then 

    let j++

    echo " there are ${#j} notes that are : pretty good "

elif [[ $# -ge 14 ]]; 

    let k++

    echo " there are ${#k} notes that are : good "

shell-script shell scripting function

share|improve this question

edited Dec 19 '18 at 12:18

Rania

asked Dec 19 '18 at 9:17

RaniaRania

611 bronze badge

bumped to the homepage by Community♦ 39 mins ago

This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please try to format your question by editing it, using the formatting tools provided by U&L. If possible, code that's running would be helpful. Also, I am having a difficult time understanding your question. Can you maybe rephrase it?
  
  – OneK
  Dec 19 '18 at 9:25
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Please don't post images of text or code! It makes it impossible to copy the code to an editor, and the reader can't control the colors, the font etc. That JPG with serious compression artifacts is especially hard to read. Just copy and paste the code itself, and make sure to format code in code blocks (see the editing help)
  
  – ilkkachu
  Dec 19 '18 at 10:01
  

  
  
  
  

add a comment
 | 

I'm trying to create a shell script taking as argument a series of averages and assign for each note an observation, example :

There are 5 averages that are introduced.

There are 2 notes that are: pretty good.

There are 3 notes that are: well

....

for i in $@

if [[ $# -ge 16 ]]; 

then 

    let j++

    echo " there are ${#j} notes that are : pretty good "

elif [[ $# -ge 14 ]]; 

    let k++

    echo " there are ${#k} notes that are : good "

shell-script shell scripting function

share|improve this question

edited Dec 19 '18 at 12:18

Rania

asked Dec 19 '18 at 9:17

RaniaRania

611 bronze badge

for i in $@

if [[ $# -ge 16 ]]; 

then 

    let j++

    echo " there are ${#j} notes that are : pretty good "

elif [[ $# -ge 14 ]]; 

    let k++

    echo " there are ${#k} notes that are : good "

share|improve this question

edited Dec 19 '18 at 12:18

Rania

asked Dec 19 '18 at 9:17

RaniaRania

611 bronze badge

share|improve this question

edited Dec 19 '18 at 12:18

Rania

asked Dec 19 '18 at 9:17

RaniaRania

611 bronze badge

asked Dec 19 '18 at 9:17

RaniaRania

611 bronze badge

asked Dec 19 '18 at 9:17

RaniaRania

611 bronze badge

1 Answer
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0

Count your things first, then separately report the result:

#!/bin/bash



for a do

    if (( a >= 10 && a < 12 )); then

        pass=$(( pass + 1 ))

    elif (( etc. for the other conditions ))

    fi

done



printf '%d passedn' "$pass"

There is no need to test on $# as the loop (if written as above) would not execute at all if no arguments were passed.

share|improve this answer

answered Dec 19 '18 at 9:52

Kusalananda♦Kusalananda

166k2020 gold badges323323 silver badges516516 bronze badges

add a comment
 | 

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0

Count your things first, then separately report the result:

#!/bin/bash



for a do

    if (( a >= 10 && a < 12 )); then

        pass=$(( pass + 1 ))

    elif (( etc. for the other conditions ))

    fi

done



printf '%d passedn' "$pass"

There is no need to test on $# as the loop (if written as above) would not execute at all if no arguments were passed.

share|improve this answer

answered Dec 19 '18 at 9:52

Kusalananda♦Kusalananda

166k2020 gold badges323323 silver badges516516 bronze badges

add a comment
 | 

0

Count your things first, then separately report the result:

#!/bin/bash



for a do

    if (( a >= 10 && a < 12 )); then

        pass=$(( pass + 1 ))

    elif (( etc. for the other conditions ))

    fi

done



printf '%d passedn' "$pass"

There is no need to test on $# as the loop (if written as above) would not execute at all if no arguments were passed.

share|improve this answer

answered Dec 19 '18 at 9:52

Kusalananda♦Kusalananda

166k2020 gold badges323323 silver badges516516 bronze badges

add a comment
 | 

Count your things first, then separately report the result:

#!/bin/bash



for a do

    if (( a >= 10 && a < 12 )); then

        pass=$(( pass + 1 ))

    elif (( etc. for the other conditions ))

    fi

done



printf '%d passedn' "$pass"

There is no need to test on $# as the loop (if written as above) would not execute at all if no arguments were passed.

share|improve this answer

answered Dec 19 '18 at 9:52

Kusalananda♦Kusalananda

166k2020 gold badges323323 silver badges516516 bronze badges

#!/bin/bash



for a do

    if (( a >= 10 && a < 12 )); then

        pass=$(( pass + 1 ))

    elif (( etc. for the other conditions ))

    fi

done



printf '%d passedn' "$pass"

share|improve this answer

answered Dec 19 '18 at 9:52

Kusalananda♦Kusalananda

166k2020 gold badges323323 silver badges516516 bronze badges

answered Dec 19 '18 at 9:52

Kusalananda♦Kusalananda

166k2020 gold badges323323 silver badges516516 bronze badges

answered Dec 19 '18 at 9:52

Kusalananda♦Kusalananda

166k2020 gold badges323323 silver badges516516 bronze badges