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Bash String manipulation when string contains parentheses
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Why I closed the “Why is Kali so hard” questionrenaming files without the **rename** commandBash - Continuous String Manipulationmoving a (file | directory) while avoiding filename collisionsPiping bash string manipulationBash regex string manipulation bugReturning a variable from a functionBash script to select files to zip/unzipSearch directories for multi line stringBash Completion for Paths and Nothing Elserename a file removing part of the filename bash script
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
I have a directory full of files with the name template
xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip
The zip files contain a file yrq000.dat and I don't want to overwrite them when the files are uncompressed.
I am creating a processing script but I want to name that common file a name associated with its source zip and I'm checking the method:
for f in $(ls xxx*)
do
uniquename="${f%%(wrx.*zip}"
done
I can't figure out how to strip that opening parens from the string.
Is that possible with the bash string manipulation the way I am doing it?
That is to say, it does not work. What do I need to add or remove so that it does work?
bash shell-script
asked 7 hours ago
Ken IngramKen Ingram
1235
add a comment |
I have a directory full of files with the name template
xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip
The zip files contain a file yrq000.dat and I don't want to overwrite them when the files are uncompressed.
I am creating a processing script but I want to name that common file a name associated with its source zip and I'm checking the method:
for f in $(ls xxx*)
do
uniquename="${f%%(wrx.*zip}"
done
I can't figure out how to strip that opening parens from the string.
Is that possible with the bash string manipulation the way I am doing it?
That is to say, it does not work. What do I need to add or remove so that it does work?
bash shell-script
asked 7 hours ago
Ken IngramKen Ingram
1235
What exactly is the problem here? Consider adding example input and the corresponding desired output.
– igal
7 hours ago
add a comment |
I have a directory full of files with the name template
xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip
The zip files contain a file yrq000.dat and I don't want to overwrite them when the files are uncompressed.
I am creating a processing script but I want to name that common file a name associated with its source zip and I'm checking the method:
for f in $(ls xxx*)
do
uniquename="${f%%(wrx.*zip}"
done
I can't figure out how to strip that opening parens from the string.
Is that possible with the bash string manipulation the way I am doing it?
That is to say, it does not work. What do I need to add or remove so that it does work?
bash shell-script
asked 7 hours ago
Ken IngramKen Ingram
1235
I have a directory full of files with the name template
xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip
The zip files contain a file yrq000.dat and I don't want to overwrite them when the files are uncompressed.
I am creating a processing script but I want to name that common file a name associated with its source zip and I'm checking the method:
for f in $(ls xxx*)
do
uniquename="${f%%(wrx.*zip}"
done
I can't figure out how to strip that opening parens from the string.
Is that possible with the bash string manipulation the way I am doing it?
That is to say, it does not work. What do I need to add or remove so that it does work?
bash shell-script
bash shell-script
asked 7 hours ago
Ken IngramKen Ingram
1235
asked 7 hours ago
Ken IngramKen Ingram
1235
edited 7 hours ago
Ken Ingram
asked 7 hours ago
Ken IngramKen Ingram
1235
asked 7 hours ago
Ken IngramKen Ingram
1235
asked 7 hours ago
Ken IngramKen Ingram
1235
1235
What exactly is the problem here? Consider adding example input and the corresponding desired output.
– igal
7 hours ago
add a comment |
What exactly is the problem here? Consider adding example input and the corresponding desired output.
– igal
7 hours ago
What exactly is the problem here? Consider adding example input and the corresponding desired output.
– igal
7 hours ago
What exactly is the problem here? Consider adding example input and the corresponding desired output.
– igal
7 hours ago
add a comment |
1 Answer
1
active
oldest
votes
Try removing the dot from your pattern, i.e.:
for f in xxx*;
do
uniquename="${f%%(wrx*zip}";
echo "${uniquename}";
done
That takes files whose names are of the form xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip and converts them to strings of the form xxx[0-9][0-9][0-9[0-9]ss. Is that what you're trying to accomplish?
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
answered 7 hours ago
igaligal
6,1761638
Yeah that did it. I see that I was using the "." as though it were a regex, when in fact it is taken as literal.
– Ken Ingram
6 hours ago
2
Bash Pitfall #1
– steeldriver
6 hours ago
Interesting. I typically used expansion to select the "for" range and then when I saw "$()" was a tool I began using it. I guess I made some incorrect assumptions about why my loops wood break when filenames had whitespace or non-standard characters.
– Ken Ingram
5 hours ago
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Try removing the dot from your pattern, i.e.:
for f in xxx*;
do
uniquename="${f%%(wrx*zip}";
echo "${uniquename}";
done
That takes files whose names are of the form xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip and converts them to strings of the form xxx[0-9][0-9][0-9[0-9]ss. Is that what you're trying to accomplish?
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
answered 7 hours ago
igaligal
6,1761638
Yeah that did it. I see that I was using the "." as though it were a regex, when in fact it is taken as literal.
– Ken Ingram
6 hours ago
2
Bash Pitfall #1
– steeldriver
6 hours ago
Interesting. I typically used expansion to select the "for" range and then when I saw "$()" was a tool I began using it. I guess I made some incorrect assumptions about why my loops wood break when filenames had whitespace or non-standard characters.
– Ken Ingram
5 hours ago
add a comment |
Try removing the dot from your pattern, i.e.:
for f in xxx*;
do
uniquename="${f%%(wrx*zip}";
echo "${uniquename}";
done
That takes files whose names are of the form xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip and converts them to strings of the form xxx[0-9][0-9][0-9[0-9]ss. Is that what you're trying to accomplish?
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
answered 7 hours ago
igaligal
6,1761638
Yeah that did it. I see that I was using the "." as though it were a regex, when in fact it is taken as literal.
– Ken Ingram
6 hours ago
2
Bash Pitfall #1
– steeldriver
6 hours ago
Interesting. I typically used expansion to select the "for" range and then when I saw "$()" was a tool I began using it. I guess I made some incorrect assumptions about why my loops wood break when filenames had whitespace or non-standard characters.
– Ken Ingram
5 hours ago
add a comment |
Try removing the dot from your pattern, i.e.:
for f in xxx*;
do
uniquename="${f%%(wrx*zip}";
echo "${uniquename}";
done
That takes files whose names are of the form xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip and converts them to strings of the form xxx[0-9][0-9][0-9[0-9]ss. Is that what you're trying to accomplish?
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
answered 7 hours ago
igaligal
6,1761638
Try removing the dot from your pattern, i.e.:
for f in xxx*;
do
uniquename="${f%%(wrx*zip}";
echo "${uniquename}";
done
That takes files whose names are of the form xxx[0-9][0-9][0-9[0-9]ss(wrx-mmm).zip and converts them to strings of the form xxx[0-9][0-9][0-9[0-9]ss. Is that what you're trying to accomplish?
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
answered 7 hours ago
igaligal
6,1761638
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
edited 5 hours ago
Jeff Schaller♦
45.1k1164147
45.1k1164147
answered 7 hours ago
igaligal
6,1761638
answered 7 hours ago
igaligal
6,1761638
answered 7 hours ago
igaligal
6,1761638
6,1761638
Yeah that did it. I see that I was using the "." as though it were a regex, when in fact it is taken as literal.
– Ken Ingram
6 hours ago
2
Bash Pitfall #1
– steeldriver
6 hours ago
Interesting. I typically used expansion to select the "for" range and then when I saw "$()" was a tool I began using it. I guess I made some incorrect assumptions about why my loops wood break when filenames had whitespace or non-standard characters.
– Ken Ingram
5 hours ago
add a comment |
Yeah that did it. I see that I was using the "." as though it were a regex, when in fact it is taken as literal.
– Ken Ingram
6 hours ago
2
Bash Pitfall #1
– steeldriver
6 hours ago
Interesting. I typically used expansion to select the "for" range and then when I saw "$()" was a tool I began using it. I guess I made some incorrect assumptions about why my loops wood break when filenames had whitespace or non-standard characters.
– Ken Ingram
5 hours ago
Yeah that did it. I see that I was using the "." as though it were a regex, when in fact it is taken as literal.
– Ken Ingram
6 hours ago
Yeah that did it. I see that I was using the "." as though it were a regex, when in fact it is taken as literal.
– Ken Ingram
6 hours ago
2
2
Bash Pitfall #1
– steeldriver
6 hours ago
Bash Pitfall #1
– steeldriver
6 hours ago
Interesting. I typically used expansion to select the "for" range and then when I saw "$()" was a tool I began using it. I guess I made some incorrect assumptions about why my loops wood break when filenames had whitespace or non-standard characters.
– Ken Ingram
5 hours ago
Interesting. I typically used expansion to select the "for" range and then when I saw "$()" was a tool I began using it. I guess I made some incorrect assumptions about why my loops wood break when filenames had whitespace or non-standard characters.
– Ken Ingram
5 hours ago
add a comment |
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What exactly is the problem here? Consider adding example input and the corresponding desired output.
– igal
7 hours ago