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How to convert array of objects to single object which has dynamic key in typescript
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6
This question might be similar to frequently asked one, but this one has some different approach.
In my angular 7 application, I have the following 5 arrays which needs to be converted to the below single object with dynamic key based on the id.
{
"enabled-41": true,
"enabled-42": true,
"enabled-43": true,
"enabled-44": true,
"enabled-45": false,
"abc-41": "some description 1",
"abc-42": "some description 12",
"abc-43": "some description 123",
"abc-44": "some description 1234",
"abc-45": null,
"def-41": "some description 2",
"def-42": "some description 23",
"def-43": "some description 234",
"def-44": "some description 2345",
"def-45": null,
"type-41": "def",
"type-42": "abc",
"type-43": "def",
"type-44": "abc",
"type-45": null,
"weight-41": "25",
"weight-42": "25",
"weight-43": "25",
"weight-44": "25",
"weight-45": null
}
let arr = [
{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[item] = item.value;
return obj;
}, {})
console.log(result);I have tried using reduce function, but cannot able to get the right way to convert to a single object with the above format based on dynamic key (joining id with hypen).
Can someone help me with this?
javascript arrays typescript object ecmascript-6
edited 54 mins ago
Jack Bashford
19.2k52050
asked 1 hour ago
UI_DevUI_Dev
1,31792453
add a comment |
6
This question might be similar to frequently asked one, but this one has some different approach.
In my angular 7 application, I have the following 5 arrays which needs to be converted to the below single object with dynamic key based on the id.
{
"enabled-41": true,
"enabled-42": true,
"enabled-43": true,
"enabled-44": true,
"enabled-45": false,
"abc-41": "some description 1",
"abc-42": "some description 12",
"abc-43": "some description 123",
"abc-44": "some description 1234",
"abc-45": null,
"def-41": "some description 2",
"def-42": "some description 23",
"def-43": "some description 234",
"def-44": "some description 2345",
"def-45": null,
"type-41": "def",
"type-42": "abc",
"type-43": "def",
"type-44": "abc",
"type-45": null,
"weight-41": "25",
"weight-42": "25",
"weight-43": "25",
"weight-44": "25",
"weight-45": null
}
let arr = [
{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[item] = item.value;
return obj;
}, {})
console.log(result);I have tried using reduce function, but cannot able to get the right way to convert to a single object with the above format based on dynamic key (joining id with hypen).
Can someone help me with this?
javascript arrays typescript object ecmascript-6
edited 54 mins ago
Jack Bashford
19.2k52050
asked 1 hour ago
UI_DevUI_Dev
1,31792453
What about theCriteriaobject? What should happen? Should it be discarded?
– Jack Bashford
1 hour ago
Yes Criteria object can be discarded and want to get the single object as above
– UI_Dev
1 hour ago
add a comment |
6
6
6
1
This question might be similar to frequently asked one, but this one has some different approach.
In my angular 7 application, I have the following 5 arrays which needs to be converted to the below single object with dynamic key based on the id.
{
"enabled-41": true,
"enabled-42": true,
"enabled-43": true,
"enabled-44": true,
"enabled-45": false,
"abc-41": "some description 1",
"abc-42": "some description 12",
"abc-43": "some description 123",
"abc-44": "some description 1234",
"abc-45": null,
"def-41": "some description 2",
"def-42": "some description 23",
"def-43": "some description 234",
"def-44": "some description 2345",
"def-45": null,
"type-41": "def",
"type-42": "abc",
"type-43": "def",
"type-44": "abc",
"type-45": null,
"weight-41": "25",
"weight-42": "25",
"weight-43": "25",
"weight-44": "25",
"weight-45": null
}
let arr = [
{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[item] = item.value;
return obj;
}, {})
console.log(result);I have tried using reduce function, but cannot able to get the right way to convert to a single object with the above format based on dynamic key (joining id with hypen).
Can someone help me with this?
javascript arrays typescript object ecmascript-6
edited 54 mins ago
Jack Bashford
19.2k52050
asked 1 hour ago
UI_DevUI_Dev
1,31792453
This question might be similar to frequently asked one, but this one has some different approach.
In my angular 7 application, I have the following 5 arrays which needs to be converted to the below single object with dynamic key based on the id.
{
"enabled-41": true,
"enabled-42": true,
"enabled-43": true,
"enabled-44": true,
"enabled-45": false,
"abc-41": "some description 1",
"abc-42": "some description 12",
"abc-43": "some description 123",
"abc-44": "some description 1234",
"abc-45": null,
"def-41": "some description 2",
"def-42": "some description 23",
"def-43": "some description 234",
"def-44": "some description 2345",
"def-45": null,
"type-41": "def",
"type-42": "abc",
"type-43": "def",
"type-44": "abc",
"type-45": null,
"weight-41": "25",
"weight-42": "25",
"weight-43": "25",
"weight-44": "25",
"weight-45": null
}
let arr = [
{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[item] = item.value;
return obj;
}, {})
console.log(result);I have tried using reduce function, but cannot able to get the right way to convert to a single object with the above format based on dynamic key (joining id with hypen).
Can someone help me with this?
let arr = [
{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[item] = item.value;
return obj;
}, {})
console.log(result);let arr = [
{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[item] = item.value;
return obj;
}, {})
console.log(result);javascript arrays typescript object ecmascript-6
javascript arrays typescript object ecmascript-6
edited 54 mins ago
Jack Bashford
19.2k52050
asked 1 hour ago
UI_DevUI_Dev
1,31792453
edited 54 mins ago
Jack Bashford
19.2k52050
asked 1 hour ago
UI_DevUI_Dev
1,31792453
edited 54 mins ago
Jack Bashford
19.2k52050
edited 54 mins ago
Jack Bashford
19.2k52050
edited 54 mins ago
Jack Bashford
19.2k52050
19.2k52050
asked 1 hour ago
UI_DevUI_Dev
1,31792453
asked 1 hour ago
UI_DevUI_Dev
1,31792453
asked 1 hour ago
UI_DevUI_Dev
1,31792453
1,31792453
What about theCriteriaobject? What should happen? Should it be discarded?
– Jack Bashford
1 hour ago
Yes Criteria object can be discarded and want to get the single object as above
– UI_Dev
1 hour ago
add a comment |
What about theCriteriaobject? What should happen? Should it be discarded?
– Jack Bashford
1 hour ago
Yes Criteria object can be discarded and want to get the single object as above
– UI_Dev
1 hour ago
What about the
Criteria object? What should happen? Should it be discarded?– Jack Bashford
1 hour ago
What about the
Criteria object? What should happen? Should it be discarded?– Jack Bashford
1 hour ago
Yes Criteria object can be discarded and want to get the single object as above
– UI_Dev
1 hour ago
Yes Criteria object can be discarded and want to get the single object as above
– UI_Dev
1 hour ago
add a comment |
4 Answers
4
active
oldest
votes
4
You code is almost there. But object keys order is not guaranteed. Inside the reduce callback function add the keys in the accumulator and corresponding value.
Use template literals & square notation while creating the object keys
let arr = [{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[`enabled-${item.id}`] = item.enabled;
obj[`abc-${item.id}`] = item.abc;
obj[`def-${item.id}`] = item.def;
obj[`type-${item.id}`] = item.type;
obj[`weight-${item.id}`] = item.weight;
return obj;
}, {});
console.log(result)answered 1 hour ago
brkbrk
30.8k32446
Thanks, is there any possibility with the object key order?
– UI_Dev
52 mins ago
@UI_Dev hopefully this link stackoverflow.com/questions/5525795/… will help you
– brk
50 mins ago
Thank you... @brk
– UI_Dev
41 mins ago
why downvote? Please clarify
– brk
6 mins ago
add a comment |
4
You can use reduce with Object.keys, and place all keys you wish to exclude in an array and check against that:
let arr = [{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let exclude = ["id", "Criteria"];
let result = arr.reduce((acc, curr) => {
let id = curr.id;
Object.entries(curr).forEach(([k, v]) => {
if (!exclude.includes(k)) acc[`${k}-${id}`] = v;
});
return acc;
}, {});
console.log(result);answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
Thanks Jack...!
– UI_Dev
40 mins ago
add a comment |
2
Assuming you want to exclude all the properties whose value is an object maybe you can go with this generic idea that uses Object.entries() to traverse the inner objects and some destructuring features.
let arr=[{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let result = arr.reduce((obj, {id, ...rest}) =>
{
Object.entries(rest).forEach(([k, v]) =>
{
if (Object(v) !== v) obj[`${k}-${id}`] = v;
});
return obj;
}, {});
console.log(result);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}answered 51 mins ago
ShiderszShidersz
11.2k2933
Thanks Shidersz..!
– UI_Dev
40 mins ago
add a comment |
1
Oh, man... I just got beat. Here's my solution.
let arr= [] // hold the final object array
let keys = [] // temp item to hold the value of each key
// iterate over each key
Object.keys(input).forEach((key) => {
let pair = key.split('-') // split the key into the real key and the index
// if the index isn't in the array, push it there (this keeps the same order)
if (keys.indexOf(pair[1])===-1) {
keys.push(pair[1])
}
// use object.assign to add the keys to the existing object in the right place in the array.
arr[keys.indexOf(pair[1])] = Object.assign({}, arr[keys.indexOf(pair[1])], {[pair[0]]: input[key]}, { id: pair[1] })
})
answered 48 mins ago
tagyoureittagyoureit
1065
add a comment |
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4 Answers
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4 Answers
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4
You code is almost there. But object keys order is not guaranteed. Inside the reduce callback function add the keys in the accumulator and corresponding value.
Use template literals & square notation while creating the object keys
let arr = [{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[`enabled-${item.id}`] = item.enabled;
obj[`abc-${item.id}`] = item.abc;
obj[`def-${item.id}`] = item.def;
obj[`type-${item.id}`] = item.type;
obj[`weight-${item.id}`] = item.weight;
return obj;
}, {});
console.log(result)answered 1 hour ago
brkbrk
30.8k32446
Thanks, is there any possibility with the object key order?
– UI_Dev
52 mins ago
@UI_Dev hopefully this link stackoverflow.com/questions/5525795/… will help you
– brk
50 mins ago
Thank you... @brk
– UI_Dev
41 mins ago
why downvote? Please clarify
– brk
6 mins ago
add a comment |
4
You code is almost there. But object keys order is not guaranteed. Inside the reduce callback function add the keys in the accumulator and corresponding value.
Use template literals & square notation while creating the object keys
let arr = [{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[`enabled-${item.id}`] = item.enabled;
obj[`abc-${item.id}`] = item.abc;
obj[`def-${item.id}`] = item.def;
obj[`type-${item.id}`] = item.type;
obj[`weight-${item.id}`] = item.weight;
return obj;
}, {});
console.log(result)answered 1 hour ago
brkbrk
30.8k32446
Thanks, is there any possibility with the object key order?
– UI_Dev
52 mins ago
@UI_Dev hopefully this link stackoverflow.com/questions/5525795/… will help you
– brk
50 mins ago
Thank you... @brk
– UI_Dev
41 mins ago
why downvote? Please clarify
– brk
6 mins ago
add a comment |
4
4
4
You code is almost there. But object keys order is not guaranteed. Inside the reduce callback function add the keys in the accumulator and corresponding value.
Use template literals & square notation while creating the object keys
let arr = [{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[`enabled-${item.id}`] = item.enabled;
obj[`abc-${item.id}`] = item.abc;
obj[`def-${item.id}`] = item.def;
obj[`type-${item.id}`] = item.type;
obj[`weight-${item.id}`] = item.weight;
return obj;
}, {});
console.log(result)answered 1 hour ago
brkbrk
30.8k32446
You code is almost there. But object keys order is not guaranteed. Inside the reduce callback function add the keys in the accumulator and corresponding value.
Use template literals & square notation while creating the object keys
let arr = [{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[`enabled-${item.id}`] = item.enabled;
obj[`abc-${item.id}`] = item.abc;
obj[`def-${item.id}`] = item.def;
obj[`type-${item.id}`] = item.type;
obj[`weight-${item.id}`] = item.weight;
return obj;
}, {});
console.log(result)let arr = [{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[`enabled-${item.id}`] = item.enabled;
obj[`abc-${item.id}`] = item.abc;
obj[`def-${item.id}`] = item.def;
obj[`type-${item.id}`] = item.type;
obj[`weight-${item.id}`] = item.weight;
return obj;
}, {});
console.log(result)let arr = [{
"id": 41,
"abc": "some description 1",
"def": "some description 2",
"type": "def",
"Criteria": {
"id": 5,
"question": "follow-up",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 42,
"abc": "some description 12",
"def": "some description 23",
"type": "abc",
"Criteria": {
"id": 1,
"question": "coverage",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 43,
"abc": "some description 123",
"def": "some description 234",
"type": "def",
"Criteria": {
"id": 4,
"question": "Price",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 44,
"abc": "some description 1234",
"def": "some description 2345",
"type": "abc",
"Criteria": {
"id": 3,
"question": "Exchange",
"definition": "definition content",
"status": true
},
"weight": 25,
"enabled": true
},
{
"id": 45,
"Criteria": {
"id": 2,
"definition": "definition conent",
"question": "Random",
"status": true
},
"type": null,
"abc": null,
"def": null,
"weight": 0,
"enabled": false
}
];
let result = arr.reduce(function(obj, item) {
obj[`enabled-${item.id}`] = item.enabled;
obj[`abc-${item.id}`] = item.abc;
obj[`def-${item.id}`] = item.def;
obj[`type-${item.id}`] = item.type;
obj[`weight-${item.id}`] = item.weight;
return obj;
}, {});
console.log(result)answered 1 hour ago
brkbrk
30.8k32446
answered 1 hour ago
brkbrk
30.8k32446
answered 1 hour ago
brkbrk
30.8k32446
answered 1 hour ago
brkbrk
30.8k32446
30.8k32446
Thanks, is there any possibility with the object key order?
– UI_Dev
52 mins ago
@UI_Dev hopefully this link stackoverflow.com/questions/5525795/… will help you
– brk
50 mins ago
Thank you... @brk
– UI_Dev
41 mins ago
why downvote? Please clarify
– brk
6 mins ago
add a comment |
Thanks, is there any possibility with the object key order?
– UI_Dev
52 mins ago
@UI_Dev hopefully this link stackoverflow.com/questions/5525795/… will help you
– brk
50 mins ago
Thank you... @brk
– UI_Dev
41 mins ago
why downvote? Please clarify
– brk
6 mins ago
Thanks, is there any possibility with the object key order?
– UI_Dev
52 mins ago
Thanks, is there any possibility with the object key order?
– UI_Dev
52 mins ago
@UI_Dev hopefully this link stackoverflow.com/questions/5525795/… will help you
– brk
50 mins ago
@UI_Dev hopefully this link stackoverflow.com/questions/5525795/… will help you
– brk
50 mins ago
Thank you... @brk
– UI_Dev
41 mins ago
Thank you... @brk
– UI_Dev
41 mins ago
why downvote? Please clarify
– brk
6 mins ago
why downvote? Please clarify
– brk
6 mins ago
add a comment |
4
You can use reduce with Object.keys, and place all keys you wish to exclude in an array and check against that:
let arr = [{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let exclude = ["id", "Criteria"];
let result = arr.reduce((acc, curr) => {
let id = curr.id;
Object.entries(curr).forEach(([k, v]) => {
if (!exclude.includes(k)) acc[`${k}-${id}`] = v;
});
return acc;
}, {});
console.log(result);answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
Thanks Jack...!
– UI_Dev
40 mins ago
add a comment |
4
You can use reduce with Object.keys, and place all keys you wish to exclude in an array and check against that:
let arr = [{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let exclude = ["id", "Criteria"];
let result = arr.reduce((acc, curr) => {
let id = curr.id;
Object.entries(curr).forEach(([k, v]) => {
if (!exclude.includes(k)) acc[`${k}-${id}`] = v;
});
return acc;
}, {});
console.log(result);answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
Thanks Jack...!
– UI_Dev
40 mins ago
add a comment |
4
4
4
You can use reduce with Object.keys, and place all keys you wish to exclude in an array and check against that:
let arr = [{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let exclude = ["id", "Criteria"];
let result = arr.reduce((acc, curr) => {
let id = curr.id;
Object.entries(curr).forEach(([k, v]) => {
if (!exclude.includes(k)) acc[`${k}-${id}`] = v;
});
return acc;
}, {});
console.log(result);answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
You can use reduce with Object.keys, and place all keys you wish to exclude in an array and check against that:
let arr = [{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let exclude = ["id", "Criteria"];
let result = arr.reduce((acc, curr) => {
let id = curr.id;
Object.entries(curr).forEach(([k, v]) => {
if (!exclude.includes(k)) acc[`${k}-${id}`] = v;
});
return acc;
}, {});
console.log(result);let arr = [{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let exclude = ["id", "Criteria"];
let result = arr.reduce((acc, curr) => {
let id = curr.id;
Object.entries(curr).forEach(([k, v]) => {
if (!exclude.includes(k)) acc[`${k}-${id}`] = v;
});
return acc;
}, {});
console.log(result);let arr = [{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let exclude = ["id", "Criteria"];
let result = arr.reduce((acc, curr) => {
let id = curr.id;
Object.entries(curr).forEach(([k, v]) => {
if (!exclude.includes(k)) acc[`${k}-${id}`] = v;
});
return acc;
}, {});
console.log(result);answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
answered 55 mins ago
Jack BashfordJack Bashford
19.2k52050
19.2k52050
Thanks Jack...!
– UI_Dev
40 mins ago
add a comment |
Thanks Jack...!
– UI_Dev
40 mins ago
Thanks Jack...!
– UI_Dev
40 mins ago
Thanks Jack...!
– UI_Dev
40 mins ago
add a comment |
2
Assuming you want to exclude all the properties whose value is an object maybe you can go with this generic idea that uses Object.entries() to traverse the inner objects and some destructuring features.
let arr=[{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let result = arr.reduce((obj, {id, ...rest}) =>
{
Object.entries(rest).forEach(([k, v]) =>
{
if (Object(v) !== v) obj[`${k}-${id}`] = v;
});
return obj;
}, {});
console.log(result);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}answered 51 mins ago
ShiderszShidersz
11.2k2933
Thanks Shidersz..!
– UI_Dev
40 mins ago
add a comment |
2
Assuming you want to exclude all the properties whose value is an object maybe you can go with this generic idea that uses Object.entries() to traverse the inner objects and some destructuring features.
let arr=[{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let result = arr.reduce((obj, {id, ...rest}) =>
{
Object.entries(rest).forEach(([k, v]) =>
{
if (Object(v) !== v) obj[`${k}-${id}`] = v;
});
return obj;
}, {});
console.log(result);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}answered 51 mins ago
ShiderszShidersz
11.2k2933
Thanks Shidersz..!
– UI_Dev
40 mins ago
add a comment |
2
2
2
Assuming you want to exclude all the properties whose value is an object maybe you can go with this generic idea that uses Object.entries() to traverse the inner objects and some destructuring features.
let arr=[{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let result = arr.reduce((obj, {id, ...rest}) =>
{
Object.entries(rest).forEach(([k, v]) =>
{
if (Object(v) !== v) obj[`${k}-${id}`] = v;
});
return obj;
}, {});
console.log(result);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}answered 51 mins ago
ShiderszShidersz
11.2k2933
Assuming you want to exclude all the properties whose value is an object maybe you can go with this generic idea that uses Object.entries() to traverse the inner objects and some destructuring features.
let arr=[{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let result = arr.reduce((obj, {id, ...rest}) =>
{
Object.entries(rest).forEach(([k, v]) =>
{
if (Object(v) !== v) obj[`${k}-${id}`] = v;
});
return obj;
}, {});
console.log(result);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}let arr=[{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let result = arr.reduce((obj, {id, ...rest}) =>
{
Object.entries(rest).forEach(([k, v]) =>
{
if (Object(v) !== v) obj[`${k}-${id}`] = v;
});
return obj;
}, {});
console.log(result);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}let arr=[{"id":41,"abc":"some description 1","def":"some description 2","type":"def","Criteria":{"id":5,"question":"follow-up","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":42,"abc":"some description 12","def":"some description 23","type":"abc","Criteria":{"id":1,"question":"coverage","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":43,"abc":"some description 123","def":"some description 234","type":"def","Criteria":{"id":4,"question":"Price","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":44,"abc":"some description 1234","def":"some description 2345","type":"abc","Criteria":{"id":3,"question":"Exchange","definition":"definition content","status":true},"weight":25,"enabled":true},{"id":45,"Criteria":{"id":2,"definition":"definition conent","question":"Random","status":true},"type":null,"abc":null,"def":null,"weight":0,"enabled":false}];
let result = arr.reduce((obj, {id, ...rest}) =>
{
Object.entries(rest).forEach(([k, v]) =>
{
if (Object(v) !== v) obj[`${k}-${id}`] = v;
});
return obj;
}, {});
console.log(result);.as-console {background-color:black !important; color:lime;}
.as-console-wrapper {max-height:100% !important; top:0;}answered 51 mins ago
ShiderszShidersz
11.2k2933
answered 51 mins ago
ShiderszShidersz
11.2k2933
answered 51 mins ago
ShiderszShidersz
11.2k2933
answered 51 mins ago
ShiderszShidersz
11.2k2933
11.2k2933
Thanks Shidersz..!
– UI_Dev
40 mins ago
add a comment |
Thanks Shidersz..!
– UI_Dev
40 mins ago
Thanks Shidersz..!
– UI_Dev
40 mins ago
Thanks Shidersz..!
– UI_Dev
40 mins ago
add a comment |
1
Oh, man... I just got beat. Here's my solution.
let arr= [] // hold the final object array
let keys = [] // temp item to hold the value of each key
// iterate over each key
Object.keys(input).forEach((key) => {
let pair = key.split('-') // split the key into the real key and the index
// if the index isn't in the array, push it there (this keeps the same order)
if (keys.indexOf(pair[1])===-1) {
keys.push(pair[1])
}
// use object.assign to add the keys to the existing object in the right place in the array.
arr[keys.indexOf(pair[1])] = Object.assign({}, arr[keys.indexOf(pair[1])], {[pair[0]]: input[key]}, { id: pair[1] })
})
answered 48 mins ago
tagyoureittagyoureit
1065
add a comment |
1
Oh, man... I just got beat. Here's my solution.
let arr= [] // hold the final object array
let keys = [] // temp item to hold the value of each key
// iterate over each key
Object.keys(input).forEach((key) => {
let pair = key.split('-') // split the key into the real key and the index
// if the index isn't in the array, push it there (this keeps the same order)
if (keys.indexOf(pair[1])===-1) {
keys.push(pair[1])
}
// use object.assign to add the keys to the existing object in the right place in the array.
arr[keys.indexOf(pair[1])] = Object.assign({}, arr[keys.indexOf(pair[1])], {[pair[0]]: input[key]}, { id: pair[1] })
})
answered 48 mins ago
tagyoureittagyoureit
1065
add a comment |
1
1
1
Oh, man... I just got beat. Here's my solution.
let arr= [] // hold the final object array
let keys = [] // temp item to hold the value of each key
// iterate over each key
Object.keys(input).forEach((key) => {
let pair = key.split('-') // split the key into the real key and the index
// if the index isn't in the array, push it there (this keeps the same order)
if (keys.indexOf(pair[1])===-1) {
keys.push(pair[1])
}
// use object.assign to add the keys to the existing object in the right place in the array.
arr[keys.indexOf(pair[1])] = Object.assign({}, arr[keys.indexOf(pair[1])], {[pair[0]]: input[key]}, { id: pair[1] })
})
answered 48 mins ago
tagyoureittagyoureit
1065
Oh, man... I just got beat. Here's my solution.
let arr= [] // hold the final object array
let keys = [] // temp item to hold the value of each key
// iterate over each key
Object.keys(input).forEach((key) => {
let pair = key.split('-') // split the key into the real key and the index
// if the index isn't in the array, push it there (this keeps the same order)
if (keys.indexOf(pair[1])===-1) {
keys.push(pair[1])
}
// use object.assign to add the keys to the existing object in the right place in the array.
arr[keys.indexOf(pair[1])] = Object.assign({}, arr[keys.indexOf(pair[1])], {[pair[0]]: input[key]}, { id: pair[1] })
})
answered 48 mins ago
tagyoureittagyoureit
1065
answered 48 mins ago
tagyoureittagyoureit
1065
answered 48 mins ago
tagyoureittagyoureit
1065
answered 48 mins ago
tagyoureittagyoureit
1065
1065
add a comment |
add a comment |
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What about the
Criteriaobject? What should happen? Should it be discarded?– Jack Bashford
1 hour ago
Yes Criteria object can be discarded and want to get the single object as above
– UI_Dev
1 hour ago