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make bash exit if declare statement fails

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0

tl;dr I want bash to automatically exit after declare var=$(false).

My bash scripts use set -e. However, when using declare variable declaration idiom, the declare appears to "block" returning the return code from a shell substitution.

$ var=$(false)

$ echo $?

1



$ declare var=$(false)

$ echo $?

0

Therefore, bash will not exit on error (given set -e or set errexit). I know I could test var but that is too cumbersome after every declare statement.

How to automatically exit bash after a failure during declare?

bash bash-expansion

share|improve this question

edited 28 mins ago

JamesThomasMoon1979

asked 34 mins ago

JamesThomasMoon1979JamesThomasMoon1979

276211

add a comment | 

0

tl;dr I want bash to automatically exit after declare var=$(false).

My bash scripts use set -e. However, when using declare variable declaration idiom, the declare appears to "block" returning the return code from a shell substitution.

$ var=$(false)

$ echo $?

1



$ declare var=$(false)

$ echo $?

0

Therefore, bash will not exit on error (given set -e or set errexit). I know I could test var but that is too cumbersome after every declare statement.

How to automatically exit bash after a failure during declare?

bash bash-expansion

share|improve this question

edited 28 mins ago

JamesThomasMoon1979

asked 34 mins ago

JamesThomasMoon1979JamesThomasMoon1979

276211

add a comment | 

tl;dr I want bash to automatically exit after declare var=$(false).

My bash scripts use set -e. However, when using declare variable declaration idiom, the declare appears to "block" returning the return code from a shell substitution.

$ var=$(false)

$ echo $?

1



$ declare var=$(false)

$ echo $?

0

Therefore, bash will not exit on error (given set -e or set errexit). I know I could test var but that is too cumbersome after every declare statement.

How to automatically exit bash after a failure during declare?

bash bash-expansion

share|improve this question

edited 28 mins ago

JamesThomasMoon1979

asked 34 mins ago

JamesThomasMoon1979JamesThomasMoon1979

276211

$ var=$(false)

$ echo $?

1



$ declare var=$(false)

$ echo $?

0

share|improve this question

edited 28 mins ago

JamesThomasMoon1979

asked 34 mins ago

JamesThomasMoon1979JamesThomasMoon1979

276211

share|improve this question

edited 28 mins ago

JamesThomasMoon1979

asked 34 mins ago

JamesThomasMoon1979JamesThomasMoon1979

276211

asked 34 mins ago

JamesThomasMoon1979JamesThomasMoon1979

276211

asked 34 mins ago

JamesThomasMoon1979JamesThomasMoon1979

276211