Alternatives to achieve certain output formatDynamically format labels/columns of a LaTeX table generated in...
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Alternatives to achieve certain output format
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Alternatives to achieve certain output format
Dynamically format labels/columns of a LaTeX table generated in R/knitr/xtableHow can I format this in lyx?Array stretch only for certain rowsUsing nearrow and searrow to separate an equation in two alternativesSwap two array elementsarray: set width for certain columnsPlacing the middle of a predefined picture at a certain node
Consider the following MWE
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{ccccccccccccccccccccccc}
^{12} mathrm{C}&+&^{1} mathrm{H} &longrightarrow& ^{13}mathrm{N}&+&gamma\
&&&&^{13} mathrm{N}& longrightarrow&^{13} mathrm{C}&+&e^{+}&+&nu\
&&&&&&^{13} mathrm{C}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{14} mathrm{N}&+&gamma\
&&&&&&&&&&^{14} mathrm{N}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{15} mathrm{O}&+&gamma\
&&&&&&&&&&&&&&^{15} mathrm{O}& longrightarrow&^{15} mathrm{N}&+&e^{+}&+&nu\
&&&&&&&&&&&&&&&&^{15} mathrm{N}&+&^{1} mathrm{H} &longrightarrow&^{12} mathrm{C}&+&^{4} mathrm{He}
end{array}}
$
end{document}
with the output
The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..
arrays chemistry
add a comment |
Consider the following MWE
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{ccccccccccccccccccccccc}
^{12} mathrm{C}&+&^{1} mathrm{H} &longrightarrow& ^{13}mathrm{N}&+&gamma\
&&&&^{13} mathrm{N}& longrightarrow&^{13} mathrm{C}&+&e^{+}&+&nu\
&&&&&&^{13} mathrm{C}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{14} mathrm{N}&+&gamma\
&&&&&&&&&&^{14} mathrm{N}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{15} mathrm{O}&+&gamma\
&&&&&&&&&&&&&&^{15} mathrm{O}& longrightarrow&^{15} mathrm{N}&+&e^{+}&+&nu\
&&&&&&&&&&&&&&&&^{15} mathrm{N}&+&^{1} mathrm{H} &longrightarrow&^{12} mathrm{C}&+&^{4} mathrm{He}
end{array}}
$
end{document}
with the output
The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..
arrays chemistry
add a comment |
Consider the following MWE
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{ccccccccccccccccccccccc}
^{12} mathrm{C}&+&^{1} mathrm{H} &longrightarrow& ^{13}mathrm{N}&+&gamma\
&&&&^{13} mathrm{N}& longrightarrow&^{13} mathrm{C}&+&e^{+}&+&nu\
&&&&&&^{13} mathrm{C}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{14} mathrm{N}&+&gamma\
&&&&&&&&&&^{14} mathrm{N}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{15} mathrm{O}&+&gamma\
&&&&&&&&&&&&&&^{15} mathrm{O}& longrightarrow&^{15} mathrm{N}&+&e^{+}&+&nu\
&&&&&&&&&&&&&&&&^{15} mathrm{N}&+&^{1} mathrm{H} &longrightarrow&^{12} mathrm{C}&+&^{4} mathrm{He}
end{array}}
$
end{document}
with the output
The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..
arrays chemistry
Consider the following MWE
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{ccccccccccccccccccccccc}
^{12} mathrm{C}&+&^{1} mathrm{H} &longrightarrow& ^{13}mathrm{N}&+&gamma\
&&&&^{13} mathrm{N}& longrightarrow&^{13} mathrm{C}&+&e^{+}&+&nu\
&&&&&&^{13} mathrm{C}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{14} mathrm{N}&+&gamma\
&&&&&&&&&&^{14} mathrm{N}&+&^{mathrm{l}} mathrm{H}& longrightarrow&^{15} mathrm{O}&+&gamma\
&&&&&&&&&&&&&&^{15} mathrm{O}& longrightarrow&^{15} mathrm{N}&+&e^{+}&+&nu\
&&&&&&&&&&&&&&&&^{15} mathrm{N}&+&^{1} mathrm{H} &longrightarrow&^{12} mathrm{C}&+&^{4} mathrm{He}
end{array}}
$
end{document}
with the output
The output is pretty much what I'm looking for, but the way I get it seems rather clunky to me... Is there a better way to get the same output? The only relevant part here is that the same elements in each reaction need to be below each other... The spacing of the other parts doesn't have to be the same as in the picture..
arrays chemistry
arrays chemistry
asked 9 hours ago
SitoSito
3241212
3241212
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
It's a matter of opinion whether this is less clunky...it eliminates all &
tab characters, but requires multiple stackunder
s and some bracing.
The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace,stackengine}
begin{document}
renewcommandstackalignment{l}
renewcommandstacktype{L}
setstackgap{L}{1.4baselineskip}
stackMath
$displaystyle
^{12}mathrm{C}+^{1}mathrm{H}longrightarrow stackunder{^{13}mathrm{N}+gamma}{
^{13}mathrm{N}longrightarrow stackunder{^{13}mathrm{C}+e^{+}+nu}{
^{13}mathrm{C}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{14}mathrm{N}+gamma}{
^{14}mathrm{N}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{15}mathrm{O}+gamma}{
^{15}mathrm{O}longrightarrow stackunder{^{15}mathrm{N}+e^{+}+nu}{
^{15}mathrm{N}+^{1}mathrm{H}longrightarrow ^{12}mathrm{C}+^{4}mathrm{He}
}}}}}
$
end{document}
add a comment |
I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
I have used newcommand
to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm{...}
.
Also, I changed the 23 c
s you had in the array to *{23}{c}
.
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
% Usage:
% data{operand-1}{operator-1}{operand-2}{operator-2}{operand-3}{operator-3}{operand-4}
% Simple example:
% data{a}{+}{b}{-}{c}{*}{d}
newcommand{data}[7]{%
ensuremath{%
mathrm{#1} & mathrm{#2} & mathrm{#3} & mathrm{#4} & mathrm{#5} & mathrm{#6} & mathrm{#7}
}%
}%
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{*{23}{c}}
data{^{12} C}{+} {^{1} H} {longrightarrow} {^{13} N} {+}{gamma} \
&&&& data{^{13} N}{longrightarrow} {^{13} C} {+} {e^{+}} {+}{nu} \
&&&&&& data{^{13} C}{+} {^{1} H} {longrightarrow} {^{14} N} {+}{gamma} \
&&&&&&&&&& data{^{14} N}{+} {^{1} H} {longrightarrow} {^{15} O} {+}{gamma} \
&&&&&&&&&&&&&& data{^{15} O}{longrightarrow} {^{15} N} {+} {e^{+}} {+}{nu} \
&&&&&&&&&&&&&&&& data{^{15} N}{+} {^{1} H} {longrightarrow} {^{12} C} {+}{^{4} He}\
end{array}}
$
end{document}
add a comment |
Enough simple?
documentclass{report}
usepackage{mhchem,parskip}
defa{phantom{ce{^12C + ^1H ->}}}
defb{phantom{ce{^13N ->}}}
begin{document}
ce{^12C + ^1H -> ^13N + gamma}par
ace{^13N -> ^13C + $e^+$ + nu}par
abce{^13C + ^1H -> ^14N + gamma}
end{document}
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
It's a matter of opinion whether this is less clunky...it eliminates all &
tab characters, but requires multiple stackunder
s and some bracing.
The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace,stackengine}
begin{document}
renewcommandstackalignment{l}
renewcommandstacktype{L}
setstackgap{L}{1.4baselineskip}
stackMath
$displaystyle
^{12}mathrm{C}+^{1}mathrm{H}longrightarrow stackunder{^{13}mathrm{N}+gamma}{
^{13}mathrm{N}longrightarrow stackunder{^{13}mathrm{C}+e^{+}+nu}{
^{13}mathrm{C}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{14}mathrm{N}+gamma}{
^{14}mathrm{N}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{15}mathrm{O}+gamma}{
^{15}mathrm{O}longrightarrow stackunder{^{15}mathrm{N}+e^{+}+nu}{
^{15}mathrm{N}+^{1}mathrm{H}longrightarrow ^{12}mathrm{C}+^{4}mathrm{He}
}}}}}
$
end{document}
add a comment |
It's a matter of opinion whether this is less clunky...it eliminates all &
tab characters, but requires multiple stackunder
s and some bracing.
The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace,stackengine}
begin{document}
renewcommandstackalignment{l}
renewcommandstacktype{L}
setstackgap{L}{1.4baselineskip}
stackMath
$displaystyle
^{12}mathrm{C}+^{1}mathrm{H}longrightarrow stackunder{^{13}mathrm{N}+gamma}{
^{13}mathrm{N}longrightarrow stackunder{^{13}mathrm{C}+e^{+}+nu}{
^{13}mathrm{C}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{14}mathrm{N}+gamma}{
^{14}mathrm{N}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{15}mathrm{O}+gamma}{
^{15}mathrm{O}longrightarrow stackunder{^{15}mathrm{N}+e^{+}+nu}{
^{15}mathrm{N}+^{1}mathrm{H}longrightarrow ^{12}mathrm{C}+^{4}mathrm{He}
}}}}}
$
end{document}
add a comment |
It's a matter of opinion whether this is less clunky...it eliminates all &
tab characters, but requires multiple stackunder
s and some bracing.
The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace,stackengine}
begin{document}
renewcommandstackalignment{l}
renewcommandstacktype{L}
setstackgap{L}{1.4baselineskip}
stackMath
$displaystyle
^{12}mathrm{C}+^{1}mathrm{H}longrightarrow stackunder{^{13}mathrm{N}+gamma}{
^{13}mathrm{N}longrightarrow stackunder{^{13}mathrm{C}+e^{+}+nu}{
^{13}mathrm{C}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{14}mathrm{N}+gamma}{
^{14}mathrm{N}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{15}mathrm{O}+gamma}{
^{15}mathrm{O}longrightarrow stackunder{^{15}mathrm{N}+e^{+}+nu}{
^{15}mathrm{N}+^{1}mathrm{H}longrightarrow ^{12}mathrm{C}+^{4}mathrm{He}
}}}}}
$
end{document}
It's a matter of opinion whether this is less clunky...it eliminates all &
tab characters, but requires multiple stackunder
s and some bracing.
The appearance is a bit different, however "the same elements of each reaction are below each other", as requested by the OP. While there are no other alignments that apply one may observe that the spacing on any given line is "correct".
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace,stackengine}
begin{document}
renewcommandstackalignment{l}
renewcommandstacktype{L}
setstackgap{L}{1.4baselineskip}
stackMath
$displaystyle
^{12}mathrm{C}+^{1}mathrm{H}longrightarrow stackunder{^{13}mathrm{N}+gamma}{
^{13}mathrm{N}longrightarrow stackunder{^{13}mathrm{C}+e^{+}+nu}{
^{13}mathrm{C}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{14}mathrm{N}+gamma}{
^{14}mathrm{N}+^{mathrm{l}}mathrm{H}longrightarrow stackunder{^{15}mathrm{O}+gamma}{
^{15}mathrm{O}longrightarrow stackunder{^{15}mathrm{N}+e^{+}+nu}{
^{15}mathrm{N}+^{1}mathrm{H}longrightarrow ^{12}mathrm{C}+^{4}mathrm{He}
}}}}}
$
end{document}
answered 8 hours ago
Steven B. SegletesSteven B. Segletes
166k9209426
166k9209426
add a comment |
add a comment |
I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
I have used newcommand
to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm{...}
.
Also, I changed the 23 c
s you had in the array to *{23}{c}
.
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
% Usage:
% data{operand-1}{operator-1}{operand-2}{operator-2}{operand-3}{operator-3}{operand-4}
% Simple example:
% data{a}{+}{b}{-}{c}{*}{d}
newcommand{data}[7]{%
ensuremath{%
mathrm{#1} & mathrm{#2} & mathrm{#3} & mathrm{#4} & mathrm{#5} & mathrm{#6} & mathrm{#7}
}%
}%
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{*{23}{c}}
data{^{12} C}{+} {^{1} H} {longrightarrow} {^{13} N} {+}{gamma} \
&&&& data{^{13} N}{longrightarrow} {^{13} C} {+} {e^{+}} {+}{nu} \
&&&&&& data{^{13} C}{+} {^{1} H} {longrightarrow} {^{14} N} {+}{gamma} \
&&&&&&&&&& data{^{14} N}{+} {^{1} H} {longrightarrow} {^{15} O} {+}{gamma} \
&&&&&&&&&&&&&& data{^{15} O}{longrightarrow} {^{15} N} {+} {e^{+}} {+}{nu} \
&&&&&&&&&&&&&&&& data{^{15} N}{+} {^{1} H} {longrightarrow} {^{12} C} {+}{^{4} He}\
end{array}}
$
end{document}
add a comment |
I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
I have used newcommand
to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm{...}
.
Also, I changed the 23 c
s you had in the array to *{23}{c}
.
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
% Usage:
% data{operand-1}{operator-1}{operand-2}{operator-2}{operand-3}{operator-3}{operand-4}
% Simple example:
% data{a}{+}{b}{-}{c}{*}{d}
newcommand{data}[7]{%
ensuremath{%
mathrm{#1} & mathrm{#2} & mathrm{#3} & mathrm{#4} & mathrm{#5} & mathrm{#6} & mathrm{#7}
}%
}%
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{*{23}{c}}
data{^{12} C}{+} {^{1} H} {longrightarrow} {^{13} N} {+}{gamma} \
&&&& data{^{13} N}{longrightarrow} {^{13} C} {+} {e^{+}} {+}{nu} \
&&&&&& data{^{13} C}{+} {^{1} H} {longrightarrow} {^{14} N} {+}{gamma} \
&&&&&&&&&& data{^{14} N}{+} {^{1} H} {longrightarrow} {^{15} O} {+}{gamma} \
&&&&&&&&&&&&&& data{^{15} O}{longrightarrow} {^{15} N} {+} {e^{+}} {+}{nu} \
&&&&&&&&&&&&&&&& data{^{15} N}{+} {^{1} H} {longrightarrow} {^{12} C} {+}{^{4} He}\
end{array}}
$
end{document}
add a comment |
I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
I have used newcommand
to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm{...}
.
Also, I changed the 23 c
s you had in the array to *{23}{c}
.
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
% Usage:
% data{operand-1}{operator-1}{operand-2}{operator-2}{operand-3}{operator-3}{operand-4}
% Simple example:
% data{a}{+}{b}{-}{c}{*}{d}
newcommand{data}[7]{%
ensuremath{%
mathrm{#1} & mathrm{#2} & mathrm{#3} & mathrm{#4} & mathrm{#5} & mathrm{#6} & mathrm{#7}
}%
}%
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{*{23}{c}}
data{^{12} C}{+} {^{1} H} {longrightarrow} {^{13} N} {+}{gamma} \
&&&& data{^{13} N}{longrightarrow} {^{13} C} {+} {e^{+}} {+}{nu} \
&&&&&& data{^{13} C}{+} {^{1} H} {longrightarrow} {^{14} N} {+}{gamma} \
&&&&&&&&&& data{^{14} N}{+} {^{1} H} {longrightarrow} {^{15} O} {+}{gamma} \
&&&&&&&&&&&&&& data{^{15} O}{longrightarrow} {^{15} N} {+} {e^{+}} {+}{nu} \
&&&&&&&&&&&&&&&& data{^{15} N}{+} {^{1} H} {longrightarrow} {^{12} C} {+}{^{4} He}\
end{array}}
$
end{document}
I suggest to align your entries like the way I did (using Tab) to make it easier to read and modify if needed.
I have used newcommand
to create a way for you to enter the data of a row and every cell in the array is encapsulated by mathrm{...}
.
Also, I changed the 23 c
s you had in the array to *{23}{c}
.
documentclass[border=10 pt]{standalone}
usepackage{mathtools,setspace}
% Usage:
% data{operand-1}{operator-1}{operand-2}{operator-2}{operand-3}{operator-3}{operand-4}
% Simple example:
% data{a}{+}{b}{-}{c}{*}{d}
newcommand{data}[7]{%
ensuremath{%
mathrm{#1} & mathrm{#2} & mathrm{#3} & mathrm{#4} & mathrm{#5} & mathrm{#6} & mathrm{#7}
}%
}%
begin{document}
$displaystyle
{setstretch{1.5}
begin{array}{*{23}{c}}
data{^{12} C}{+} {^{1} H} {longrightarrow} {^{13} N} {+}{gamma} \
&&&& data{^{13} N}{longrightarrow} {^{13} C} {+} {e^{+}} {+}{nu} \
&&&&&& data{^{13} C}{+} {^{1} H} {longrightarrow} {^{14} N} {+}{gamma} \
&&&&&&&&&& data{^{14} N}{+} {^{1} H} {longrightarrow} {^{15} O} {+}{gamma} \
&&&&&&&&&&&&&& data{^{15} O}{longrightarrow} {^{15} N} {+} {e^{+}} {+}{nu} \
&&&&&&&&&&&&&&&& data{^{15} N}{+} {^{1} H} {longrightarrow} {^{12} C} {+}{^{4} He}\
end{array}}
$
end{document}
edited 8 hours ago
answered 8 hours ago
M. Al JumailyM. Al Jumaily
1,1361210
1,1361210
add a comment |
add a comment |
Enough simple?
documentclass{report}
usepackage{mhchem,parskip}
defa{phantom{ce{^12C + ^1H ->}}}
defb{phantom{ce{^13N ->}}}
begin{document}
ce{^12C + ^1H -> ^13N + gamma}par
ace{^13N -> ^13C + $e^+$ + nu}par
abce{^13C + ^1H -> ^14N + gamma}
end{document}
add a comment |
Enough simple?
documentclass{report}
usepackage{mhchem,parskip}
defa{phantom{ce{^12C + ^1H ->}}}
defb{phantom{ce{^13N ->}}}
begin{document}
ce{^12C + ^1H -> ^13N + gamma}par
ace{^13N -> ^13C + $e^+$ + nu}par
abce{^13C + ^1H -> ^14N + gamma}
end{document}
add a comment |
Enough simple?
documentclass{report}
usepackage{mhchem,parskip}
defa{phantom{ce{^12C + ^1H ->}}}
defb{phantom{ce{^13N ->}}}
begin{document}
ce{^12C + ^1H -> ^13N + gamma}par
ace{^13N -> ^13C + $e^+$ + nu}par
abce{^13C + ^1H -> ^14N + gamma}
end{document}
Enough simple?
documentclass{report}
usepackage{mhchem,parskip}
defa{phantom{ce{^12C + ^1H ->}}}
defb{phantom{ce{^13N ->}}}
begin{document}
ce{^12C + ^1H -> ^13N + gamma}par
ace{^13N -> ^13C + $e^+$ + nu}par
abce{^13C + ^1H -> ^14N + gamma}
end{document}
answered 1 hour ago
FranFran
54.3k6122184
54.3k6122184
add a comment |
add a comment |
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