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Fetching logs from log file using grep

How to match multiple lines starting with a TAB, and the line before the 1st one in a group?Return line conditonally on next lineHow to write and handle custom log file properly?GREP uppercase characters from a specific column, pipe the result to same file as new columnTail Grep - Print surrounding lines until pattern is matchedGetting a range of lines between timestamps from /var/log/messagesHow to remove a group of lines from a file?Grep file contents EXCEPT match case WITH contextgrep or awk to extact xml from log based on search stringgrep everything up until and including a pattern

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

I am trying to fetch logs from log file using grep command and format of log file is as follows:

[1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

at com.own.ws.wim.util.UniqueNameHelper.formatUniqueName(UniqueNameHelper.java:102)

at com.own.ws.wim.ProfileManager.getImpl(ProfileManager.java:1569)

Until now, I am able to fetch logs but I want stack trace as well.

grep -i '^[[:space:]]*at' --before-context=2 SystemOut.log | grep "1/13/16 7:[1-60]" 



output : [1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

Any idea how this can be achieved?

grep logs

share|improve this question

edited Jan 14 '16 at 9:03

Kevdog777

2,1221313 gold badges3434 silver badges6161 bronze badges

asked Jan 14 '16 at 8:33

Anil KumarAnil Kumar

10111 bronze badge

bumped to the homepage by Community♦ 1 hour ago

This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.

add a comment | 

0

I am trying to fetch logs from log file using grep command and format of log file is as follows:

[1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

at com.own.ws.wim.util.UniqueNameHelper.formatUniqueName(UniqueNameHelper.java:102)

at com.own.ws.wim.ProfileManager.getImpl(ProfileManager.java:1569)

Until now, I am able to fetch logs but I want stack trace as well.

grep -i '^[[:space:]]*at' --before-context=2 SystemOut.log | grep "1/13/16 7:[1-60]" 



output : [1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

Any idea how this can be achieved?

grep logs

share|improve this question

edited Jan 14 '16 at 9:03

Kevdog777

2,1221313 gold badges3434 silver badges6161 bronze badges

asked Jan 14 '16 at 8:33

Anil KumarAnil Kumar

10111 bronze badge

bumped to the homepage by Community♦ 1 hour ago

This question has answers that may be good or bad; the system has marked it active so that they can be reviewed.

add a comment | 

I am trying to fetch logs from log file using grep command and format of log file is as follows:

[1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

at com.own.ws.wim.util.UniqueNameHelper.formatUniqueName(UniqueNameHelper.java:102)

at com.own.ws.wim.ProfileManager.getImpl(ProfileManager.java:1569)

Until now, I am able to fetch logs but I want stack trace as well.

grep -i '^[[:space:]]*at' --before-context=2 SystemOut.log | grep "1/13/16 7:[1-60]" 



output : [1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

Any idea how this can be achieved?

grep logs

share|improve this question

edited Jan 14 '16 at 9:03

Kevdog777

2,1221313 gold badges3434 silver badges6161 bronze badges

asked Jan 14 '16 at 8:33

Anil KumarAnil Kumar

10111 bronze badge

[1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

at com.own.ws.wim.util.UniqueNameHelper.formatUniqueName(UniqueNameHelper.java:102)

at com.own.ws.wim.ProfileManager.getImpl(ProfileManager.java:1569)

grep -i '^[[:space:]]*at' --before-context=2 SystemOut.log | grep "1/13/16 7:[1-60]" 



output : [1/10/16 23:55:33:018 PST] 00000057 ServerObj E   SECJ0373E: Exception message

share|improve this question

edited Jan 14 '16 at 9:03

Kevdog777

2,1221313 gold badges3434 silver badges6161 bronze badges

asked Jan 14 '16 at 8:33

Anil KumarAnil Kumar

10111 bronze badge

share|improve this question

edited Jan 14 '16 at 9:03

Kevdog777

2,1221313 gold badges3434 silver badges6161 bronze badges

asked Jan 14 '16 at 8:33

Anil KumarAnil Kumar

10111 bronze badge

edited Jan 14 '16 at 9:03

Kevdog777

2,1221313 gold badges3434 silver badges6161 bronze badges

edited Jan 14 '16 at 9:03

Kevdog777

2,1221313 gold badges3434 silver badges6161 bronze badges

asked Jan 14 '16 at 8:33

Anil KumarAnil Kumar

10111 bronze badge

asked Jan 14 '16 at 8:33

Anil KumarAnil Kumar

10111 bronze badge

1 Answer
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0

Awk with a field separator of "at" can also work. "^[" matches lines starting with the date stamp and $1 is the first field.

awk -F"at" '/^[/{print $1}' test

Based on your comment and if I understand properly what you need, the awk command should include the lines you are looking for with your grep range between 7 and 8 o'clock.

However, it sounds like you need two lists. To do this you could run the awk command on your log file and output it to another file. You could then awk/grep the second file.

awk -F"at" '/^[/{print $1}' test>> ExtractedLogs.txt

awk -F"at" '$1 ~ "07:"{print $1}' ExtractedLogs.txt>> StackTraceOnly.txt

share|improve this answer

edited Jan 15 '16 at 13:59

answered Jan 14 '16 at 12:24

rcjohnsonrcjohnson

83055 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  grep "1/13/16 7:[1-60]" --> This is fetching based on time from 7 to 8 0'clock. So I just want to combine these two filters.
  
  – Anil Kumar
  Jan 14 '16 at 13:22
  

  
  
  
  

add a comment | 

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0

Awk with a field separator of "at" can also work. "^[" matches lines starting with the date stamp and $1 is the first field.

awk -F"at" '/^[/{print $1}' test

Based on your comment and if I understand properly what you need, the awk command should include the lines you are looking for with your grep range between 7 and 8 o'clock.

However, it sounds like you need two lists. To do this you could run the awk command on your log file and output it to another file. You could then awk/grep the second file.

awk -F"at" '/^[/{print $1}' test>> ExtractedLogs.txt

awk -F"at" '$1 ~ "07:"{print $1}' ExtractedLogs.txt>> StackTraceOnly.txt

share|improve this answer

edited Jan 15 '16 at 13:59

answered Jan 14 '16 at 12:24

rcjohnsonrcjohnson

83055 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  grep "1/13/16 7:[1-60]" --> This is fetching based on time from 7 to 8 0'clock. So I just want to combine these two filters.
  
  – Anil Kumar
  Jan 14 '16 at 13:22
  

  
  
  
  

add a comment | 

0

Awk with a field separator of "at" can also work. "^[" matches lines starting with the date stamp and $1 is the first field.

awk -F"at" '/^[/{print $1}' test

Based on your comment and if I understand properly what you need, the awk command should include the lines you are looking for with your grep range between 7 and 8 o'clock.

However, it sounds like you need two lists. To do this you could run the awk command on your log file and output it to another file. You could then awk/grep the second file.

awk -F"at" '/^[/{print $1}' test>> ExtractedLogs.txt

awk -F"at" '$1 ~ "07:"{print $1}' ExtractedLogs.txt>> StackTraceOnly.txt

share|improve this answer

edited Jan 15 '16 at 13:59

answered Jan 14 '16 at 12:24

rcjohnsonrcjohnson

83055 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  grep "1/13/16 7:[1-60]" --> This is fetching based on time from 7 to 8 0'clock. So I just want to combine these two filters.
  
  – Anil Kumar
  Jan 14 '16 at 13:22
  

  
  
  
  

add a comment | 

Awk with a field separator of "at" can also work. "^[" matches lines starting with the date stamp and $1 is the first field.

awk -F"at" '/^[/{print $1}' test

Based on your comment and if I understand properly what you need, the awk command should include the lines you are looking for with your grep range between 7 and 8 o'clock.

However, it sounds like you need two lists. To do this you could run the awk command on your log file and output it to another file. You could then awk/grep the second file.

awk -F"at" '/^[/{print $1}' test>> ExtractedLogs.txt

awk -F"at" '$1 ~ "07:"{print $1}' ExtractedLogs.txt>> StackTraceOnly.txt

share|improve this answer

edited Jan 15 '16 at 13:59

answered Jan 14 '16 at 12:24

rcjohnsonrcjohnson

83055 silver badges1010 bronze badges

awk -F"at" '/^[/{print $1}' test

awk -F"at" '/^[/{print $1}' test>> ExtractedLogs.txt

awk -F"at" '$1 ~ "07:"{print $1}' ExtractedLogs.txt>> StackTraceOnly.txt

share|improve this answer

edited Jan 15 '16 at 13:59

answered Jan 14 '16 at 12:24

rcjohnsonrcjohnson

83055 silver badges1010 bronze badges

answered Jan 14 '16 at 12:24

rcjohnsonrcjohnson

83055 silver badges1010 bronze badges

answered Jan 14 '16 at 12:24

rcjohnsonrcjohnson

83055 silver badges1010 bronze badges