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0

I have a bash script named test.sh as below:

#!/bin/bash



while :

do

    echo xxx

    sleep 1

done

I don't know why ./test.sh & | ./test.sh gives me an error: -bash: syntax error near unexpected token |', whereas ./test.sh | ./test.sh and ./test.sh | ./test.sh & work.

bash pipe

share|improve this question

asked 50 mins ago

YvesYves

9891025

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @NasirRiley nope, it's perfectly fine to run it in the background: { echo yup & } | cat or { ./test.sh & } | ./test.sh are fine. It's just a limitation of the grammar.
  
  – mosvy
  38 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @mosvy That isn't the same thing. If you remove the curly brackets then the error occurs with either of those commands. In the context that he's trying to run it, it's going to return that error which is why it doesn't occur when the ampersand is removed.
  
  – Nasir Riley
  33 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @NasirRiley do you mean that { a & } | b won't run a in the background? It will.
  
  – mosvy
  29 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  BTW, the full shell grammar is here. It's obvious from following the productions that you cannot write a & | b, but that doesn't mean that you can't pipe the output of a bg command to a fg command. You can do that fine. Just add some extra braces.
  
  – mosvy
  26 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @mosvy That literal command wouldn't run anywhere because a and b are not commands unless you've set an alias to something(I'm joking). What I mean is that the way that it functions is not the same. Perhaps I should delete my previous comment to clarify what I actually mean.
  
  – Nasir Riley
  25 mins ago
  

  
  
  
  

 | 
show 4 more comments

0

I have a bash script named test.sh as below:

#!/bin/bash



while :

do

    echo xxx

    sleep 1

done

I don't know why ./test.sh & | ./test.sh gives me an error: -bash: syntax error near unexpected token |', whereas ./test.sh | ./test.sh and ./test.sh | ./test.sh & work.

bash pipe

share|improve this question

asked 50 mins ago

YvesYves

9891025

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @NasirRiley nope, it's perfectly fine to run it in the background: { echo yup & } | cat or { ./test.sh & } | ./test.sh are fine. It's just a limitation of the grammar.
  
  – mosvy
  38 mins ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @mosvy That isn't the same thing. If you remove the curly brackets then the error occurs with either of those commands. In the context that he's trying to run it, it's going to return that error which is why it doesn't occur when the ampersand is removed.
  
  – Nasir Riley
  33 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @NasirRiley do you mean that { a & } | b won't run a in the background? It will.
  
  – mosvy
  29 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  BTW, the full shell grammar is here. It's obvious from following the productions that you cannot write a & | b, but that doesn't mean that you can't pipe the output of a bg command to a fg command. You can do that fine. Just add some extra braces.
  
  – mosvy
  26 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @mosvy That literal command wouldn't run anywhere because a and b are not commands unless you've set an alias to something(I'm joking). What I mean is that the way that it functions is not the same. Perhaps I should delete my previous comment to clarify what I actually mean.
  
  – Nasir Riley
  25 mins ago
  

  
  
  
  

 | 
show 4 more comments

I have a bash script named test.sh as below:

#!/bin/bash



while :

do

    echo xxx

    sleep 1

done

I don't know why ./test.sh & | ./test.sh gives me an error: -bash: syntax error near unexpected token |', whereas ./test.sh | ./test.sh and ./test.sh | ./test.sh & work.

bash pipe

share|improve this question

asked 50 mins ago

YvesYves

9891025

#!/bin/bash



while :

do

    echo xxx

    sleep 1

done

share|improve this question

asked 50 mins ago

YvesYves

9891025

share|improve this question

asked 50 mins ago

YvesYves

9891025

asked 50 mins ago

YvesYves

9891025

asked 50 mins ago

YvesYves

9891025