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Generating random numbers that keep a minimum distance


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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







2












$begingroup$


I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[{nCells, min,test,i,j,r},
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], {j, i}
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$












  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    7 hours ago


















2












$begingroup$


I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[{nCells, min,test,i,j,r},
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], {j, i}
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$












  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    7 hours ago














2












2








2





$begingroup$


I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[{nCells, min,test,i,j,r},
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], {j, i}
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$




I want to create a list of n random integers from 1 to m, where all integers have to be at least a certain distance min apart (i.e. 3 integers out of Range[10], keeping a minimum distance of 2)



This is the module I created to fullfill that purpose:



StartGen[MinimalDistance_] := 
Module[{nCells, min,test,i,j,r},
min = MinimalDistance;

(*Just create a Random Sample from Range[m] if min=0
is chosen*)
If[min == 0,
nCells = Sort[RandomSample[Range[m], n]];
Return[nCells]
,
nCells = Table[0, n];
nCells[[1]] = RandomInteger[m];
i = 1; j = 1;

(*Only execute if n integers out of m actually can
keep a minimum distance of min*)
If[m/(n (min + 1)) >= 1,

While[i <= n,
(*Generate random integers from Range[m] until one
fits with the already assigned Integers*)
r = RandomInteger[m];
test = True;
Do[If[Abs[nCells[[j]] - r] <= min,
test = False; Break[],
test = True], {j, i}
];
If[test == True, nCells[[i]] = r; i++, Null];
];

nCells = Sort[nCells];
Return[nCells];
,
Print["Impossible figuration for m n and min"];
];
];
];


Now the performance problem this creates is quite obvious: If the number of possible integers m and the minimum distance min are too big, as the While loop goes on fewer and fewer generated integers will fit the requirements and it gets harder and harder to hit those few integers through generating random numbers out of Range[m]. (For me this module couldn't produce lists for n=100,m=1000,min=8.)



I think the solution to this problem lies in reducing the number of Integers to choose from as the calculation go on, i.e. eliminate integers that dont fit the requirements anymore.



I tried implementing this with some variants of the DeleteCases[] function but I always ended up just creating more iterative calculations that would worsen the performance once again.

Is there an elegant way to do this?







list-manipulation performance-tuning






share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question







New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question






New contributor



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Check out our Code of Conduct.








asked 8 hours ago









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New contributor



Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Maxim Hanselowski is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.














  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    7 hours ago


















  • $begingroup$
    Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
    $endgroup$
    – Henrik Schumacher
    7 hours ago
















$begingroup$
Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
$endgroup$
– Henrik Schumacher
7 hours ago




$begingroup$
Your problem is that Length[Range[8, 1000, 2 8 - 1]] equals 67 which is less than 100. So that's just not always possible with n=100, m=1000, and min=8.
$endgroup$
– Henrik Schumacher
7 hours ago










2 Answers
2






active

oldest

votes


















2












$begingroup$

How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



gen2[m_, n_, min_] := Module[{nCells, set},
set = Range[m];
nCells = RandomSample[set, 1];
While[Length[nCells] < n && Length[set] > 0,
set = Complement[set,
Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
If[Length[set] < 1, Print["Couldn't pick ", n],
nCells = Join[nCells, RandomSample[set, 1]]];
];
nCells]


Table[gen2[10, 3, 2], {10}] // Column
(*
{4,7,10}
{8,3,6}
{2,6,9}
{5,8,3}
{7,10,1}
{3,10,6}
{3,7,10}
{3,9,6}
{1,10,5}
{9,2,6} *)


As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



gen2[1000, 100, 8]
(*
Couldn't pick 100
{599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
231, 539, 327, 731, 776, 456, 799, 64, 722, 271} *)



But 7 is fine:



test = gen2[1000, 100, 7]
(*
{556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
311, 273} *)


Test the minimum distance between numbers:



stest = Sort[test];
Min[Table[stest[[i]] - stest[[i - 1]], {i, 2, Length[test]}]]
(* 7 *)
```





share|improve this answer









$endgroup$





















    2












    $begingroup$


    1. Construct a random sample from Range[m] satisfying the minimum
      distance requirements taking into account the fact that if $x_k$ is
      selected at step $k$, the choices in step $k+1$ are restricted to
      the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
      additional elements in remaining steps satisfying the minimum distance constraint.

    2. Shuffle the list obtained in the first step




    ClearAll[f]
    f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
    FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


    Examples:



    Table[f[10, 3, 2], {5}]



    {{8, 3, 6}, {6, 10, 8}, {8, 5, 10}, {8, 10, 6}, {10, 1, 4}}




    Min[Differences@Sort@#] & /@ %



    {2, 2, 2, 2, 3}




    f[10, 4, 3]



    f[10, 4, 3] (* impossible *)




    f[1000, 100, 8]



    {848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
    936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
    928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
    688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
    624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
    24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
    768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
    360, 257, 440}




    Min @ Differences@ Sort @ %



    8




    res = f[10000000, 10000, 800]; // AbsoluteTiming // First



    0.105936




    Min @ Differences @ Sort @ res



    800




    Update: An alternative implementation using NestList:



    ClearAll[f2]
    f2[m_, n_, d_] /; n d <= m := Module[{k = 1}, RandomSample @ Rest @
    NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





    share|improve this answer











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      2 Answers
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      2 Answers
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      2












      $begingroup$

      How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



      gen2[m_, n_, min_] := Module[{nCells, set},
      set = Range[m];
      nCells = RandomSample[set, 1];
      While[Length[nCells] < n && Length[set] > 0,
      set = Complement[set,
      Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
      If[Length[set] < 1, Print["Couldn't pick ", n],
      nCells = Join[nCells, RandomSample[set, 1]]];
      ];
      nCells]


      Table[gen2[10, 3, 2], {10}] // Column
      (*
      {4,7,10}
      {8,3,6}
      {2,6,9}
      {5,8,3}
      {7,10,1}
      {3,10,6}
      {3,7,10}
      {3,9,6}
      {1,10,5}
      {9,2,6} *)


      As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



      gen2[1000, 100, 8]
      (*
      Couldn't pick 100
      {599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
      371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
      812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
      742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
      107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
      129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
      231, 539, 327, 731, 776, 456, 799, 64, 722, 271} *)



      But 7 is fine:



      test = gen2[1000, 100, 7]
      (*
      {556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
      55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
      519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
      997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
      259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
      493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
      580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
      311, 273} *)


      Test the minimum distance between numbers:



      stest = Sort[test];
      Min[Table[stest[[i]] - stest[[i - 1]], {i, 2, Length[test]}]]
      (* 7 *)
      ```





      share|improve this answer









      $endgroup$


















        2












        $begingroup$

        How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



        gen2[m_, n_, min_] := Module[{nCells, set},
        set = Range[m];
        nCells = RandomSample[set, 1];
        While[Length[nCells] < n && Length[set] > 0,
        set = Complement[set,
        Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
        If[Length[set] < 1, Print["Couldn't pick ", n],
        nCells = Join[nCells, RandomSample[set, 1]]];
        ];
        nCells]


        Table[gen2[10, 3, 2], {10}] // Column
        (*
        {4,7,10}
        {8,3,6}
        {2,6,9}
        {5,8,3}
        {7,10,1}
        {3,10,6}
        {3,7,10}
        {3,9,6}
        {1,10,5}
        {9,2,6} *)


        As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



        gen2[1000, 100, 8]
        (*
        Couldn't pick 100
        {599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
        371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
        812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
        742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
        107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
        129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
        231, 539, 327, 731, 776, 456, 799, 64, 722, 271} *)



        But 7 is fine:



        test = gen2[1000, 100, 7]
        (*
        {556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
        55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
        519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
        997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
        259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
        493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
        580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
        311, 273} *)


        Test the minimum distance between numbers:



        stest = Sort[test];
        Min[Table[stest[[i]] - stest[[i - 1]], {i, 2, Length[test]}]]
        (* 7 *)
        ```





        share|improve this answer









        $endgroup$
















          2












          2








          2





          $begingroup$

          How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



          gen2[m_, n_, min_] := Module[{nCells, set},
          set = Range[m];
          nCells = RandomSample[set, 1];
          While[Length[nCells] < n && Length[set] > 0,
          set = Complement[set,
          Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
          If[Length[set] < 1, Print["Couldn't pick ", n],
          nCells = Join[nCells, RandomSample[set, 1]]];
          ];
          nCells]


          Table[gen2[10, 3, 2], {10}] // Column
          (*
          {4,7,10}
          {8,3,6}
          {2,6,9}
          {5,8,3}
          {7,10,1}
          {3,10,6}
          {3,7,10}
          {3,9,6}
          {1,10,5}
          {9,2,6} *)


          As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



          gen2[1000, 100, 8]
          (*
          Couldn't pick 100
          {599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
          371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
          812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
          742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
          107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
          129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
          231, 539, 327, 731, 776, 456, 799, 64, 722, 271} *)



          But 7 is fine:



          test = gen2[1000, 100, 7]
          (*
          {556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
          55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
          519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
          997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
          259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
          493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
          580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
          311, 273} *)


          Test the minimum distance between numbers:



          stest = Sort[test];
          Min[Table[stest[[i]] - stest[[i - 1]], {i, 2, Length[test]}]]
          (* 7 *)
          ```





          share|improve this answer









          $endgroup$



          How about something like this - rather than picking random numbers until one satisfies the minimum distance criteria, pick the random number from a set that excludes disallowed values.



          gen2[m_, n_, min_] := Module[{nCells, set},
          set = Range[m];
          nCells = RandomSample[set, 1];
          While[Length[nCells] < n && Length[set] > 0,
          set = Complement[set,
          Range[nCells[[-1]] - min + 1, nCells[[-1]] + min - 1]];
          If[Length[set] < 1, Print["Couldn't pick ", n],
          nCells = Join[nCells, RandomSample[set, 1]]];
          ];
          nCells]


          Table[gen2[10, 3, 2], {10}] // Column
          (*
          {4,7,10}
          {8,3,6}
          {2,6,9}
          {5,8,3}
          {7,10,1}
          {3,10,6}
          {3,7,10}
          {3,9,6}
          {1,10,5}
          {9,2,6} *)


          As noted by Henrik Schumacher in the comments, n=100, m=1000, min=8 doesn't work most of the time (you get an empty set before you pick 100 numbers):



          gen2[1000, 100, 8]
          (*
          Couldn't pick 100
          {599, 14, 526, 475, 52, 448, 791, 576, 196, 711, 941, 35, 211, 483,
          371, 401, 827, 354, 757, 547, 858, 86, 222, 336, 696, 913, 419, 386,
          812, 363, 982, 974, 563, 966, 665, 279, 955, 494, 243, 675, 151, 994,
          742, 5, 298, 438, 901, 316, 24, 627, 636, 873, 411, 684, 261, 516,
          107, 586, 138, 768, 508, 290, 650, 253, 850, 116, 73, 464, 173, 163,
          129, 94, 428, 346, 842, 609, 888, 306, 619, 181, 922, 44, 555, 931,
          231, 539, 327, 731, 776, 456, 799, 64, 722, 271} *)



          But 7 is fine:



          test = gen2[1000, 100, 7]
          (*
          {556, 966, 917, 863, 425, 155, 414, 504, 43, 82, 395, 196, 765, 701,
          55, 330, 935, 626, 337, 843, 511, 885, 441, 834, 756, 117, 572, 285,
          519, 17, 189, 658, 563, 817, 266, 727, 28, 854, 805, 747, 775, 210,
          997, 546, 138, 303, 608, 295, 900, 145, 718, 355, 176, 666, 130, 946,
          259, 102, 405, 795, 452, 649, 480, 591, 240, 363, 63, 641, 95, 694,
          493, 221, 536, 978, 633, 784, 739, 387, 871, 827, 675, 465, 10, 954,
          580, 599, 686, 878, 36, 1, 926, 373, 320, 529, 348, 248, 708, 893,
          311, 273} *)


          Test the minimum distance between numbers:



          stest = Sort[test];
          Min[Table[stest[[i]] - stest[[i - 1]], {i, 2, Length[test]}]]
          (* 7 *)
          ```






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 6 hours ago









          MelaGoMelaGo

          2,0361 gold badge1 silver badge7 bronze badges




          2,0361 gold badge1 silver badge7 bronze badges

























              2












              $begingroup$


              1. Construct a random sample from Range[m] satisfying the minimum
                distance requirements taking into account the fact that if $x_k$ is
                selected at step $k$, the choices in step $k+1$ are restricted to
                the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
                additional elements in remaining steps satisfying the minimum distance constraint.

              2. Shuffle the list obtained in the first step




              ClearAll[f]
              f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
              FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


              Examples:



              Table[f[10, 3, 2], {5}]



              {{8, 3, 6}, {6, 10, 8}, {8, 5, 10}, {8, 10, 6}, {10, 1, 4}}




              Min[Differences@Sort@#] & /@ %



              {2, 2, 2, 2, 3}




              f[10, 4, 3]



              f[10, 4, 3] (* impossible *)




              f[1000, 100, 8]



              {848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
              936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
              928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
              688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
              624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
              24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
              768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
              360, 257, 440}




              Min @ Differences@ Sort @ %



              8




              res = f[10000000, 10000, 800]; // AbsoluteTiming // First



              0.105936




              Min @ Differences @ Sort @ res



              800




              Update: An alternative implementation using NestList:



              ClearAll[f2]
              f2[m_, n_, d_] /; n d <= m := Module[{k = 1}, RandomSample @ Rest @
              NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





              share|improve this answer











              $endgroup$


















                2












                $begingroup$


                1. Construct a random sample from Range[m] satisfying the minimum
                  distance requirements taking into account the fact that if $x_k$ is
                  selected at step $k$, the choices in step $k+1$ are restricted to
                  the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
                  additional elements in remaining steps satisfying the minimum distance constraint.

                2. Shuffle the list obtained in the first step




                ClearAll[f]
                f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
                FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


                Examples:



                Table[f[10, 3, 2], {5}]



                {{8, 3, 6}, {6, 10, 8}, {8, 5, 10}, {8, 10, 6}, {10, 1, 4}}




                Min[Differences@Sort@#] & /@ %



                {2, 2, 2, 2, 3}




                f[10, 4, 3]



                f[10, 4, 3] (* impossible *)




                f[1000, 100, 8]



                {848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
                936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
                928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
                688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
                624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
                24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
                768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
                360, 257, 440}




                Min @ Differences@ Sort @ %



                8




                res = f[10000000, 10000, 800]; // AbsoluteTiming // First



                0.105936




                Min @ Differences @ Sort @ res



                800




                Update: An alternative implementation using NestList:



                ClearAll[f2]
                f2[m_, n_, d_] /; n d <= m := Module[{k = 1}, RandomSample @ Rest @
                NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





                share|improve this answer











                $endgroup$
















                  2












                  2








                  2





                  $begingroup$


                  1. Construct a random sample from Range[m] satisfying the minimum
                    distance requirements taking into account the fact that if $x_k$ is
                    selected at step $k$, the choices in step $k+1$ are restricted to
                    the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
                    additional elements in remaining steps satisfying the minimum distance constraint.

                  2. Shuffle the list obtained in the first step




                  ClearAll[f]
                  f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
                  FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


                  Examples:



                  Table[f[10, 3, 2], {5}]



                  {{8, 3, 6}, {6, 10, 8}, {8, 5, 10}, {8, 10, 6}, {10, 1, 4}}




                  Min[Differences@Sort@#] & /@ %



                  {2, 2, 2, 2, 3}




                  f[10, 4, 3]



                  f[10, 4, 3] (* impossible *)




                  f[1000, 100, 8]



                  {848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
                  936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
                  928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
                  688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
                  624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
                  24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
                  768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
                  360, 257, 440}




                  Min @ Differences@ Sort @ %



                  8




                  res = f[10000000, 10000, 800]; // AbsoluteTiming // First



                  0.105936




                  Min @ Differences @ Sort @ res



                  800




                  Update: An alternative implementation using NestList:



                  ClearAll[f2]
                  f2[m_, n_, d_] /; n d <= m := Module[{k = 1}, RandomSample @ Rest @
                  NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]





                  share|improve this answer











                  $endgroup$




                  1. Construct a random sample from Range[m] satisfying the minimum
                    distance requirements taking into account the fact that if $x_k$ is
                    selected at step $k$, the choices in step $k+1$ are restricted to
                    the range from $x_k + d$ to $m - (n-k)d$ to be able to get $n-k$
                    additional elements in remaining steps satisfying the minimum distance constraint.

                  2. Shuffle the list obtained in the first step




                  ClearAll[f]
                  f[m_, n_, d_] /; n d <= m := RandomSample @ Rest @
                  FoldList[RandomChoice[Range[# + Boole[#2 > 1] d, m - (n - #2) d]] &, 1, Range[n]]


                  Examples:



                  Table[f[10, 3, 2], {5}]



                  {{8, 3, 6}, {6, 10, 8}, {8, 5, 10}, {8, 10, 6}, {10, 1, 4}}




                  Min[Differences@Sort@#] & /@ %



                  {2, 2, 2, 2, 3}




                  f[10, 4, 3]



                  f[10, 4, 3] (* impossible *)




                  f[1000, 100, 8]



                  {848, 808, 189, 776, 680, 824, 472, 728, 352, 976, 736, 544, 504,
                  936, 904, 408, 720, 400, 816, 448, 856, 560, 279, 336, 312, 512, 888,
                  928, 424, 944, 584, 480, 238, 552, 920, 568, 528, 600, 952, 304, 536,
                  688, 632, 712, 992, 592, 616, 221, 896, 456, 864, 344, 792, 744, 392,
                  624, 320, 984, 576, 206, 648, 960, 368, 840, 872, 376, 328, 752, 832,
                  24, 288, 640, 416, 1000, 760, 696, 520, 488, 672, 464, 249, 800, 968,
                  768, 664, 432, 384, 784, 271, 912, 296, 656, 704, 496, 608, 230, 880,
                  360, 257, 440}




                  Min @ Differences@ Sort @ %



                  8




                  res = f[10000000, 10000, 800]; // AbsoluteTiming // First



                  0.105936




                  Min @ Differences @ Sort @ res



                  800




                  Update: An alternative implementation using NestList:



                  ClearAll[f2]
                  f2[m_, n_, d_] /; n d <= m := Module[{k = 1}, RandomSample @ Rest @
                  NestList[RandomChoice[Range[# + Boole[k++ > 1] d, m - (n - k) d]] &, 1, n]]






                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited 2 hours ago

























                  answered 6 hours ago









                  kglrkglr

                  204k10 gold badges233 silver badges463 bronze badges




                  204k10 gold badges233 silver badges463 bronze badges






















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