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multiplying two array in python3.7
Tensorflow neural network TypeError: Fetch argument has invalid typeAppending to numpy array for creating datasetCustom conditional Keras metricTypeError: '<' not supported between instances of 'int' and 'str'The truth value of an array with more than one element is ambiguousHow feed a numpy array in batches in KerasPython: multiplication of sparse matrices slower in csr_matrix than numpy
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$begingroup$
I am trying to multiply two array in python 3.7 using numpy by using the following syntax:
array1 = np.array([{1,2,3,4},{5,6,7,8}])
print (array1)
array2=array1*array1
print(array2)
but this error arises
TypeError: unsupported operand type(s) for *: 'set' and 'set'
python numpy
New contributor
Charvi Yadav is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
I am trying to multiply two array in python 3.7 using numpy by using the following syntax:
array1 = np.array([{1,2,3,4},{5,6,7,8}])
print (array1)
array2=array1*array1
print(array2)
but this error arises
TypeError: unsupported operand type(s) for *: 'set' and 'set'
python numpy
New contributor
Charvi Yadav is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I am trying to multiply two array in python 3.7 using numpy by using the following syntax:
array1 = np.array([{1,2,3,4},{5,6,7,8}])
print (array1)
array2=array1*array1
print(array2)
but this error arises
TypeError: unsupported operand type(s) for *: 'set' and 'set'
python numpy
New contributor
Charvi Yadav is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I am trying to multiply two array in python 3.7 using numpy by using the following syntax:
array1 = np.array([{1,2,3,4},{5,6,7,8}])
print (array1)
array2=array1*array1
print(array2)
but this error arises
TypeError: unsupported operand type(s) for *: 'set' and 'set'
python numpy
python numpy
New contributor
Charvi Yadav is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Charvi Yadav is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 10 hours ago
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
Peter
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asked 11 hours ago
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
Charvi YadavCharvi Yadav
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add a comment |
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1 Answer
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$begingroup$
You are simply defining your array so that it is made of python set
s. That is a different data structure which is not able to be multiplied, unlike an array.
Just change your code to this:
array1 = np.array([[1,2,3,4],[5,6,7,8]])
The only difference is using square brackets instead of curly ones. These are python list
objects (or standard arrays).
array2=array1*array1
print(array2)
[[ 1 4 9 16]
[25 36 49 64]]
$endgroup$
add a comment |
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1 Answer
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1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You are simply defining your array so that it is made of python set
s. That is a different data structure which is not able to be multiplied, unlike an array.
Just change your code to this:
array1 = np.array([[1,2,3,4],[5,6,7,8]])
The only difference is using square brackets instead of curly ones. These are python list
objects (or standard arrays).
array2=array1*array1
print(array2)
[[ 1 4 9 16]
[25 36 49 64]]
$endgroup$
add a comment |
$begingroup$
You are simply defining your array so that it is made of python set
s. That is a different data structure which is not able to be multiplied, unlike an array.
Just change your code to this:
array1 = np.array([[1,2,3,4],[5,6,7,8]])
The only difference is using square brackets instead of curly ones. These are python list
objects (or standard arrays).
array2=array1*array1
print(array2)
[[ 1 4 9 16]
[25 36 49 64]]
$endgroup$
add a comment |
$begingroup$
You are simply defining your array so that it is made of python set
s. That is a different data structure which is not able to be multiplied, unlike an array.
Just change your code to this:
array1 = np.array([[1,2,3,4],[5,6,7,8]])
The only difference is using square brackets instead of curly ones. These are python list
objects (or standard arrays).
array2=array1*array1
print(array2)
[[ 1 4 9 16]
[25 36 49 64]]
$endgroup$
You are simply defining your array so that it is made of python set
s. That is a different data structure which is not able to be multiplied, unlike an array.
Just change your code to this:
array1 = np.array([[1,2,3,4],[5,6,7,8]])
The only difference is using square brackets instead of curly ones. These are python list
objects (or standard arrays).
array2=array1*array1
print(array2)
[[ 1 4 9 16]
[25 36 49 64]]
answered 8 hours ago

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n1k31t4n1k31t4
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