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Dynamic variable with dynamic results in bash

Processing bash variable with sedbash: dynamic environment controlI cannot understand bash script resultsDynamic Variable in KornShell Scriptbash dynamic (variable) variable namescompare variable with string bashReading dynamic variable from envPortable way to run command without PATH from bash scriptproblem with dynamic variable on a bash script

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{
margin-bottom:0;
}

0

dubdub_count=3

for (( i=1; i<=${dubdub_count}; i++ )); do

  my_apps --ammount=${dubdub_count}

done

The program will return the IP Address
Example results

app1=10.10.10.1

app2=10.10.10.2

app3=10.10.10.3

Theses ip addresses will be used in other service. I want to run that IP Addrs like this bellow

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3 --master

If i change dubdub_count=3 to be dubdub_count=4
My script must be able to be run like this

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3,http://10.10.10.4 --master

I have read dynamic var in bash as keyword in stackoverflow, still i can't find out the best solution for that.
Should i suggest the my_apps developer to change the results method ?

bash shell-script

share

edited 2 mins ago

Nicky Puff

asked 7 mins ago

Nicky PuffNicky Puff

1844 bronze badges

add a comment
 | 

0

dubdub_count=3

for (( i=1; i<=${dubdub_count}; i++ )); do

  my_apps --ammount=${dubdub_count}

done

The program will return the IP Address
Example results

app1=10.10.10.1

app2=10.10.10.2

app3=10.10.10.3

Theses ip addresses will be used in other service. I want to run that IP Addrs like this bellow

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3 --master

If i change dubdub_count=3 to be dubdub_count=4
My script must be able to be run like this

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3,http://10.10.10.4 --master

I have read dynamic var in bash as keyword in stackoverflow, still i can't find out the best solution for that.
Should i suggest the my_apps developer to change the results method ?

bash shell-script

share

edited 2 mins ago

Nicky Puff

asked 7 mins ago

Nicky PuffNicky Puff

1844 bronze badges

add a comment
 | 

dubdub_count=3

for (( i=1; i<=${dubdub_count}; i++ )); do

  my_apps --ammount=${dubdub_count}

done

The program will return the IP Address
Example results

app1=10.10.10.1

app2=10.10.10.2

app3=10.10.10.3

Theses ip addresses will be used in other service. I want to run that IP Addrs like this bellow

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3 --master

If i change dubdub_count=3 to be dubdub_count=4
My script must be able to be run like this

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3,http://10.10.10.4 --master

I have read dynamic var in bash as keyword in stackoverflow, still i can't find out the best solution for that.
Should i suggest the my_apps developer to change the results method ?

bash shell-script

share

edited 2 mins ago

Nicky Puff

asked 7 mins ago

Nicky PuffNicky Puff

1844 bronze badges

for (( i=1; i<=${dubdub_count}; i++ )); do

  my_apps --ammount=${dubdub_count}

done

app1=10.10.10.1

app2=10.10.10.2

app3=10.10.10.3

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3 --master

/usr/local/bin/apiserver --dubdub=http://10.10.10.1:8080,http://10.10.10.2:8080,http://10.10.10.3,http://10.10.10.4 --master

share

edited 2 mins ago

Nicky Puff

asked 7 mins ago

Nicky PuffNicky Puff

1844 bronze badges

share

edited 2 mins ago

Nicky Puff

asked 7 mins ago

Nicky PuffNicky Puff

1844 bronze badges

asked 7 mins ago

Nicky PuffNicky Puff

1844 bronze badges

asked 7 mins ago

Nicky PuffNicky Puff

1844 bronze badges