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Why don't the currents clash in a 3 phase delta connection?
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Consider 3 windings, a, b and c. L1 is connected to A, L2 to B and L3 to C. The 3 windings are then connected in delta.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, what will the current direction through the windings look like? Particularly through the bridge which connects a1 to b2...
Will we at any point have the current from 2 different phases going towards each other?
three-phase winding delta star
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
$endgroup$
add a comment |
$begingroup$
Consider 3 windings, a, b and c. L1 is connected to A, L2 to B and L3 to C. The 3 windings are then connected in delta.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, what will the current direction through the windings look like? Particularly through the bridge which connects a1 to b2...
Will we at any point have the current from 2 different phases going towards each other?
three-phase winding delta star
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
$endgroup$
$begingroup$
As far as I remember, the current in any one phase is the sum of the currents in the other two, make sure of the signs...
$endgroup$
– Solar Mike
8 hours ago
add a comment |
$begingroup$
Consider 3 windings, a, b and c. L1 is connected to A, L2 to B and L3 to C. The 3 windings are then connected in delta.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, what will the current direction through the windings look like? Particularly through the bridge which connects a1 to b2...
Will we at any point have the current from 2 different phases going towards each other?
three-phase winding delta star
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
$endgroup$
Consider 3 windings, a, b and c. L1 is connected to A, L2 to B and L3 to C. The 3 windings are then connected in delta.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, what will the current direction through the windings look like? Particularly through the bridge which connects a1 to b2...
Will we at any point have the current from 2 different phases going towards each other?
three-phase winding delta star
three-phase winding delta star
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
asked 8 hours ago
Ph3ngPh3ng
1215 bronze badges
1215 bronze badges
$begingroup$
As far as I remember, the current in any one phase is the sum of the currents in the other two, make sure of the signs...
$endgroup$
– Solar Mike
8 hours ago
add a comment |
$begingroup$
As far as I remember, the current in any one phase is the sum of the currents in the other two, make sure of the signs...
$endgroup$
– Solar Mike
8 hours ago
$begingroup$
As far as I remember, the current in any one phase is the sum of the currents in the other two, make sure of the signs...
$endgroup$
– Solar Mike
8 hours ago
$begingroup$
As far as I remember, the current in any one phase is the sum of the currents in the other two, make sure of the signs...
$endgroup$
– Solar Mike
8 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
Figure 1. Three-phase currents in a balanced system at various points in time. They always sum to zero.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, ...
That never happens. Have a look at Figure 1 points (1) and (2) and you will see that only one phase can be maximum at any time and at that time the other two are at half-maximum and in the opposite direction.
... what will the current direction through the windings look like?
They will look the same but with the minor complexity that the currents are out of phase with the phase-neutral voltages.
Will we at any point have the current from 2 different phases going towards each other?
Yes. At Figure 1 (2), 90°, the current in on the black phase is split in two leaving on the red and blue phases at half the input current. 60° earlier (1) blue and black are at 0.5 positive with red at peak negative.
The currents always sum to zero, even if the load is unbalanced. If you run the three wires through a clamp-on meter it will read zero.
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
$endgroup$
$begingroup$
Just a clarification, For star connections, an imbalance in currents will be consumed by the neutral connection, if there is no neutral it will instead shift the center points voltage towards, which allows the currents to sum to 0.
$endgroup$
– Reroute
3 hours ago
add a comment |
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1 Answer
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1 Answer
1
active
oldest
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active
oldest
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$begingroup$
Figure 1. Three-phase currents in a balanced system at various points in time. They always sum to zero.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, ...
That never happens. Have a look at Figure 1 points (1) and (2) and you will see that only one phase can be maximum at any time and at that time the other two are at half-maximum and in the opposite direction.
... what will the current direction through the windings look like?
They will look the same but with the minor complexity that the currents are out of phase with the phase-neutral voltages.
Will we at any point have the current from 2 different phases going towards each other?
Yes. At Figure 1 (2), 90°, the current in on the black phase is split in two leaving on the red and blue phases at half the input current. 60° earlier (1) blue and black are at 0.5 positive with red at peak negative.
The currents always sum to zero, even if the load is unbalanced. If you run the three wires through a clamp-on meter it will read zero.
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
$endgroup$
$begingroup$
Just a clarification, For star connections, an imbalance in currents will be consumed by the neutral connection, if there is no neutral it will instead shift the center points voltage towards, which allows the currents to sum to 0.
$endgroup$
– Reroute
3 hours ago
add a comment |
$begingroup$
Figure 1. Three-phase currents in a balanced system at various points in time. They always sum to zero.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, ...
That never happens. Have a look at Figure 1 points (1) and (2) and you will see that only one phase can be maximum at any time and at that time the other two are at half-maximum and in the opposite direction.
... what will the current direction through the windings look like?
They will look the same but with the minor complexity that the currents are out of phase with the phase-neutral voltages.
Will we at any point have the current from 2 different phases going towards each other?
Yes. At Figure 1 (2), 90°, the current in on the black phase is split in two leaving on the red and blue phases at half the input current. 60° earlier (1) blue and black are at 0.5 positive with red at peak negative.
The currents always sum to zero, even if the load is unbalanced. If you run the three wires through a clamp-on meter it will read zero.
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
$endgroup$
$begingroup$
Just a clarification, For star connections, an imbalance in currents will be consumed by the neutral connection, if there is no neutral it will instead shift the center points voltage towards, which allows the currents to sum to 0.
$endgroup$
– Reroute
3 hours ago
add a comment |
$begingroup$
Figure 1. Three-phase currents in a balanced system at various points in time. They always sum to zero.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, ...
That never happens. Have a look at Figure 1 points (1) and (2) and you will see that only one phase can be maximum at any time and at that time the other two are at half-maximum and in the opposite direction.
... what will the current direction through the windings look like?
They will look the same but with the minor complexity that the currents are out of phase with the phase-neutral voltages.
Will we at any point have the current from 2 different phases going towards each other?
Yes. At Figure 1 (2), 90°, the current in on the black phase is split in two leaving on the red and blue phases at half the input current. 60° earlier (1) blue and black are at 0.5 positive with red at peak negative.
The currents always sum to zero, even if the load is unbalanced. If you run the three wires through a clamp-on meter it will read zero.
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
$endgroup$
Figure 1. Three-phase currents in a balanced system at various points in time. They always sum to zero.
If we could freeze frame the voltage waveform where L1 and L2 are positive maximum and L3 is negative, ...
That never happens. Have a look at Figure 1 points (1) and (2) and you will see that only one phase can be maximum at any time and at that time the other two are at half-maximum and in the opposite direction.
... what will the current direction through the windings look like?
They will look the same but with the minor complexity that the currents are out of phase with the phase-neutral voltages.
Will we at any point have the current from 2 different phases going towards each other?
Yes. At Figure 1 (2), 90°, the current in on the black phase is split in two leaving on the red and blue phases at half the input current. 60° earlier (1) blue and black are at 0.5 positive with red at peak negative.
The currents always sum to zero, even if the load is unbalanced. If you run the three wires through a clamp-on meter it will read zero.
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
edited 3 hours ago
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
answered 7 hours ago
TransistorTransistor
99.9k8 gold badges101 silver badges220 bronze badges
99.9k8 gold badges101 silver badges220 bronze badges
$begingroup$
Just a clarification, For star connections, an imbalance in currents will be consumed by the neutral connection, if there is no neutral it will instead shift the center points voltage towards, which allows the currents to sum to 0.
$endgroup$
– Reroute
3 hours ago
add a comment |
$begingroup$
Just a clarification, For star connections, an imbalance in currents will be consumed by the neutral connection, if there is no neutral it will instead shift the center points voltage towards, which allows the currents to sum to 0.
$endgroup$
– Reroute
3 hours ago
$begingroup$
Just a clarification, For star connections, an imbalance in currents will be consumed by the neutral connection, if there is no neutral it will instead shift the center points voltage towards, which allows the currents to sum to 0.
$endgroup$
– Reroute
3 hours ago
$begingroup$
Just a clarification, For star connections, an imbalance in currents will be consumed by the neutral connection, if there is no neutral it will instead shift the center points voltage towards, which allows the currents to sum to 0.
$endgroup$
– Reroute
3 hours ago
add a comment |
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$begingroup$
As far as I remember, the current in any one phase is the sum of the currents in the other two, make sure of the signs...
$endgroup$
– Solar Mike
8 hours ago