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How to get the available space of $HOME as a variable in shell scripting?


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2















I am writing a bash script to install a program for different users.



For that I want to make sure that each user has at least 500Mb available in their $HOME. My $HOME directory looks as follows



jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142


My idea is to use df -h /path/to/home | awk but I am not sure how I can get the actual available space from df -h. Any help please? Thanks, Jen.



jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home









share|improve this question




















  • 1





    @EODCraft Staff : Nop! :)

    – Jenny
    yesterday






  • 1





    df -P /path/to/home | awk 'NR>1 {print $4}'?

    – Cyrus
    yesterday








  • 1





    There's no 1,7G. There's at the moment 4216832.

    – Cyrus
    yesterday








  • 1





    Ah! I thought I should actually get the space in the partition /dev/sda1 2,9G 1,1G 1,7G 40% /

    – Jenny
    yesterday






  • 1





    If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the diskquota command to check the available space. You may want to check if an equivalent system exists at your institution.

    – nneonneo
    yesterday


















2















I am writing a bash script to install a program for different users.



For that I want to make sure that each user has at least 500Mb available in their $HOME. My $HOME directory looks as follows



jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142


My idea is to use df -h /path/to/home | awk but I am not sure how I can get the actual available space from df -h. Any help please? Thanks, Jen.



jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home









share|improve this question




















  • 1





    @EODCraft Staff : Nop! :)

    – Jenny
    yesterday






  • 1





    df -P /path/to/home | awk 'NR>1 {print $4}'?

    – Cyrus
    yesterday








  • 1





    There's no 1,7G. There's at the moment 4216832.

    – Cyrus
    yesterday








  • 1





    Ah! I thought I should actually get the space in the partition /dev/sda1 2,9G 1,1G 1,7G 40% /

    – Jenny
    yesterday






  • 1





    If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the diskquota command to check the available space. You may want to check if an equivalent system exists at your institution.

    – nneonneo
    yesterday














2












2








2








I am writing a bash script to install a program for different users.



For that I want to make sure that each user has at least 500Mb available in their $HOME. My $HOME directory looks as follows



jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142


My idea is to use df -h /path/to/home | awk but I am not sure how I can get the actual available space from df -h. Any help please? Thanks, Jen.



jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home









share|improve this question
















I am writing a bash script to install a program for different users.



For that I want to make sure that each user has at least 500Mb available in their $HOME. My $HOME directory looks as follows



jen@ser23:~$ df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda1 2,9G 1,1G 1,7G 40% /
udev 10M 0 10M 0% /dev
tmpfs 13G 826M 12G 7% /run
/dev/sda3 15G 9,8G 4,1G 71% /usr
tmpfs 32G 0 32G 0% /dev/shm
tmpfs 5,0M 0 5,0M 0% /run/lock
tmpfs 32G 0 32G 0% /sys/fs/cgroup
/dev/mapper/local_disk_1-tmp 3,7G 21M 3,7G 1% /tmp
/dev/mapper/local_disk_1-opt 20G 2,0G 18G 10% /opt
/dev/mapper/local_disk_1-project1 401G 287G 114G 72% /project1
/dev/mapper/local_disk_1-var 3,8G 1,7G 1,7G 50% /var
/dev/mapper/local_disk_1-project2 99G 70G 29G 71% /project2
/dev/mapper/local_disk_1-usr_local 2,0G 3,4M 1,9G 1% /usr/local
nfs4.sf0.ise.fhg.de:/g/6/TSB/Archiv 632T 349T 276T 56% /net/p/600/groupdrives/TSB/Archiv
nfs4.sf0.ise.fhg.de:/home 632T 349T 276T 56% /net/home
tmpfs 6,4G 0 6,4G 0% /run/user/12419
tmpfs 6,4G 4,0K 6,4G 1% /run/user/13471
tmpfs 6,4G 4,0K 6,4G 1% /run/user/9351
tmpfs 6,4G 0 6,4G 0% /run/user/13142


My idea is to use df -h /path/to/home | awk but I am not sure how I can get the actual available space from df -h. Any help please? Thanks, Jen.



jen@ser23:~$ df -P /net/home/j/jen
Filesystem 1024-blocks Used Available Capacity Mounted on
nfs4.sf0.dfd.fhg.de:/home 5242880 1026048 4216832 20% /net/home






command-line bash scripts






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited yesterday







Jenny

















asked yesterday









JennyJenny

1018




1018








  • 1





    @EODCraft Staff : Nop! :)

    – Jenny
    yesterday






  • 1





    df -P /path/to/home | awk 'NR>1 {print $4}'?

    – Cyrus
    yesterday








  • 1





    There's no 1,7G. There's at the moment 4216832.

    – Cyrus
    yesterday








  • 1





    Ah! I thought I should actually get the space in the partition /dev/sda1 2,9G 1,1G 1,7G 40% /

    – Jenny
    yesterday






  • 1





    If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the diskquota command to check the available space. You may want to check if an equivalent system exists at your institution.

    – nneonneo
    yesterday














  • 1





    @EODCraft Staff : Nop! :)

    – Jenny
    yesterday






  • 1





    df -P /path/to/home | awk 'NR>1 {print $4}'?

    – Cyrus
    yesterday








  • 1





    There's no 1,7G. There's at the moment 4216832.

    – Cyrus
    yesterday








  • 1





    Ah! I thought I should actually get the space in the partition /dev/sda1 2,9G 1,1G 1,7G 40% /

    – Jenny
    yesterday






  • 1





    If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the diskquota command to check the available space. You may want to check if an equivalent system exists at your institution.

    – nneonneo
    yesterday








1




1





@EODCraft Staff : Nop! :)

– Jenny
yesterday





@EODCraft Staff : Nop! :)

– Jenny
yesterday




1




1





df -P /path/to/home | awk 'NR>1 {print $4}'?

– Cyrus
yesterday







df -P /path/to/home | awk 'NR>1 {print $4}'?

– Cyrus
yesterday






1




1





There's no 1,7G. There's at the moment 4216832.

– Cyrus
yesterday







There's no 1,7G. There's at the moment 4216832.

– Cyrus
yesterday






1




1





Ah! I thought I should actually get the space in the partition /dev/sda1 2,9G 1,1G 1,7G 40% /

– Jenny
yesterday





Ah! I thought I should actually get the space in the partition /dev/sda1 2,9G 1,1G 1,7G 40% /

– Jenny
yesterday




1




1





If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the diskquota command to check the available space. You may want to check if an equivalent system exists at your institution.

– nneonneo
yesterday





If you’re on a big shared system, it’s quite possible that individual accounts have quotas, separate from the available mounted storage. For example, at my old institution, you used the diskquota command to check the available space. You may want to check if an equivalent system exists at your institution.

– nneonneo
yesterday










3 Answers
3






active

oldest

votes


















4














The important point to remember is that df operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen operates on the filesystem mounted at /net/home, which is nfs4.sf0.ise.fhg.de network attached storage apparently.



The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du and in particular du -shx /net/home/user.



Keypoints (for more read man du):





  • du is recursive by default


  • -s provides summary instead of listing filesizes individually


  • -h provides human readable output. If you require further processing on data, -b might be more preferable.


  • -x is to keep du descending into another. For instance, you could have another network server attached to /net/home/user/anotherplace, so processing that directory is undesirable as it will give incorrect filesystem usage results.


Considering that this is an assignment, further processing and manipulations on output of du are left to the reader to implement






share|improve this answer

































    1














    It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:



    DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
    if [ $DFHOME -lt 500000 ]; then
    echo "You don't got enough space!";
    fi


    I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.






    share|improve this answer

































      1














      No need to parse df output with awk, you can use --output switch:



      df --output=avail "$HOME" | tail -n1





      --output[=FIELD_LIST]

      use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.



      FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
      get'







      share|improve this answer
























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        3 Answers
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        3 Answers
        3






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        active

        oldest

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        4














        The important point to remember is that df operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen operates on the filesystem mounted at /net/home, which is nfs4.sf0.ise.fhg.de network attached storage apparently.



        The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du and in particular du -shx /net/home/user.



        Keypoints (for more read man du):





        • du is recursive by default


        • -s provides summary instead of listing filesizes individually


        • -h provides human readable output. If you require further processing on data, -b might be more preferable.


        • -x is to keep du descending into another. For instance, you could have another network server attached to /net/home/user/anotherplace, so processing that directory is undesirable as it will give incorrect filesystem usage results.


        Considering that this is an assignment, further processing and manipulations on output of du are left to the reader to implement






        share|improve this answer






























          4














          The important point to remember is that df operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen operates on the filesystem mounted at /net/home, which is nfs4.sf0.ise.fhg.de network attached storage apparently.



          The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du and in particular du -shx /net/home/user.



          Keypoints (for more read man du):





          • du is recursive by default


          • -s provides summary instead of listing filesizes individually


          • -h provides human readable output. If you require further processing on data, -b might be more preferable.


          • -x is to keep du descending into another. For instance, you could have another network server attached to /net/home/user/anotherplace, so processing that directory is undesirable as it will give incorrect filesystem usage results.


          Considering that this is an assignment, further processing and manipulations on output of du are left to the reader to implement






          share|improve this answer




























            4












            4








            4







            The important point to remember is that df operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen operates on the filesystem mounted at /net/home, which is nfs4.sf0.ise.fhg.de network attached storage apparently.



            The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du and in particular du -shx /net/home/user.



            Keypoints (for more read man du):





            • du is recursive by default


            • -s provides summary instead of listing filesizes individually


            • -h provides human readable output. If you require further processing on data, -b might be more preferable.


            • -x is to keep du descending into another. For instance, you could have another network server attached to /net/home/user/anotherplace, so processing that directory is undesirable as it will give incorrect filesystem usage results.


            Considering that this is an assignment, further processing and manipulations on output of du are left to the reader to implement






            share|improve this answer















            The important point to remember is that df operates on filesystems, which may be attached to particular folders, and if you specify a path or file, it will resolve to usage of the filesystem on which file/folder resides. So df -P /net/home/j/jen operates on the filesystem mounted at /net/home, which is nfs4.sf0.ise.fhg.de network attached storage apparently.



            The usage of a directory and all the files requires a recursive solution that will traverse files and directories within particular directory. The tool that you seek then, is du and in particular du -shx /net/home/user.



            Keypoints (for more read man du):





            • du is recursive by default


            • -s provides summary instead of listing filesizes individually


            • -h provides human readable output. If you require further processing on data, -b might be more preferable.


            • -x is to keep du descending into another. For instance, you could have another network server attached to /net/home/user/anotherplace, so processing that directory is undesirable as it will give incorrect filesystem usage results.


            Considering that this is an assignment, further processing and manipulations on output of du are left to the reader to implement







            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 20 hours ago

























            answered yesterday









            Sergiy KolodyazhnyySergiy Kolodyazhnyy

            75k9155327




            75k9155327

























                1














                It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:



                DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
                if [ $DFHOME -lt 500000 ]; then
                echo "You don't got enough space!";
                fi


                I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.






                share|improve this answer






























                  1














                  It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:



                  DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
                  if [ $DFHOME -lt 500000 ]; then
                  echo "You don't got enough space!";
                  fi


                  I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.






                  share|improve this answer




























                    1












                    1








                    1







                    It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:



                    DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
                    if [ $DFHOME -lt 500000 ]; then
                    echo "You don't got enough space!";
                    fi


                    I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.






                    share|improve this answer















                    It looks like you're heading towards a workable solution already in the comments, but I'm going to throw this in:



                    DFHOME=$( df $HOME | awk {'print $4;'} | tail -n 1 )
                    if [ $DFHOME -lt 500000 ]; then
                    echo "You don't got enough space!";
                    fi


                    I'd recommend not using -h because if the size is small enough, the G will turn to an M and your solution might break.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited yesterday

























                    answered yesterday









                    KarlKarl

                    215




                    215























                        1














                        No need to parse df output with awk, you can use --output switch:



                        df --output=avail "$HOME" | tail -n1





                        --output[=FIELD_LIST]

                        use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.



                        FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
                        get'







                        share|improve this answer




























                          1














                          No need to parse df output with awk, you can use --output switch:



                          df --output=avail "$HOME" | tail -n1





                          --output[=FIELD_LIST]

                          use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.



                          FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
                          get'







                          share|improve this answer


























                            1












                            1








                            1







                            No need to parse df output with awk, you can use --output switch:



                            df --output=avail "$HOME" | tail -n1





                            --output[=FIELD_LIST]

                            use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.



                            FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
                            get'







                            share|improve this answer













                            No need to parse df output with awk, you can use --output switch:



                            df --output=avail "$HOME" | tail -n1





                            --output[=FIELD_LIST]

                            use the output format defined by FIELD_LIST, or print all fields if FIELD_LIST is omitted.



                            FIELD_LIST is a comma-separated list of columns to be included. Valid field names are: 'source', 'fstype', 'itotal', 'iused', 'iavail', 'ipcent', 'size', 'used', 'avail', 'pcent', 'file' and 'tar‐
                            get'








                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 18 hours ago









                            RoVoRoVo

                            8,1701943




                            8,1701943






























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