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How to use password retrieved from `pass` in a shell script
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I stored a password in using the pass and based I am trying to automate a VPN Connection process using Cisco Anyconnect. The VPN works, I confirmed that. The script I am trying to use is:
pass=$(pass branch/key)
vpn -s connect vpn.server.host << "EOF"
0
username
"$pass"
y
exit
EOF
Suppose I save that as .connectvpn and say source .connectvpn then it should start a VPN tunnel and get a connection going.
If in the file I get rid of the variable I am trying to use (pass), and put the actual password on the fifth line I know it works. The trouble I am having is with the bash variable approach.
bash terminal
asked yesterday
ITAITA
1032
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I stored a password in using the pass and based I am trying to automate a VPN Connection process using Cisco Anyconnect. The VPN works, I confirmed that. The script I am trying to use is:
pass=$(pass branch/key)
vpn -s connect vpn.server.host << "EOF"
0
username
"$pass"
y
exit
EOF
Suppose I save that as .connectvpn and say source .connectvpn then it should start a VPN tunnel and get a connection going.
If in the file I get rid of the variable I am trying to use (pass), and put the actual password on the fifth line I know it works. The trouble I am having is with the bash variable approach.
bash terminal
asked yesterday
ITAITA
1032
New contributor
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I stored a password in using the pass and based I am trying to automate a VPN Connection process using Cisco Anyconnect. The VPN works, I confirmed that. The script I am trying to use is:
pass=$(pass branch/key)
vpn -s connect vpn.server.host << "EOF"
0
username
"$pass"
y
exit
EOF
Suppose I save that as .connectvpn and say source .connectvpn then it should start a VPN tunnel and get a connection going.
If in the file I get rid of the variable I am trying to use (pass), and put the actual password on the fifth line I know it works. The trouble I am having is with the bash variable approach.
bash terminal
asked yesterday
ITAITA
1032
New contributor
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I stored a password in using the pass and based I am trying to automate a VPN Connection process using Cisco Anyconnect. The VPN works, I confirmed that. The script I am trying to use is:
pass=$(pass branch/key)
vpn -s connect vpn.server.host << "EOF"
0
username
"$pass"
y
exit
EOF
Suppose I save that as .connectvpn and say source .connectvpn then it should start a VPN tunnel and get a connection going.
If in the file I get rid of the variable I am trying to use (pass), and put the actual password on the fifth line I know it works. The trouble I am having is with the bash variable approach.
bash terminal
bash terminal
asked yesterday
ITAITA
1032
New contributor
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
ITAITA
1032
New contributor
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
ITAITA
1032
New contributor
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked yesterday
ITAITA
1032
asked yesterday
ITAITA
1032
1032
New contributor
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
ITA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
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add a comment |
1 Answer
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votes
Your problem is that you have quoted the delimiter, "EOF". When the delimiter of a here-document is quoted, no parameter expansion is performed on the body, so your password gets its literal value, "$pass". Try using EOF without quotes as a delimiter.
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
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1 Answer
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active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Your problem is that you have quoted the delimiter, "EOF". When the delimiter of a here-document is quoted, no parameter expansion is performed on the body, so your password gets its literal value, "$pass". Try using EOF without quotes as a delimiter.
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
add a comment |
Your problem is that you have quoted the delimiter, "EOF". When the delimiter of a here-document is quoted, no parameter expansion is performed on the body, so your password gets its literal value, "$pass". Try using EOF without quotes as a delimiter.
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
add a comment |
Your problem is that you have quoted the delimiter, "EOF". When the delimiter of a here-document is quoted, no parameter expansion is performed on the body, so your password gets its literal value, "$pass". Try using EOF without quotes as a delimiter.
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
Your problem is that you have quoted the delimiter, "EOF". When the delimiter of a here-document is quoted, no parameter expansion is performed on the body, so your password gets its literal value, "$pass". Try using EOF without quotes as a delimiter.
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
answered yesterday
Dmitry GrigoryevDmitry Grigoryev
5,1241045
5,1241045
add a comment |
add a comment |
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