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I need to check a list of directories if it contains a directory newer than 1 month before now

list all files newer than given timestamp and sort themExpression error in bash scriptcannot move Directory not emptyPreform operation in bash only if a variable is less than a second variablemysql backup and rsync script problemcleaning output of a script so it's descending, gives package names and cleanly existsFind list of directories one level deep from matching directoryList directory hierarchy with files before subdirectoriesHouskeep old files and dirsEqually divide contents of a directory between disks - rounded up to the nearest top level directory

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

I'll try to explain what i have done until now.

First of all i have build the list of directories i want to investigate with the code below:

$MDIR="/home/user/scripts/fcron"

DIRS=`ls -l $MDIR | egrep '^d' | awk '{print $9}' | grep ^$ts-`

The DIRS list now contain directory names of the form :

NETGEAR-2013-06-30

NETGEAR-2013-07-01

........

NETGEAR-2013-05-05

Now i need to check all those directories (contained in list DIRS) and i need to find one that is newer than 1 month before now (e.g 27 or 29 days). In case i find one match i need to exit the script.

In 'pseudocode' i would write:

for dir is DIRS:

    if dir is newer than 30 days old:

       exit the script

    else:

       continue

My difficulty is in translating just the above 'pseudocode' in a bash script.

/////Latest Update/////

OK i have updated the part with the pseudocode with this:

    for DIR is $DIRS;

    do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

        echo "exiting!!"       

    exit

    else

        continue

    fi

    done

But now i am getting this :

 line 40: syntax error: unexpected word (expecting "do")

bash shell-script

share|improve this question

edited 56 mins ago

Rui F Ribeiro

42.5k1485146

asked Jun 30 '13 at 22:46

Vaios ArgiropoulosVaios Argiropoulos

63211

add a comment | 

0

I'll try to explain what i have done until now.

First of all i have build the list of directories i want to investigate with the code below:

$MDIR="/home/user/scripts/fcron"

DIRS=`ls -l $MDIR | egrep '^d' | awk '{print $9}' | grep ^$ts-`

The DIRS list now contain directory names of the form :

NETGEAR-2013-06-30

NETGEAR-2013-07-01

........

NETGEAR-2013-05-05

Now i need to check all those directories (contained in list DIRS) and i need to find one that is newer than 1 month before now (e.g 27 or 29 days). In case i find one match i need to exit the script.

In 'pseudocode' i would write:

for dir is DIRS:

    if dir is newer than 30 days old:

       exit the script

    else:

       continue

My difficulty is in translating just the above 'pseudocode' in a bash script.

/////Latest Update/////

OK i have updated the part with the pseudocode with this:

    for DIR is $DIRS;

    do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

        echo "exiting!!"       

    exit

    else

        continue

    fi

    done

But now i am getting this :

 line 40: syntax error: unexpected word (expecting "do")

bash shell-script

share|improve this question

edited 56 mins ago

Rui F Ribeiro

42.5k1485146

asked Jun 30 '13 at 22:46

Vaios ArgiropoulosVaios Argiropoulos

63211

add a comment | 

I'll try to explain what i have done until now.

First of all i have build the list of directories i want to investigate with the code below:

$MDIR="/home/user/scripts/fcron"

DIRS=`ls -l $MDIR | egrep '^d' | awk '{print $9}' | grep ^$ts-`

The DIRS list now contain directory names of the form :

NETGEAR-2013-06-30

NETGEAR-2013-07-01

........

NETGEAR-2013-05-05

Now i need to check all those directories (contained in list DIRS) and i need to find one that is newer than 1 month before now (e.g 27 or 29 days). In case i find one match i need to exit the script.

In 'pseudocode' i would write:

for dir is DIRS:

    if dir is newer than 30 days old:

       exit the script

    else:

       continue

My difficulty is in translating just the above 'pseudocode' in a bash script.

/////Latest Update/////

OK i have updated the part with the pseudocode with this:

    for DIR is $DIRS;

    do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

        echo "exiting!!"       

    exit

    else

        continue

    fi

    done

But now i am getting this :

 line 40: syntax error: unexpected word (expecting "do")

bash shell-script

share|improve this question

edited 56 mins ago

Rui F Ribeiro

42.5k1485146

asked Jun 30 '13 at 22:46

Vaios ArgiropoulosVaios Argiropoulos

63211

$MDIR="/home/user/scripts/fcron"

DIRS=`ls -l $MDIR | egrep '^d' | awk '{print $9}' | grep ^$ts-`

NETGEAR-2013-06-30

NETGEAR-2013-07-01

........

NETGEAR-2013-05-05

for dir is DIRS:

    if dir is newer than 30 days old:

       exit the script

    else:

       continue

    for DIR is $DIRS;

    do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

        echo "exiting!!"       

    exit

    else

        continue

    fi

    done

 line 40: syntax error: unexpected word (expecting "do")

share|improve this question

edited 56 mins ago

Rui F Ribeiro

42.5k1485146

asked Jun 30 '13 at 22:46

Vaios ArgiropoulosVaios Argiropoulos

63211

share|improve this question

edited 56 mins ago

Rui F Ribeiro

42.5k1485146

asked Jun 30 '13 at 22:46

Vaios ArgiropoulosVaios Argiropoulos

63211

edited 56 mins ago

Rui F Ribeiro

42.5k1485146

edited 56 mins ago

Rui F Ribeiro

42.5k1485146

asked Jun 30 '13 at 22:46

Vaios ArgiropoulosVaios Argiropoulos

63211

asked Jun 30 '13 at 22:46

Vaios ArgiropoulosVaios Argiropoulos

63211

2 Answers
2

active

oldest

votes

3

Try doing this :

dirs='dir1 dir2 dir3'



for dir is $dirs; do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

       exit

    else

       continue

    fi

done

share|improve this answer

answered Jun 30 '13 at 22:51

Gilles QuenotGilles Quenot

16.6k14054

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'll try later. I'am off to bed.
  
  – Vaios Argiropoulos
  Jun 30 '13 at 22:59
  

  
  
  
  

add a comment | 

1

The general approach:

find . -mindepth 1 -maxdepth 1 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

Using your DIRS:

find $DIRS -maxdepth 0 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

share|improve this answer

answered Jun 30 '13 at 23:06

Hauke LagingHauke Laging

58.2k1289137

add a comment | 

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3

Try doing this :

dirs='dir1 dir2 dir3'



for dir is $dirs; do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

       exit

    else

       continue

    fi

done

share|improve this answer

answered Jun 30 '13 at 22:51

Gilles QuenotGilles Quenot

16.6k14054

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'll try later. I'am off to bed.
  
  – Vaios Argiropoulos
  Jun 30 '13 at 22:59
  

  
  
  
  

add a comment | 

3

Try doing this :

dirs='dir1 dir2 dir3'



for dir is $dirs; do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

       exit

    else

       continue

    fi

done

share|improve this answer

answered Jun 30 '13 at 22:51

Gilles QuenotGilles Quenot

16.6k14054

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'll try later. I'am off to bed.
  
  – Vaios Argiropoulos
  Jun 30 '13 at 22:59
  

  
  
  
  

add a comment | 

Try doing this :

dirs='dir1 dir2 dir3'



for dir is $dirs; do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

       exit

    else

       continue

    fi

done

share|improve this answer

answered Jun 30 '13 at 22:51

Gilles QuenotGilles Quenot

16.6k14054

dirs='dir1 dir2 dir3'



for dir is $dirs; do

    if (( $(stat -c %Y "$dir") < $(date +%s) - 3600*24*30 )); then

       exit

    else

       continue

    fi

done

share|improve this answer

answered Jun 30 '13 at 22:51

Gilles QuenotGilles Quenot

16.6k14054

answered Jun 30 '13 at 22:51

Gilles QuenotGilles Quenot

16.6k14054

answered Jun 30 '13 at 22:51

Gilles QuenotGilles Quenot

16.6k14054

1

The general approach:

find . -mindepth 1 -maxdepth 1 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

Using your DIRS:

find $DIRS -maxdepth 0 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

share|improve this answer

answered Jun 30 '13 at 23:06

Hauke LagingHauke Laging

58.2k1289137

add a comment | 

1

The general approach:

find . -mindepth 1 -maxdepth 1 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

Using your DIRS:

find $DIRS -maxdepth 0 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

share|improve this answer

answered Jun 30 '13 at 23:06

Hauke LagingHauke Laging

58.2k1289137

add a comment | 

The general approach:

find . -mindepth 1 -maxdepth 1 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

Using your DIRS:

find $DIRS -maxdepth 0 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

share|improve this answer

answered Jun 30 '13 at 23:06

Hauke LagingHauke Laging

58.2k1289137

find . -mindepth 1 -maxdepth 1 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

find $DIRS -maxdepth 0 -type d 

  -newermt "$(date --date="1 month ago 00:00" --rfc-3339=seconds)"

share|improve this answer

answered Jun 30 '13 at 23:06

Hauke LagingHauke Laging

58.2k1289137

answered Jun 30 '13 at 23:06

Hauke LagingHauke Laging

58.2k1289137

answered Jun 30 '13 at 23:06

Hauke LagingHauke Laging

58.2k1289137