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AWK - “for loop” inside of new line print

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

2

I'm searching how to put for loop inside "print" - I've managed how to get all information what I need from log file but if I use "for loop" after print then each new information is given in new line. I know that is calling print each time so... how to print all in new line?
For example this:

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " "} {for(i=12; i<=NF; i++) print $i}'

Give me that output:

66.249.65.172 - [29/May/2019:02:48:20 +0200]

"Mozilla/5.0

(compatible;

Googlebot/2.1;

+http://www.google.com/bot.html)"

But when I want to pass at end what I found between 12 col and NF:

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " " for(i=12; i<=NF; i++) " " $i}'

Then I get only:

66.249.65.172 - [29/May/2019:02:48:20 +0200]

I'm heading to output like:

66.249.65.172 - [29/May/2019:02:48:20 +0200] "Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html)"

awk

share|improve this question

edited 48 mins ago

TheTanadu

asked 55 mins ago

TheTanaduTheTanadu

228

add a comment | 

2

I'm searching how to put for loop inside "print" - I've managed how to get all information what I need from log file but if I use "for loop" after print then each new information is given in new line. I know that is calling print each time so... how to print all in new line?
For example this:

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " "} {for(i=12; i<=NF; i++) print $i}'

Give me that output:

66.249.65.172 - [29/May/2019:02:48:20 +0200]

"Mozilla/5.0

(compatible;

Googlebot/2.1;

+http://www.google.com/bot.html)"

But when I want to pass at end what I found between 12 col and NF:

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " " for(i=12; i<=NF; i++) " " $i}'

Then I get only:

66.249.65.172 - [29/May/2019:02:48:20 +0200]

I'm heading to output like:

66.249.65.172 - [29/May/2019:02:48:20 +0200] "Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html)"

awk

share|improve this question

edited 48 mins ago

TheTanadu

asked 55 mins ago

TheTanaduTheTanadu

228

add a comment | 

I'm searching how to put for loop inside "print" - I've managed how to get all information what I need from log file but if I use "for loop" after print then each new information is given in new line. I know that is calling print each time so... how to print all in new line?
For example this:

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " "} {for(i=12; i<=NF; i++) print $i}'

Give me that output:

66.249.65.172 - [29/May/2019:02:48:20 +0200]

"Mozilla/5.0

(compatible;

Googlebot/2.1;

+http://www.google.com/bot.html)"

But when I want to pass at end what I found between 12 col and NF:

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " " for(i=12; i<=NF; i++) " " $i}'

Then I get only:

66.249.65.172 - [29/May/2019:02:48:20 +0200]

I'm heading to output like:

66.249.65.172 - [29/May/2019:02:48:20 +0200] "Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html)"

awk

share|improve this question

edited 48 mins ago

TheTanadu

asked 55 mins ago

TheTanaduTheTanadu

228

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " "} {for(i=12; i<=NF; i++) print $i}'

66.249.65.172 - [29/May/2019:02:48:20 +0200]

"Mozilla/5.0

(compatible;

Googlebot/2.1;

+http://www.google.com/bot.html)"

cat /var/log/apache2/domlogs/xxxx/xxxx.com* | awk -F " " '{print $1 " - " $4 " " $5 " " for(i=12; i<=NF; i++) " " $i}'

66.249.65.172 - [29/May/2019:02:48:20 +0200]

66.249.65.172 - [29/May/2019:02:48:20 +0200] "Mozilla/5.0 (compatible; Googlebot/2.1; +http://www.google.com/bot.html)"

share|improve this question

edited 48 mins ago

TheTanadu

asked 55 mins ago

TheTanaduTheTanadu

228

share|improve this question

edited 48 mins ago

TheTanadu

asked 55 mins ago

TheTanaduTheTanadu

228

asked 55 mins ago

TheTanaduTheTanadu

228

asked 55 mins ago

TheTanaduTheTanadu

228

1 Answer
1

active

oldest

votes

2

You need to use printf() over print because the latter by default embeds a newline after the string provided. Modify your code to use printf with format specifiers for each of the strings.

awk '{ printf "%s - %s  %s ", $1, $4, $5 } 

     { for(i=12; i<=NF; i++) printf "%s ", $i; printf "n" }'

share|improve this answer

edited 29 mins ago

answered 35 mins ago

InianInian

6,1901633

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you so much - that's did the trick - only I've added extra space here "%s - %s %s " because output had lack of it
  
  – TheTanadu
  31 mins ago
  

  
  
  
  

add a comment | 

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2

You need to use printf() over print because the latter by default embeds a newline after the string provided. Modify your code to use printf with format specifiers for each of the strings.

awk '{ printf "%s - %s  %s ", $1, $4, $5 } 

     { for(i=12; i<=NF; i++) printf "%s ", $i; printf "n" }'

share|improve this answer

edited 29 mins ago

answered 35 mins ago

InianInian

6,1901633

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you so much - that's did the trick - only I've added extra space here "%s - %s %s " because output had lack of it
  
  – TheTanadu
  31 mins ago
  

  
  
  
  

add a comment | 

2

You need to use printf() over print because the latter by default embeds a newline after the string provided. Modify your code to use printf with format specifiers for each of the strings.

awk '{ printf "%s - %s  %s ", $1, $4, $5 } 

     { for(i=12; i<=NF; i++) printf "%s ", $i; printf "n" }'

share|improve this answer

edited 29 mins ago

answered 35 mins ago

InianInian

6,1901633

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thank you so much - that's did the trick - only I've added extra space here "%s - %s %s " because output had lack of it
  
  – TheTanadu
  31 mins ago
  

  
  
  
  

add a comment | 

You need to use printf() over print because the latter by default embeds a newline after the string provided. Modify your code to use printf with format specifiers for each of the strings.

awk '{ printf "%s - %s  %s ", $1, $4, $5 } 

     { for(i=12; i<=NF; i++) printf "%s ", $i; printf "n" }'

share|improve this answer

edited 29 mins ago

answered 35 mins ago

InianInian

6,1901633

awk '{ printf "%s - %s  %s ", $1, $4, $5 } 

     { for(i=12; i<=NF; i++) printf "%s ", $i; printf "n" }'

share|improve this answer

edited 29 mins ago

answered 35 mins ago

InianInian

6,1901633

answered 35 mins ago

InianInian

6,1901633

answered 35 mins ago

InianInian

6,1901633