Mdthbs

The following code is a simple example of passing arguments from TeX to Lua. Just passing the arguments directly (the version without luastringN) gives an error.

(./luafunction.aux)./luafunction.lua:2: attempt to concatenate local 's' (a nil value)

stack traceback:

        ./luafunction.lua:2: in function 'joinstring'

        [directlua]:1: in main chunk.

joinstring #1#2-> directlua {joinstring(#1, #2)}



l.19 joinstring{foo}{bar}

I noticed that other code used the macro luastringN when passing arguments from TeX to Lua, so I did too. But this is completely Cargo Cult programming, because I have no idea why. The docunentation in the luacode manual isn't very enlightening. On section 1.2 on page 3 of the v1.2a manual where luastringN is documented, it talks about escaping special characters. But there are no special characters in my example. And I don't understand what special handling is required to pass from TeX to Lua. Explanations appreciated - feel free to dumb it down.

Additionally, this answer to the question "LuaLaTeX set a path in lua" mentioned that one should use token.get_macro instead. The documentation on pg 10.6.4 of the luatex v 1.10 manual says:

The get_macro function can be used to get the content of a macro

but I'm not sure what that means. Also, I did a search in TeX SE for token.get_macro, and got two hits.

So is that a better choice, and if so, why? And what does the get_macro function do, exactly?

documentclass{article}

usepackage{luacode}

usepackage{filecontents}

begin{filecontents*}{luafunction2.lua}

function joinstring (s, t)

 tex.sprint(s .. t)

end



end{filecontents*}

directlua{require "luafunction2.lua"}

begin{document}



newcommandjoinstring[2]

{

  % directlua{joinstring(#1, #2)}

  directlua{joinstring(luastringN{#1}, luastringN{#2})}

}



joinstring{foo}{bar}



end{document}

Chat room discussion starts around here

All that luastringN does here is provide a wrapper for luaescapestring plus a few wrinkles. I'd just write that out, at least for a 'practice' file

documentclass{article}

usepackage{filecontents}

begin{filecontents*}{luafunction2.lua}

function joinstring (s, t)

 tex.sprint(s .. t)

end

end{filecontents*}

directlua{require "luafunction2.lua"}

begin{document}



newcommandjoinstring[2]

{%

  directlua{joinstring(

    "luaescapestring{unexpanded{#1}}",

    "luaescapestring{unexpanded{#2}}")

  }%

}



joinstring{foo}{bar}



end{document}

Notice that luaescapestring carries out (e-type) expansion, so we need unexpanded to avoid strange stuff happening. Also notice the " characters, which are needed to tell Lua we are passing a string. We don't have to worry about any " in the TeX input as luaescapestring makes them safe.

Since the Lua function tex.sprint expects to operate on strings (either string constants, variables of type string, or something that can be coerced into type string on the fly), defining the LaTeX-side macro as

newcommandjoinstring[2]{directlua{joinstring(#1,#2)}}

and then running

joinstring{foo}{bar}

is incorrect, because foo and bar are not automatically converted into what Lua recognizes as strings. Indeed, the error message you reproduced shows that Lua considers foo and bar to be of type nil. Variables of type nil are definitely going to trip up the string concatenation operation .. in the tex.sprint ( s .. t ) instruction.

The two obvious remedies are

1. 
   

   Place explicit quotation marks around the arguments of joinstring, i.e., run

   
   
   

   joinstring{"foo"}{"bar"}
   
   

   
   


2. 
   

   define the LaTeX macro as

   
   
   

   newcommandjoinstring[2]{directlua{joinstring("#1","#2")}}
   
   

   
   
   

   I suppose that one could say that luastring{#1} and especially luastringN{#1} are elaborations (say, to prohibit expansion of #1) of the "#1" approach. They are also more robust in the sense that they can handle unbalanced (single and double) quote marks in their arguments; unbalanced double-quote marks is something that would trip up the "#1" approach.

   
   

A full MWE that implements the second idea -- notice that for the simple code at hand it's not necessary to load the luacode package:

documentclass{article}

directlua{function joinstring (s,t) tex.sprint (s..t) end}

newcommandjoinstring[2]{directlua{joinstring("#1","#2")}}     

begin{document}

joinstring{foo}{bar}

end{document}

As an alternative to the luaescapestring based solution in the other answers, you can also use the token library to pass arguments from TeX to Lua. This leads to minor speed improvements, because LuaTeX doesn't have to escape the string only for Lua to parse it again. So you might consider it especially when you expect long strings. Also this avoids mixing TeX and Lua code which can help if you later decide to use your code with luafunction (or luadef).

Anyway, you first have to decide if you want (e-type) expansion or not. The token functions always expand the arguments, so you have to apply unexpanded if you do not want this. Then you can use token.scan_argument to read a argument that is given directly after the whole Lua code. If you decide to read an expanded argument, you can also handle the argument reading entirely through Lua, but then slightly different scanning rules apply. Especially in simple cases no braces are required around string arguments.

Here are some examples to see the actual effects of the different options:

documentclass{article}

usepackage{luacode}

usepackage{filecontents}

begin{filecontents*}{luafunction2.lua}

function joinstring (s, t)

 tex.write(s, ', ' , t, ': ')

 tex.sprint(s .. t .. '.')

end

end{filecontents*}

directlua{require "luafunction2.lua"}

begin{document}



newcommandjoinstring[2]{

  directlua{joinstring(token.scan_argument(), token.scan_argument())}%

  {unexpanded{#1}}{unexpanded{#2}}

}



newcommandexpandedjoinstring[2]

{

  directlua{joinstring(token.scan_argument(), token.scan_argument())}%

  {#1}{#2}%

}



newcommandotherexpandedjoinstring

{

  directlua{joinstring(token.scan_argument(), token.scan_argument())}%

}



newcommandfoo{foo}

newcommandBar{bar}

verb|joinstring{foo}{bar}|: joinstring{foo}{bar}\

verb|joinstring{foo}{Bar}|: joinstring{foo}{Bar}\

verb|joinstring foo bar|: joinstring foo bar\

verb|expandedjoinstring{foo}{bar}|: expandedjoinstring{foo}{bar}\

verb|expandedjoinstring{foo}{Bar}|: expandedjoinstring{foo}{Bar}\

verb|expandedjoinstring foo bar|: expandedjoinstring foo bar\

verb|otherexpandedjoinstring{foo}{bar}|: otherexpandedjoinstring{foo}{bar}\

verb|otherexpandedjoinstring{foo}{Bar}|: otherexpandedjoinstring{foo}{Bar}\

verb|otherexpandedjoinstring foo bar|: otherexpandedjoinstring foo bar\

end{document}