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Why is this bash script read line code giving me errors?

Why does my cronjob not execute my shell-script?Capture errors in a SFTP scriptWhy does “bash -x” break this script?Why this option not working in this Bash script?Skip catching errors in a shell scriptWhy is this script giving an “Unexpected end of file” syntax error?Why can't I execute this script?Can someone explain this line of code/command please?expect script giving errorWhy does this Bash script to print command line arguments not work?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

Why is this bash script read line code giving me errors?

read -p "Does this require cropping? (y/n)? " answer

case ${answer:0:1} in

    y|Y )

mkdir cropped; for i in *.mp4; do ffmpeg -i "$i" -filter:v "crop=1900:1080:-20:0" cropped/"${i%.*}.mp4"; rm -r *.mp4; cd cropped; cp -r *.mp4 ../

    ;;

    * )

mkdir no

    ;;

esac

When I give an answer, I get this back from terminal:

Does this require cropping? (y/n)? n

/usr/local/bin/prep: line 17: syntax error near unexpected token `;;'

/usr/local/bin/prep: line 17: `    ;;'

However, it works perfectly fine if my executed (YES) answer code is changed something like, rather than the whole mkdir cropped; for i in *.mp4...:

mkdir yes

bash shell-script command-line scripting error-handling

share|improve this question

asked 46 mins ago

AnonymousAnonymous

1147

add a comment | 

0

Why is this bash script read line code giving me errors?

read -p "Does this require cropping? (y/n)? " answer

case ${answer:0:1} in

    y|Y )

mkdir cropped; for i in *.mp4; do ffmpeg -i "$i" -filter:v "crop=1900:1080:-20:0" cropped/"${i%.*}.mp4"; rm -r *.mp4; cd cropped; cp -r *.mp4 ../

    ;;

    * )

mkdir no

    ;;

esac

When I give an answer, I get this back from terminal:

Does this require cropping? (y/n)? n

/usr/local/bin/prep: line 17: syntax error near unexpected token `;;'

/usr/local/bin/prep: line 17: `    ;;'

However, it works perfectly fine if my executed (YES) answer code is changed something like, rather than the whole mkdir cropped; for i in *.mp4...:

mkdir yes

bash shell-script command-line scripting error-handling

share|improve this question

asked 46 mins ago

AnonymousAnonymous

1147

add a comment | 

Why is this bash script read line code giving me errors?

read -p "Does this require cropping? (y/n)? " answer

case ${answer:0:1} in

    y|Y )

mkdir cropped; for i in *.mp4; do ffmpeg -i "$i" -filter:v "crop=1900:1080:-20:0" cropped/"${i%.*}.mp4"; rm -r *.mp4; cd cropped; cp -r *.mp4 ../

    ;;

    * )

mkdir no

    ;;

esac

When I give an answer, I get this back from terminal:

Does this require cropping? (y/n)? n

/usr/local/bin/prep: line 17: syntax error near unexpected token `;;'

/usr/local/bin/prep: line 17: `    ;;'

However, it works perfectly fine if my executed (YES) answer code is changed something like, rather than the whole mkdir cropped; for i in *.mp4...:

mkdir yes

bash shell-script command-line scripting error-handling

share|improve this question

asked 46 mins ago

AnonymousAnonymous

1147

read -p "Does this require cropping? (y/n)? " answer

case ${answer:0:1} in

    y|Y )

mkdir cropped; for i in *.mp4; do ffmpeg -i "$i" -filter:v "crop=1900:1080:-20:0" cropped/"${i%.*}.mp4"; rm -r *.mp4; cd cropped; cp -r *.mp4 ../

    ;;

    * )

mkdir no

    ;;

esac

Does this require cropping? (y/n)? n

/usr/local/bin/prep: line 17: syntax error near unexpected token `;;'

/usr/local/bin/prep: line 17: `    ;;'

mkdir yes

share|improve this question

asked 46 mins ago

AnonymousAnonymous

1147

share|improve this question

asked 46 mins ago

AnonymousAnonymous

1147

asked 46 mins ago

AnonymousAnonymous

1147

asked 46 mins ago

AnonymousAnonymous

1147

1 Answer
1

active

oldest

votes

1

You are missing the done on your for loop, so the no ) and stuff is part of the loop.

share|improve this answer

answered 40 mins ago

icarusicarus

6,76111632

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ohhhh.. you mean after *.mp4 ../ so it should be *.mp4 ../ done ?
  
  – Anonymous
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  seems to be missing ; done ... got it, thanks!
  
  – Anonymous
  24 mins ago
  

  
  
  
  

add a comment | 

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1

You are missing the done on your for loop, so the no ) and stuff is part of the loop.

share|improve this answer

answered 40 mins ago

icarusicarus

6,76111632

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ohhhh.. you mean after *.mp4 ../ so it should be *.mp4 ../ done ?
  
  – Anonymous
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  seems to be missing ; done ... got it, thanks!
  
  – Anonymous
  24 mins ago
  

  
  
  
  

add a comment | 

1

You are missing the done on your for loop, so the no ) and stuff is part of the loop.

share|improve this answer

answered 40 mins ago

icarusicarus

6,76111632

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ohhhh.. you mean after *.mp4 ../ so it should be *.mp4 ../ done ?
  
  – Anonymous
  28 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  seems to be missing ; done ... got it, thanks!
  
  – Anonymous
  24 mins ago
  

  
  
  
  

add a comment | 

You are missing the done on your for loop, so the no ) and stuff is part of the loop.

share|improve this answer

answered 40 mins ago

icarusicarus

6,76111632

share|improve this answer

answered 40 mins ago

icarusicarus

6,76111632

answered 40 mins ago

icarusicarus

6,76111632

answered 40 mins ago

icarusicarus

6,76111632