How to split the polynomial .How to find all elements of a factor group?Split groups and quasi-split...
How deep is the Underdark? What is its max and median depth?
Can two waves interfere head on?
Host telling me to cancel my booking in exchange for a discount?
Why can't a country print its own money to spend it only abroad?
What does Windows' "Tuning up Application Start" do?
Does a hash function have a Upper bound on input length?
Ethiopian Airlines tickets seem to always have the same price regardless of the proximity of the date?
Find position equal columns of matrix
1025th term of the given sequence.
why neutral does not shock. how can a neutral be neutral in ac current?
Why didn't NASA launch communications relay satellites for the Apollo missions?
What does a Nintendo Game Boy do when turned on without a game cartridge inserted?
Can a creature sustain itself by eating its own severed body parts?
How does the Gameboy's memory bank switching work?
Why is the forgetful functor representable?
Would using carbon dioxide as fuel work to reduce the greenhouse effect?
P-adic functions on annuli
3D cursor orientation
How to hide your own body?
Difference between string += s1 and string = string + s1
Manager is asking me to eat breakfast from now on
I want light controlled by one switch, not two
Do gauntlets count as armor?
Do you need to have the original move to take a "Replaces:" move?
How to split the polynomial .
How to find all elements of a factor group?Split groups and quasi-split groups.Definition of split of exact sequenceIrreducibility of a cubic polynomialDetermine the irreducibility of polynomial.How to find the minimal polynomial.polynomial with a root but no linear factorReducing polynomial modulo $n$Finding minimal polynomial when the straight equation must be reduced.Splitting field of polynomial is F8
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
$begingroup$
How do I split $x^2-5 $ in $mathbb{Z}/5mathbb{Z}$ ? Since $0$ is a root I have $x $ as linear factor . How can I find the other linear factor ?
abstract-algebra number-theory
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
$endgroup$
add a comment |
$begingroup$
How do I split $x^2-5 $ in $mathbb{Z}/5mathbb{Z}$ ? Since $0$ is a root I have $x $ as linear factor . How can I find the other linear factor ?
abstract-algebra number-theory
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
$endgroup$
1
$begingroup$
$x^2=xtimes x$
$endgroup$
– J. W. Tanner
10 hours ago
add a comment |
$begingroup$
How do I split $x^2-5 $ in $mathbb{Z}/5mathbb{Z}$ ? Since $0$ is a root I have $x $ as linear factor . How can I find the other linear factor ?
abstract-algebra number-theory
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
$endgroup$
How do I split $x^2-5 $ in $mathbb{Z}/5mathbb{Z}$ ? Since $0$ is a root I have $x $ as linear factor . How can I find the other linear factor ?
abstract-algebra number-theory
abstract-algebra number-theory
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
asked 10 hours ago
AnabolicHorseAnabolicHorse
1708 bronze badges
1708 bronze badges
1
$begingroup$
$x^2=xtimes x$
$endgroup$
– J. W. Tanner
10 hours ago
add a comment |
1
$begingroup$
$x^2=xtimes x$
$endgroup$
– J. W. Tanner
10 hours ago
1
1
$begingroup$
$x^2=xtimes x$
$endgroup$
– J. W. Tanner
10 hours ago
$begingroup$
$x^2=xtimes x$
$endgroup$
– J. W. Tanner
10 hours ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Note that $x^2-5 = x^2$, which is already factorised.
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
$endgroup$
add a comment |
$begingroup$
Hint: Vieta's formulas still work. The sum of the two roots equals the (negative of the) coefficient of the first degree term.
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "69"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
noCode: true, onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3299829%2fhow-to-split-the-polynomial%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Note that $x^2-5 = x^2$, which is already factorised.
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
$endgroup$
add a comment |
$begingroup$
Note that $x^2-5 = x^2$, which is already factorised.
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
$endgroup$
add a comment |
$begingroup$
Note that $x^2-5 = x^2$, which is already factorised.
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
$endgroup$
Note that $x^2-5 = x^2$, which is already factorised.
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
answered 10 hours ago
Patrick StevensPatrick Stevens
29.4k5 gold badges29 silver badges75 bronze badges
29.4k5 gold badges29 silver badges75 bronze badges
add a comment |
add a comment |
$begingroup$
Hint: Vieta's formulas still work. The sum of the two roots equals the (negative of the) coefficient of the first degree term.
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
$endgroup$
add a comment |
$begingroup$
Hint: Vieta's formulas still work. The sum of the two roots equals the (negative of the) coefficient of the first degree term.
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
$endgroup$
add a comment |
$begingroup$
Hint: Vieta's formulas still work. The sum of the two roots equals the (negative of the) coefficient of the first degree term.
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
$endgroup$
Hint: Vieta's formulas still work. The sum of the two roots equals the (negative of the) coefficient of the first degree term.
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
answered 10 hours ago
ArthurArthur
132k9 gold badges127 silver badges219 bronze badges
132k9 gold badges127 silver badges219 bronze badges
add a comment |
add a comment |
Thanks for contributing an answer to Mathematics Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmath.stackexchange.com%2fquestions%2f3299829%2fhow-to-split-the-polynomial%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
$begingroup$
$x^2=xtimes x$
$endgroup$
– J. W. Tanner
10 hours ago