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Awk to get all my regular users in shadow

Convey some message to all usersHow can I process multi-line records with awk in a bash script?return value from awkUpstart - unable to read /etc/shadow unless sudoBash: Regular Expressions in substitutionSet expire date for usersGet one element of path string using bashSeparating Commands in a Script File?Substitute cut command inside AWK scriptMake variables show a column with awk

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

5

I have a script.

I want to get all my regular users from /etc/shadow e.g all users which second term in shadow file begins with $ or !$.

My pattern is

sudo getent shadow | awk -F: '$2 ~ /^$/ || /^!$/ {print $1}'

It doesn't work for now.

bash scripts

share|improve this question

edited 10 hours ago

Eliah Kagan

87.7k2222 gold badges243243 silver badges386386 bronze badges

asked 10 hours ago

danasodanaso

6755 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  does it have to be awk? :-)
  
  – Rinzwind
  10 hours ago
  

  
  
  
  

add a comment | 

5

I have a script.

I want to get all my regular users from /etc/shadow e.g all users which second term in shadow file begins with $ or !$.

My pattern is

sudo getent shadow | awk -F: '$2 ~ /^$/ || /^!$/ {print $1}'

It doesn't work for now.

bash scripts

share|improve this question

edited 10 hours ago

Eliah Kagan

87.7k2222 gold badges243243 silver badges386386 bronze badges

asked 10 hours ago

danasodanaso

6755 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  does it have to be awk? :-)
  
  – Rinzwind
  10 hours ago
  

  
  
  
  

add a comment | 

I have a script.

I want to get all my regular users from /etc/shadow e.g all users which second term in shadow file begins with $ or !$.

My pattern is

sudo getent shadow | awk -F: '$2 ~ /^$/ || /^!$/ {print $1}'

It doesn't work for now.

bash scripts

share|improve this question

edited 10 hours ago

Eliah Kagan

87.7k2222 gold badges243243 silver badges386386 bronze badges

asked 10 hours ago

danasodanaso

6755 bronze badges

sudo getent shadow | awk -F: '$2 ~ /^$/ || /^!$/ {print $1}'

share|improve this question

edited 10 hours ago

Eliah Kagan

87.7k2222 gold badges243243 silver badges386386 bronze badges

asked 10 hours ago

danasodanaso

6755 bronze badges

share|improve this question

edited 10 hours ago

Eliah Kagan

87.7k2222 gold badges243243 silver badges386386 bronze badges

asked 10 hours ago

danasodanaso

6755 bronze badges

edited 10 hours ago

Eliah Kagan

87.7k2222 gold badges243243 silver badges386386 bronze badges

edited 10 hours ago

Eliah Kagan

87.7k2222 gold badges243243 silver badges386386 bronze badges

asked 10 hours ago

danasodanaso

6755 bronze badges

asked 10 hours ago

danasodanaso

6755 bronze badges

2 Answers
2

active

oldest

votes

8

You need to escape the $, as it is a special char for "End of Line" much like ^ is "Beginning of Line".

sudo getent shadow | awk -F: '$2 ~ /^$/ || $2 ~  /^!$/ {print $1}'

share|improve this answer

edited 10 hours ago

answered 10 hours ago

pLumopLumo

10.5k2121 silver badges4848 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  +1 good catch :)
  
  – Rinzwind
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, it works. I just need to not include root user
  
  – danaso
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Simplified: awk -F: '$2 ~ /^!?$/ {print $1}' - This combines the two match tests and says "match a dollar sign at the beginning of the field, optionally (?) preceded by a !"
  
  – Dennis Williamson
  27 mins ago
  

  
  
  
  

add a comment | 

3

All users with a password set can be listed like this:

getent shadow | egrep '^[^:]*:[*!]:' -v | cut -f1 -d:

share|improve this answer

answered 10 hours ago

RinzwindRinzwind

220k2929 gold badges425425 silver badges567567 bronze badges

add a comment | 

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8

You need to escape the $, as it is a special char for "End of Line" much like ^ is "Beginning of Line".

sudo getent shadow | awk -F: '$2 ~ /^$/ || $2 ~  /^!$/ {print $1}'

share|improve this answer

edited 10 hours ago

answered 10 hours ago

pLumopLumo

10.5k2121 silver badges4848 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  +1 good catch :)
  
  – Rinzwind
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, it works. I just need to not include root user
  
  – danaso
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Simplified: awk -F: '$2 ~ /^!?$/ {print $1}' - This combines the two match tests and says "match a dollar sign at the beginning of the field, optionally (?) preceded by a !"
  
  – Dennis Williamson
  27 mins ago
  

  
  
  
  

add a comment | 

8

You need to escape the $, as it is a special char for "End of Line" much like ^ is "Beginning of Line".

sudo getent shadow | awk -F: '$2 ~ /^$/ || $2 ~  /^!$/ {print $1}'

share|improve this answer

edited 10 hours ago

answered 10 hours ago

pLumopLumo

10.5k2121 silver badges4848 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  +1 good catch :)
  
  – Rinzwind
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks, it works. I just need to not include root user
  
  – danaso
  10 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Simplified: awk -F: '$2 ~ /^!?$/ {print $1}' - This combines the two match tests and says "match a dollar sign at the beginning of the field, optionally (?) preceded by a !"
  
  – Dennis Williamson
  27 mins ago
  

  
  
  
  

add a comment | 

You need to escape the $, as it is a special char for "End of Line" much like ^ is "Beginning of Line".

sudo getent shadow | awk -F: '$2 ~ /^$/ || $2 ~  /^!$/ {print $1}'

share|improve this answer

edited 10 hours ago

answered 10 hours ago

pLumopLumo

10.5k2121 silver badges4848 bronze badges

sudo getent shadow | awk -F: '$2 ~ /^$/ || $2 ~  /^!$/ {print $1}'

share|improve this answer

edited 10 hours ago

answered 10 hours ago

pLumopLumo

10.5k2121 silver badges4848 bronze badges

answered 10 hours ago

pLumopLumo

10.5k2121 silver badges4848 bronze badges

answered 10 hours ago

pLumopLumo

10.5k2121 silver badges4848 bronze badges

3

All users with a password set can be listed like this:

getent shadow | egrep '^[^:]*:[*!]:' -v | cut -f1 -d:

share|improve this answer

answered 10 hours ago

RinzwindRinzwind

220k2929 gold badges425425 silver badges567567 bronze badges

add a comment | 

3

All users with a password set can be listed like this:

getent shadow | egrep '^[^:]*:[*!]:' -v | cut -f1 -d:

share|improve this answer

answered 10 hours ago

RinzwindRinzwind

220k2929 gold badges425425 silver badges567567 bronze badges

add a comment | 

All users with a password set can be listed like this:

getent shadow | egrep '^[^:]*:[*!]:' -v | cut -f1 -d:

share|improve this answer

answered 10 hours ago

RinzwindRinzwind

220k2929 gold badges425425 silver badges567567 bronze badges

getent shadow | egrep '^[^:]*:[*!]:' -v | cut -f1 -d:

share|improve this answer

answered 10 hours ago

RinzwindRinzwind

220k2929 gold badges425425 silver badges567567 bronze badges

answered 10 hours ago

RinzwindRinzwind

220k2929 gold badges425425 silver badges567567 bronze badges

answered 10 hours ago

RinzwindRinzwind

220k2929 gold badges425425 silver badges567567 bronze badges