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zsh: Is it possible to implement a `local export`?
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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
Is it possible to implement a local export
in zsh? Possibly using try and always?
Does this create race-conditions?
By local export, I mean sth exactly like a local variable, that is accessible to the subprocesses (in scope).
Example:
function a() {
local export YACY_TIMEOUT=60
yacy -r -d sth
}
export YACY_TIMEOUT=4
echo "$YACY_TIMEOUT" # 4
a
echo "$YACY_TIMEOUT" # 4
zsh environment-variables
add a comment |
Is it possible to implement a local export
in zsh? Possibly using try and always?
Does this create race-conditions?
By local export, I mean sth exactly like a local variable, that is accessible to the subprocesses (in scope).
Example:
function a() {
local export YACY_TIMEOUT=60
yacy -r -d sth
}
export YACY_TIMEOUT=4
echo "$YACY_TIMEOUT" # 4
a
echo "$YACY_TIMEOUT" # 4
zsh environment-variables
What would it be local to? Please show an example use case.
– muru
1 hour ago
@muru done .............
– HappyFace
1 hour ago
add a comment |
Is it possible to implement a local export
in zsh? Possibly using try and always?
Does this create race-conditions?
By local export, I mean sth exactly like a local variable, that is accessible to the subprocesses (in scope).
Example:
function a() {
local export YACY_TIMEOUT=60
yacy -r -d sth
}
export YACY_TIMEOUT=4
echo "$YACY_TIMEOUT" # 4
a
echo "$YACY_TIMEOUT" # 4
zsh environment-variables
Is it possible to implement a local export
in zsh? Possibly using try and always?
Does this create race-conditions?
By local export, I mean sth exactly like a local variable, that is accessible to the subprocesses (in scope).
Example:
function a() {
local export YACY_TIMEOUT=60
yacy -r -d sth
}
export YACY_TIMEOUT=4
echo "$YACY_TIMEOUT" # 4
a
echo "$YACY_TIMEOUT" # 4
zsh environment-variables
zsh environment-variables
edited 1 hour ago
HappyFace
asked 1 hour ago
HappyFaceHappyFace
3731 silver badge11 bronze badges
3731 silver badge11 bronze badges
What would it be local to? Please show an example use case.
– muru
1 hour ago
@muru done .............
– HappyFace
1 hour ago
add a comment |
What would it be local to? Please show an example use case.
– muru
1 hour ago
@muru done .............
– HappyFace
1 hour ago
What would it be local to? Please show an example use case.
– muru
1 hour ago
What would it be local to? Please show an example use case.
– muru
1 hour ago
@muru done .............
– HappyFace
1 hour ago
@muru done .............
– HappyFace
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
Use a subshell:
function a() (
YACY_TIMEOUT=60
yacy -r -d sth
)
Example:
% a () ( TIMEOUT=60; env | grep TIMEOUT )
% export TIMEOUT=4
% echo $TIMEOUT
4
% a
TIMEOUT=60
% echo $TIMEOUT
4
But there, theYACY_TIMEOUT
is only exported in the function it was already exported in the caller.
– Stéphane Chazelas
1 min ago
add a comment |
This doesn't do exactly what you want, as it doesn't actually create a new variable in the current shell:
a () {
YACY_TIMEOUT=60 yacy -r -d std
}
This is the standard syntax for running a command and giving it a particular value of an environment variable. The variable YACY_TIMEOUT
, if it exists in the same scope as the body of the a
function, would not be modified.
This would work in any POSIX shell.
What this does not do is to allow you to use YACY_TIMEOUT
with the "local" value inside the function before calling yacy
.
In zsh
or any other shell that supports local variables declared with local
, you could do
a () {
local YACY_TIMEOUT=60
YACY_TIMEOUT=$YACY_TIMEOUT yacy -r -d sth
}
Here, YACY_TIMEOUT
would be local to the a
function. The injection of the variable as an environment variable in the yacy
process happens as in the first example I gave, by preceding the invocation by an assignment.
Now YACY_TIMEOUT
is both local and is also available in the yacy
process' environment. This would work in any shell that supports using local
to declare local variables.
This necessates having code written in a specialized manner. The subshell solution works with any code, including code that we can not modify.
– HappyFace
23 mins ago
@HappyFace What part of the code are you not able to modify? Also note that I'm not doing anything "special" here, and that the second piece of code is not very different from your own proposal.
– Kusalananda♦
22 mins ago
add a comment |
Variables are always available to sub-processes. In:
a=1
(echo "$a")
you see 1.
I think what you meant is that you want the variable to have a local scope and be exported to the environment so that they are passed as environment variables to commands that are executed. The execution of a command is the thing that wipes the memory a process (and the environment is a way to preserve some data across it), forking a child copies the entire memory so everything is preserved.
For that, you can use local -x
:
a=(1 2)
f() {
local -x a=3
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
gives:
typeset -x a=3
3
typeset -a a=( 1 2 )
Or you can export
it after having been declared local
:
a=(1 2)
f() {
local a=3
export a
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
Note that you can pass a variable in the environment of a single command without defining it otherwise as a shell variable with:
a=(1 2)
f() {
a=3 printenv a # printenv being *executed*
}
f
typeset -p a
Note that local
originated in the Almquist shell in the late 80s, but works differently from zsh
's. In the Almquist shell (and its descendants like dash and the sh of NetBSD/FreeBSD), local
only affects the scope of a variable and doesn't change the value or attributes of a variable.
zsh's local
works more like ksh93's typeset
in that it declares a brand new variable that is independent from the one in the outer scope.
ksh88, bash and pdksh's local
/typeset
try to do that as well but still inherit some attributes from the variable of the outer scope including the export attribute. That changed in ksh93 though note that ksh93 also switched to static scoping and only implements local scope in functions declared with the function f { ...; }
syntax.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Use a subshell:
function a() (
YACY_TIMEOUT=60
yacy -r -d sth
)
Example:
% a () ( TIMEOUT=60; env | grep TIMEOUT )
% export TIMEOUT=4
% echo $TIMEOUT
4
% a
TIMEOUT=60
% echo $TIMEOUT
4
But there, theYACY_TIMEOUT
is only exported in the function it was already exported in the caller.
– Stéphane Chazelas
1 min ago
add a comment |
Use a subshell:
function a() (
YACY_TIMEOUT=60
yacy -r -d sth
)
Example:
% a () ( TIMEOUT=60; env | grep TIMEOUT )
% export TIMEOUT=4
% echo $TIMEOUT
4
% a
TIMEOUT=60
% echo $TIMEOUT
4
But there, theYACY_TIMEOUT
is only exported in the function it was already exported in the caller.
– Stéphane Chazelas
1 min ago
add a comment |
Use a subshell:
function a() (
YACY_TIMEOUT=60
yacy -r -d sth
)
Example:
% a () ( TIMEOUT=60; env | grep TIMEOUT )
% export TIMEOUT=4
% echo $TIMEOUT
4
% a
TIMEOUT=60
% echo $TIMEOUT
4
Use a subshell:
function a() (
YACY_TIMEOUT=60
yacy -r -d sth
)
Example:
% a () ( TIMEOUT=60; env | grep TIMEOUT )
% export TIMEOUT=4
% echo $TIMEOUT
4
% a
TIMEOUT=60
% echo $TIMEOUT
4
answered 1 hour ago
murumuru
43.5k5 gold badges108 silver badges181 bronze badges
43.5k5 gold badges108 silver badges181 bronze badges
But there, theYACY_TIMEOUT
is only exported in the function it was already exported in the caller.
– Stéphane Chazelas
1 min ago
add a comment |
But there, theYACY_TIMEOUT
is only exported in the function it was already exported in the caller.
– Stéphane Chazelas
1 min ago
But there, the
YACY_TIMEOUT
is only exported in the function it was already exported in the caller.– Stéphane Chazelas
1 min ago
But there, the
YACY_TIMEOUT
is only exported in the function it was already exported in the caller.– Stéphane Chazelas
1 min ago
add a comment |
This doesn't do exactly what you want, as it doesn't actually create a new variable in the current shell:
a () {
YACY_TIMEOUT=60 yacy -r -d std
}
This is the standard syntax for running a command and giving it a particular value of an environment variable. The variable YACY_TIMEOUT
, if it exists in the same scope as the body of the a
function, would not be modified.
This would work in any POSIX shell.
What this does not do is to allow you to use YACY_TIMEOUT
with the "local" value inside the function before calling yacy
.
In zsh
or any other shell that supports local variables declared with local
, you could do
a () {
local YACY_TIMEOUT=60
YACY_TIMEOUT=$YACY_TIMEOUT yacy -r -d sth
}
Here, YACY_TIMEOUT
would be local to the a
function. The injection of the variable as an environment variable in the yacy
process happens as in the first example I gave, by preceding the invocation by an assignment.
Now YACY_TIMEOUT
is both local and is also available in the yacy
process' environment. This would work in any shell that supports using local
to declare local variables.
This necessates having code written in a specialized manner. The subshell solution works with any code, including code that we can not modify.
– HappyFace
23 mins ago
@HappyFace What part of the code are you not able to modify? Also note that I'm not doing anything "special" here, and that the second piece of code is not very different from your own proposal.
– Kusalananda♦
22 mins ago
add a comment |
This doesn't do exactly what you want, as it doesn't actually create a new variable in the current shell:
a () {
YACY_TIMEOUT=60 yacy -r -d std
}
This is the standard syntax for running a command and giving it a particular value of an environment variable. The variable YACY_TIMEOUT
, if it exists in the same scope as the body of the a
function, would not be modified.
This would work in any POSIX shell.
What this does not do is to allow you to use YACY_TIMEOUT
with the "local" value inside the function before calling yacy
.
In zsh
or any other shell that supports local variables declared with local
, you could do
a () {
local YACY_TIMEOUT=60
YACY_TIMEOUT=$YACY_TIMEOUT yacy -r -d sth
}
Here, YACY_TIMEOUT
would be local to the a
function. The injection of the variable as an environment variable in the yacy
process happens as in the first example I gave, by preceding the invocation by an assignment.
Now YACY_TIMEOUT
is both local and is also available in the yacy
process' environment. This would work in any shell that supports using local
to declare local variables.
This necessates having code written in a specialized manner. The subshell solution works with any code, including code that we can not modify.
– HappyFace
23 mins ago
@HappyFace What part of the code are you not able to modify? Also note that I'm not doing anything "special" here, and that the second piece of code is not very different from your own proposal.
– Kusalananda♦
22 mins ago
add a comment |
This doesn't do exactly what you want, as it doesn't actually create a new variable in the current shell:
a () {
YACY_TIMEOUT=60 yacy -r -d std
}
This is the standard syntax for running a command and giving it a particular value of an environment variable. The variable YACY_TIMEOUT
, if it exists in the same scope as the body of the a
function, would not be modified.
This would work in any POSIX shell.
What this does not do is to allow you to use YACY_TIMEOUT
with the "local" value inside the function before calling yacy
.
In zsh
or any other shell that supports local variables declared with local
, you could do
a () {
local YACY_TIMEOUT=60
YACY_TIMEOUT=$YACY_TIMEOUT yacy -r -d sth
}
Here, YACY_TIMEOUT
would be local to the a
function. The injection of the variable as an environment variable in the yacy
process happens as in the first example I gave, by preceding the invocation by an assignment.
Now YACY_TIMEOUT
is both local and is also available in the yacy
process' environment. This would work in any shell that supports using local
to declare local variables.
This doesn't do exactly what you want, as it doesn't actually create a new variable in the current shell:
a () {
YACY_TIMEOUT=60 yacy -r -d std
}
This is the standard syntax for running a command and giving it a particular value of an environment variable. The variable YACY_TIMEOUT
, if it exists in the same scope as the body of the a
function, would not be modified.
This would work in any POSIX shell.
What this does not do is to allow you to use YACY_TIMEOUT
with the "local" value inside the function before calling yacy
.
In zsh
or any other shell that supports local variables declared with local
, you could do
a () {
local YACY_TIMEOUT=60
YACY_TIMEOUT=$YACY_TIMEOUT yacy -r -d sth
}
Here, YACY_TIMEOUT
would be local to the a
function. The injection of the variable as an environment variable in the yacy
process happens as in the first example I gave, by preceding the invocation by an assignment.
Now YACY_TIMEOUT
is both local and is also available in the yacy
process' environment. This would work in any shell that supports using local
to declare local variables.
answered 26 mins ago
Kusalananda♦Kusalananda
158k18 gold badges313 silver badges498 bronze badges
158k18 gold badges313 silver badges498 bronze badges
This necessates having code written in a specialized manner. The subshell solution works with any code, including code that we can not modify.
– HappyFace
23 mins ago
@HappyFace What part of the code are you not able to modify? Also note that I'm not doing anything "special" here, and that the second piece of code is not very different from your own proposal.
– Kusalananda♦
22 mins ago
add a comment |
This necessates having code written in a specialized manner. The subshell solution works with any code, including code that we can not modify.
– HappyFace
23 mins ago
@HappyFace What part of the code are you not able to modify? Also note that I'm not doing anything "special" here, and that the second piece of code is not very different from your own proposal.
– Kusalananda♦
22 mins ago
This necessates having code written in a specialized manner. The subshell solution works with any code, including code that we can not modify.
– HappyFace
23 mins ago
This necessates having code written in a specialized manner. The subshell solution works with any code, including code that we can not modify.
– HappyFace
23 mins ago
@HappyFace What part of the code are you not able to modify? Also note that I'm not doing anything "special" here, and that the second piece of code is not very different from your own proposal.
– Kusalananda♦
22 mins ago
@HappyFace What part of the code are you not able to modify? Also note that I'm not doing anything "special" here, and that the second piece of code is not very different from your own proposal.
– Kusalananda♦
22 mins ago
add a comment |
Variables are always available to sub-processes. In:
a=1
(echo "$a")
you see 1.
I think what you meant is that you want the variable to have a local scope and be exported to the environment so that they are passed as environment variables to commands that are executed. The execution of a command is the thing that wipes the memory a process (and the environment is a way to preserve some data across it), forking a child copies the entire memory so everything is preserved.
For that, you can use local -x
:
a=(1 2)
f() {
local -x a=3
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
gives:
typeset -x a=3
3
typeset -a a=( 1 2 )
Or you can export
it after having been declared local
:
a=(1 2)
f() {
local a=3
export a
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
Note that you can pass a variable in the environment of a single command without defining it otherwise as a shell variable with:
a=(1 2)
f() {
a=3 printenv a # printenv being *executed*
}
f
typeset -p a
Note that local
originated in the Almquist shell in the late 80s, but works differently from zsh
's. In the Almquist shell (and its descendants like dash and the sh of NetBSD/FreeBSD), local
only affects the scope of a variable and doesn't change the value or attributes of a variable.
zsh's local
works more like ksh93's typeset
in that it declares a brand new variable that is independent from the one in the outer scope.
ksh88, bash and pdksh's local
/typeset
try to do that as well but still inherit some attributes from the variable of the outer scope including the export attribute. That changed in ksh93 though note that ksh93 also switched to static scoping and only implements local scope in functions declared with the function f { ...; }
syntax.
add a comment |
Variables are always available to sub-processes. In:
a=1
(echo "$a")
you see 1.
I think what you meant is that you want the variable to have a local scope and be exported to the environment so that they are passed as environment variables to commands that are executed. The execution of a command is the thing that wipes the memory a process (and the environment is a way to preserve some data across it), forking a child copies the entire memory so everything is preserved.
For that, you can use local -x
:
a=(1 2)
f() {
local -x a=3
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
gives:
typeset -x a=3
3
typeset -a a=( 1 2 )
Or you can export
it after having been declared local
:
a=(1 2)
f() {
local a=3
export a
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
Note that you can pass a variable in the environment of a single command without defining it otherwise as a shell variable with:
a=(1 2)
f() {
a=3 printenv a # printenv being *executed*
}
f
typeset -p a
Note that local
originated in the Almquist shell in the late 80s, but works differently from zsh
's. In the Almquist shell (and its descendants like dash and the sh of NetBSD/FreeBSD), local
only affects the scope of a variable and doesn't change the value or attributes of a variable.
zsh's local
works more like ksh93's typeset
in that it declares a brand new variable that is independent from the one in the outer scope.
ksh88, bash and pdksh's local
/typeset
try to do that as well but still inherit some attributes from the variable of the outer scope including the export attribute. That changed in ksh93 though note that ksh93 also switched to static scoping and only implements local scope in functions declared with the function f { ...; }
syntax.
add a comment |
Variables are always available to sub-processes. In:
a=1
(echo "$a")
you see 1.
I think what you meant is that you want the variable to have a local scope and be exported to the environment so that they are passed as environment variables to commands that are executed. The execution of a command is the thing that wipes the memory a process (and the environment is a way to preserve some data across it), forking a child copies the entire memory so everything is preserved.
For that, you can use local -x
:
a=(1 2)
f() {
local -x a=3
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
gives:
typeset -x a=3
3
typeset -a a=( 1 2 )
Or you can export
it after having been declared local
:
a=(1 2)
f() {
local a=3
export a
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
Note that you can pass a variable in the environment of a single command without defining it otherwise as a shell variable with:
a=(1 2)
f() {
a=3 printenv a # printenv being *executed*
}
f
typeset -p a
Note that local
originated in the Almquist shell in the late 80s, but works differently from zsh
's. In the Almquist shell (and its descendants like dash and the sh of NetBSD/FreeBSD), local
only affects the scope of a variable and doesn't change the value or attributes of a variable.
zsh's local
works more like ksh93's typeset
in that it declares a brand new variable that is independent from the one in the outer scope.
ksh88, bash and pdksh's local
/typeset
try to do that as well but still inherit some attributes from the variable of the outer scope including the export attribute. That changed in ksh93 though note that ksh93 also switched to static scoping and only implements local scope in functions declared with the function f { ...; }
syntax.
Variables are always available to sub-processes. In:
a=1
(echo "$a")
you see 1.
I think what you meant is that you want the variable to have a local scope and be exported to the environment so that they are passed as environment variables to commands that are executed. The execution of a command is the thing that wipes the memory a process (and the environment is a way to preserve some data across it), forking a child copies the entire memory so everything is preserved.
For that, you can use local -x
:
a=(1 2)
f() {
local -x a=3
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
gives:
typeset -x a=3
3
typeset -a a=( 1 2 )
Or you can export
it after having been declared local
:
a=(1 2)
f() {
local a=3
export a
typeset -p a
printenv a # printenv being *executed*
}
f
typeset -p a
Note that you can pass a variable in the environment of a single command without defining it otherwise as a shell variable with:
a=(1 2)
f() {
a=3 printenv a # printenv being *executed*
}
f
typeset -p a
Note that local
originated in the Almquist shell in the late 80s, but works differently from zsh
's. In the Almquist shell (and its descendants like dash and the sh of NetBSD/FreeBSD), local
only affects the scope of a variable and doesn't change the value or attributes of a variable.
zsh's local
works more like ksh93's typeset
in that it declares a brand new variable that is independent from the one in the outer scope.
ksh88, bash and pdksh's local
/typeset
try to do that as well but still inherit some attributes from the variable of the outer scope including the export attribute. That changed in ksh93 though note that ksh93 also switched to static scoping and only implements local scope in functions declared with the function f { ...; }
syntax.
edited 4 mins ago
answered 21 mins ago
Stéphane ChazelasStéphane Chazelas
328k57 gold badges638 silver badges1006 bronze badges
328k57 gold badges638 silver badges1006 bronze badges
add a comment |
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What would it be local to? Please show an example use case.
– muru
1 hour ago
@muru done .............
– HappyFace
1 hour ago