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Checking if string ends with a number throws “unexpected operator”

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}

0

I'm trying to check wether the file name of the script I run ends with a number or not:

#!/bin/sh

name=$(basename "$0" .sh)

[ $name =~ ^.[0-9]$ ] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $numb

my shell file is named mh03.sh and this is the output if I run it:

$ ./mh3.sh

./mh3.sh: 3: [: mh3: unexpected operator

1

can someone tell me why I get this exception and how I can fix it?

bash regular-expression

share|improve this question

asked 40 mins ago

Nicola UetzNicola Uetz

11555 bronze badges

add a comment | 

0

I'm trying to check wether the file name of the script I run ends with a number or not:

#!/bin/sh

name=$(basename "$0" .sh)

[ $name =~ ^.[0-9]$ ] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $numb

my shell file is named mh03.sh and this is the output if I run it:

$ ./mh3.sh

./mh3.sh: 3: [: mh3: unexpected operator

1

can someone tell me why I get this exception and how I can fix it?

bash regular-expression

share|improve this question

asked 40 mins ago

Nicola UetzNicola Uetz

11555 bronze badges

add a comment | 

I'm trying to check wether the file name of the script I run ends with a number or not:

#!/bin/sh

name=$(basename "$0" .sh)

[ $name =~ ^.[0-9]$ ] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $numb

my shell file is named mh03.sh and this is the output if I run it:

$ ./mh3.sh

./mh3.sh: 3: [: mh3: unexpected operator

1

can someone tell me why I get this exception and how I can fix it?

bash regular-expression

share|improve this question

asked 40 mins ago

Nicola UetzNicola Uetz

11555 bronze badges

#!/bin/sh

name=$(basename "$0" .sh)

[ $name =~ ^.[0-9]$ ] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $numb

$ ./mh3.sh

./mh3.sh: 3: [: mh3: unexpected operator

1

share|improve this question

asked 40 mins ago

Nicola UetzNicola Uetz

11555 bronze badges

share|improve this question

asked 40 mins ago

Nicola UetzNicola Uetz

11555 bronze badges

asked 40 mins ago

Nicola UetzNicola Uetz

11555 bronze badges

asked 40 mins ago

Nicola UetzNicola Uetz

11555 bronze badges

2 Answers
2

active

oldest

votes

1

The regex match operator =~ is not supported in the single square brackets. You need double square brackets for it to work.

[[ $name =~ ^.[0-9]$ ]]

Note that you don't need a regex, you can use a normal pattern:

[[ $name = *[0-9] ]]

or, if you need the name to contain something before the digit,

[[ $name = *?[0-9] ]]

share|improve this answer

answered 31 mins ago

chorobachoroba

29.3k44 gold badges5757 silver badges8181 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Oh good to know! But now it gives me the following exception: ./mh3.sh: 3: ./mh3.sh: [[: not found
  
  – Nicola Uetz
  26 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I found the second issue by myself... Appearently I have to use #!/bin/bash instead of #!/bin/sh... I just wonder why.
  
  – Nicola Uetz
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  /bin/sh is not the same as "bash". If you want to use bash semantics then use #!/bin/bash.
  
  – Stephen Harris
  5 mins ago
  

  
  
  
  

add a comment | 

1

[: =~: binary operator expected

the error is [$name =~ ^.[0-9]$ ]
encolse it with [],

try,

#!/bin/sh

name=$(basename "$0" .sh)

[[ $name =~ ^.[0-9]$ ]] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $num

and it works.

share|improve this answer

answered 30 mins ago

Cosmo ArunCosmo Arun

4144 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I don't know which one of you were first. But either way it just prints me a new exception: ./mh3.sh: 3: ./mh3.sh: [[: not found
  
  – Nicola Uetz
  25 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I found the second issue by myself... Appearently I have to use #!/bin/bash instead of #!/bin/sh... I just wonder why.
  
  – Nicola Uetz
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i guess you /bin/bash is not really bash, try typing this and execute, /bin/bash -c "type [["
  
  – Cosmo Arun
  19 mins ago
  
  
  

  
  
  
  

add a comment | 

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1

The regex match operator =~ is not supported in the single square brackets. You need double square brackets for it to work.

[[ $name =~ ^.[0-9]$ ]]

Note that you don't need a regex, you can use a normal pattern:

[[ $name = *[0-9] ]]

or, if you need the name to contain something before the digit,

[[ $name = *?[0-9] ]]

share|improve this answer

answered 31 mins ago

chorobachoroba

29.3k44 gold badges5757 silver badges8181 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Oh good to know! But now it gives me the following exception: ./mh3.sh: 3: ./mh3.sh: [[: not found
  
  – Nicola Uetz
  26 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I found the second issue by myself... Appearently I have to use #!/bin/bash instead of #!/bin/sh... I just wonder why.
  
  – Nicola Uetz
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  /bin/sh is not the same as "bash". If you want to use bash semantics then use #!/bin/bash.
  
  – Stephen Harris
  5 mins ago
  

  
  
  
  

add a comment | 

1

The regex match operator =~ is not supported in the single square brackets. You need double square brackets for it to work.

[[ $name =~ ^.[0-9]$ ]]

Note that you don't need a regex, you can use a normal pattern:

[[ $name = *[0-9] ]]

or, if you need the name to contain something before the digit,

[[ $name = *?[0-9] ]]

share|improve this answer

answered 31 mins ago

chorobachoroba

29.3k44 gold badges5757 silver badges8181 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Oh good to know! But now it gives me the following exception: ./mh3.sh: 3: ./mh3.sh: [[: not found
  
  – Nicola Uetz
  26 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I found the second issue by myself... Appearently I have to use #!/bin/bash instead of #!/bin/sh... I just wonder why.
  
  – Nicola Uetz
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  /bin/sh is not the same as "bash". If you want to use bash semantics then use #!/bin/bash.
  
  – Stephen Harris
  5 mins ago
  

  
  
  
  

add a comment | 

The regex match operator =~ is not supported in the single square brackets. You need double square brackets for it to work.

[[ $name =~ ^.[0-9]$ ]]

Note that you don't need a regex, you can use a normal pattern:

[[ $name = *[0-9] ]]

or, if you need the name to contain something before the digit,

[[ $name = *?[0-9] ]]

share|improve this answer

answered 31 mins ago

chorobachoroba

29.3k44 gold badges5757 silver badges8181 bronze badges

[[ $name =~ ^.[0-9]$ ]]

[[ $name = *[0-9] ]]

[[ $name = *?[0-9] ]]

share|improve this answer

answered 31 mins ago

chorobachoroba

29.3k44 gold badges5757 silver badges8181 bronze badges

answered 31 mins ago

chorobachoroba

29.3k44 gold badges5757 silver badges8181 bronze badges

answered 31 mins ago

chorobachoroba

29.3k44 gold badges5757 silver badges8181 bronze badges

1

[: =~: binary operator expected

the error is [$name =~ ^.[0-9]$ ]
encolse it with [],

try,

#!/bin/sh

name=$(basename "$0" .sh)

[[ $name =~ ^.[0-9]$ ]] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $num

and it works.

share|improve this answer

answered 30 mins ago

Cosmo ArunCosmo Arun

4144 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I don't know which one of you were first. But either way it just prints me a new exception: ./mh3.sh: 3: ./mh3.sh: [[: not found
  
  – Nicola Uetz
  25 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I found the second issue by myself... Appearently I have to use #!/bin/bash instead of #!/bin/sh... I just wonder why.
  
  – Nicola Uetz
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i guess you /bin/bash is not really bash, try typing this and execute, /bin/bash -c "type [["
  
  – Cosmo Arun
  19 mins ago
  
  
  

  
  
  
  

add a comment | 

1

[: =~: binary operator expected

the error is [$name =~ ^.[0-9]$ ]
encolse it with [],

try,

#!/bin/sh

name=$(basename "$0" .sh)

[[ $name =~ ^.[0-9]$ ]] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $num

and it works.

share|improve this answer

answered 30 mins ago

Cosmo ArunCosmo Arun

4144 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I don't know which one of you were first. But either way it just prints me a new exception: ./mh3.sh: 3: ./mh3.sh: [[: not found
  
  – Nicola Uetz
  25 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  I found the second issue by myself... Appearently I have to use #!/bin/bash instead of #!/bin/sh... I just wonder why.
  
  – Nicola Uetz
  19 mins ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  i guess you /bin/bash is not really bash, try typing this and execute, /bin/bash -c "type [["
  
  – Cosmo Arun
  19 mins ago
  
  
  

  
  
  
  

add a comment | 

[: =~: binary operator expected

the error is [$name =~ ^.[0-9]$ ]
encolse it with [],

try,

#!/bin/sh

name=$(basename "$0" .sh)

[[ $name =~ ^.[0-9]$ ]] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $num

and it works.

share|improve this answer

answered 30 mins ago

Cosmo ArunCosmo Arun

4144 bronze badges

#!/bin/sh

name=$(basename "$0" .sh)

[[ $name =~ ^.[0-9]$ ]] && numb=$(echo $name | sed 's/[^0-9]*//g') || numb=1

echo $num

share|improve this answer

answered 30 mins ago

Cosmo ArunCosmo Arun

4144 bronze badges

answered 30 mins ago

Cosmo ArunCosmo Arun

4144 bronze badges

answered 30 mins ago

Cosmo ArunCosmo Arun

4144 bronze badges