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I am creating a shell script by using grep to track a log

grep log lines of a specific id requestScript to log temperatureWill zgrep recursively search zips embedded within zips?Add time from all log files using bashgrep script - output lines at the same time into echoParameter expansionExecute independent greps in a single shell scriptHow to run string with values as a command in bash?Error in grep command to exit from a Unix Script

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

Instead of printing out this,

============ Normal grep location of the files ============

ems_inet1/SystemOut1.log

ems_rpt1/SystemOut_19.09.09_23.00.00.log

ems_rpt1/SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1/SystemOut_19.05.12_23.00.00.log.gz

I want to print out this instead,

============ Normal grep location of the files ============

ems_inet1 - SystemOut1.log

ems_rpt1 - SystemOut_19.09.09_23.00.00.log

ems_rpt1 - SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1 - SystemOut_19.05.12_23.00.00.log.gz

I does not want to have a slash and i want to separate it by a " - " dash

here is the my code

echo "============ Normal grep location of the files ============"

grep -Erl "${input}" ems*/SystemOut*.log

#

echo "============ Compress grep location of the files ============"

zgrep -Erl "${input}" ems*/SystemOut*.log.gz

bash shell grep

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asked 1 hour ago

Jun HaoJun Hao

1

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Instead of printing out this,

============ Normal grep location of the files ============

ems_inet1/SystemOut1.log

ems_rpt1/SystemOut_19.09.09_23.00.00.log

ems_rpt1/SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1/SystemOut_19.05.12_23.00.00.log.gz

I want to print out this instead,

============ Normal grep location of the files ============

ems_inet1 - SystemOut1.log

ems_rpt1 - SystemOut_19.09.09_23.00.00.log

ems_rpt1 - SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1 - SystemOut_19.05.12_23.00.00.log.gz

I does not want to have a slash and i want to separate it by a " - " dash

here is the my code

echo "============ Normal grep location of the files ============"

grep -Erl "${input}" ems*/SystemOut*.log

#

echo "============ Compress grep location of the files ============"

zgrep -Erl "${input}" ems*/SystemOut*.log.gz

bash shell grep

share|improve this question

asked 1 hour ago

Jun HaoJun Hao

1

New contributor

Jun Hao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment
 | 

Instead of printing out this,

============ Normal grep location of the files ============

ems_inet1/SystemOut1.log

ems_rpt1/SystemOut_19.09.09_23.00.00.log

ems_rpt1/SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1/SystemOut_19.05.12_23.00.00.log.gz

I want to print out this instead,

============ Normal grep location of the files ============

ems_inet1 - SystemOut1.log

ems_rpt1 - SystemOut_19.09.09_23.00.00.log

ems_rpt1 - SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1 - SystemOut_19.05.12_23.00.00.log.gz

I does not want to have a slash and i want to separate it by a " - " dash

here is the my code

echo "============ Normal grep location of the files ============"

grep -Erl "${input}" ems*/SystemOut*.log

#

echo "============ Compress grep location of the files ============"

zgrep -Erl "${input}" ems*/SystemOut*.log.gz

bash shell grep

share|improve this question

asked 1 hour ago

Jun HaoJun Hao

1

New contributor

Jun Hao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

============ Normal grep location of the files ============

ems_inet1/SystemOut1.log

ems_rpt1/SystemOut_19.09.09_23.00.00.log

ems_rpt1/SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1/SystemOut_19.05.12_23.00.00.log.gz

============ Normal grep location of the files ============

ems_inet1 - SystemOut1.log

ems_rpt1 - SystemOut_19.09.09_23.00.00.log

ems_rpt1 - SystemOut_19.09.11_23.00.00.log

============ Compress grep location of the files ============

ems_rpt1 - SystemOut_19.05.12_23.00.00.log.gz

echo "============ Normal grep location of the files ============"

grep -Erl "${input}" ems*/SystemOut*.log

#

echo "============ Compress grep location of the files ============"

zgrep -Erl "${input}" ems*/SystemOut*.log.gz

share|improve this question

asked 1 hour ago

Jun HaoJun Hao

1

New contributor

Jun Hao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 1 hour ago

Jun HaoJun Hao

1

New contributor

Jun Hao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

Jun HaoJun Hao

1

New contributor

Jun Hao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

Jun HaoJun Hao

1

1 Answer
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grep -Erl "${input}" ems*/SystemOut*.log | sed 's#/# - #'

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answered 14 mins ago

WhiteWindWhiteWind

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0

grep -Erl "${input}" ems*/SystemOut*.log | sed 's#/# - #'

share|improve this answer

answered 14 mins ago

WhiteWindWhiteWind

22611 silver badge66 bronze badges

add a comment
 | 

0

grep -Erl "${input}" ems*/SystemOut*.log | sed 's#/# - #'

share|improve this answer

answered 14 mins ago

WhiteWindWhiteWind

22611 silver badge66 bronze badges

add a comment
 | 

grep -Erl "${input}" ems*/SystemOut*.log | sed 's#/# - #'

share|improve this answer

answered 14 mins ago

WhiteWindWhiteWind

22611 silver badge66 bronze badges

grep -Erl "${input}" ems*/SystemOut*.log | sed 's#/# - #'

share|improve this answer

answered 14 mins ago

WhiteWindWhiteWind

22611 silver badge66 bronze badges

answered 14 mins ago

WhiteWindWhiteWind

22611 silver badge66 bronze badges

answered 14 mins ago

WhiteWindWhiteWind

22611 silver badge66 bronze badges