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What is the missing number, can anyone solve this? My original puzzle


Find the missing number: A Pentagonal pattern puzzleMissing number in this sequence?Draw the item after decoding the instructionsPredict the missing number in this sequenceFind the missing piece to complete the patternWhat letters should be here?Reasoning - Find Missing NumberFill the grid (pattern)Can you find the next number in the following series?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







4












$begingroup$


What is the missing number that should be put in place of the question mark?



3,3=17



2,5=28



3,4=24



4,5=40



5,8=88



6,11=156



6,9=?










share|improve this question











$endgroup$





















    4












    $begingroup$


    What is the missing number that should be put in place of the question mark?



    3,3=17



    2,5=28



    3,4=24



    4,5=40



    5,8=88



    6,11=156



    6,9=?










    share|improve this question











    $endgroup$

















      4












      4








      4





      $begingroup$


      What is the missing number that should be put in place of the question mark?



      3,3=17



      2,5=28



      3,4=24



      4,5=40



      5,8=88



      6,11=156



      6,9=?










      share|improve this question











      $endgroup$




      What is the missing number that should be put in place of the question mark?



      3,3=17



      2,5=28



      3,4=24



      4,5=40



      5,8=88



      6,11=156



      6,9=?







      pattern






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited 4 hours ago







      Deepthinker101

















      asked 8 hours ago









      Deepthinker101Deepthinker101

      516 bronze badges




      516 bronze badges

























          2 Answers
          2






          active

          oldest

          votes


















          5














          $begingroup$

          If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is




          $Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.







          share|improve this answer











          $endgroup$















          • $begingroup$
            It doesnt work for 6,11 but fits all others. Maybe there was a typo?
            $endgroup$
            – Belhenix
            6 hours ago






          • 2




            $begingroup$
            It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
            $endgroup$
            – JS1
            6 hours ago










          • $begingroup$
            yes you were right there was an error in the puzzle
            $endgroup$
            – Deepthinker101
            4 hours ago



















          0














          $begingroup$

          Is this the answer?




          116




          The pattern/reasoning is




          (a^2 + b^2) -1 = answer







          share|improve this answer








          New contributor



          MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
          Check out our Code of Conduct.





          $endgroup$


















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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            5














            $begingroup$

            If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is




            $Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.







            share|improve this answer











            $endgroup$















            • $begingroup$
              It doesnt work for 6,11 but fits all others. Maybe there was a typo?
              $endgroup$
              – Belhenix
              6 hours ago






            • 2




              $begingroup$
              It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
              $endgroup$
              – JS1
              6 hours ago










            • $begingroup$
              yes you were right there was an error in the puzzle
              $endgroup$
              – Deepthinker101
              4 hours ago
















            5














            $begingroup$

            If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is




            $Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.







            share|improve this answer











            $endgroup$















            • $begingroup$
              It doesnt work for 6,11 but fits all others. Maybe there was a typo?
              $endgroup$
              – Belhenix
              6 hours ago






            • 2




              $begingroup$
              It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
              $endgroup$
              – JS1
              6 hours ago










            • $begingroup$
              yes you were right there was an error in the puzzle
              $endgroup$
              – Deepthinker101
              4 hours ago














            5














            5










            5







            $begingroup$

            If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is




            $Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.







            share|improve this answer











            $endgroup$



            If the three numbers in each "equation" are $a$, $b$, $c$ then one possible solution is




            $Min(a, 5)^2 + b^2 - 1 = c$, giving the answer $c = 105$ for the last.








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 6 hours ago

























            answered 6 hours ago









            JensJens

            2613 bronze badges




            2613 bronze badges















            • $begingroup$
              It doesnt work for 6,11 but fits all others. Maybe there was a typo?
              $endgroup$
              – Belhenix
              6 hours ago






            • 2




              $begingroup$
              It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
              $endgroup$
              – JS1
              6 hours ago










            • $begingroup$
              yes you were right there was an error in the puzzle
              $endgroup$
              – Deepthinker101
              4 hours ago


















            • $begingroup$
              It doesnt work for 6,11 but fits all others. Maybe there was a typo?
              $endgroup$
              – Belhenix
              6 hours ago






            • 2




              $begingroup$
              It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
              $endgroup$
              – JS1
              6 hours ago










            • $begingroup$
              yes you were right there was an error in the puzzle
              $endgroup$
              – Deepthinker101
              4 hours ago
















            $begingroup$
            It doesnt work for 6,11 but fits all others. Maybe there was a typo?
            $endgroup$
            – Belhenix
            6 hours ago




            $begingroup$
            It doesnt work for 6,11 but fits all others. Maybe there was a typo?
            $endgroup$
            – Belhenix
            6 hours ago




            2




            2




            $begingroup$
            It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
            $endgroup$
            – JS1
            6 hours ago




            $begingroup$
            It works. But I wonder if "6,11 = 146" was meant to be "6,11 = 156" which would remove the need for the whole "Min" part of it which seems a bit arbitrary?
            $endgroup$
            – JS1
            6 hours ago












            $begingroup$
            yes you were right there was an error in the puzzle
            $endgroup$
            – Deepthinker101
            4 hours ago




            $begingroup$
            yes you were right there was an error in the puzzle
            $endgroup$
            – Deepthinker101
            4 hours ago













            0














            $begingroup$

            Is this the answer?




            116




            The pattern/reasoning is




            (a^2 + b^2) -1 = answer







            share|improve this answer








            New contributor



            MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.





            $endgroup$




















              0














              $begingroup$

              Is this the answer?




              116




              The pattern/reasoning is




              (a^2 + b^2) -1 = answer







              share|improve this answer








              New contributor



              MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
              Check out our Code of Conduct.





              $endgroup$


















                0














                0










                0







                $begingroup$

                Is this the answer?




                116




                The pattern/reasoning is




                (a^2 + b^2) -1 = answer







                share|improve this answer








                New contributor



                MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.





                $endgroup$



                Is this the answer?




                116




                The pattern/reasoning is




                (a^2 + b^2) -1 = answer








                share|improve this answer








                New contributor



                MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.








                share|improve this answer



                share|improve this answer






                New contributor



                MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.








                answered 35 mins ago









                MobileGlickMobileGlick

                111 bronze badge




                111 bronze badge




                New contributor



                MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.




                New contributor




                MobileGlick is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.




































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