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Replacing with sed expression

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

-1

I'm trying to get a value such as

"909,999"

With this (the example is replacing it with nothing):

sed 's/["][0-9]+[,][0-9]+["]//g'

But it's not working.

sed regular-expression

share|improve this question

edited 55 mins ago

Rui F Ribeiro

42.8k1688149

asked 3 hours ago

Gabriel A. ZorrillaGabriel A. Zorrilla

249512

• 
  
  
  

  
  6
  

  
  
  
  
  
  

  
  
  What is the text that you are feeding into sed? Does it work if you run with sed -E (your expression looks like an extended regular expression, unless the pluses are supposed to be literal). Why do you use ["] instead of just "? The double quote is not special in a regular expression. Likewise for the comma. Also, you are replacing the matched thing with nothing.
  
  – Kusalananda♦
  3 hours ago
  
  
  

  
  
  
  

add a comment | 

-1

I'm trying to get a value such as

"909,999"

With this (the example is replacing it with nothing):

sed 's/["][0-9]+[,][0-9]+["]//g'

But it's not working.

sed regular-expression

share|improve this question

edited 55 mins ago

Rui F Ribeiro

42.8k1688149

asked 3 hours ago

Gabriel A. ZorrillaGabriel A. Zorrilla

249512

• 
  
  
  

  
  6
  

  
  
  
  
  
  

  
  
  What is the text that you are feeding into sed? Does it work if you run with sed -E (your expression looks like an extended regular expression, unless the pluses are supposed to be literal). Why do you use ["] instead of just "? The double quote is not special in a regular expression. Likewise for the comma. Also, you are replacing the matched thing with nothing.
  
  – Kusalananda♦
  3 hours ago
  
  
  

  
  
  
  

add a comment | 

I'm trying to get a value such as

"909,999"

With this (the example is replacing it with nothing):

sed 's/["][0-9]+[,][0-9]+["]//g'

But it's not working.

sed regular-expression

share|improve this question

edited 55 mins ago

Rui F Ribeiro

42.8k1688149

asked 3 hours ago

Gabriel A. ZorrillaGabriel A. Zorrilla

249512

"909,999"

sed 's/["][0-9]+[,][0-9]+["]//g'

share|improve this question

edited 55 mins ago

Rui F Ribeiro

42.8k1688149

asked 3 hours ago

Gabriel A. ZorrillaGabriel A. Zorrilla

249512

share|improve this question

edited 55 mins ago

Rui F Ribeiro

42.8k1688149

asked 3 hours ago

Gabriel A. ZorrillaGabriel A. Zorrilla

249512

edited 55 mins ago

Rui F Ribeiro

42.8k1688149

edited 55 mins ago

Rui F Ribeiro

42.8k1688149

asked 3 hours ago

Gabriel A. ZorrillaGabriel A. Zorrilla

249512

asked 3 hours ago

Gabriel A. ZorrillaGabriel A. Zorrilla

249512

1 Answer
1

active

oldest

votes

0

If you want to replace the pattern, you can use sed -E or escape the + characters as suggested by @Kusalananda:

$ printf '"123.456"n"909,999"n"100"n' | sed -E 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

or

$ printf '"123.456"n"909,999"n"100"n' | sed 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

Note that the g is not needed in this example as there is only one substitution per line.

If you want to delete the matching line(s), you could use d to delete the pattern space:

$ printf '"123.456"n"909,999"n"100"n' | sed '/"[0-9]+,[0-9]+"/d'

"123.456"

"100"

share|improve this answer

answered 2 hours ago

FreddyFreddy

4,1831420

add a comment | 

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0

If you want to replace the pattern, you can use sed -E or escape the + characters as suggested by @Kusalananda:

$ printf '"123.456"n"909,999"n"100"n' | sed -E 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

or

$ printf '"123.456"n"909,999"n"100"n' | sed 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

Note that the g is not needed in this example as there is only one substitution per line.

If you want to delete the matching line(s), you could use d to delete the pattern space:

$ printf '"123.456"n"909,999"n"100"n' | sed '/"[0-9]+,[0-9]+"/d'

"123.456"

"100"

share|improve this answer

answered 2 hours ago

FreddyFreddy

4,1831420

add a comment | 

0

If you want to replace the pattern, you can use sed -E or escape the + characters as suggested by @Kusalananda:

$ printf '"123.456"n"909,999"n"100"n' | sed -E 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

or

$ printf '"123.456"n"909,999"n"100"n' | sed 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

Note that the g is not needed in this example as there is only one substitution per line.

If you want to delete the matching line(s), you could use d to delete the pattern space:

$ printf '"123.456"n"909,999"n"100"n' | sed '/"[0-9]+,[0-9]+"/d'

"123.456"

"100"

share|improve this answer

answered 2 hours ago

FreddyFreddy

4,1831420

add a comment | 

If you want to replace the pattern, you can use sed -E or escape the + characters as suggested by @Kusalananda:

$ printf '"123.456"n"909,999"n"100"n' | sed -E 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

or

$ printf '"123.456"n"909,999"n"100"n' | sed 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

Note that the g is not needed in this example as there is only one substitution per line.

If you want to delete the matching line(s), you could use d to delete the pattern space:

$ printf '"123.456"n"909,999"n"100"n' | sed '/"[0-9]+,[0-9]+"/d'

"123.456"

"100"

share|improve this answer

answered 2 hours ago

FreddyFreddy

4,1831420

$ printf '"123.456"n"909,999"n"100"n' | sed -E 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

$ printf '"123.456"n"909,999"n"100"n' | sed 's/"[0-9]+,[0-9]+"//g'

"123.456"



"100"

$ printf '"123.456"n"909,999"n"100"n' | sed '/"[0-9]+,[0-9]+"/d'

"123.456"

"100"

share|improve this answer

answered 2 hours ago

FreddyFreddy

4,1831420

answered 2 hours ago

FreddyFreddy

4,1831420

answered 2 hours ago

FreddyFreddy

4,1831420