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insert multiple lines to script with sed

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

i'm trying to insert variables before specific line in my script. this is the code that i'm using:

var1=$(echo "database1=")

var2=$(echo "database2=")

var3=$(echo "database3=")



sed -i "/#variables/i 

$var1

$var2

$var3" /data1/create_database 

i expect that create_database be like this after i run above command:

database1=

database2=

database3=

#variables 

but i get this result:

database1= database2= database3=

#variables

tried few ways nothing worked. what should i do?

bash shell-script centos sed

share|improve this question

asked 31 mins ago

BlackCrystalBlackCrystal

39311 silver badge1414 bronze badges

add a comment | 

0

i'm trying to insert variables before specific line in my script. this is the code that i'm using:

var1=$(echo "database1=")

var2=$(echo "database2=")

var3=$(echo "database3=")



sed -i "/#variables/i 

$var1

$var2

$var3" /data1/create_database 

i expect that create_database be like this after i run above command:

database1=

database2=

database3=

#variables 

but i get this result:

database1= database2= database3=

#variables

tried few ways nothing worked. what should i do?

bash shell-script centos sed

share|improve this question

asked 31 mins ago

BlackCrystalBlackCrystal

39311 silver badge1414 bronze badges

add a comment | 

i'm trying to insert variables before specific line in my script. this is the code that i'm using:

var1=$(echo "database1=")

var2=$(echo "database2=")

var3=$(echo "database3=")



sed -i "/#variables/i 

$var1

$var2

$var3" /data1/create_database 

i expect that create_database be like this after i run above command:

database1=

database2=

database3=

#variables 

but i get this result:

database1= database2= database3=

#variables

tried few ways nothing worked. what should i do?

bash shell-script centos sed

share|improve this question

asked 31 mins ago

BlackCrystalBlackCrystal

39311 silver badge1414 bronze badges

var1=$(echo "database1=")

var2=$(echo "database2=")

var3=$(echo "database3=")



sed -i "/#variables/i 

$var1

$var2

$var3" /data1/create_database 

database1=

database2=

database3=

#variables 

database1= database2= database3=

#variables

share|improve this question

asked 31 mins ago

BlackCrystalBlackCrystal

39311 silver badge1414 bronze badges

share|improve this question

asked 31 mins ago

BlackCrystalBlackCrystal

39311 silver badge1414 bronze badges

asked 31 mins ago

BlackCrystalBlackCrystal

39311 silver badge1414 bronze badges

asked 31 mins ago

BlackCrystalBlackCrystal

39311 silver badge1414 bronze badges