Search and display row of third wordprint line only if number in third field is greater than XBash script to...
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Search and display row of third word
print line only if number in third field is greater than XBash script to rename files from a text file sourceExtract values from filename and add it into a text fileUsing AWK to Print Output of Combination of Unspecified Number of FilesShell script to move files if certain percentage of lines contain a certain stringExchanging One Column From File1 with files from File2How to select a row with latest date and timeCommand line method to find repeat-word typos, with line numbersHow to identify, sort descending and display the top 10 blocks of text, by categoryAssigning variables from text in filenameConvert password with special characters for use with expect script
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
How do I display rows that have value larger than 60 on the third word column?
Text file
7/12/2019 23:59:45 39.00
7/12/2019 23:59:50 60.38
7/12/2019 23:59:55 0.53
7/12/2019 00:00:00 2.10
7/12/2019 00:00:05 113.98
...
Display
7/12/2019 23:59:50 60.38
7/12/2019 00:00:05 113.98
Assuming the range value of 3rd word column is from 0.00 to 999.99, and number of characters in date & time is constant. I am new to this and any help would be greatly appreciated.
bash shell-script grep
New contributor
add a comment |
How do I display rows that have value larger than 60 on the third word column?
Text file
7/12/2019 23:59:45 39.00
7/12/2019 23:59:50 60.38
7/12/2019 23:59:55 0.53
7/12/2019 00:00:00 2.10
7/12/2019 00:00:05 113.98
...
Display
7/12/2019 23:59:50 60.38
7/12/2019 00:00:05 113.98
Assuming the range value of 3rd word column is from 0.00 to 999.99, and number of characters in date & time is constant. I am new to this and any help would be greatly appreciated.
bash shell-script grep
New contributor
1
Possible duplicate of print line only if number in third field is greater than X
– GypsyCosmonaut
37 mins ago
add a comment |
How do I display rows that have value larger than 60 on the third word column?
Text file
7/12/2019 23:59:45 39.00
7/12/2019 23:59:50 60.38
7/12/2019 23:59:55 0.53
7/12/2019 00:00:00 2.10
7/12/2019 00:00:05 113.98
...
Display
7/12/2019 23:59:50 60.38
7/12/2019 00:00:05 113.98
Assuming the range value of 3rd word column is from 0.00 to 999.99, and number of characters in date & time is constant. I am new to this and any help would be greatly appreciated.
bash shell-script grep
New contributor
How do I display rows that have value larger than 60 on the third word column?
Text file
7/12/2019 23:59:45 39.00
7/12/2019 23:59:50 60.38
7/12/2019 23:59:55 0.53
7/12/2019 00:00:00 2.10
7/12/2019 00:00:05 113.98
...
Display
7/12/2019 23:59:50 60.38
7/12/2019 00:00:05 113.98
Assuming the range value of 3rd word column is from 0.00 to 999.99, and number of characters in date & time is constant. I am new to this and any help would be greatly appreciated.
bash shell-script grep
bash shell-script grep
New contributor
New contributor
New contributor
asked 1 hour ago
machinecatmachinecat
11 bronze badge
11 bronze badge
New contributor
New contributor
1
Possible duplicate of print line only if number in third field is greater than X
– GypsyCosmonaut
37 mins ago
add a comment |
1
Possible duplicate of print line only if number in third field is greater than X
– GypsyCosmonaut
37 mins ago
1
1
Possible duplicate of print line only if number in third field is greater than X
– GypsyCosmonaut
37 mins ago
Possible duplicate of print line only if number in third field is greater than X
– GypsyCosmonaut
37 mins ago
add a comment |
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machinecat is a new contributor. Be nice, and check out our Code of Conduct.
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1
Possible duplicate of print line only if number in third field is greater than X
– GypsyCosmonaut
37 mins ago