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Converting Piecewise function to C code


Converting ConditionalExpression to PiecewiseTransform Piecewise[] into sum of indicatorsIs there a way to symbolically invert a piecewise functionUnderstanding a piecewise function generated by MathematicaPiecewise function and integral functionPiecewise function with integer conditionsPiecewise function extractionForce derivative of piecewise function at boundary points to be one-sided derivativePiecewise-constant function with infinitely many piecesPiecewise function






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}







5












$begingroup$


I'm trying to convert a function to C Code



f = D[Piecewise[{{x^2, -10 < x < 0}, {x, x > 0}}], x]



I decided to scan through conditions and corresponding output formulas, but the conditions are not expressed in proper form.



For example element f[[1]][[2, 2]] is



-10 < x < 0 // CForm



Inequality(-10,Less,x,Less,0)



Which looks nothing like a proper C Form. However inequality with one side:



f[[1]][[1, 2]] // CForm



Gives a proper string



x < -10



How do I get the proper form like x>-10&&x<0?










share|improve this question









$endgroup$





















    5












    $begingroup$


    I'm trying to convert a function to C Code



    f = D[Piecewise[{{x^2, -10 < x < 0}, {x, x > 0}}], x]



    I decided to scan through conditions and corresponding output formulas, but the conditions are not expressed in proper form.



    For example element f[[1]][[2, 2]] is



    -10 < x < 0 // CForm



    Inequality(-10,Less,x,Less,0)



    Which looks nothing like a proper C Form. However inequality with one side:



    f[[1]][[1, 2]] // CForm



    Gives a proper string



    x < -10



    How do I get the proper form like x>-10&&x<0?










    share|improve this question









    $endgroup$

















      5












      5








      5





      $begingroup$


      I'm trying to convert a function to C Code



      f = D[Piecewise[{{x^2, -10 < x < 0}, {x, x > 0}}], x]



      I decided to scan through conditions and corresponding output formulas, but the conditions are not expressed in proper form.



      For example element f[[1]][[2, 2]] is



      -10 < x < 0 // CForm



      Inequality(-10,Less,x,Less,0)



      Which looks nothing like a proper C Form. However inequality with one side:



      f[[1]][[1, 2]] // CForm



      Gives a proper string



      x < -10



      How do I get the proper form like x>-10&&x<0?










      share|improve this question









      $endgroup$




      I'm trying to convert a function to C Code



      f = D[Piecewise[{{x^2, -10 < x < 0}, {x, x > 0}}], x]



      I decided to scan through conditions and corresponding output formulas, but the conditions are not expressed in proper form.



      For example element f[[1]][[2, 2]] is



      -10 < x < 0 // CForm



      Inequality(-10,Less,x,Less,0)



      Which looks nothing like a proper C Form. However inequality with one side:



      f[[1]][[1, 2]] // CForm



      Gives a proper string



      x < -10



      How do I get the proper form like x>-10&&x<0?







      piecewise code-generation






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 13 hours ago









      Vsevolod A.Vsevolod A.

      5292 silver badges11 bronze badges




      5292 silver badges11 bronze badges

























          1 Answer
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          $begingroup$

          -10 < x < 0 // LogicalExpand // CForm

          (* -10 < x && x < 0 *)





          share|improve this answer









          $endgroup$


















            Your Answer








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            $begingroup$

            -10 < x < 0 // LogicalExpand // CForm

            (* -10 < x && x < 0 *)





            share|improve this answer









            $endgroup$




















              6












              $begingroup$

              -10 < x < 0 // LogicalExpand // CForm

              (* -10 < x && x < 0 *)





              share|improve this answer









              $endgroup$


















                6












                6








                6





                $begingroup$

                -10 < x < 0 // LogicalExpand // CForm

                (* -10 < x && x < 0 *)





                share|improve this answer









                $endgroup$



                -10 < x < 0 // LogicalExpand // CForm

                (* -10 < x && x < 0 *)






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 13 hours ago









                xzczdxzczd

                29k6 gold badges81 silver badges273 bronze badges




                29k6 gold badges81 silver badges273 bronze badges

































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