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Tee all SSH Session Output (by default)

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1

Currently I am trying to do something similar to what PuTTY does on Windows. I want to capture ssh session info. I want to be able to see stdout in a log file based on the hour, and separate the logs based on host. Now tee works well but you will always need to remember to type out tee and the date and directory. Thats just not really practical. Does someone know of a way to do what I am asking? I looked into adding the Local command option to my ssh configs but that as you would imagine it is not(cannot) be used to capture output as it appears to run the command after the ssh session starts.

ssh

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edited 2 days ago

Yilmaz

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1

Currently I am trying to do something similar to what PuTTY does on Windows. I want to capture ssh session info. I want to be able to see stdout in a log file based on the hour, and separate the logs based on host. Now tee works well but you will always need to remember to type out tee and the date and directory. Thats just not really practical. Does someone know of a way to do what I am asking? I looked into adding the Local command option to my ssh configs but that as you would imagine it is not(cannot) be used to capture output as it appears to run the command after the ssh session starts.

ssh

share|improve this question

edited 2 days ago

Yilmaz

13311 silver badge1111 bronze badges

asked 2 days ago

DaemonSlayer2048DaemonSlayer2048

611 bronze badge

New contributor

DaemonSlayer2048 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

add a comment | 

Currently I am trying to do something similar to what PuTTY does on Windows. I want to capture ssh session info. I want to be able to see stdout in a log file based on the hour, and separate the logs based on host. Now tee works well but you will always need to remember to type out tee and the date and directory. Thats just not really practical. Does someone know of a way to do what I am asking? I looked into adding the Local command option to my ssh configs but that as you would imagine it is not(cannot) be used to capture output as it appears to run the command after the ssh session starts.

ssh

share|improve this question

edited 2 days ago

Yilmaz

13311 silver badge1111 bronze badges

asked 2 days ago

DaemonSlayer2048DaemonSlayer2048

611 bronze badge

New contributor

DaemonSlayer2048 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 2 days ago

Yilmaz

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asked 2 days ago

DaemonSlayer2048DaemonSlayer2048

611 bronze badge

New contributor

DaemonSlayer2048 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 2 days ago

Yilmaz

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asked 2 days ago

DaemonSlayer2048DaemonSlayer2048

611 bronze badge

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edited 2 days ago

Yilmaz

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edited 2 days ago

Yilmaz

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asked 2 days ago

DaemonSlayer2048DaemonSlayer2048

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You can create a wrapper that you would use instead of ssh
command. It could be:

tssh() { ssh "$@" | tee "$(date +%m_%Y_%H:%M:%S)"; }

You can now use tssh with all options you would normally use with
ssh. SSH session will be logged to a file, for example
08_2019_16:43:50. See man date for explanation of + format
specifiers.

However, it's harder to embed host name in the name of the output log
file. You can use a wrapper like that but you need to remember to
always pass host as the first parameter:

tssh()

{

    if [ ! "$#" -eq 1 ]

    then

    printf "Error: Host missingn" >&2

    return 0

    fi



    ssh "$@" | tee "$1_$(date +%m_%Y_%H:%M:%S)"

}

For example:

   $ tssh localhost -vv

   $ logout

Output log file will contain hostname in its name, for example:

   localhost_08_2019_16:47:41

share|improve this answer

edited 2 days ago

answered 2 days ago

Arkadiusz DrabczykArkadiusz Drabczyk

8,83533 gold badges2020 silver badges3636 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thats pretty clean, I like it. I think I can ake it a bit further and maybe make a folder per host and place the log file in that folder. Just for some simple house keeping. A little mkdir -p would handle new hosts too. Thank you Arkadiusz, that should help me get started.
  
  – DaemonSlayer2048
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ok. You can now mark this question as answered to let other users know your problem is solved.
  
  – Arkadiusz Drabczyk
  yesterday
  

  
  
  
  

add a comment | 

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0

You can create a wrapper that you would use instead of ssh
command. It could be:

tssh() { ssh "$@" | tee "$(date +%m_%Y_%H:%M:%S)"; }

You can now use tssh with all options you would normally use with
ssh. SSH session will be logged to a file, for example
08_2019_16:43:50. See man date for explanation of + format
specifiers.

However, it's harder to embed host name in the name of the output log
file. You can use a wrapper like that but you need to remember to
always pass host as the first parameter:

tssh()

{

    if [ ! "$#" -eq 1 ]

    then

    printf "Error: Host missingn" >&2

    return 0

    fi



    ssh "$@" | tee "$1_$(date +%m_%Y_%H:%M:%S)"

}

For example:

   $ tssh localhost -vv

   $ logout

Output log file will contain hostname in its name, for example:

   localhost_08_2019_16:47:41

share|improve this answer

edited 2 days ago

answered 2 days ago

Arkadiusz DrabczykArkadiusz Drabczyk

8,83533 gold badges2020 silver badges3636 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thats pretty clean, I like it. I think I can ake it a bit further and maybe make a folder per host and place the log file in that folder. Just for some simple house keeping. A little mkdir -p would handle new hosts too. Thank you Arkadiusz, that should help me get started.
  
  – DaemonSlayer2048
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ok. You can now mark this question as answered to let other users know your problem is solved.
  
  – Arkadiusz Drabczyk
  yesterday
  

  
  
  
  

add a comment | 

0

You can create a wrapper that you would use instead of ssh
command. It could be:

tssh() { ssh "$@" | tee "$(date +%m_%Y_%H:%M:%S)"; }

You can now use tssh with all options you would normally use with
ssh. SSH session will be logged to a file, for example
08_2019_16:43:50. See man date for explanation of + format
specifiers.

However, it's harder to embed host name in the name of the output log
file. You can use a wrapper like that but you need to remember to
always pass host as the first parameter:

tssh()

{

    if [ ! "$#" -eq 1 ]

    then

    printf "Error: Host missingn" >&2

    return 0

    fi



    ssh "$@" | tee "$1_$(date +%m_%Y_%H:%M:%S)"

}

For example:

   $ tssh localhost -vv

   $ logout

Output log file will contain hostname in its name, for example:

   localhost_08_2019_16:47:41

share|improve this answer

edited 2 days ago

answered 2 days ago

Arkadiusz DrabczykArkadiusz Drabczyk

8,83533 gold badges2020 silver badges3636 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thats pretty clean, I like it. I think I can ake it a bit further and maybe make a folder per host and place the log file in that folder. Just for some simple house keeping. A little mkdir -p would handle new hosts too. Thank you Arkadiusz, that should help me get started.
  
  – DaemonSlayer2048
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Ok. You can now mark this question as answered to let other users know your problem is solved.
  
  – Arkadiusz Drabczyk
  yesterday
  

  
  
  
  

add a comment | 

You can create a wrapper that you would use instead of ssh
command. It could be:

tssh() { ssh "$@" | tee "$(date +%m_%Y_%H:%M:%S)"; }

You can now use tssh with all options you would normally use with
ssh. SSH session will be logged to a file, for example
08_2019_16:43:50. See man date for explanation of + format
specifiers.

However, it's harder to embed host name in the name of the output log
file. You can use a wrapper like that but you need to remember to
always pass host as the first parameter:

tssh()

{

    if [ ! "$#" -eq 1 ]

    then

    printf "Error: Host missingn" >&2

    return 0

    fi



    ssh "$@" | tee "$1_$(date +%m_%Y_%H:%M:%S)"

}

For example:

   $ tssh localhost -vv

   $ logout

Output log file will contain hostname in its name, for example:

   localhost_08_2019_16:47:41

share|improve this answer

edited 2 days ago

answered 2 days ago

Arkadiusz DrabczykArkadiusz Drabczyk

8,83533 gold badges2020 silver badges3636 bronze badges

tssh() { ssh "$@" | tee "$(date +%m_%Y_%H:%M:%S)"; }

tssh()

{

    if [ ! "$#" -eq 1 ]

    then

    printf "Error: Host missingn" >&2

    return 0

    fi



    ssh "$@" | tee "$1_$(date +%m_%Y_%H:%M:%S)"

}

   $ tssh localhost -vv

   $ logout

   localhost_08_2019_16:47:41

share|improve this answer

edited 2 days ago

answered 2 days ago

Arkadiusz DrabczykArkadiusz Drabczyk

8,83533 gold badges2020 silver badges3636 bronze badges

answered 2 days ago

Arkadiusz DrabczykArkadiusz Drabczyk

8,83533 gold badges2020 silver badges3636 bronze badges

answered 2 days ago

Arkadiusz DrabczykArkadiusz Drabczyk

8,83533 gold badges2020 silver badges3636 bronze badges