If an object moving in a circle experiences centripetal force, then doesn't it also experience centrifugal...

What did the controller say during my approach to land (audio clip)?

Applications of mathematics in clinical setting

Norwegian refuses EU delay (4.7 hours) compensation because it turned out there was nothing wrong with the aircraft

How do I clean sealant/silicon from a glass mirror?

How do I improve in sight reading?

Social leper versus social leopard

How do rulers get rich from war?

What do solvers like Gurobi and CPLEX do when they run into hard instances of MIP

What is a Heptagon Number™?

Do the villains know Batman has no superpowers?

Is It Possible to Have Different Sea Levels, Eventually Causing New Landforms to Appear?

What do these pins mean? Where should I plug them in?

Wired to Wireless Doorbell

Can multiple wall timers turn lights on or off when required?

Do liquid propellant rocket engines experience thrust oscillation?

Algorithm that spans orthogonal vectors: Python

How to deal with my team leader who keeps calling me about project updates even though I am on leave for personal reasons?

Did Apollo carry and use WD40?

What is the most damaging one handed melee weapon?

When does removing Goblin Warchief affect its cost reduction ability?

Is it really necessary to have 4 hours meeting in Sprint planning?

use of the disk command

Writing a letter of recommendation for a mediocre student

Can one guy with a duplicator initiate a nuclear apocalypse?



If an object moving in a circle experiences centripetal force, then doesn't it also experience centrifugal force, because of Newton's third law?


Why do we feel a force in circular motion?Does centrifugal force exist?Reference frame and centrifugal forceWhy does a string remain taut in circular motionWho plays the role of centrifugal force in an inertial frame of reference?Why is centrifugal force considered fictitious, when it's the one that feels real to us when we are moving in a circle?Why do we only feel the centrifugal force?How is centrifugal force derived?What happens to net acceleration in a non-inertial reference frame with cenripetal force?Why do we feel a force in circular motion?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







2












$begingroup$


When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.










share|cite|improve this question











$endgroup$





















    2












    $begingroup$


    When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.










    share|cite|improve this question











    $endgroup$

















      2












      2








      2





      $begingroup$


      When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.










      share|cite|improve this question











      $endgroup$




      When an object moves in a circle, there's an acceleration towards the center of the circle, the centripetal acceleration, which also gives us the centrifugal force (since $F = ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force). But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0. So my question is, what is actually this reaction force that's created by the centripetal force, and where does the centrifugal force come from? I do know that the centrifugal force can be viewed as an inertial force in a certian reference frame, but is there any way to describe it in another way? I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.







      newtonian-mechanics reference-frames centripetal-force centrifugal-force






      share|cite|improve this question















      share|cite|improve this question













      share|cite|improve this question




      share|cite|improve this question








      edited 53 mins ago









      knzhou

      55.9k14 gold badges159 silver badges269 bronze badges




      55.9k14 gold badges159 silver badges269 bronze badges










      asked 12 hours ago









      MelvinMelvin

      3982 silver badges11 bronze badges




      3982 silver badges11 bronze badges

























          5 Answers
          5






          active

          oldest

          votes


















          0














          $begingroup$

          Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.



          In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.



          Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.






          share|cite|improve this answer









          $endgroup$















          • $begingroup$
            oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
            $endgroup$
            – Melvin
            11 hours ago










          • $begingroup$
            Still Newton's laws, just more than you learn in an average highschool physics class.
            $endgroup$
            – Ryan_L
            11 hours ago










          • $begingroup$
            ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
            $endgroup$
            – Melvin
            11 hours ago






          • 1




            $begingroup$
            A rotating reference frame is NOT inertial because it is accelerating.
            $endgroup$
            – Ryan_L
            11 hours ago






          • 1




            $begingroup$
            In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
            $endgroup$
            – Ryan_L
            11 hours ago



















          5














          $begingroup$

          This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.






          share|cite|improve this answer









          $endgroup$























            1














            $begingroup$


            which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).




            You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.



            Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.




            But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.




            A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.



            A circular motion happens because




            • you swing something around in a string (the outwards force acts on your hand)

            • you turn with your car (the outwards force acts on the ground/asphault/planet)

            • a satellite is orbiting Earth (the outwards force acts on the Earth)

            • etc.


            There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.




            I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.




            You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.



            It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.



            In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.






            share|cite|improve this answer











            $endgroup$























              1














              $begingroup$

              Imagine an object connected by a string moving in a circular motion.




              what is actually this reaction force that's created by the centripetal force?




              The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.



              The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.




              where does the centrifugal force come from?




              The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.



              There is no Newton third law pair to the centrifugal force.






              share|cite|improve this answer









              $endgroup$























                0














                $begingroup$


                But this is obviously not true since that would mean that the net
                acceleration on the object moving in the circle would be 0.




                That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.



                Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.



                Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.



                Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.



                Hope this helps.






                share|cite|improve this answer









                $endgroup$


















                  Your Answer








                  StackExchange.ready(function() {
                  var channelOptions = {
                  tags: "".split(" "),
                  id: "151"
                  };
                  initTagRenderer("".split(" "), "".split(" "), channelOptions);

                  StackExchange.using("externalEditor", function() {
                  // Have to fire editor after snippets, if snippets enabled
                  if (StackExchange.settings.snippets.snippetsEnabled) {
                  StackExchange.using("snippets", function() {
                  createEditor();
                  });
                  }
                  else {
                  createEditor();
                  }
                  });

                  function createEditor() {
                  StackExchange.prepareEditor({
                  heartbeatType: 'answer',
                  autoActivateHeartbeat: false,
                  convertImagesToLinks: false,
                  noModals: true,
                  showLowRepImageUploadWarning: true,
                  reputationToPostImages: null,
                  bindNavPrevention: true,
                  postfix: "",
                  imageUploader: {
                  brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
                  contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/4.0/"u003ecc by-sa 4.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
                  allowUrls: true
                  },
                  noCode: true, onDemand: true,
                  discardSelector: ".discard-answer"
                  ,immediatelyShowMarkdownHelp:true
                  });


                  }
                  });















                  draft saved

                  draft discarded
















                  StackExchange.ready(
                  function () {
                  StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f503488%2fif-an-object-moving-in-a-circle-experiences-centripetal-force-then-doesnt-it-a%23new-answer', 'question_page');
                  }
                  );

                  Post as a guest















                  Required, but never shown

























                  5 Answers
                  5






                  active

                  oldest

                  votes








                  5 Answers
                  5






                  active

                  oldest

                  votes









                  active

                  oldest

                  votes






                  active

                  oldest

                  votes









                  0














                  $begingroup$

                  Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.



                  In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.



                  Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.






                  share|cite|improve this answer









                  $endgroup$















                  • $begingroup$
                    oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
                    $endgroup$
                    – Melvin
                    11 hours ago










                  • $begingroup$
                    Still Newton's laws, just more than you learn in an average highschool physics class.
                    $endgroup$
                    – Ryan_L
                    11 hours ago










                  • $begingroup$
                    ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
                    $endgroup$
                    – Melvin
                    11 hours ago






                  • 1




                    $begingroup$
                    A rotating reference frame is NOT inertial because it is accelerating.
                    $endgroup$
                    – Ryan_L
                    11 hours ago






                  • 1




                    $begingroup$
                    In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
                    $endgroup$
                    – Ryan_L
                    11 hours ago
















                  0














                  $begingroup$

                  Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.



                  In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.



                  Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.






                  share|cite|improve this answer









                  $endgroup$















                  • $begingroup$
                    oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
                    $endgroup$
                    – Melvin
                    11 hours ago










                  • $begingroup$
                    Still Newton's laws, just more than you learn in an average highschool physics class.
                    $endgroup$
                    – Ryan_L
                    11 hours ago










                  • $begingroup$
                    ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
                    $endgroup$
                    – Melvin
                    11 hours ago






                  • 1




                    $begingroup$
                    A rotating reference frame is NOT inertial because it is accelerating.
                    $endgroup$
                    – Ryan_L
                    11 hours ago






                  • 1




                    $begingroup$
                    In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
                    $endgroup$
                    – Ryan_L
                    11 hours ago














                  0














                  0










                  0







                  $begingroup$

                  Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.



                  In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.



                  Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.






                  share|cite|improve this answer









                  $endgroup$



                  Lets look at the Earth-moon system for an example. The centripetal force is Earth's gravity, keeping the Moon from flying away. But this works both ways, the Earth is pulled towards the Moon just as hard as the moon is pulled towards the Earth.



                  In your car example, the angle of the front tires means some percentage of the force of the car is spent on turning the car. The opposite force is spent trying to push the roadway in the opposite direction. It's the same as driving forwards really, except your force vector isn't parallel with your velocity vector.



                  Quick little aside: Newton's laws, the ones you learn in High-school anyways, only work in inertial reference frames. Centrifugal force does exist in a rotating reference frame.







                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered 11 hours ago









                  Ryan_LRyan_L

                  1945 bronze badges




                  1945 bronze badges















                  • $begingroup$
                    oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
                    $endgroup$
                    – Melvin
                    11 hours ago










                  • $begingroup$
                    Still Newton's laws, just more than you learn in an average highschool physics class.
                    $endgroup$
                    – Ryan_L
                    11 hours ago










                  • $begingroup$
                    ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
                    $endgroup$
                    – Melvin
                    11 hours ago






                  • 1




                    $begingroup$
                    A rotating reference frame is NOT inertial because it is accelerating.
                    $endgroup$
                    – Ryan_L
                    11 hours ago






                  • 1




                    $begingroup$
                    In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
                    $endgroup$
                    – Ryan_L
                    11 hours ago


















                  • $begingroup$
                    oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
                    $endgroup$
                    – Melvin
                    11 hours ago










                  • $begingroup$
                    Still Newton's laws, just more than you learn in an average highschool physics class.
                    $endgroup$
                    – Ryan_L
                    11 hours ago










                  • $begingroup$
                    ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
                    $endgroup$
                    – Melvin
                    11 hours ago






                  • 1




                    $begingroup$
                    A rotating reference frame is NOT inertial because it is accelerating.
                    $endgroup$
                    – Ryan_L
                    11 hours ago






                  • 1




                    $begingroup$
                    In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
                    $endgroup$
                    – Ryan_L
                    11 hours ago
















                  $begingroup$
                  oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
                  $endgroup$
                  – Melvin
                  11 hours ago




                  $begingroup$
                  oh, so what would you use instead of Newton's laws in a non-inertial frame of reference?
                  $endgroup$
                  – Melvin
                  11 hours ago












                  $begingroup$
                  Still Newton's laws, just more than you learn in an average highschool physics class.
                  $endgroup$
                  – Ryan_L
                  11 hours ago




                  $begingroup$
                  Still Newton's laws, just more than you learn in an average highschool physics class.
                  $endgroup$
                  – Ryan_L
                  11 hours ago












                  $begingroup$
                  ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
                  $endgroup$
                  – Melvin
                  11 hours ago




                  $begingroup$
                  ok, but an inertia frame of reference is that the frame of reference or coordinate system is not moving, right?
                  $endgroup$
                  – Melvin
                  11 hours ago




                  1




                  1




                  $begingroup$
                  A rotating reference frame is NOT inertial because it is accelerating.
                  $endgroup$
                  – Ryan_L
                  11 hours ago




                  $begingroup$
                  A rotating reference frame is NOT inertial because it is accelerating.
                  $endgroup$
                  – Ryan_L
                  11 hours ago




                  1




                  1




                  $begingroup$
                  In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
                  $endgroup$
                  – Ryan_L
                  11 hours ago




                  $begingroup$
                  In an inertial reference frame, an object is "pulled" away from the center of rotation by it's tangential inertia. In a rotating reference frame, the object has no inertia and is being pulled away by centrifugal force. Centripetal force exists in both reference frames. Whether centrifugal force or inertia is responsible depends on where the observer is.
                  $endgroup$
                  – Ryan_L
                  11 hours ago













                  5














                  $begingroup$

                  This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.






                  share|cite|improve this answer









                  $endgroup$




















                    5














                    $begingroup$

                    This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.






                    share|cite|improve this answer









                    $endgroup$


















                      5














                      5










                      5







                      $begingroup$

                      This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.






                      share|cite|improve this answer









                      $endgroup$



                      This is a common misinterpretation of Newton's third law, often stated as "to every action, there's an equal and opposite reaction." As you surmise, "action" and "reaction" refer to forces. However, they refer to forces acting on different things. Otherwise, nothing could accelerate, ever: if every force were always canceled out by an equal and opposite force, no force could ever do anything. Instead, forces occur between objects--say car and road, to take your example. The road exerts an inward force on the car, which, you're right, is the centripetal force. The equal and opposite force is exerted by the car, on the road. The two forces are acting on different things, so they do not cancel. This second force (the force exerted by the car on the road) is sometimes referred to as the "reactive centrifugal force," which is confusing, because it's different from the more common meaning of centrifugal force.







                      share|cite|improve this answer












                      share|cite|improve this answer



                      share|cite|improve this answer










                      answered 11 hours ago









                      Ben51Ben51

                      4,1888 silver badges30 bronze badges




                      4,1888 silver badges30 bronze badges


























                          1














                          $begingroup$


                          which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).




                          You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.



                          Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.




                          But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.




                          A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.



                          A circular motion happens because




                          • you swing something around in a string (the outwards force acts on your hand)

                          • you turn with your car (the outwards force acts on the ground/asphault/planet)

                          • a satellite is orbiting Earth (the outwards force acts on the Earth)

                          • etc.


                          There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.




                          I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.




                          You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.



                          It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.



                          In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.






                          share|cite|improve this answer











                          $endgroup$




















                            1














                            $begingroup$


                            which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).




                            You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.



                            Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.




                            But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.




                            A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.



                            A circular motion happens because




                            • you swing something around in a string (the outwards force acts on your hand)

                            • you turn with your car (the outwards force acts on the ground/asphault/planet)

                            • a satellite is orbiting Earth (the outwards force acts on the Earth)

                            • etc.


                            There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.




                            I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.




                            You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.



                            It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.



                            In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.






                            share|cite|improve this answer











                            $endgroup$


















                              1














                              1










                              1







                              $begingroup$


                              which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).




                              You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.



                              Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.




                              But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.




                              A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.



                              A circular motion happens because




                              • you swing something around in a string (the outwards force acts on your hand)

                              • you turn with your car (the outwards force acts on the ground/asphault/planet)

                              • a satellite is orbiting Earth (the outwards force acts on the Earth)

                              • etc.


                              There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.




                              I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.




                              You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.



                              It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.



                              In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.






                              share|cite|improve this answer











                              $endgroup$




                              which also gives us the centrifugal force (since $F=ma$ is the equation for a force and the acceleration of an object, therefore, is caused by a force).




                              You shouldn't call it "centrifugal force", but rather centripetal force. A centripetal force inwards causes the centripetal acceleration inwards. When people say "centrifugal force", they usually mean the feeling of being swung outwards, so this imaginary "centrifugal force" would be opposite to the actual centripetal force.



                              Note, though, that there is no such thing as a centrifugal force (it just feels like there is, but that's just an illusion); there is only a centripetal force.




                              But according to newton's third law, for every action, there is an equal and opposite reaction, which would mean that because of the centripetal force there's an equal force outwards, which I would say is the centrifugal force. But this is obviously not true since that would mean that the net acceleration on the object moving in the circle would be 0.




                              A very important note: The action/reaction forces in Newton's 3rd law do not act on the same object. Your object is pulled inwards and another object is simultaneously pulled outwards (the opposite way) with an equal force.



                              A circular motion happens because




                              • you swing something around in a string (the outwards force acts on your hand)

                              • you turn with your car (the outwards force acts on the ground/asphault/planet)

                              • a satellite is orbiting Earth (the outwards force acts on the Earth)

                              • etc.


                              There is always a source of the inwards force; there is always an interaction with something else, before a force can be present. That "something else", is what feels the reaction force via Newton's 3rd law.




                              I can imagine that the centripetal force may come from friction with the road if you're in a car and if the reaction force is the force into the ground it makes sense, except for the centrifugal force.




                              You are basically answering the question here yourself. The only last thing to point out is, as mentioned above, that there is no such thing as a "centrifugal force". That is a bad term, because it is not a force. It is a feeling. You are swung outwards against the window when a car turns, not because some "centrifugal force" pushes you outwards, but because the car is pulled inwards by the centripetal force.



                              It is not you being pushed outwards, it is the car moving away from the straight path your body has and thus pulling you along. But from the perspective of the car it looks like you are the one moving and not the car - that is just an illusion, a trick by our brains. The same trick happens when a guy on roller skates is standing in a bus. When the bus accelerates, it looks like he rolls backwards - but it is not him rolling backwards, it is the bus rolling forwards away from underneath his feet.



                              In summary: It is not you moving outwards, it is the car moving into you. Nothing pushes you outwards, and there is no motion/acceleration outwards which would be caused by any force. Only the feeling/illusion of it.







                              share|cite|improve this answer














                              share|cite|improve this answer



                              share|cite|improve this answer








                              edited 9 hours ago

























                              answered 9 hours ago









                              SteevenSteeven

                              29.9k8 gold badges72 silver badges121 bronze badges




                              29.9k8 gold badges72 silver badges121 bronze badges


























                                  1














                                  $begingroup$

                                  Imagine an object connected by a string moving in a circular motion.




                                  what is actually this reaction force that's created by the centripetal force?




                                  The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.



                                  The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.




                                  where does the centrifugal force come from?




                                  The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.



                                  There is no Newton third law pair to the centrifugal force.






                                  share|cite|improve this answer









                                  $endgroup$




















                                    1














                                    $begingroup$

                                    Imagine an object connected by a string moving in a circular motion.




                                    what is actually this reaction force that's created by the centripetal force?




                                    The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.



                                    The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.




                                    where does the centrifugal force come from?




                                    The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.



                                    There is no Newton third law pair to the centrifugal force.






                                    share|cite|improve this answer









                                    $endgroup$


















                                      1














                                      1










                                      1







                                      $begingroup$

                                      Imagine an object connected by a string moving in a circular motion.




                                      what is actually this reaction force that's created by the centripetal force?




                                      The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.



                                      The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.




                                      where does the centrifugal force come from?




                                      The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.



                                      There is no Newton third law pair to the centrifugal force.






                                      share|cite|improve this answer









                                      $endgroup$



                                      Imagine an object connected by a string moving in a circular motion.




                                      what is actually this reaction force that's created by the centripetal force?




                                      The force on a object, which causes the centripetal acceleration of an object, is due to another entity - the action, eg the force on the object due to the string.



                                      The Newton third law pair is the force on another entity due to the object - the reaction, eg the force on the string due to the object.




                                      where does the centrifugal force come from?




                                      The centrifugal force is not a real force, rather it is introduced for the convenience of being able to use Newton’s second law in the rotational (non-inertial) frame of the object.



                                      There is no Newton third law pair to the centrifugal force.







                                      share|cite|improve this answer












                                      share|cite|improve this answer



                                      share|cite|improve this answer










                                      answered 8 hours ago









                                      FarcherFarcher

                                      56.6k3 gold badges45 silver badges123 bronze badges




                                      56.6k3 gold badges45 silver badges123 bronze badges


























                                          0














                                          $begingroup$


                                          But this is obviously not true since that would mean that the net
                                          acceleration on the object moving in the circle would be 0.




                                          That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.



                                          Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.



                                          Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.



                                          Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.



                                          Hope this helps.






                                          share|cite|improve this answer









                                          $endgroup$




















                                            0














                                            $begingroup$


                                            But this is obviously not true since that would mean that the net
                                            acceleration on the object moving in the circle would be 0.




                                            That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.



                                            Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.



                                            Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.



                                            Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.



                                            Hope this helps.






                                            share|cite|improve this answer









                                            $endgroup$


















                                              0














                                              0










                                              0







                                              $begingroup$


                                              But this is obviously not true since that would mean that the net
                                              acceleration on the object moving in the circle would be 0.




                                              That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.



                                              Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.



                                              Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.



                                              Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.



                                              Hope this helps.






                                              share|cite|improve this answer









                                              $endgroup$




                                              But this is obviously not true since that would mean that the net
                                              acceleration on the object moving in the circle would be 0.




                                              That is not correct. An object is undergoing acceleration if either its speed changes, it changes direction, or both. According to Newtons first law, a body moving in a straight line at constant speed will continue to do so unless acted upon by a net external force. At any instant in time the velocity vector of a body undergoing circular motion is tangent to the circle. The inertia of the body resists a change in direction of that vector. The centrifugal force is a fictitious force that appears to be acting on the body in a non-inertial (accelerating) reference frame due to the inertia of the body. The centripetal force is the net force acting on the object forcing it to constantly change direction towards the center of the circular path.



                                              Perhaps it is easiest to see this if you consider a car driving in a straight line at constant speed. An object is on the passenger seat. The driver (in this case on the left side of the car) makes a sharp left turn, which is the beginning of circular motion. The object on the seat slides towards the passenger side door. The driver experiences the sensation of being pushed towards the passenger side. But neither the driver nor the object is subjected to any contact force pushing them in that direction. They are experiencing a centrifugal (fictitious) force.



                                              Now suppose instead that the object does not slide on the seat because of the static friction between the object and the seat. The static friction force is a centripetal force towards the center of the circular preventing the object from continuing in a straight line as viewed from an inertial reference frame (e.g., the road). This is the same thing that is happening in your example.



                                              Bottom line: The centripetal force keeps changing the direction of the object towards the center of the circular path. A change in direction of the motion of an object results in an acceleration even if the speed of the object is unchanged.



                                              Hope this helps.







                                              share|cite|improve this answer












                                              share|cite|improve this answer



                                              share|cite|improve this answer










                                              answered 10 hours ago









                                              Bob DBob D

                                              13.7k3 gold badges12 silver badges40 bronze badges




                                              13.7k3 gold badges12 silver badges40 bronze badges


































                                                  draft saved

                                                  draft discarded



















































                                                  Thanks for contributing an answer to Physics Stack Exchange!


                                                  • Please be sure to answer the question. Provide details and share your research!

                                                  But avoid



                                                  • Asking for help, clarification, or responding to other answers.

                                                  • Making statements based on opinion; back them up with references or personal experience.


                                                  Use MathJax to format equations. MathJax reference.


                                                  To learn more, see our tips on writing great answers.




                                                  draft saved


                                                  draft discarded














                                                  StackExchange.ready(
                                                  function () {
                                                  StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fphysics.stackexchange.com%2fquestions%2f503488%2fif-an-object-moving-in-a-circle-experiences-centripetal-force-then-doesnt-it-a%23new-answer', 'question_page');
                                                  }
                                                  );

                                                  Post as a guest















                                                  Required, but never shown





















































                                                  Required, but never shown














                                                  Required, but never shown












                                                  Required, but never shown







                                                  Required, but never shown

































                                                  Required, but never shown














                                                  Required, but never shown












                                                  Required, but never shown







                                                  Required, but never shown







                                                  Popular posts from this blog

                                                  Taj Mahal Inhaltsverzeichnis Aufbau | Geschichte | 350-Jahr-Feier | Heutige Bedeutung | Siehe auch |...

                                                  Baia Sprie Cuprins Etimologie | Istorie | Demografie | Politică și administrație | Arii naturale...

                                                  Nicolae Petrescu-Găină Cuprins Biografie | Opera | In memoriam | Varia | Controverse, incertitudini...