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Scripting School Assignment renaming files without extension .old to have .old

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

-1

The goal of the script is to change the file extension of files that do not have the .old extension to contain it after the script. Another goal is to do it with a for loop piped with grep -v to check match filenames not containing .old. From what I have read this is not proper technique, however this assignment is submitted virtually and will not be accepted unless the code is written in this way and returns the correct values.

The tricky part is that the files needing to be renamed are file1 file2.old file3old and file4.old. The only issue I'm having with different iterations of the code is that either it will completely ignore the file3old or it will rename it to file3old.old. Another problem is that I can iterate the code to change file3old to file3.old but the loop checks all of the files and displays an error saying that file2.old and file4.old already exist.

Here is the code I have so far:

!#/bin/bash

filename=$1

for filename in $(ls $1 | grep -v '.old$')

do

     mv $1/"$filename" $1/"file"$#".old"

done

grep scripting mv for loop-device

share|improve this question

edited 46 mins ago

Rui F Ribeiro

42.1k1484142

asked 5 hours ago

matthew2196matthew2196

1

New contributor

matthew2196 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why would you rename file3old to file3.old?
  
  – jsotola
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes it needs to be renamed to file3.old
  
  – matthew2196
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can you post the sample contents of the filename and expected output
  
  – Kamaraj
  1 hour ago
  

  
  
  
  

add a comment | 

-1

The goal of the script is to change the file extension of files that do not have the .old extension to contain it after the script. Another goal is to do it with a for loop piped with grep -v to check match filenames not containing .old. From what I have read this is not proper technique, however this assignment is submitted virtually and will not be accepted unless the code is written in this way and returns the correct values.

The tricky part is that the files needing to be renamed are file1 file2.old file3old and file4.old. The only issue I'm having with different iterations of the code is that either it will completely ignore the file3old or it will rename it to file3old.old. Another problem is that I can iterate the code to change file3old to file3.old but the loop checks all of the files and displays an error saying that file2.old and file4.old already exist.

Here is the code I have so far:

!#/bin/bash

filename=$1

for filename in $(ls $1 | grep -v '.old$')

do

     mv $1/"$filename" $1/"file"$#".old"

done

grep scripting mv for loop-device

share|improve this question

edited 46 mins ago

Rui F Ribeiro

42.1k1484142

asked 5 hours ago

matthew2196matthew2196

1

New contributor

matthew2196 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  why would you rename file3old to file3.old?
  
  – jsotola
  4 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes it needs to be renamed to file3.old
  
  – matthew2196
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  can you post the sample contents of the filename and expected output
  
  – Kamaraj
  1 hour ago
  

  
  
  
  

add a comment | 

The goal of the script is to change the file extension of files that do not have the .old extension to contain it after the script. Another goal is to do it with a for loop piped with grep -v to check match filenames not containing .old. From what I have read this is not proper technique, however this assignment is submitted virtually and will not be accepted unless the code is written in this way and returns the correct values.

The tricky part is that the files needing to be renamed are file1 file2.old file3old and file4.old. The only issue I'm having with different iterations of the code is that either it will completely ignore the file3old or it will rename it to file3old.old. Another problem is that I can iterate the code to change file3old to file3.old but the loop checks all of the files and displays an error saying that file2.old and file4.old already exist.

Here is the code I have so far:

!#/bin/bash

filename=$1

for filename in $(ls $1 | grep -v '.old$')

do

     mv $1/"$filename" $1/"file"$#".old"

done

grep scripting mv for loop-device

share|improve this question

edited 46 mins ago

Rui F Ribeiro

42.1k1484142

asked 5 hours ago

matthew2196matthew2196

1

New contributor

matthew2196 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

!#/bin/bash

filename=$1

for filename in $(ls $1 | grep -v '.old$')

do

     mv $1/"$filename" $1/"file"$#".old"

done

share|improve this question

edited 46 mins ago

Rui F Ribeiro

42.1k1484142

asked 5 hours ago

matthew2196matthew2196

1

New contributor

matthew2196 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 46 mins ago

Rui F Ribeiro

42.1k1484142

asked 5 hours ago

matthew2196matthew2196

1

New contributor

matthew2196 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 46 mins ago

Rui F Ribeiro

42.1k1484142

edited 46 mins ago

Rui F Ribeiro

42.1k1484142

asked 5 hours ago

matthew2196matthew2196

1

New contributor

matthew2196 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 5 hours ago

matthew2196matthew2196

1

1 Answer
1

active

oldest

votes

0

prename (check out the -n option);

rename 's/([0-9])[^0-9]*$/$1.old/g' *

for (will not work on large sets of files);

for F in * ; do

    N="$(echo "$F" | perl -pe 's/.?old$//g' ).old";

    if [ "$F" == "$N" ] ; then

        continue;

    fi

    mv "$F" "$N"

done

grep pipe (use -print0 if you want to deal with n in file names);

while read -r F ; do

    N="$(echo "$F" | perl -pe 's/old$//g' ).old";

    mv "$F" "$N"

done < <(find . -type f | grep -Pv ".old$")

share|improve this answer

edited 2 hours ago

answered 3 hours ago

user1133275user1133275

3,7741924

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Unfortunately this doesn't work with the online submission, it only wants code formatted with a while loop with ls piped into a grep -v argument.
  
  – matthew2196
  2 hours ago
  

  
  
  
  

add a comment | 

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0

prename (check out the -n option);

rename 's/([0-9])[^0-9]*$/$1.old/g' *

for (will not work on large sets of files);

for F in * ; do

    N="$(echo "$F" | perl -pe 's/.?old$//g' ).old";

    if [ "$F" == "$N" ] ; then

        continue;

    fi

    mv "$F" "$N"

done

grep pipe (use -print0 if you want to deal with n in file names);

while read -r F ; do

    N="$(echo "$F" | perl -pe 's/old$//g' ).old";

    mv "$F" "$N"

done < <(find . -type f | grep -Pv ".old$")

share|improve this answer

edited 2 hours ago

answered 3 hours ago

user1133275user1133275

3,7741924

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Unfortunately this doesn't work with the online submission, it only wants code formatted with a while loop with ls piped into a grep -v argument.
  
  – matthew2196
  2 hours ago
  

  
  
  
  

add a comment | 

0

prename (check out the -n option);

rename 's/([0-9])[^0-9]*$/$1.old/g' *

for (will not work on large sets of files);

for F in * ; do

    N="$(echo "$F" | perl -pe 's/.?old$//g' ).old";

    if [ "$F" == "$N" ] ; then

        continue;

    fi

    mv "$F" "$N"

done

grep pipe (use -print0 if you want to deal with n in file names);

while read -r F ; do

    N="$(echo "$F" | perl -pe 's/old$//g' ).old";

    mv "$F" "$N"

done < <(find . -type f | grep -Pv ".old$")

share|improve this answer

edited 2 hours ago

answered 3 hours ago

user1133275user1133275

3,7741924

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Unfortunately this doesn't work with the online submission, it only wants code formatted with a while loop with ls piped into a grep -v argument.
  
  – matthew2196
  2 hours ago
  

  
  
  
  

add a comment | 

prename (check out the -n option);

rename 's/([0-9])[^0-9]*$/$1.old/g' *

for (will not work on large sets of files);

for F in * ; do

    N="$(echo "$F" | perl -pe 's/.?old$//g' ).old";

    if [ "$F" == "$N" ] ; then

        continue;

    fi

    mv "$F" "$N"

done

grep pipe (use -print0 if you want to deal with n in file names);

while read -r F ; do

    N="$(echo "$F" | perl -pe 's/old$//g' ).old";

    mv "$F" "$N"

done < <(find . -type f | grep -Pv ".old$")

share|improve this answer

edited 2 hours ago

answered 3 hours ago

user1133275user1133275

3,7741924

rename 's/([0-9])[^0-9]*$/$1.old/g' *

for F in * ; do

    N="$(echo "$F" | perl -pe 's/.?old$//g' ).old";

    if [ "$F" == "$N" ] ; then

        continue;

    fi

    mv "$F" "$N"

done

while read -r F ; do

    N="$(echo "$F" | perl -pe 's/old$//g' ).old";

    mv "$F" "$N"

done < <(find . -type f | grep -Pv ".old$")

share|improve this answer

edited 2 hours ago

answered 3 hours ago

user1133275user1133275

3,7741924

answered 3 hours ago

user1133275user1133275

3,7741924

answered 3 hours ago

user1133275user1133275

3,7741924