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From the list of 3-tuples, how can I select tuples which contain one for more nines?

Find positions of items in a list based on neighboursHow to delete list items that contain a non-numeric PartSelect out of nested listSelecting list elements depending if they contain sub-list elementsEliminating items from list by ruleSelect UPPER CASE list items with spaces and punctuationSelect sublists that contain $n$ odd numbersDeleting items from a list when they meet certain criteriaSelect data from a listSelect items in a list that contain criteria #2

8

1

$begingroup$

From the list

Tuples[{1, 2, 3, 4, 9}, 3]

how can I select exactly those 3-tuples that contain one for more nines?

This is the result I want:

{{1, 1, 9}, {1, 2, 9}, {1, 3, 9}, {1, 4, 9}, {1, 9, 1}  ... {9, 9, 4}, {9, 9, 9}}

list-manipulation

share|improve this question

edited 1 hour ago

m_goldberg

90.4k873203

asked 22 hours ago

CarbajoCarbajo

703

New contributor

Carbajo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Help > Wolfram Docuentation, enter "select" (with or without quotes). First hit is to Select...
  $endgroup$
  – Daniel Lichtblau
  17 hours ago
  

  
  
  
  

add a comment | 

8

1

$begingroup$

From the list

Tuples[{1, 2, 3, 4, 9}, 3]

how can I select exactly those 3-tuples that contain one for more nines?

This is the result I want:

{{1, 1, 9}, {1, 2, 9}, {1, 3, 9}, {1, 4, 9}, {1, 9, 1}  ... {9, 9, 4}, {9, 9, 9}}

list-manipulation

share|improve this question

edited 1 hour ago

m_goldberg

90.4k873203

asked 22 hours ago

CarbajoCarbajo

703

New contributor

Carbajo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  $begingroup$
  Help > Wolfram Docuentation, enter "select" (with or without quotes). First hit is to Select...
  $endgroup$
  – Daniel Lichtblau
  17 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

From the list

Tuples[{1, 2, 3, 4, 9}, 3]

how can I select exactly those 3-tuples that contain one for more nines?

This is the result I want:

{{1, 1, 9}, {1, 2, 9}, {1, 3, 9}, {1, 4, 9}, {1, 9, 1}  ... {9, 9, 4}, {9, 9, 9}}

list-manipulation

share|improve this question

edited 1 hour ago

m_goldberg

90.4k873203

asked 22 hours ago

CarbajoCarbajo

703

New contributor

Carbajo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

$endgroup$

Tuples[{1, 2, 3, 4, 9}, 3]

share|improve this question

edited 1 hour ago

m_goldberg

90.4k873203

asked 22 hours ago

CarbajoCarbajo

703

New contributor

Carbajo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 1 hour ago

m_goldberg

90.4k873203

asked 22 hours ago

CarbajoCarbajo

703

New contributor

Carbajo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 1 hour ago

m_goldberg

90.4k873203

edited 1 hour ago

m_goldberg

90.4k873203

asked 22 hours ago

CarbajoCarbajo

703

New contributor

Carbajo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 22 hours ago

CarbajoCarbajo

703

4 Answers
4

active

oldest

votes

8

$begingroup$

list=Tuples[{1, 2, 3, 4, 9}, 3] ;

Cases[{___,9,___}]@list

{{1, 1, 9}, {1, 2, 9}, {1, 3, 9}, {1, 4, 9}, {1, 9, 1}, {1, 9, 2}, {1,
9, 3}, {1, 9, 4}, {1, 9, 9},

{2, 1, 9}, {2, 2, 9}, {2, 3, 9}, {2,
4, 9}, {2, 9, 1}, {2, 9, 2}, {2, 9, 3}, {2, 9, 4}, {2, 9, 9},

{3, 1,
9}, {3, 2, 9}, {3, 3, 9}, {3, 4, 9}, {3, 9, 1}, {3, 9, 2}, {3, 9,
3}, {3, 9, 4}, {3, 9, 9},

{4, 1, 9}, {4, 2, 9}, {4, 3, 9}, {4, 4, 9}, {4, 9, 1}, {4, 9, 2}, {4, 9, 3}, {4, 9, 4}, {4, 9, 9},

{9, 1, 1}, {9, 1, 2}, {9, 1, 3}, {9, 1, 4}, {9, 1, 9}, {9, 2, 1}, {9, 2,
2}, {9, 2, 3}, {9, 2, 4}, {9, 2, 9},

{9, 3, 1}, {9, 3, 2}, {9, 3,
3}, {9, 3, 4}, {9, 3, 9}, {9, 4, 1}, {9, 4, 2}, {9, 4, 3}, {9, 4,
4}, {9, 4, 9},

{9, 9, 1}, {9, 9, 2}, {9, 9, 3}, {9, 9, 4}, {9, 9,
9}}

share|improve this answer

answered 22 hours ago

kglrkglr

196k10216439

$endgroup$

add a comment | 

6

$begingroup$

try

Select[Tuples[{1,2,3,4,9},3],MemberQ@9]   

{{1,1,9},{1,2,9},{1,3,9},{1,4,9},{1,9,1},{1,9,2},{1,9,3},{1,9,4},{1,9,9},{2,1,9},{2,2,9},{2,3,9},{2,4,9},{2,9,1},{2,9,2},{2,9,3},{2,9,4},{2,9,9},{3,1,9},{3,2,9},{3,3,9},{3,4,9},{3,9,1},{3,9,2},{3,9,3},{3,9,4},{3,9,9},{4,1,9},{4,2,9},{4,3,9},{4,4,9},{4,9,1},{4,9,2},{4,9,3},{4,9,4},{4,9,9},{9,1,1},{9,1,2},{9,1,3},{9,1,4},{9,1,9},{9,2,1},{9,2,2},{9,2,3},{9,2,4},{9,2,9},{9,3,1},{9,3,2},{9,3,3},{9,3,4},{9,3,9},{9,4,1},{9,4,2},{9,4,3},{9,4,4},{9,4,9},{9,9,1},{9,9,2},{9,9,3},{9,9,4},{9,9,9}}

share|improve this answer

edited 19 hours ago

answered 22 hours ago

J42161217J42161217

5,400525

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This can even be shortened to Select[Tuples[{1,2,3,4,9},3], MemberQ[9]].
  $endgroup$
  – Henrik Schumacher
  19 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @HenrikSchumacher nice!
  $endgroup$
  – J42161217
  19 hours ago
  

  
  
  
  

add a comment | 

2

$begingroup$

L = Tuples[{1, 2, 3, 4, 9}, 3];



Pick[L, Total /@ UnitBox[L - 9], 1 | 2 | 3]

Or

Pick[L, Total /@ UnitStep[L - 8], 1 | 2 | 3]

share|improve this answer

answered 18 hours ago

Okkes DulgerciOkkes Dulgerci

5,6661920

$endgroup$

add a comment | 

1

$begingroup$

lst // Pick[#, Times@@@(# /. 9-> 0), 0] &

and

Pick[lst,Times@@@(lst/. 9-> 0),0]==

Pick[lst, MemberQ[#,9]&/@lst]

share|improve this answer

answered 21 hours ago

user1066user1066

6,27822033

$endgroup$

add a comment | 

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8

$begingroup$

list=Tuples[{1, 2, 3, 4, 9}, 3] ;

Cases[{___,9,___}]@list

{{1, 1, 9}, {1, 2, 9}, {1, 3, 9}, {1, 4, 9}, {1, 9, 1}, {1, 9, 2}, {1,
9, 3}, {1, 9, 4}, {1, 9, 9},

{2, 1, 9}, {2, 2, 9}, {2, 3, 9}, {2,
4, 9}, {2, 9, 1}, {2, 9, 2}, {2, 9, 3}, {2, 9, 4}, {2, 9, 9},

{3, 1,
9}, {3, 2, 9}, {3, 3, 9}, {3, 4, 9}, {3, 9, 1}, {3, 9, 2}, {3, 9,
3}, {3, 9, 4}, {3, 9, 9},

{4, 1, 9}, {4, 2, 9}, {4, 3, 9}, {4, 4, 9}, {4, 9, 1}, {4, 9, 2}, {4, 9, 3}, {4, 9, 4}, {4, 9, 9},

{9, 1, 1}, {9, 1, 2}, {9, 1, 3}, {9, 1, 4}, {9, 1, 9}, {9, 2, 1}, {9, 2,
2}, {9, 2, 3}, {9, 2, 4}, {9, 2, 9},

{9, 3, 1}, {9, 3, 2}, {9, 3,
3}, {9, 3, 4}, {9, 3, 9}, {9, 4, 1}, {9, 4, 2}, {9, 4, 3}, {9, 4,
4}, {9, 4, 9},

{9, 9, 1}, {9, 9, 2}, {9, 9, 3}, {9, 9, 4}, {9, 9,
9}}

share|improve this answer

answered 22 hours ago

kglrkglr

196k10216439

$endgroup$

add a comment | 

8

$begingroup$

list=Tuples[{1, 2, 3, 4, 9}, 3] ;

Cases[{___,9,___}]@list

{{1, 1, 9}, {1, 2, 9}, {1, 3, 9}, {1, 4, 9}, {1, 9, 1}, {1, 9, 2}, {1,
9, 3}, {1, 9, 4}, {1, 9, 9},

{2, 1, 9}, {2, 2, 9}, {2, 3, 9}, {2,
4, 9}, {2, 9, 1}, {2, 9, 2}, {2, 9, 3}, {2, 9, 4}, {2, 9, 9},

{3, 1,
9}, {3, 2, 9}, {3, 3, 9}, {3, 4, 9}, {3, 9, 1}, {3, 9, 2}, {3, 9,
3}, {3, 9, 4}, {3, 9, 9},

{4, 1, 9}, {4, 2, 9}, {4, 3, 9}, {4, 4, 9}, {4, 9, 1}, {4, 9, 2}, {4, 9, 3}, {4, 9, 4}, {4, 9, 9},

{9, 1, 1}, {9, 1, 2}, {9, 1, 3}, {9, 1, 4}, {9, 1, 9}, {9, 2, 1}, {9, 2,
2}, {9, 2, 3}, {9, 2, 4}, {9, 2, 9},

{9, 3, 1}, {9, 3, 2}, {9, 3,
3}, {9, 3, 4}, {9, 3, 9}, {9, 4, 1}, {9, 4, 2}, {9, 4, 3}, {9, 4,
4}, {9, 4, 9},

{9, 9, 1}, {9, 9, 2}, {9, 9, 3}, {9, 9, 4}, {9, 9,
9}}

share|improve this answer

answered 22 hours ago

kglrkglr

196k10216439

$endgroup$

add a comment | 

$begingroup$

list=Tuples[{1, 2, 3, 4, 9}, 3] ;

Cases[{___,9,___}]@list

{{1, 1, 9}, {1, 2, 9}, {1, 3, 9}, {1, 4, 9}, {1, 9, 1}, {1, 9, 2}, {1,
9, 3}, {1, 9, 4}, {1, 9, 9},

{2, 1, 9}, {2, 2, 9}, {2, 3, 9}, {2,
4, 9}, {2, 9, 1}, {2, 9, 2}, {2, 9, 3}, {2, 9, 4}, {2, 9, 9},

{3, 1,
9}, {3, 2, 9}, {3, 3, 9}, {3, 4, 9}, {3, 9, 1}, {3, 9, 2}, {3, 9,
3}, {3, 9, 4}, {3, 9, 9},

{4, 1, 9}, {4, 2, 9}, {4, 3, 9}, {4, 4, 9}, {4, 9, 1}, {4, 9, 2}, {4, 9, 3}, {4, 9, 4}, {4, 9, 9},

{9, 1, 1}, {9, 1, 2}, {9, 1, 3}, {9, 1, 4}, {9, 1, 9}, {9, 2, 1}, {9, 2,
2}, {9, 2, 3}, {9, 2, 4}, {9, 2, 9},

{9, 3, 1}, {9, 3, 2}, {9, 3,
3}, {9, 3, 4}, {9, 3, 9}, {9, 4, 1}, {9, 4, 2}, {9, 4, 3}, {9, 4,
4}, {9, 4, 9},

{9, 9, 1}, {9, 9, 2}, {9, 9, 3}, {9, 9, 4}, {9, 9,
9}}

share|improve this answer

answered 22 hours ago

kglrkglr

196k10216439

$endgroup$

list=Tuples[{1, 2, 3, 4, 9}, 3] ;

Cases[{___,9,___}]@list

share|improve this answer

answered 22 hours ago

kglrkglr

196k10216439

answered 22 hours ago

kglrkglr

196k10216439

answered 22 hours ago

kglrkglr

196k10216439

6

$begingroup$

try

Select[Tuples[{1,2,3,4,9},3],MemberQ@9]   

{{1,1,9},{1,2,9},{1,3,9},{1,4,9},{1,9,1},{1,9,2},{1,9,3},{1,9,4},{1,9,9},{2,1,9},{2,2,9},{2,3,9},{2,4,9},{2,9,1},{2,9,2},{2,9,3},{2,9,4},{2,9,9},{3,1,9},{3,2,9},{3,3,9},{3,4,9},{3,9,1},{3,9,2},{3,9,3},{3,9,4},{3,9,9},{4,1,9},{4,2,9},{4,3,9},{4,4,9},{4,9,1},{4,9,2},{4,9,3},{4,9,4},{4,9,9},{9,1,1},{9,1,2},{9,1,3},{9,1,4},{9,1,9},{9,2,1},{9,2,2},{9,2,3},{9,2,4},{9,2,9},{9,3,1},{9,3,2},{9,3,3},{9,3,4},{9,3,9},{9,4,1},{9,4,2},{9,4,3},{9,4,4},{9,4,9},{9,9,1},{9,9,2},{9,9,3},{9,9,4},{9,9,9}}

share|improve this answer

edited 19 hours ago

answered 22 hours ago

J42161217J42161217

5,400525

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This can even be shortened to Select[Tuples[{1,2,3,4,9},3], MemberQ[9]].
  $endgroup$
  – Henrik Schumacher
  19 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @HenrikSchumacher nice!
  $endgroup$
  – J42161217
  19 hours ago
  

  
  
  
  

add a comment | 

6

$begingroup$

try

Select[Tuples[{1,2,3,4,9},3],MemberQ@9]   

{{1,1,9},{1,2,9},{1,3,9},{1,4,9},{1,9,1},{1,9,2},{1,9,3},{1,9,4},{1,9,9},{2,1,9},{2,2,9},{2,3,9},{2,4,9},{2,9,1},{2,9,2},{2,9,3},{2,9,4},{2,9,9},{3,1,9},{3,2,9},{3,3,9},{3,4,9},{3,9,1},{3,9,2},{3,9,3},{3,9,4},{3,9,9},{4,1,9},{4,2,9},{4,3,9},{4,4,9},{4,9,1},{4,9,2},{4,9,3},{4,9,4},{4,9,9},{9,1,1},{9,1,2},{9,1,3},{9,1,4},{9,1,9},{9,2,1},{9,2,2},{9,2,3},{9,2,4},{9,2,9},{9,3,1},{9,3,2},{9,3,3},{9,3,4},{9,3,9},{9,4,1},{9,4,2},{9,4,3},{9,4,4},{9,4,9},{9,9,1},{9,9,2},{9,9,3},{9,9,4},{9,9,9}}

share|improve this answer

edited 19 hours ago

answered 22 hours ago

J42161217J42161217

5,400525

$endgroup$

• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  This can even be shortened to Select[Tuples[{1,2,3,4,9},3], MemberQ[9]].
  $endgroup$
  – Henrik Schumacher
  19 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  $begingroup$
  @HenrikSchumacher nice!
  $endgroup$
  – J42161217
  19 hours ago
  

  
  
  
  

add a comment | 

$begingroup$

try

Select[Tuples[{1,2,3,4,9},3],MemberQ@9]   

{{1,1,9},{1,2,9},{1,3,9},{1,4,9},{1,9,1},{1,9,2},{1,9,3},{1,9,4},{1,9,9},{2,1,9},{2,2,9},{2,3,9},{2,4,9},{2,9,1},{2,9,2},{2,9,3},{2,9,4},{2,9,9},{3,1,9},{3,2,9},{3,3,9},{3,4,9},{3,9,1},{3,9,2},{3,9,3},{3,9,4},{3,9,9},{4,1,9},{4,2,9},{4,3,9},{4,4,9},{4,9,1},{4,9,2},{4,9,3},{4,9,4},{4,9,9},{9,1,1},{9,1,2},{9,1,3},{9,1,4},{9,1,9},{9,2,1},{9,2,2},{9,2,3},{9,2,4},{9,2,9},{9,3,1},{9,3,2},{9,3,3},{9,3,4},{9,3,9},{9,4,1},{9,4,2},{9,4,3},{9,4,4},{9,4,9},{9,9,1},{9,9,2},{9,9,3},{9,9,4},{9,9,9}}

share|improve this answer

edited 19 hours ago

answered 22 hours ago

J42161217J42161217

5,400525

$endgroup$

Select[Tuples[{1,2,3,4,9},3],MemberQ@9]   

share|improve this answer

edited 19 hours ago

answered 22 hours ago

J42161217J42161217

5,400525

answered 22 hours ago

J42161217J42161217

5,400525

answered 22 hours ago

J42161217J42161217

5,400525

2

$begingroup$

L = Tuples[{1, 2, 3, 4, 9}, 3];



Pick[L, Total /@ UnitBox[L - 9], 1 | 2 | 3]

Or

Pick[L, Total /@ UnitStep[L - 8], 1 | 2 | 3]

share|improve this answer

answered 18 hours ago

Okkes DulgerciOkkes Dulgerci

5,6661920

$endgroup$

add a comment | 

2

$begingroup$

L = Tuples[{1, 2, 3, 4, 9}, 3];



Pick[L, Total /@ UnitBox[L - 9], 1 | 2 | 3]

Or

Pick[L, Total /@ UnitStep[L - 8], 1 | 2 | 3]

share|improve this answer

answered 18 hours ago

Okkes DulgerciOkkes Dulgerci

5,6661920

$endgroup$

add a comment | 

$begingroup$

L = Tuples[{1, 2, 3, 4, 9}, 3];



Pick[L, Total /@ UnitBox[L - 9], 1 | 2 | 3]

Or

Pick[L, Total /@ UnitStep[L - 8], 1 | 2 | 3]

share|improve this answer

answered 18 hours ago

Okkes DulgerciOkkes Dulgerci

5,6661920

$endgroup$

L = Tuples[{1, 2, 3, 4, 9}, 3];



Pick[L, Total /@ UnitBox[L - 9], 1 | 2 | 3]

Pick[L, Total /@ UnitStep[L - 8], 1 | 2 | 3]

share|improve this answer

answered 18 hours ago

Okkes DulgerciOkkes Dulgerci

5,6661920

answered 18 hours ago

Okkes DulgerciOkkes Dulgerci

5,6661920

answered 18 hours ago

Okkes DulgerciOkkes Dulgerci

5,6661920

1

$begingroup$

lst // Pick[#, Times@@@(# /. 9-> 0), 0] &

and

Pick[lst,Times@@@(lst/. 9-> 0),0]==

Pick[lst, MemberQ[#,9]&/@lst]

share|improve this answer

answered 21 hours ago

user1066user1066

6,27822033

$endgroup$

add a comment | 

1

$begingroup$

lst // Pick[#, Times@@@(# /. 9-> 0), 0] &

and

Pick[lst,Times@@@(lst/. 9-> 0),0]==

Pick[lst, MemberQ[#,9]&/@lst]

share|improve this answer

answered 21 hours ago

user1066user1066

6,27822033

$endgroup$

add a comment | 

$begingroup$

lst // Pick[#, Times@@@(# /. 9-> 0), 0] &

and

Pick[lst,Times@@@(lst/. 9-> 0),0]==

Pick[lst, MemberQ[#,9]&/@lst]

share|improve this answer

answered 21 hours ago

user1066user1066

6,27822033

$endgroup$

lst // Pick[#, Times@@@(# /. 9-> 0), 0] &

Pick[lst,Times@@@(lst/. 9-> 0),0]==

Pick[lst, MemberQ[#,9]&/@lst]

share|improve this answer

answered 21 hours ago

user1066user1066

6,27822033

answered 21 hours ago

user1066user1066

6,27822033

answered 21 hours ago

user1066user1066

6,27822033