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Why is regex [0-9]{0,2} not greedy in sed?

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

echo '123980925sriten34=ienat' | sed -e 's/^.*?([1-9][0-9]{0,2}+)([%=+-]).*/ 1 2 /'

is giving the result:

 4 =

i am expecting:

 34 =

what am i not understanding? thanks. :)

(oh and i even added the + and ? to make doubly sure, but afaik {0,2} should be greedy without the +...)

bash shell-script sed regular-expression

share|improve this question

asked 42 mins ago

runrinrunrin

1

New contributor

runrin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  perl -pe 's/^.*?([1-9][0-9]{0,2})([%=+-]).*/ $1 $2 /' is less annoying
  
  – user1133275
  35 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Isn't it more to do with the fact that the preceding .* is greedy?
  
  – steeldriver
  34 mins ago
  

  
  
  
  

add a comment | 

0

echo '123980925sriten34=ienat' | sed -e 's/^.*?([1-9][0-9]{0,2}+)([%=+-]).*/ 1 2 /'

is giving the result:

 4 =

i am expecting:

 34 =

what am i not understanding? thanks. :)

(oh and i even added the + and ? to make doubly sure, but afaik {0,2} should be greedy without the +...)

bash shell-script sed regular-expression

share|improve this question

asked 42 mins ago

runrinrunrin

1

New contributor

runrin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  perl -pe 's/^.*?([1-9][0-9]{0,2})([%=+-]).*/ $1 $2 /' is less annoying
  
  – user1133275
  35 mins ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Isn't it more to do with the fact that the preceding .* is greedy?
  
  – steeldriver
  34 mins ago
  

  
  
  
  

add a comment | 

echo '123980925sriten34=ienat' | sed -e 's/^.*?([1-9][0-9]{0,2}+)([%=+-]).*/ 1 2 /'

is giving the result:

 4 =

i am expecting:

 34 =

what am i not understanding? thanks. :)

(oh and i even added the + and ? to make doubly sure, but afaik {0,2} should be greedy without the +...)

bash shell-script sed regular-expression

share|improve this question

asked 42 mins ago

runrinrunrin

1

New contributor

runrin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

echo '123980925sriten34=ienat' | sed -e 's/^.*?([1-9][0-9]{0,2}+)([%=+-]).*/ 1 2 /'

 4 =

 34 =

share|improve this question

asked 42 mins ago

runrinrunrin

1

New contributor

runrin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 42 mins ago

runrinrunrin

1

New contributor

runrin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 42 mins ago

runrinrunrin

1

New contributor

runrin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 42 mins ago

runrinrunrin

1