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sed + delete all words that not contain string before the “dot string”

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1

I castrated the following sed syntax in order to remove from file any host
that not contain linux/LINUX

 sed -i '/linux|LINUX/!d' file

example

linux01.moon.com

solaris.moon.com

UNIX.foot.com

it will give

linux01.moon.com

but now we have other scenario that domains also include linux name as

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

it will give

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

instead of

    linux01.room_linux.com

    linux02.gt.com

    linux03.klist.com

so how to change my sed syntax in order to ignore the domain name if include linux or LINUX ?

linux sed regular-expression

share|improve this question

edited 16 hours ago

Jeff Schaller♦

48.8k1111 gold badges7272 silver badges162162 bronze badges

asked 16 hours ago

yaelyael

2,98188 gold badges4242 silver badges9292 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Are you sure you don't want to select hosts with linux in the name as soon as they also have linux in the domain? Sure?
  
  – Philippos
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I want to ignore what is in the domain , so if domain include any linux/LINUX then it will not remove it
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  But then why don't you want linux01.room_linux.com? It has linux in the host name.
  
  – Philippos
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  sorry I agree - you right
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  see my update , again I am very sorry about this - you right
  
  – yael
  16 hours ago
  

  
  
  
  

add a comment | 

1

I castrated the following sed syntax in order to remove from file any host
that not contain linux/LINUX

 sed -i '/linux|LINUX/!d' file

example

linux01.moon.com

solaris.moon.com

UNIX.foot.com

it will give

linux01.moon.com

but now we have other scenario that domains also include linux name as

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

it will give

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

instead of

    linux01.room_linux.com

    linux02.gt.com

    linux03.klist.com

so how to change my sed syntax in order to ignore the domain name if include linux or LINUX ?

linux sed regular-expression

share|improve this question

edited 16 hours ago

Jeff Schaller♦

48.8k1111 gold badges7272 silver badges162162 bronze badges

asked 16 hours ago

yaelyael

2,98188 gold badges4242 silver badges9292 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Are you sure you don't want to select hosts with linux in the name as soon as they also have linux in the domain? Sure?
  
  – Philippos
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I want to ignore what is in the domain , so if domain include any linux/LINUX then it will not remove it
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  But then why don't you want linux01.room_linux.com? It has linux in the host name.
  
  – Philippos
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  sorry I agree - you right
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  see my update , again I am very sorry about this - you right
  
  – yael
  16 hours ago
  

  
  
  
  

add a comment | 

I castrated the following sed syntax in order to remove from file any host
that not contain linux/LINUX

 sed -i '/linux|LINUX/!d' file

example

linux01.moon.com

solaris.moon.com

UNIX.foot.com

it will give

linux01.moon.com

but now we have other scenario that domains also include linux name as

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

it will give

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

instead of

    linux01.room_linux.com

    linux02.gt.com

    linux03.klist.com

so how to change my sed syntax in order to ignore the domain name if include linux or LINUX ?

linux sed regular-expression

share|improve this question

edited 16 hours ago

Jeff Schaller♦

48.8k1111 gold badges7272 silver badges162162 bronze badges

asked 16 hours ago

yaelyael

2,98188 gold badges4242 silver badges9292 bronze badges

 sed -i '/linux|LINUX/!d' file

linux01.moon.com

solaris.moon.com

UNIX.foot.com

linux01.moon.com

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

linux01.room_linux.com

linux02.gt.com

linux03.klist.com

sol.linux.com

    linux01.room_linux.com

    linux02.gt.com

    linux03.klist.com

share|improve this question

edited 16 hours ago

Jeff Schaller♦

48.8k1111 gold badges7272 silver badges162162 bronze badges

asked 16 hours ago

yaelyael

2,98188 gold badges4242 silver badges9292 bronze badges

share|improve this question

edited 16 hours ago

Jeff Schaller♦

48.8k1111 gold badges7272 silver badges162162 bronze badges

asked 16 hours ago

yaelyael

2,98188 gold badges4242 silver badges9292 bronze badges

edited 16 hours ago

Jeff Schaller♦

48.8k1111 gold badges7272 silver badges162162 bronze badges

edited 16 hours ago

Jeff Schaller♦

48.8k1111 gold badges7272 silver badges162162 bronze badges

asked 16 hours ago

yaelyael

2,98188 gold badges4242 silver badges9292 bronze badges

asked 16 hours ago

yaelyael

2,98188 gold badges4242 silver badges9292 bronze badges

2 Answers
2

active

oldest

votes

1

You need to fix the pattern to the start of the line with ^ and then allow only other characters than the dot ([^.]*) until your keyword is found:

sed -E '/^[^.]*(linux|LINUX)/!d'

Note that you need to add braces around your alternative patterns. I switched to extended regular expressions to make it more readable.

share|improve this answer

answered 16 hours ago

PhilipposPhilippos

7,13911 gold badge2020 silver badges5252 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  the problem is that - its removed all hosts in the file , so we get file empty
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  we have redhat 7.2 OS , on which OS you try it?
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This can't be an OS version issue. If your sed accepts option -E it will work. Or do your lines contain other stuff before the host?
  
  – Philippos
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I means I use the syntax - sed -iE '/^[^.]*(linux|LINUX)/!d' ( why -i flag cause remove of all hosts ? )
  
  – yael
  16 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Never concatenate options after -i! This will make the E an argument (backup file extension) for the -i option and lose the -E option! Use -i -E or -Ei.
  
  – Philippos
  16 hours ago
  

  
  
  
  

 | 
show 2 more comments

0

$ sed -e '

   h

   s/..*//;y/linux/LINUX/;/LINUX/!d

   g

' inp.file

This is the Posix sed approach you could take.

share|improve this answer

answered 53 mins ago

Rakesh SharmaRakesh Sharma

10111 silver badge22 bronze badges

add a comment | 

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1

You need to fix the pattern to the start of the line with ^ and then allow only other characters than the dot ([^.]*) until your keyword is found:

sed -E '/^[^.]*(linux|LINUX)/!d'

Note that you need to add braces around your alternative patterns. I switched to extended regular expressions to make it more readable.

share|improve this answer

answered 16 hours ago

PhilipposPhilippos

7,13911 gold badge2020 silver badges5252 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  the problem is that - its removed all hosts in the file , so we get file empty
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  we have redhat 7.2 OS , on which OS you try it?
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This can't be an OS version issue. If your sed accepts option -E it will work. Or do your lines contain other stuff before the host?
  
  – Philippos
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I means I use the syntax - sed -iE '/^[^.]*(linux|LINUX)/!d' ( why -i flag cause remove of all hosts ? )
  
  – yael
  16 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Never concatenate options after -i! This will make the E an argument (backup file extension) for the -i option and lose the -E option! Use -i -E or -Ei.
  
  – Philippos
  16 hours ago
  

  
  
  
  

 | 
show 2 more comments

1

You need to fix the pattern to the start of the line with ^ and then allow only other characters than the dot ([^.]*) until your keyword is found:

sed -E '/^[^.]*(linux|LINUX)/!d'

Note that you need to add braces around your alternative patterns. I switched to extended regular expressions to make it more readable.

share|improve this answer

answered 16 hours ago

PhilipposPhilippos

7,13911 gold badge2020 silver badges5252 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  the problem is that - its removed all hosts in the file , so we get file empty
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  we have redhat 7.2 OS , on which OS you try it?
  
  – yael
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This can't be an OS version issue. If your sed accepts option -E it will work. Or do your lines contain other stuff before the host?
  
  – Philippos
  16 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I means I use the syntax - sed -iE '/^[^.]*(linux|LINUX)/!d' ( why -i flag cause remove of all hosts ? )
  
  – yael
  16 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Never concatenate options after -i! This will make the E an argument (backup file extension) for the -i option and lose the -E option! Use -i -E or -Ei.
  
  – Philippos
  16 hours ago
  

  
  
  
  

 | 
show 2 more comments

You need to fix the pattern to the start of the line with ^ and then allow only other characters than the dot ([^.]*) until your keyword is found:

sed -E '/^[^.]*(linux|LINUX)/!d'

Note that you need to add braces around your alternative patterns. I switched to extended regular expressions to make it more readable.

share|improve this answer

answered 16 hours ago

PhilipposPhilippos

7,13911 gold badge2020 silver badges5252 bronze badges

sed -E '/^[^.]*(linux|LINUX)/!d'

share|improve this answer

answered 16 hours ago

PhilipposPhilippos

7,13911 gold badge2020 silver badges5252 bronze badges

answered 16 hours ago

PhilipposPhilippos

7,13911 gold badge2020 silver badges5252 bronze badges

answered 16 hours ago

PhilipposPhilippos

7,13911 gold badge2020 silver badges5252 bronze badges

0

$ sed -e '

   h

   s/..*//;y/linux/LINUX/;/LINUX/!d

   g

' inp.file

This is the Posix sed approach you could take.

share|improve this answer

answered 53 mins ago

Rakesh SharmaRakesh Sharma

10111 silver badge22 bronze badges

add a comment | 

0

$ sed -e '

   h

   s/..*//;y/linux/LINUX/;/LINUX/!d

   g

' inp.file

This is the Posix sed approach you could take.

share|improve this answer

answered 53 mins ago

Rakesh SharmaRakesh Sharma

10111 silver badge22 bronze badges

add a comment | 

$ sed -e '

   h

   s/..*//;y/linux/LINUX/;/LINUX/!d

   g

' inp.file

This is the Posix sed approach you could take.

share|improve this answer

answered 53 mins ago

Rakesh SharmaRakesh Sharma

10111 silver badge22 bronze badges

$ sed -e '

   h

   s/..*//;y/linux/LINUX/;/LINUX/!d

   g

' inp.file

share|improve this answer

answered 53 mins ago

Rakesh SharmaRakesh Sharma

10111 silver badge22 bronze badges

answered 53 mins ago

Rakesh SharmaRakesh Sharma

10111 silver badge22 bronze badges

answered 53 mins ago

Rakesh SharmaRakesh Sharma

10111 silver badge22 bronze badges