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Understanding find command

How to exclude a list of full directory paths in find command on SolarisLinux: Does find | xargs grep have limitations?find command with regex quantifier e.g. {1,2}-not -name does not work with findExclude directory in (native Solaris) find commandExclude from wildcard (*) using findFind command with multiple conditionsExclude a list of directories from unix find commandZipping all sub directories

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

-2

I am trying to find any file named lets say dork, but I want to exclude the files that are dork.zip. I'm also removing all the errors from permissions to directories.

So I have composed the command as such:

find /  -name "dork*" -and !"zip" 2>&1 | grep -iv "not" 

This did not work as I expected.

linux find

share|improve this question

edited 1 hour ago

Rui F Ribeiro

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asked 4 hours ago

ConfuseDConfuseD

111 bronze badge

New contributor

ConfuseD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Please explain how it is not working as you expect.
  
  – Jesse_b
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sure. I have strategically placed files dork0.log dork1.log and dork3.zip in different directories. Without the -and operator it finds all the files. but with the -and it bombs out.
  
  – ConfuseD
  3 hours ago
  
  
  

  
  
  
  

add a comment | 

-2

I am trying to find any file named lets say dork, but I want to exclude the files that are dork.zip. I'm also removing all the errors from permissions to directories.

So I have composed the command as such:

find /  -name "dork*" -and !"zip" 2>&1 | grep -iv "not" 

This did not work as I expected.

linux find

share|improve this question

edited 1 hour ago

Rui F Ribeiro

41.4k1616 gold badges9595 silver badges158158 bronze badges

asked 4 hours ago

ConfuseDConfuseD

111 bronze badge

New contributor

ConfuseD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  2
  

  
  
  
  
  
  

  
  
  Please explain how it is not working as you expect.
  
  – Jesse_b
  4 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Sure. I have strategically placed files dork0.log dork1.log and dork3.zip in different directories. Without the -and operator it finds all the files. but with the -and it bombs out.
  
  – ConfuseD
  3 hours ago
  
  
  

  
  
  
  

add a comment | 

I am trying to find any file named lets say dork, but I want to exclude the files that are dork.zip. I'm also removing all the errors from permissions to directories.

So I have composed the command as such:

find /  -name "dork*" -and !"zip" 2>&1 | grep -iv "not" 

This did not work as I expected.

linux find

share|improve this question

edited 1 hour ago

Rui F Ribeiro

41.4k1616 gold badges9595 silver badges158158 bronze badges

asked 4 hours ago

ConfuseDConfuseD

111 bronze badge

New contributor

ConfuseD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

find /  -name "dork*" -and !"zip" 2>&1 | grep -iv "not" 

share|improve this question

edited 1 hour ago

Rui F Ribeiro

41.4k1616 gold badges9595 silver badges158158 bronze badges

asked 4 hours ago

ConfuseDConfuseD

111 bronze badge

New contributor

ConfuseD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited 1 hour ago

Rui F Ribeiro

41.4k1616 gold badges9595 silver badges158158 bronze badges

asked 4 hours ago

ConfuseDConfuseD

111 bronze badge

New contributor

ConfuseD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

edited 1 hour ago

Rui F Ribeiro

41.4k1616 gold badges9595 silver badges158158 bronze badges

edited 1 hour ago

Rui F Ribeiro

41.4k1616 gold badges9595 silver badges158158 bronze badges

asked 4 hours ago

ConfuseDConfuseD

111 bronze badge

New contributor

ConfuseD is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 4 hours ago

ConfuseDConfuseD

111 bronze badge

2 Answers
2

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1

find / -name 'dork*' ! -name '*.zip'

You need to use two -name tests. One for matching dork* and one for matching *.zip. The second of these should be inverted (the !) so that the found names do not match it. There is always an implicit AND between the tests.

Making the implicit ANDs visible:

find / -name 'dork*' -a ! -name '*.zip'

Also using non-standard GNU syntax:

find / -name 'dork*' -and -not -name '*.zip'

To ignore errors produced by this, redirect the standard error stream to /dev/null with 2>/dev/null at the end.

With GNU find you could instead choose to not enter directories that are not readable:

find / ( -type d -not -readable -prune ) -or 

       ( -name 'dork*' -not -name '*.zip' -print )

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Kusalananda♦Kusalananda

162k1919 gold badges320320 silver badges507507 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I spent hours trying to figure this out and within 30 mins I have my answer. Thank you and to everyone for monitoring and helping us newbs out!
  
  – ConfuseD
  3 hours ago
  

  
  
  
  

add a comment | 

0

You're misunderstanding the syntax for the find expression. I think you're expecting the -name test to treat "dork*" -and !"zip" as the pattern it looks for, but -name expects a single pattern string, not some sort of expression. The way find is parsing it is: (the name matches dork*) and (!zip), with !zip being a separate subexpression from the -name primary. But !zip isn't a valid expression, so you get an error.

You want something more like (the name matches dork*) and (the name does not match *.zip).

find /  -name "dork*" -and '!' -name "*.zip"

(The -and is not really needed; I left it in here for clarity.)

I've made a few other corrections here: The pattern is *.zip, because zip would only match a file named exactly "zip". The ! is separated by a space so that find will recognize it as a separate element, rather than part of something else, and I single-quoted it so if you use the command interactively, the shell won't try to interpret it as a history reference.

BTW, what's going on with the 2>&1 andgrep -iv "not"`? If you're trying to filter error messages, and are using bash (not some other shell), you can use command substitution to avoid mixing the output and error streams:

find /  -name "dork*" -and '!' -name "*.zip" 2> >(grep -iv "not" >&2)

share|improve this answer

answered 3 hours ago

Gordon DavissonGordon Davisson

2,1251212 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I was just trying to filter out stderr for things like this /Users/xxxxxxxx/Library/Caches/CloudKit/com.apple.Safari: Operation not permitted find: /Users/xxxxxxxx/Library/Caches/com.apple.Safari: Operation not permitted find: /dev/fd/3: Not a directory find: /dev/fd/4: Not a directory
  
  – ConfuseD
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @ConfuseD Do you want to suppress errors entirely? If so, 2>/dev/null will do the trick.
  
  – Gordon Davisson
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes. Thanks, that works slick!!
  
  – ConfuseD
  2 hours ago
  

  
  
  
  

add a comment | 

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1

find / -name 'dork*' ! -name '*.zip'

You need to use two -name tests. One for matching dork* and one for matching *.zip. The second of these should be inverted (the !) so that the found names do not match it. There is always an implicit AND between the tests.

Making the implicit ANDs visible:

find / -name 'dork*' -a ! -name '*.zip'

Also using non-standard GNU syntax:

find / -name 'dork*' -and -not -name '*.zip'

To ignore errors produced by this, redirect the standard error stream to /dev/null with 2>/dev/null at the end.

With GNU find you could instead choose to not enter directories that are not readable:

find / ( -type d -not -readable -prune ) -or 

       ( -name 'dork*' -not -name '*.zip' -print )

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Kusalananda♦Kusalananda

162k1919 gold badges320320 silver badges507507 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I spent hours trying to figure this out and within 30 mins I have my answer. Thank you and to everyone for monitoring and helping us newbs out!
  
  – ConfuseD
  3 hours ago
  

  
  
  
  

add a comment | 

1

find / -name 'dork*' ! -name '*.zip'

You need to use two -name tests. One for matching dork* and one for matching *.zip. The second of these should be inverted (the !) so that the found names do not match it. There is always an implicit AND between the tests.

Making the implicit ANDs visible:

find / -name 'dork*' -a ! -name '*.zip'

Also using non-standard GNU syntax:

find / -name 'dork*' -and -not -name '*.zip'

To ignore errors produced by this, redirect the standard error stream to /dev/null with 2>/dev/null at the end.

With GNU find you could instead choose to not enter directories that are not readable:

find / ( -type d -not -readable -prune ) -or 

       ( -name 'dork*' -not -name '*.zip' -print )

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Kusalananda♦Kusalananda

162k1919 gold badges320320 silver badges507507 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! I spent hours trying to figure this out and within 30 mins I have my answer. Thank you and to everyone for monitoring and helping us newbs out!
  
  – ConfuseD
  3 hours ago
  

  
  
  
  

add a comment | 

find / -name 'dork*' ! -name '*.zip'

You need to use two -name tests. One for matching dork* and one for matching *.zip. The second of these should be inverted (the !) so that the found names do not match it. There is always an implicit AND between the tests.

Making the implicit ANDs visible:

find / -name 'dork*' -a ! -name '*.zip'

Also using non-standard GNU syntax:

find / -name 'dork*' -and -not -name '*.zip'

To ignore errors produced by this, redirect the standard error stream to /dev/null with 2>/dev/null at the end.

With GNU find you could instead choose to not enter directories that are not readable:

find / ( -type d -not -readable -prune ) -or 

       ( -name 'dork*' -not -name '*.zip' -print )

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Kusalananda♦Kusalananda

162k1919 gold badges320320 silver badges507507 bronze badges

find / -name 'dork*' ! -name '*.zip'

find / -name 'dork*' -a ! -name '*.zip'

find / -name 'dork*' -and -not -name '*.zip'

find / ( -type d -not -readable -prune ) -or 

       ( -name 'dork*' -not -name '*.zip' -print )

share|improve this answer

edited 3 hours ago

answered 3 hours ago

Kusalananda♦Kusalananda

162k1919 gold badges320320 silver badges507507 bronze badges

answered 3 hours ago

Kusalananda♦Kusalananda

162k1919 gold badges320320 silver badges507507 bronze badges

answered 3 hours ago

Kusalananda♦Kusalananda

162k1919 gold badges320320 silver badges507507 bronze badges

0

You're misunderstanding the syntax for the find expression. I think you're expecting the -name test to treat "dork*" -and !"zip" as the pattern it looks for, but -name expects a single pattern string, not some sort of expression. The way find is parsing it is: (the name matches dork*) and (!zip), with !zip being a separate subexpression from the -name primary. But !zip isn't a valid expression, so you get an error.

You want something more like (the name matches dork*) and (the name does not match *.zip).

find /  -name "dork*" -and '!' -name "*.zip"

(The -and is not really needed; I left it in here for clarity.)

I've made a few other corrections here: The pattern is *.zip, because zip would only match a file named exactly "zip". The ! is separated by a space so that find will recognize it as a separate element, rather than part of something else, and I single-quoted it so if you use the command interactively, the shell won't try to interpret it as a history reference.

BTW, what's going on with the 2>&1 andgrep -iv "not"`? If you're trying to filter error messages, and are using bash (not some other shell), you can use command substitution to avoid mixing the output and error streams:

find /  -name "dork*" -and '!' -name "*.zip" 2> >(grep -iv "not" >&2)

share|improve this answer

answered 3 hours ago

Gordon DavissonGordon Davisson

2,1251212 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I was just trying to filter out stderr for things like this /Users/xxxxxxxx/Library/Caches/CloudKit/com.apple.Safari: Operation not permitted find: /Users/xxxxxxxx/Library/Caches/com.apple.Safari: Operation not permitted find: /dev/fd/3: Not a directory find: /dev/fd/4: Not a directory
  
  – ConfuseD
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @ConfuseD Do you want to suppress errors entirely? If so, 2>/dev/null will do the trick.
  
  – Gordon Davisson
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes. Thanks, that works slick!!
  
  – ConfuseD
  2 hours ago
  

  
  
  
  

add a comment | 

0

You're misunderstanding the syntax for the find expression. I think you're expecting the -name test to treat "dork*" -and !"zip" as the pattern it looks for, but -name expects a single pattern string, not some sort of expression. The way find is parsing it is: (the name matches dork*) and (!zip), with !zip being a separate subexpression from the -name primary. But !zip isn't a valid expression, so you get an error.

You want something more like (the name matches dork*) and (the name does not match *.zip).

find /  -name "dork*" -and '!' -name "*.zip"

(The -and is not really needed; I left it in here for clarity.)

I've made a few other corrections here: The pattern is *.zip, because zip would only match a file named exactly "zip". The ! is separated by a space so that find will recognize it as a separate element, rather than part of something else, and I single-quoted it so if you use the command interactively, the shell won't try to interpret it as a history reference.

BTW, what's going on with the 2>&1 andgrep -iv "not"`? If you're trying to filter error messages, and are using bash (not some other shell), you can use command substitution to avoid mixing the output and error streams:

find /  -name "dork*" -and '!' -name "*.zip" 2> >(grep -iv "not" >&2)

share|improve this answer

answered 3 hours ago

Gordon DavissonGordon Davisson

2,1251212 silver badges1010 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I was just trying to filter out stderr for things like this /Users/xxxxxxxx/Library/Caches/CloudKit/com.apple.Safari: Operation not permitted find: /Users/xxxxxxxx/Library/Caches/com.apple.Safari: Operation not permitted find: /dev/fd/3: Not a directory find: /dev/fd/4: Not a directory
  
  – ConfuseD
  3 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @ConfuseD Do you want to suppress errors entirely? If so, 2>/dev/null will do the trick.
  
  – Gordon Davisson
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  yes. Thanks, that works slick!!
  
  – ConfuseD
  2 hours ago
  

  
  
  
  

add a comment | 

You're misunderstanding the syntax for the find expression. I think you're expecting the -name test to treat "dork*" -and !"zip" as the pattern it looks for, but -name expects a single pattern string, not some sort of expression. The way find is parsing it is: (the name matches dork*) and (!zip), with !zip being a separate subexpression from the -name primary. But !zip isn't a valid expression, so you get an error.

You want something more like (the name matches dork*) and (the name does not match *.zip).

find /  -name "dork*" -and '!' -name "*.zip"

(The -and is not really needed; I left it in here for clarity.)

I've made a few other corrections here: The pattern is *.zip, because zip would only match a file named exactly "zip". The ! is separated by a space so that find will recognize it as a separate element, rather than part of something else, and I single-quoted it so if you use the command interactively, the shell won't try to interpret it as a history reference.

BTW, what's going on with the 2>&1 andgrep -iv "not"`? If you're trying to filter error messages, and are using bash (not some other shell), you can use command substitution to avoid mixing the output and error streams:

find /  -name "dork*" -and '!' -name "*.zip" 2> >(grep -iv "not" >&2)

share|improve this answer

answered 3 hours ago

Gordon DavissonGordon Davisson

2,1251212 silver badges1010 bronze badges

find /  -name "dork*" -and '!' -name "*.zip"

find /  -name "dork*" -and '!' -name "*.zip" 2> >(grep -iv "not" >&2)

share|improve this answer

answered 3 hours ago

Gordon DavissonGordon Davisson

2,1251212 silver badges1010 bronze badges

answered 3 hours ago

Gordon DavissonGordon Davisson

2,1251212 silver badges1010 bronze badges

answered 3 hours ago

Gordon DavissonGordon Davisson

2,1251212 silver badges1010 bronze badges