Standard cumulative distribution function with optimization model variableIs my approach to my internship...
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Standard cumulative distribution function with optimization model variable
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We all know that expressions in mathematical optimization models can't contain "black boxes" around a decision variable since everything has to be written using mathematical expressions. For example, "yes/no" decisions can't be written as "if this then that" expressions in a model, but can be written using big-$M$ constraints with a binary variable.
What is the recommended way of writing a model that must compute the value of a cumulative distribution function from a decision variable?
For example, let's suppose we have a model with the following constraint:
$$Phi_X(x)le b$$
where $Phi_X(x)$ is the cumulative distribution function of the standard Normal random variable $Xsim N(mu = 0,sigma =1)$, $x$ is a decision variable, and $b$ is a parameter of the model.
Is there any way of converting this kind of constraint into a valid mathematical formulation? What is the approach suggested by experts? Does that kind of constraint absolutely require the use of special tools that can't be found in regular optimization solvers?
optimization modeling probability-distributions
$endgroup$
add a comment
|
$begingroup$
We all know that expressions in mathematical optimization models can't contain "black boxes" around a decision variable since everything has to be written using mathematical expressions. For example, "yes/no" decisions can't be written as "if this then that" expressions in a model, but can be written using big-$M$ constraints with a binary variable.
What is the recommended way of writing a model that must compute the value of a cumulative distribution function from a decision variable?
For example, let's suppose we have a model with the following constraint:
$$Phi_X(x)le b$$
where $Phi_X(x)$ is the cumulative distribution function of the standard Normal random variable $Xsim N(mu = 0,sigma =1)$, $x$ is a decision variable, and $b$ is a parameter of the model.
Is there any way of converting this kind of constraint into a valid mathematical formulation? What is the approach suggested by experts? Does that kind of constraint absolutely require the use of special tools that can't be found in regular optimization solvers?
optimization modeling probability-distributions
$endgroup$
$begingroup$
What do you men by "characteristic function of the standard deviation", care to explain?
$endgroup$
– kjetil b halvorsen
5 hours ago
$begingroup$
Is it me or English lacks this definition? "Loi normale centrée réduite" (in French) is what I mean. The "default" standard law, when the average is 0 and the standard error is 1.
$endgroup$
– V. Brunelle
4 hours ago
$begingroup$
I do not speak french, so let us wait for some french speaker to show up ...
$endgroup$
– kjetil b halvorsen
4 hours ago
$begingroup$
Is $Phi(x)$ the CDF? As in $Phi_X(x) = P(Xle x)$ for the standard Normal distribution for $Xsim N(mu =0, sigma = 1)$, $text{E}[X]=mu$ and $sqrt{text{Var}(X)}=sigma$?
$endgroup$
– SecretAgentMan
2 hours ago
$begingroup$
@SecretAgentMan Yes it is. µ=0 and sigma=1.
$endgroup$
– V. Brunelle
2 hours ago
add a comment
|
$begingroup$
We all know that expressions in mathematical optimization models can't contain "black boxes" around a decision variable since everything has to be written using mathematical expressions. For example, "yes/no" decisions can't be written as "if this then that" expressions in a model, but can be written using big-$M$ constraints with a binary variable.
What is the recommended way of writing a model that must compute the value of a cumulative distribution function from a decision variable?
For example, let's suppose we have a model with the following constraint:
$$Phi_X(x)le b$$
where $Phi_X(x)$ is the cumulative distribution function of the standard Normal random variable $Xsim N(mu = 0,sigma =1)$, $x$ is a decision variable, and $b$ is a parameter of the model.
Is there any way of converting this kind of constraint into a valid mathematical formulation? What is the approach suggested by experts? Does that kind of constraint absolutely require the use of special tools that can't be found in regular optimization solvers?
optimization modeling probability-distributions
$endgroup$
We all know that expressions in mathematical optimization models can't contain "black boxes" around a decision variable since everything has to be written using mathematical expressions. For example, "yes/no" decisions can't be written as "if this then that" expressions in a model, but can be written using big-$M$ constraints with a binary variable.
What is the recommended way of writing a model that must compute the value of a cumulative distribution function from a decision variable?
For example, let's suppose we have a model with the following constraint:
$$Phi_X(x)le b$$
where $Phi_X(x)$ is the cumulative distribution function of the standard Normal random variable $Xsim N(mu = 0,sigma =1)$, $x$ is a decision variable, and $b$ is a parameter of the model.
Is there any way of converting this kind of constraint into a valid mathematical formulation? What is the approach suggested by experts? Does that kind of constraint absolutely require the use of special tools that can't be found in regular optimization solvers?
optimization modeling probability-distributions
optimization modeling probability-distributions
edited 1 hour ago
SecretAgentMan
1,1122 silver badges23 bronze badges
1,1122 silver badges23 bronze badges
asked 8 hours ago
V. BrunelleV. Brunelle
1617 bronze badges
1617 bronze badges
$begingroup$
What do you men by "characteristic function of the standard deviation", care to explain?
$endgroup$
– kjetil b halvorsen
5 hours ago
$begingroup$
Is it me or English lacks this definition? "Loi normale centrée réduite" (in French) is what I mean. The "default" standard law, when the average is 0 and the standard error is 1.
$endgroup$
– V. Brunelle
4 hours ago
$begingroup$
I do not speak french, so let us wait for some french speaker to show up ...
$endgroup$
– kjetil b halvorsen
4 hours ago
$begingroup$
Is $Phi(x)$ the CDF? As in $Phi_X(x) = P(Xle x)$ for the standard Normal distribution for $Xsim N(mu =0, sigma = 1)$, $text{E}[X]=mu$ and $sqrt{text{Var}(X)}=sigma$?
$endgroup$
– SecretAgentMan
2 hours ago
$begingroup$
@SecretAgentMan Yes it is. µ=0 and sigma=1.
$endgroup$
– V. Brunelle
2 hours ago
add a comment
|
$begingroup$
What do you men by "characteristic function of the standard deviation", care to explain?
$endgroup$
– kjetil b halvorsen
5 hours ago
$begingroup$
Is it me or English lacks this definition? "Loi normale centrée réduite" (in French) is what I mean. The "default" standard law, when the average is 0 and the standard error is 1.
$endgroup$
– V. Brunelle
4 hours ago
$begingroup$
I do not speak french, so let us wait for some french speaker to show up ...
$endgroup$
– kjetil b halvorsen
4 hours ago
$begingroup$
Is $Phi(x)$ the CDF? As in $Phi_X(x) = P(Xle x)$ for the standard Normal distribution for $Xsim N(mu =0, sigma = 1)$, $text{E}[X]=mu$ and $sqrt{text{Var}(X)}=sigma$?
$endgroup$
– SecretAgentMan
2 hours ago
$begingroup$
@SecretAgentMan Yes it is. µ=0 and sigma=1.
$endgroup$
– V. Brunelle
2 hours ago
$begingroup$
What do you men by "characteristic function of the standard deviation", care to explain?
$endgroup$
– kjetil b halvorsen
5 hours ago
$begingroup$
What do you men by "characteristic function of the standard deviation", care to explain?
$endgroup$
– kjetil b halvorsen
5 hours ago
$begingroup$
Is it me or English lacks this definition? "Loi normale centrée réduite" (in French) is what I mean. The "default" standard law, when the average is 0 and the standard error is 1.
$endgroup$
– V. Brunelle
4 hours ago
$begingroup$
Is it me or English lacks this definition? "Loi normale centrée réduite" (in French) is what I mean. The "default" standard law, when the average is 0 and the standard error is 1.
$endgroup$
– V. Brunelle
4 hours ago
$begingroup$
I do not speak french, so let us wait for some french speaker to show up ...
$endgroup$
– kjetil b halvorsen
4 hours ago
$begingroup$
I do not speak french, so let us wait for some french speaker to show up ...
$endgroup$
– kjetil b halvorsen
4 hours ago
$begingroup$
Is $Phi(x)$ the CDF? As in $Phi_X(x) = P(Xle x)$ for the standard Normal distribution for $Xsim N(mu =0, sigma = 1)$, $text{E}[X]=mu$ and $sqrt{text{Var}(X)}=sigma$?
$endgroup$
– SecretAgentMan
2 hours ago
$begingroup$
Is $Phi(x)$ the CDF? As in $Phi_X(x) = P(Xle x)$ for the standard Normal distribution for $Xsim N(mu =0, sigma = 1)$, $text{E}[X]=mu$ and $sqrt{text{Var}(X)}=sigma$?
$endgroup$
– SecretAgentMan
2 hours ago
$begingroup$
@SecretAgentMan Yes it is. µ=0 and sigma=1.
$endgroup$
– V. Brunelle
2 hours ago
$begingroup$
@SecretAgentMan Yes it is. µ=0 and sigma=1.
$endgroup$
– V. Brunelle
2 hours ago
add a comment
|
1 Answer
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votes
$begingroup$
For strictly increasing CDFs, you can invert:
$$x le Phi^{-1}(b)$$
$endgroup$
add a comment
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$begingroup$
For strictly increasing CDFs, you can invert:
$$x le Phi^{-1}(b)$$
$endgroup$
add a comment
|
$begingroup$
For strictly increasing CDFs, you can invert:
$$x le Phi^{-1}(b)$$
$endgroup$
add a comment
|
$begingroup$
For strictly increasing CDFs, you can invert:
$$x le Phi^{-1}(b)$$
$endgroup$
For strictly increasing CDFs, you can invert:
$$x le Phi^{-1}(b)$$
answered 8 hours ago
Rob PrattRob Pratt
1,4671 silver badge12 bronze badges
1,4671 silver badge12 bronze badges
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$begingroup$
What do you men by "characteristic function of the standard deviation", care to explain?
$endgroup$
– kjetil b halvorsen
5 hours ago
$begingroup$
Is it me or English lacks this definition? "Loi normale centrée réduite" (in French) is what I mean. The "default" standard law, when the average is 0 and the standard error is 1.
$endgroup$
– V. Brunelle
4 hours ago
$begingroup$
I do not speak french, so let us wait for some french speaker to show up ...
$endgroup$
– kjetil b halvorsen
4 hours ago
$begingroup$
Is $Phi(x)$ the CDF? As in $Phi_X(x) = P(Xle x)$ for the standard Normal distribution for $Xsim N(mu =0, sigma = 1)$, $text{E}[X]=mu$ and $sqrt{text{Var}(X)}=sigma$?
$endgroup$
– SecretAgentMan
2 hours ago
$begingroup$
@SecretAgentMan Yes it is. µ=0 and sigma=1.
$endgroup$
– V. Brunelle
2 hours ago