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Copying lines from one file to another using sed and shell variables

Using sed to replace a string with special chars with another string with special charactersCutting logs (and not copying) from a log file between two time stampsShell Script to insert lines in between filePerforming Prime Key function using 'Sed' in BashDelete all lines that contain duplicate lettersFind words after specific symbol on linesed - calling a variable from a file with multilineReplace a pattern in File1 and replace it with corresponding matched pattern + column in File2Fixing a .csv file where some rows have missing columnsHow can I use sed to insert some text after a multiline match?

.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}

0

I've been trying to figure out how to copy lines from one file to the end of another using sed with some shell variables.

sed -n "$var1,$var2'p'" file1.txt > file2.txt

I've tried that and many close variations but no cigar. Could someone please enlighten me about the correct syntax? Thanks.

shell sed variable-substitution

share|improve this question

asked 1 hour ago

CrushCrush

1

New contributor

Crush is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What error do you receive when running the sed command in your question? Please edit your post and provide that information.
  
  – Peschke
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  > file2.txt will overwrite file2: if you want to append the copied lines to the end of the file, use >> file2.txt
  
  – steeldriver
  1 hour ago
  

  
  
  
  

add a comment | 

0

I've been trying to figure out how to copy lines from one file to the end of another using sed with some shell variables.

sed -n "$var1,$var2'p'" file1.txt > file2.txt

I've tried that and many close variations but no cigar. Could someone please enlighten me about the correct syntax? Thanks.

shell sed variable-substitution

share|improve this question

asked 1 hour ago

CrushCrush

1

New contributor

Crush is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  What error do you receive when running the sed command in your question? Please edit your post and provide that information.
  
  – Peschke
  1 hour ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  > file2.txt will overwrite file2: if you want to append the copied lines to the end of the file, use >> file2.txt
  
  – steeldriver
  1 hour ago
  

  
  
  
  

add a comment | 

I've been trying to figure out how to copy lines from one file to the end of another using sed with some shell variables.

sed -n "$var1,$var2'p'" file1.txt > file2.txt

I've tried that and many close variations but no cigar. Could someone please enlighten me about the correct syntax? Thanks.

shell sed variable-substitution

share|improve this question

asked 1 hour ago

CrushCrush

1

New contributor

Crush is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 1 hour ago

CrushCrush

1

New contributor

Crush is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

asked 1 hour ago

CrushCrush

1

New contributor

Crush is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

CrushCrush

1

New contributor

Crush is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 1 hour ago

CrushCrush

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2 Answers
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Use curly braces around your variable names:

sed -n "${var1},${var2}p" file1.txt > file2.txt

The braces around the first variable are not needed, but better make it consistent.

share|improve this answer

answered 1 hour ago

FreddyFreddy

6,84811 gold badge66 silver badges2424 bronze badges

add a comment | 

0

Freddy's answer works, but lacks an explanation. The sed format that you are probably aiming for is something like

sed -n 4,6p file1.txt

Where I've used 4 and 6 as dummy numbers.

Let's examine your expression, using these dummy numbers again, and the echo command.

$ var1=4

$ var2=6

$ echo "$var1,$var2'p'"

4,6'p'

Because you enclosed the 's in the "s, they are interpreted literally, and you are literal 's to the sed command. Hence, when you try to run your command:

$ sed -n "$var1,$var2'p'" file1.txt

sed: -e expression #1, char 4: unknown command: `''

Solution

You can remove the 's from your expression, but this would change the variable name to $var2p instead. Hence, as Freddy suggests, you can use {…} to explicitly enclose the variable name(s). i.e.

sed -n "${var1},${var2}p" file1.txt

You can test if this works by putting an echo before the command. An alternative format is

sed -n "$var1,$var2"p file1.txt

but IMO it's less readable.

Finally, as steeldriver points out, if you are aiming to append to the file, use >> file2.txt instead of > file2.txt.

share

answered 8 mins ago

SparhawkSparhawk

11.3k88 gold badges5353 silver badges107107 bronze badges

add a comment | 

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0

Use curly braces around your variable names:

sed -n "${var1},${var2}p" file1.txt > file2.txt

The braces around the first variable are not needed, but better make it consistent.

share|improve this answer

answered 1 hour ago

FreddyFreddy

6,84811 gold badge66 silver badges2424 bronze badges

add a comment | 

0

Use curly braces around your variable names:

sed -n "${var1},${var2}p" file1.txt > file2.txt

The braces around the first variable are not needed, but better make it consistent.

share|improve this answer

answered 1 hour ago

FreddyFreddy

6,84811 gold badge66 silver badges2424 bronze badges

add a comment | 

Use curly braces around your variable names:

sed -n "${var1},${var2}p" file1.txt > file2.txt

The braces around the first variable are not needed, but better make it consistent.

share|improve this answer

answered 1 hour ago

FreddyFreddy

6,84811 gold badge66 silver badges2424 bronze badges

sed -n "${var1},${var2}p" file1.txt > file2.txt

share|improve this answer

answered 1 hour ago

FreddyFreddy

6,84811 gold badge66 silver badges2424 bronze badges

answered 1 hour ago

FreddyFreddy

6,84811 gold badge66 silver badges2424 bronze badges

answered 1 hour ago

FreddyFreddy

6,84811 gold badge66 silver badges2424 bronze badges

0

Freddy's answer works, but lacks an explanation. The sed format that you are probably aiming for is something like

sed -n 4,6p file1.txt

Where I've used 4 and 6 as dummy numbers.

Let's examine your expression, using these dummy numbers again, and the echo command.

$ var1=4

$ var2=6

$ echo "$var1,$var2'p'"

4,6'p'

Because you enclosed the 's in the "s, they are interpreted literally, and you are literal 's to the sed command. Hence, when you try to run your command:

$ sed -n "$var1,$var2'p'" file1.txt

sed: -e expression #1, char 4: unknown command: `''

Solution

You can remove the 's from your expression, but this would change the variable name to $var2p instead. Hence, as Freddy suggests, you can use {…} to explicitly enclose the variable name(s). i.e.

sed -n "${var1},${var2}p" file1.txt

You can test if this works by putting an echo before the command. An alternative format is

sed -n "$var1,$var2"p file1.txt

but IMO it's less readable.

Finally, as steeldriver points out, if you are aiming to append to the file, use >> file2.txt instead of > file2.txt.

share

answered 8 mins ago

SparhawkSparhawk

11.3k88 gold badges5353 silver badges107107 bronze badges

add a comment | 

0

Freddy's answer works, but lacks an explanation. The sed format that you are probably aiming for is something like

sed -n 4,6p file1.txt

Where I've used 4 and 6 as dummy numbers.

Let's examine your expression, using these dummy numbers again, and the echo command.

$ var1=4

$ var2=6

$ echo "$var1,$var2'p'"

4,6'p'

Because you enclosed the 's in the "s, they are interpreted literally, and you are literal 's to the sed command. Hence, when you try to run your command:

$ sed -n "$var1,$var2'p'" file1.txt

sed: -e expression #1, char 4: unknown command: `''

Solution

You can remove the 's from your expression, but this would change the variable name to $var2p instead. Hence, as Freddy suggests, you can use {…} to explicitly enclose the variable name(s). i.e.

sed -n "${var1},${var2}p" file1.txt

You can test if this works by putting an echo before the command. An alternative format is

sed -n "$var1,$var2"p file1.txt

but IMO it's less readable.

Finally, as steeldriver points out, if you are aiming to append to the file, use >> file2.txt instead of > file2.txt.

share

answered 8 mins ago

SparhawkSparhawk

11.3k88 gold badges5353 silver badges107107 bronze badges

add a comment | 

Freddy's answer works, but lacks an explanation. The sed format that you are probably aiming for is something like

sed -n 4,6p file1.txt

Where I've used 4 and 6 as dummy numbers.

Let's examine your expression, using these dummy numbers again, and the echo command.

$ var1=4

$ var2=6

$ echo "$var1,$var2'p'"

4,6'p'

Because you enclosed the 's in the "s, they are interpreted literally, and you are literal 's to the sed command. Hence, when you try to run your command:

$ sed -n "$var1,$var2'p'" file1.txt

sed: -e expression #1, char 4: unknown command: `''

Solution

You can remove the 's from your expression, but this would change the variable name to $var2p instead. Hence, as Freddy suggests, you can use {…} to explicitly enclose the variable name(s). i.e.

sed -n "${var1},${var2}p" file1.txt

You can test if this works by putting an echo before the command. An alternative format is

sed -n "$var1,$var2"p file1.txt

but IMO it's less readable.

Finally, as steeldriver points out, if you are aiming to append to the file, use >> file2.txt instead of > file2.txt.

share

answered 8 mins ago

SparhawkSparhawk

11.3k88 gold badges5353 silver badges107107 bronze badges

sed -n 4,6p file1.txt

$ var1=4

$ var2=6

$ echo "$var1,$var2'p'"

4,6'p'

$ sed -n "$var1,$var2'p'" file1.txt

sed: -e expression #1, char 4: unknown command: `''

sed -n "${var1},${var2}p" file1.txt

sed -n "$var1,$var2"p file1.txt

share

answered 8 mins ago

SparhawkSparhawk

11.3k88 gold badges5353 silver badges107107 bronze badges

answered 8 mins ago

SparhawkSparhawk

11.3k88 gold badges5353 silver badges107107 bronze badges

answered 8 mins ago

SparhawkSparhawk

11.3k88 gold badges5353 silver badges107107 bronze badges