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$begingroup$
We have a voltage source of 5 V and a resistor of 100 Ω is connected to it. The other end of the resistor is connected nowhere. To simplify terminal “A” of resistor is connected to 5 V & Terminal “B” is not connected anywhere. So my questions are
- What will be the Voltage value at the Terminal “B” of the resistor? and How?
- Will there be a decrease in Voltage from 5 V or it remains 5 V on the both terminals of the resistor?
- What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V - Voltage at terminal “B” ?
voltage resistors
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
We have a voltage source of 5 V and a resistor of 100 Ω is connected to it. The other end of the resistor is connected nowhere. To simplify terminal “A” of resistor is connected to 5 V & Terminal “B” is not connected anywhere. So my questions are
- What will be the Voltage value at the Terminal “B” of the resistor? and How?
- Will there be a decrease in Voltage from 5 V or it remains 5 V on the both terminals of the resistor?
- What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V - Voltage at terminal “B” ?
voltage resistors
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
2
$begingroup$
The third question is the one you need to answer first.
$endgroup$
– Marcus Müller
20 hours ago
$begingroup$
What is the other point in the circuit to which you are making your voltage measurements? The other side of the 5V supply? Terminal "A"?
$endgroup$
– Peter Jennings
20 hours ago
$begingroup$
Try drawing the circuit. There is a great tool on this site. It may clarify the situation for you.
$endgroup$
– Warren Hill
20 hours ago
add a comment |
$begingroup$
We have a voltage source of 5 V and a resistor of 100 Ω is connected to it. The other end of the resistor is connected nowhere. To simplify terminal “A” of resistor is connected to 5 V & Terminal “B” is not connected anywhere. So my questions are
- What will be the Voltage value at the Terminal “B” of the resistor? and How?
- Will there be a decrease in Voltage from 5 V or it remains 5 V on the both terminals of the resistor?
- What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V - Voltage at terminal “B” ?
voltage resistors
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
We have a voltage source of 5 V and a resistor of 100 Ω is connected to it. The other end of the resistor is connected nowhere. To simplify terminal “A” of resistor is connected to 5 V & Terminal “B” is not connected anywhere. So my questions are
- What will be the Voltage value at the Terminal “B” of the resistor? and How?
- Will there be a decrease in Voltage from 5 V or it remains 5 V on the both terminals of the resistor?
- What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V - Voltage at terminal “B” ?
voltage resistors
voltage resistors
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
edited 20 hours ago
Marcus Müller
39.9k3 gold badges66 silver badges108 bronze badges
39.9k3 gold badges66 silver badges108 bronze badges
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
asked 21 hours ago
Mark SEBASTIENMark SEBASTIEN
241 bronze badge
241 bronze badge
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Mark SEBASTIEN is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
2
$begingroup$
The third question is the one you need to answer first.
$endgroup$
– Marcus Müller
20 hours ago
$begingroup$
What is the other point in the circuit to which you are making your voltage measurements? The other side of the 5V supply? Terminal "A"?
$endgroup$
– Peter Jennings
20 hours ago
$begingroup$
Try drawing the circuit. There is a great tool on this site. It may clarify the situation for you.
$endgroup$
– Warren Hill
20 hours ago
add a comment |
2
$begingroup$
The third question is the one you need to answer first.
$endgroup$
– Marcus Müller
20 hours ago
$begingroup$
What is the other point in the circuit to which you are making your voltage measurements? The other side of the 5V supply? Terminal "A"?
$endgroup$
– Peter Jennings
20 hours ago
$begingroup$
Try drawing the circuit. There is a great tool on this site. It may clarify the situation for you.
$endgroup$
– Warren Hill
20 hours ago
2
2
$begingroup$
The third question is the one you need to answer first.
$endgroup$
– Marcus Müller
20 hours ago
$begingroup$
The third question is the one you need to answer first.
$endgroup$
– Marcus Müller
20 hours ago
$begingroup$
What is the other point in the circuit to which you are making your voltage measurements? The other side of the 5V supply? Terminal "A"?
$endgroup$
– Peter Jennings
20 hours ago
$begingroup$
What is the other point in the circuit to which you are making your voltage measurements? The other side of the 5V supply? Terminal "A"?
$endgroup$
– Peter Jennings
20 hours ago
$begingroup$
Try drawing the circuit. There is a great tool on this site. It may clarify the situation for you.
$endgroup$
– Warren Hill
20 hours ago
$begingroup$
Try drawing the circuit. There is a great tool on this site. It may clarify the situation for you.
$endgroup$
– Warren Hill
20 hours ago
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Let's turn your word picture into a real picture so we can see what's happening
simulate this circuit – Schematic created using CircuitLab
Voltage is always measured between two points, so when we quote the voltage of a single point, it's always understood that we are measuring the difference to some reference point.
I've taken the liberty of adding the ground or '0V' symbol. You've told us that 'A' is at 5v, which implies that you're taking the negative terminal of your power supply as your 0V reference.
No current flows through R1, so the voltage across it is zero. This means that B is also at 5v.
Voltage is a potential. A good analogy is 'vertical height' in earth's gravity field, as far as energy goes.
In fact, it's such a well ingrained analogy that you'll notice I drew the diagram with height up the page to represent voltage. Most electronic engineers will do this, as it makes any schematic easier to understand.
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
$endgroup$
$begingroup$
Re, "No current flows through R1, so the voltage across it is zero." If you wanted to expand your answer a tiny bit, that would be a good place to mention Ohm's Law.
$endgroup$
– Solomon Slow
12 hours ago
$begingroup$
If you draw the resistor downwards, nothing will change. I don't know whether that information is helpful for @Mark or further confuses him. At least he didn't ask for it. I doubt he can deal with this information at his point of understanding.
$endgroup$
– Thomas Weller
11 hours ago
$begingroup$
V=I.R and this is a "pull up" resistor. The air gap between B and ground can be considered of sufficient resistance to be infinite. We could redraw the circuit as a voltage divider with ever increasing values between B and ground.
$endgroup$
– mckenzm
5 hours ago
add a comment |
$begingroup$
Voltage is normally relative to GND (0 V) (see remark of Elliot below).
When you have two terminals A and B and they are not inside a circuit (where there is a route from VCC or some voltage source to GND), there is no voltage difference.
So the terminal A and B would be both 5V, but no electricity will flow, just nothing happens. The resistor does not change anything, it will reduce the current, but since there is no electricity flowing, it will be 0 A.
Things will change as you connect B to GND. Than B will be 0 V, and there is a voltage difference of 5V, and the resistor changes the current, and the voltage difference over the resistor will be 5 V.
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
$endgroup$
4
$begingroup$
No, voltage is not always relative to ground. Voltage is always measured between two points, and if we don't specify both points then one of them is usually assumed to be a common reference point. The common reference point may be called ground.
$endgroup$
– Elliot Alderson
17 hours ago
1
$begingroup$
@ElliotAlderson Yes true, 'always' was not good to use, but didn't want it to make it more complex than needed; I changed my answer, thanks for the improvement.
$endgroup$
– Michel Keijzers
16 hours ago
add a comment |
$begingroup$
What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V -
Voltage at terminal “B” ?
"Potential difference" is the actual meaning of voltage. When you are given two points with different voltage levels, you have the potential difference across those two points. If one point is at 20V and reference point is at 10V, you have the potential difference (voltage) of (20-10=10V). In another scenario you have the same 20V point but reference point is now at 15V. So what's the voltage now? It's 5V.
When we say voltage we mean potential difference. And when someone says 20V (like I just did above), the reference point is 0V.
simulate this circuit – Schematic created using CircuitLab
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Let's turn your word picture into a real picture so we can see what's happening
simulate this circuit – Schematic created using CircuitLab
Voltage is always measured between two points, so when we quote the voltage of a single point, it's always understood that we are measuring the difference to some reference point.
I've taken the liberty of adding the ground or '0V' symbol. You've told us that 'A' is at 5v, which implies that you're taking the negative terminal of your power supply as your 0V reference.
No current flows through R1, so the voltage across it is zero. This means that B is also at 5v.
Voltage is a potential. A good analogy is 'vertical height' in earth's gravity field, as far as energy goes.
In fact, it's such a well ingrained analogy that you'll notice I drew the diagram with height up the page to represent voltage. Most electronic engineers will do this, as it makes any schematic easier to understand.
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
$endgroup$
$begingroup$
Re, "No current flows through R1, so the voltage across it is zero." If you wanted to expand your answer a tiny bit, that would be a good place to mention Ohm's Law.
$endgroup$
– Solomon Slow
12 hours ago
$begingroup$
If you draw the resistor downwards, nothing will change. I don't know whether that information is helpful for @Mark or further confuses him. At least he didn't ask for it. I doubt he can deal with this information at his point of understanding.
$endgroup$
– Thomas Weller
11 hours ago
$begingroup$
V=I.R and this is a "pull up" resistor. The air gap between B and ground can be considered of sufficient resistance to be infinite. We could redraw the circuit as a voltage divider with ever increasing values between B and ground.
$endgroup$
– mckenzm
5 hours ago
add a comment |
$begingroup$
Let's turn your word picture into a real picture so we can see what's happening
simulate this circuit – Schematic created using CircuitLab
Voltage is always measured between two points, so when we quote the voltage of a single point, it's always understood that we are measuring the difference to some reference point.
I've taken the liberty of adding the ground or '0V' symbol. You've told us that 'A' is at 5v, which implies that you're taking the negative terminal of your power supply as your 0V reference.
No current flows through R1, so the voltage across it is zero. This means that B is also at 5v.
Voltage is a potential. A good analogy is 'vertical height' in earth's gravity field, as far as energy goes.
In fact, it's such a well ingrained analogy that you'll notice I drew the diagram with height up the page to represent voltage. Most electronic engineers will do this, as it makes any schematic easier to understand.
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
$endgroup$
$begingroup$
Re, "No current flows through R1, so the voltage across it is zero." If you wanted to expand your answer a tiny bit, that would be a good place to mention Ohm's Law.
$endgroup$
– Solomon Slow
12 hours ago
$begingroup$
If you draw the resistor downwards, nothing will change. I don't know whether that information is helpful for @Mark or further confuses him. At least he didn't ask for it. I doubt he can deal with this information at his point of understanding.
$endgroup$
– Thomas Weller
11 hours ago
$begingroup$
V=I.R and this is a "pull up" resistor. The air gap between B and ground can be considered of sufficient resistance to be infinite. We could redraw the circuit as a voltage divider with ever increasing values between B and ground.
$endgroup$
– mckenzm
5 hours ago
add a comment |
$begingroup$
Let's turn your word picture into a real picture so we can see what's happening
simulate this circuit – Schematic created using CircuitLab
Voltage is always measured between two points, so when we quote the voltage of a single point, it's always understood that we are measuring the difference to some reference point.
I've taken the liberty of adding the ground or '0V' symbol. You've told us that 'A' is at 5v, which implies that you're taking the negative terminal of your power supply as your 0V reference.
No current flows through R1, so the voltage across it is zero. This means that B is also at 5v.
Voltage is a potential. A good analogy is 'vertical height' in earth's gravity field, as far as energy goes.
In fact, it's such a well ingrained analogy that you'll notice I drew the diagram with height up the page to represent voltage. Most electronic engineers will do this, as it makes any schematic easier to understand.
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
$endgroup$
Let's turn your word picture into a real picture so we can see what's happening
simulate this circuit – Schematic created using CircuitLab
Voltage is always measured between two points, so when we quote the voltage of a single point, it's always understood that we are measuring the difference to some reference point.
I've taken the liberty of adding the ground or '0V' symbol. You've told us that 'A' is at 5v, which implies that you're taking the negative terminal of your power supply as your 0V reference.
No current flows through R1, so the voltage across it is zero. This means that B is also at 5v.
Voltage is a potential. A good analogy is 'vertical height' in earth's gravity field, as far as energy goes.
In fact, it's such a well ingrained analogy that you'll notice I drew the diagram with height up the page to represent voltage. Most electronic engineers will do this, as it makes any schematic easier to understand.
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
edited 13 hours ago
pipe
10.4k4 gold badges27 silver badges59 bronze badges
10.4k4 gold badges27 silver badges59 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
answered 20 hours ago
Neil_UKNeil_UK
85.5k2 gold badges87 silver badges197 bronze badges
85.5k2 gold badges87 silver badges197 bronze badges
$begingroup$
Re, "No current flows through R1, so the voltage across it is zero." If you wanted to expand your answer a tiny bit, that would be a good place to mention Ohm's Law.
$endgroup$
– Solomon Slow
12 hours ago
$begingroup$
If you draw the resistor downwards, nothing will change. I don't know whether that information is helpful for @Mark or further confuses him. At least he didn't ask for it. I doubt he can deal with this information at his point of understanding.
$endgroup$
– Thomas Weller
11 hours ago
$begingroup$
V=I.R and this is a "pull up" resistor. The air gap between B and ground can be considered of sufficient resistance to be infinite. We could redraw the circuit as a voltage divider with ever increasing values between B and ground.
$endgroup$
– mckenzm
5 hours ago
add a comment |
$begingroup$
Re, "No current flows through R1, so the voltage across it is zero." If you wanted to expand your answer a tiny bit, that would be a good place to mention Ohm's Law.
$endgroup$
– Solomon Slow
12 hours ago
$begingroup$
If you draw the resistor downwards, nothing will change. I don't know whether that information is helpful for @Mark or further confuses him. At least he didn't ask for it. I doubt he can deal with this information at his point of understanding.
$endgroup$
– Thomas Weller
11 hours ago
$begingroup$
V=I.R and this is a "pull up" resistor. The air gap between B and ground can be considered of sufficient resistance to be infinite. We could redraw the circuit as a voltage divider with ever increasing values between B and ground.
$endgroup$
– mckenzm
5 hours ago
$begingroup$
Re, "No current flows through R1, so the voltage across it is zero." If you wanted to expand your answer a tiny bit, that would be a good place to mention Ohm's Law.
$endgroup$
– Solomon Slow
12 hours ago
$begingroup$
Re, "No current flows through R1, so the voltage across it is zero." If you wanted to expand your answer a tiny bit, that would be a good place to mention Ohm's Law.
$endgroup$
– Solomon Slow
12 hours ago
$begingroup$
If you draw the resistor downwards, nothing will change. I don't know whether that information is helpful for @Mark or further confuses him. At least he didn't ask for it. I doubt he can deal with this information at his point of understanding.
$endgroup$
– Thomas Weller
11 hours ago
$begingroup$
If you draw the resistor downwards, nothing will change. I don't know whether that information is helpful for @Mark or further confuses him. At least he didn't ask for it. I doubt he can deal with this information at his point of understanding.
$endgroup$
– Thomas Weller
11 hours ago
$begingroup$
V=I.R and this is a "pull up" resistor. The air gap between B and ground can be considered of sufficient resistance to be infinite. We could redraw the circuit as a voltage divider with ever increasing values between B and ground.
$endgroup$
– mckenzm
5 hours ago
$begingroup$
V=I.R and this is a "pull up" resistor. The air gap between B and ground can be considered of sufficient resistance to be infinite. We could redraw the circuit as a voltage divider with ever increasing values between B and ground.
$endgroup$
– mckenzm
5 hours ago
add a comment |
$begingroup$
Voltage is normally relative to GND (0 V) (see remark of Elliot below).
When you have two terminals A and B and they are not inside a circuit (where there is a route from VCC or some voltage source to GND), there is no voltage difference.
So the terminal A and B would be both 5V, but no electricity will flow, just nothing happens. The resistor does not change anything, it will reduce the current, but since there is no electricity flowing, it will be 0 A.
Things will change as you connect B to GND. Than B will be 0 V, and there is a voltage difference of 5V, and the resistor changes the current, and the voltage difference over the resistor will be 5 V.
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
$endgroup$
4
$begingroup$
No, voltage is not always relative to ground. Voltage is always measured between two points, and if we don't specify both points then one of them is usually assumed to be a common reference point. The common reference point may be called ground.
$endgroup$
– Elliot Alderson
17 hours ago
1
$begingroup$
@ElliotAlderson Yes true, 'always' was not good to use, but didn't want it to make it more complex than needed; I changed my answer, thanks for the improvement.
$endgroup$
– Michel Keijzers
16 hours ago
add a comment |
$begingroup$
Voltage is normally relative to GND (0 V) (see remark of Elliot below).
When you have two terminals A and B and they are not inside a circuit (where there is a route from VCC or some voltage source to GND), there is no voltage difference.
So the terminal A and B would be both 5V, but no electricity will flow, just nothing happens. The resistor does not change anything, it will reduce the current, but since there is no electricity flowing, it will be 0 A.
Things will change as you connect B to GND. Than B will be 0 V, and there is a voltage difference of 5V, and the resistor changes the current, and the voltage difference over the resistor will be 5 V.
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
$endgroup$
4
$begingroup$
No, voltage is not always relative to ground. Voltage is always measured between two points, and if we don't specify both points then one of them is usually assumed to be a common reference point. The common reference point may be called ground.
$endgroup$
– Elliot Alderson
17 hours ago
1
$begingroup$
@ElliotAlderson Yes true, 'always' was not good to use, but didn't want it to make it more complex than needed; I changed my answer, thanks for the improvement.
$endgroup$
– Michel Keijzers
16 hours ago
add a comment |
$begingroup$
Voltage is normally relative to GND (0 V) (see remark of Elliot below).
When you have two terminals A and B and they are not inside a circuit (where there is a route from VCC or some voltage source to GND), there is no voltage difference.
So the terminal A and B would be both 5V, but no electricity will flow, just nothing happens. The resistor does not change anything, it will reduce the current, but since there is no electricity flowing, it will be 0 A.
Things will change as you connect B to GND. Than B will be 0 V, and there is a voltage difference of 5V, and the resistor changes the current, and the voltage difference over the resistor will be 5 V.
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
$endgroup$
Voltage is normally relative to GND (0 V) (see remark of Elliot below).
When you have two terminals A and B and they are not inside a circuit (where there is a route from VCC or some voltage source to GND), there is no voltage difference.
So the terminal A and B would be both 5V, but no electricity will flow, just nothing happens. The resistor does not change anything, it will reduce the current, but since there is no electricity flowing, it will be 0 A.
Things will change as you connect B to GND. Than B will be 0 V, and there is a voltage difference of 5V, and the resistor changes the current, and the voltage difference over the resistor will be 5 V.
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
edited 16 hours ago
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
answered 20 hours ago
Michel KeijzersMichel Keijzers
8,10510 gold badges35 silver badges79 bronze badges
8,10510 gold badges35 silver badges79 bronze badges
4
$begingroup$
No, voltage is not always relative to ground. Voltage is always measured between two points, and if we don't specify both points then one of them is usually assumed to be a common reference point. The common reference point may be called ground.
$endgroup$
– Elliot Alderson
17 hours ago
1
$begingroup$
@ElliotAlderson Yes true, 'always' was not good to use, but didn't want it to make it more complex than needed; I changed my answer, thanks for the improvement.
$endgroup$
– Michel Keijzers
16 hours ago
add a comment |
4
$begingroup$
No, voltage is not always relative to ground. Voltage is always measured between two points, and if we don't specify both points then one of them is usually assumed to be a common reference point. The common reference point may be called ground.
$endgroup$
– Elliot Alderson
17 hours ago
1
$begingroup$
@ElliotAlderson Yes true, 'always' was not good to use, but didn't want it to make it more complex than needed; I changed my answer, thanks for the improvement.
$endgroup$
– Michel Keijzers
16 hours ago
4
4
$begingroup$
No, voltage is not always relative to ground. Voltage is always measured between two points, and if we don't specify both points then one of them is usually assumed to be a common reference point. The common reference point may be called ground.
$endgroup$
– Elliot Alderson
17 hours ago
$begingroup$
No, voltage is not always relative to ground. Voltage is always measured between two points, and if we don't specify both points then one of them is usually assumed to be a common reference point. The common reference point may be called ground.
$endgroup$
– Elliot Alderson
17 hours ago
1
1
$begingroup$
@ElliotAlderson Yes true, 'always' was not good to use, but didn't want it to make it more complex than needed; I changed my answer, thanks for the improvement.
$endgroup$
– Michel Keijzers
16 hours ago
$begingroup$
@ElliotAlderson Yes true, 'always' was not good to use, but didn't want it to make it more complex than needed; I changed my answer, thanks for the improvement.
$endgroup$
– Michel Keijzers
16 hours ago
add a comment |
$begingroup$
What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V -
Voltage at terminal “B” ?
"Potential difference" is the actual meaning of voltage. When you are given two points with different voltage levels, you have the potential difference across those two points. If one point is at 20V and reference point is at 10V, you have the potential difference (voltage) of (20-10=10V). In another scenario you have the same 20V point but reference point is now at 15V. So what's the voltage now? It's 5V.
When we say voltage we mean potential difference. And when someone says 20V (like I just did above), the reference point is 0V.
simulate this circuit – Schematic created using CircuitLab
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
$endgroup$
add a comment |
$begingroup$
What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V -
Voltage at terminal “B” ?
"Potential difference" is the actual meaning of voltage. When you are given two points with different voltage levels, you have the potential difference across those two points. If one point is at 20V and reference point is at 10V, you have the potential difference (voltage) of (20-10=10V). In another scenario you have the same 20V point but reference point is now at 15V. So what's the voltage now? It's 5V.
When we say voltage we mean potential difference. And when someone says 20V (like I just did above), the reference point is 0V.
simulate this circuit – Schematic created using CircuitLab
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
$endgroup$
add a comment |
$begingroup$
What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V -
Voltage at terminal “B” ?
"Potential difference" is the actual meaning of voltage. When you are given two points with different voltage levels, you have the potential difference across those two points. If one point is at 20V and reference point is at 10V, you have the potential difference (voltage) of (20-10=10V). In another scenario you have the same 20V point but reference point is now at 15V. So what's the voltage now? It's 5V.
When we say voltage we mean potential difference. And when someone says 20V (like I just did above), the reference point is 0V.
simulate this circuit – Schematic created using CircuitLab
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
$endgroup$
What is Voltage? Is it Voltage at the Terminal “B”? or it’s 5 V -
Voltage at terminal “B” ?
"Potential difference" is the actual meaning of voltage. When you are given two points with different voltage levels, you have the potential difference across those two points. If one point is at 20V and reference point is at 10V, you have the potential difference (voltage) of (20-10=10V). In another scenario you have the same 20V point but reference point is now at 15V. So what's the voltage now? It's 5V.
When we say voltage we mean potential difference. And when someone says 20V (like I just did above), the reference point is 0V.
simulate this circuit – Schematic created using CircuitLab
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
answered 15 hours ago
JuneStar_2918JuneStar_2918
3542 silver badges11 bronze badges
3542 silver badges11 bronze badges
add a comment |
add a comment |
Mark SEBASTIEN is a new contributor. Be nice, and check out our Code of Conduct.
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2
$begingroup$
The third question is the one you need to answer first.
$endgroup$
– Marcus Müller
20 hours ago
$begingroup$
What is the other point in the circuit to which you are making your voltage measurements? The other side of the 5V supply? Terminal "A"?
$endgroup$
– Peter Jennings
20 hours ago
$begingroup$
Try drawing the circuit. There is a great tool on this site. It may clarify the situation for you.
$endgroup$
– Warren Hill
20 hours ago